Avoid multiple calls to the same table in SQL

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  Hello
  You can separate the column with a case or decode.
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  case
  When usedtype = "PF".
  then - that contain both
  0 otherwise
  end

  case
  When usedtype = 'NF '.
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• place a select query calculation in a different column in the same table

  How can I put my calculation result in a column named within the same table?

  I have a table called: dgpercentagedatachart

  I use the columns of this dgpercentagedatachart: totalcecrating divided by lowestfeederrating times 100 to get the percentage

  In the query, I gave the result the Alias of the cal

  What I want is to put this result in my application or my calculation (in percentage) in my column "percent" on my table of dgpercentagedatachart vacuum.

  How can I configure this syntax?

  This is the select query, I came with:

  Select dgpercentagedatachart.totalcecrating, dgpercentagedatachart.lowestfeederrating,.

  100.00*dgpercentagedatachart.totalcecrating/dgpercentagedatachart.lowestfeederrating as cal

  of dgpercentagedatachart;

  Here are the results:

  CAL lowestfeederrating Totalcecrating

  8,978 7.48166666666666666666666666666666666667 120

  30.951 25.7925 120

  5.04                         120                          4.2

  Hello

  2685870 wrote:

  How can I put my calculation result in a column named within the same table?

  I have a table called: dgpercentagedatachart

  I use the columns of this dgpercentagedatachart: totalcecrating divided by lowestfeederrating times 100 to get the percentage

  In the query, I gave the result the Alias of the cal

  What I want is to put this result in my application or my calculation (in percentage) in my empty column '%' on my table of dgpercentagedatachart .

  How can I configure this syntax?

  This is the select query, I came with:

  Select dgpercentagedatachart.totalcecrating, dgpercentagedatachart.lowestfeederrating,.

  100.00*dgpercentagedatachart.totalcecrating/dgpercentagedatachart.lowestfeederrating as cal

  of dgpercentagedatachart;

  Here are the results:

  CAL lowestfeederrating Totalcecrating

  8,978 7.48166666666666666666666666666666666667 120

  30.951 25.7925 120

  5.04                         120                          4.2

  To change an existing column in a table, you can use the UPDATE or MERGE, instructions like this:

  UPDATE dgpercentagedatachart

  Percentage of VALUE = 100,00 * totalcecrating

  / lowestfeederrating

  ;

  Noramlly, tables is not redundant columns like this.  If percent can always be calculated from other columns, then it is probably better to calculate at run time and store it in the database, where you will have to be updated each time the columns it depends on change.  You can use a view to avoid having to encode them the calculation.

  If you really don't want a column that can be calculated in the same lines other columns, then use a virtual column (if you use Oracle 11 or higher).

  I hope that answers your question.

  If this isn't the case, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.

  If you ask on a DML statement, such as UPDATE, the sample data will be the content of the or the tables before the DML, and the results will be the State of the or the tables changed when it's all over.

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: Re: 2. How can I ask a question on the forums?

• Loading multiple files using the same interface in ODI

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• comparing string values in the same table

  I have a table with ID (14 digit string values) starting with "A". Ex: A21849B1020792. There may be a different ID with the same substring 'B1020792' in the same table, example: A12349B1020792. If this happens, the ID of the last creation date of must be returned in the result. In other words, comparison is done on the same table. "In the example provided, say A12349B1020792 has the date of 1 January 2015 'and A21849B1020792 has date February 1, 2015", since A21849B1020792 has the most recent date, the result must contain only A21849B1020792.

  ID create_date

  ---                              ------------------

  A21849B1020792 02/01/2015

  A12349 B1020792 01/01/2015

  A12345B1234567 01/03/2015      

  A43567B1234567 01/04/2015      

  
  Here's the query I used:

  substr (a.id, 7) select sc, max (a.create_date) cd1

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A12349B1020792', 'A21849B1020792','A12345B1234567 ','A43567B1234567')

  Group of substr (a.id, 7);

  Result:

  ---------

  sc                    cd1

  ---                    ------

  B1020792 02/01/2015

  B1234567 04/01/2015

  There is one thing that I'm not able to do with my request, that is, be able to get real IDs list and not list of substrings. If I added a.id column in the select clause and the group by clause, the query includes both by substr (a.id, 7) and a.id and as a result, the query returns four lines as below:

  substr (a.id, 7) select sc, max (a.create_date) cd1, a.id ID

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A12349B1020792', 'A21849B1020792','A12345B1234567 ','A43567B1234567')

  Group by substr (a.id, 7), a.id.

  Result:

  ---------

  sc                    cd1                      ID

  ---                    ------                   ---------

  01/01/2015 A12349B1020792 B1020792

  B1020792 01/02/2015 A21849B1020792

  B1234567 01/03/2015 A12345B1234567

  B1234567 01/04/2015 A43567B1234567

  
  

  My goal is to retrieve a list of all the unique identifiers that have the later dates.

  
  

  ID:

  ---

  A21849B1020792

  A43567B1234567

  
  

  Thanks for your time in advance!
  

  Hello

  user11951344 wrote:

  I have a table with ID (14 digit string values) starting with "A". Ex: A21849B1020792. There may be a different ID with the same substring "B1020792" in the same table, example: A12349B1020792. If this is the case, the ID of the last creation date must be returned in the result. In other words, comparison is done on the same table. "In the example provided, say A12349B1020792 updated 1 January 2015 ' and A21849B1020792 a date February 1, 2015", as A21849B1020792 has the most recent date, the result should contain only the A21849B1020792.

  ID create_date

  ---                              ------------------

  A21849B1020792 02/01/2015

  A12349B1020792 01/01/2015

  A12345B1234567 03/01/2015

  A43567B1234567 01/04/2015

  Here's the query I used:

  substr (a.id, 7) select sc, max (a.create_date) cd1

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A21849B1020792', 'A12345B1234567', 'A12349B1020792', 'A43567B1234567')

  Group of substr (a.id, 7);

  Result:

  ---------

  sc                    cd1

  ---                    ------

  B1020792 02/01/2015

  B1234567 01/04/2015

  There is one thing that I am not able to do with my request, that is, the ability to retrieve the list of IDs real and not a list of substrings. If I added a.id column in the select clause and the group by clause, the query groups according to the two substr (a.id, 7) and a.id and as a result, the query returns four lines as below:

  substr (a.id, 7) select sc, max (a.create_date) cd1, a.id ID

  of table a, table b

  where a.id! = b.id

  and substr (a.id, 7) = substr (b.id, 7)

  and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

  and a.id ('A21849B1020792', 'A12345B1234567', 'A12349B1020792', 'A43567B1234567')

  Group by substr (a.id, 7), a.id.

  Result:

  ---------

  sc                    cd1                      ID

  ---                    ------                   ---------

  B1020792 01/01/2015 A12349B1020792

  B1020792 02/01/2015 A21849B1020792

  B1234567 03/01/2015 A12345B1234567

  B1234567 01/04/2015 A43567B1234567

  My goal is to retrieve a list of all the unique identifiers that have the later dates.

  ID:

  ---

  A21849B1020792

  A43567B1234567

  Thanks for your time in advance!

  If it makes sense to treat the first 6 characters of the ID separately from the rest of the id in this problem, maybe it makes sense to store those two parts of the id in two different columns.  Relational databases work best when each column of each row contains 1 single piece of data (at most).  It is so fundamental to the design of table that he called the first normal form.

  Given that the two parts are stored in column 1, so you can something like this Request Top - N:

  WITH got_r_num AS

  (

  SELECT r.id

  r.create_date AS cd1

  , RANK () OVER (PARTITION OF SUBSTR (r.id, 7))

  ORDER BY r.create_date DESC

  ) AS r_num

  FROM table_x g - g for data values

  JOIN table_x r - r for related values

  ON SUBSTR (r.id, 7) = SUBSTR (g.id, 7)

  WHERE g.id IN ('A12349B1020792'

  , "A21849B1020792".

  , "A12345B1234567".

  , "A43567B1234567".

  )

  - AND g.id LIKE 'A %' - if necessary.   The above condition ensures already g.id start with "A".

  AND r.id LIKE 'a % '.

  )

  SELECT id, create_date

  OF got_r_num

  WHERE r_num = 1

  ;

  If you would care to post CREATE TABLE and INSERT instructions for the sample data, and then I could test this.

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  11g Release 2 (11.2) for AIX 5 L Based Systems (64-bit), HP - UX

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  In the section.

  The example SQL Server multiple databases: Configuration of the modem router

  A separate instance of the gateway that is required for each SQL Server database. Each

  instance needs its own Gateway system ID (SID).

  ==========

  You will need to create a new instance of the gateway for the SQL * Server DB2 as well as a link separate db.

  Kind regards

  Mike

• Multiple constraints on the same column

  Hello experts, we can use Multiple forced on the same column in oracle as creating table, I want to add a key single and forced to check on the same column is this possible? Thanks in advance,

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  CONSTRAINT ck1 CHECK (col1 IN ('A', 'B', 'C'))

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  );

• Make a column based on another value of the column in the same table

  JDev 11.1.1.6.0

  It may be a silly question but I'm stuck

  I need to conditionally return a column that said Condition is as if the value in the other column of the same table B is equal to F. I should make A column only when this condition is met. I tried the following code:

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  	headerText = "#{bindings." A.hints.PhoneNumber1.label}.
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  	rendering = "#{rank." PhoneNumber1ResponseFlag eq 'F'} ">"
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  	ID = "ot130" / >
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  	< af:column sortProperty = "PhoneNumber1ResponseFlag."
  	sortable = "false".
  	headerText = "#{bindings." B.hints.PhoneNumber1ResponseFlag.label}.
  	ID = "c80" rendered = "true" >
  	< af:outputText value = "#{rank." PhoneNumber1ResponseFlag}.
  	ID = "ot129" / >
  	< / af:column >

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  Well, I've finally sorted it myself by managed bean.

  Here are the steps I followed:

  1. Wrote a new bean managed.
  2. Added a Boolean variable called flag and made to true when the "'PhoneNumber1ResponseFlag ' current line attribute is equal to F."
  3. Changing the property made column on this indicator.