Make a column based on another value of the column in the same table

JDev 11.1.1.6.0

It may be a silly question but I'm stuck

I need to conditionally return a column that said Condition is as if the value in the other column of the same table B is equal to F. I should make A column only when this condition is met. I tried the following code:

< af:column sortProperty = "PhoneNumber1."
sortable = "false".
headerText = "#{bindings." A.hints.PhoneNumber1.label}.
ID = "c146.
rendering = "#{rank." PhoneNumber1ResponseFlag eq 'F'} ">"
< af:outputText value = "#{rank." PhoneNumber1}.
ID = "ot130" / >
< / af:column >
< af:column sortProperty = "PhoneNumber1ResponseFlag."
sortable = "false".
headerText = "#{bindings." B.hints.PhoneNumber1ResponseFlag.label}.
ID = "c80" rendered = "true" >
< af:outputText value = "#{rank." PhoneNumber1ResponseFlag}.
ID = "ot129" / >
< / af:column >

The data presented in the table for the PhoneNumber1ResponseFlag column are F. Still my condition does not work.

Well, I've finally sorted it myself by managed bean.

Here are the steps I followed:

  1. Wrote a new bean managed.
  2. Added a Boolean variable called flag and made to true when the "'PhoneNumber1ResponseFlag ' current line attribute is equal to F."
  3. Changing the property made column on this indicator.

Tags: Java

Similar Questions

  • State of color lines based on a value in the same row

    I would like to color report lines based on a value in the same row.

    For bolting with the table 'EMP ':

    I would like job = MANAGER and Red work = CLERK to be green etc etc.

    The other example I found was the possibility of a single color either the nail or the default color.

    I'm looking for a way to do multiple colors.

    Hello

    In the model line, you can use #1 #, 2 # #, etc. to indicate where a field in the report should be released. It doesn't have to be clear - that is to say, you can use it in style tags if you wish.

    So take a query such as:

    SELECT EMPNO,
ENAME,
DEPTNO,
DECODE(DEPTNO, 10, 'green', 20, 'red', 30, 'cyan', 'white') BG_COLOUR
FROM EMP

    You get the column 1 = empno, 2 = ename, 3 = deptno and 4 = bg_colour. In the model line, you can then do:

    Before defining lines (implements the table):

    <table>
<tr><td>ID</td><td>Name</td><td>Dept</td></tr>

    After setting (farm table) lines:

    </table>

    Model 1 (used for all lines) line:

    <tr style="background-color:#4#;"><td>#1#</td><td>#2#</td><td>#3#</td></tr>

    Then, for each row, the color that has been calculated by using the DECODE function is used in the style tag for color the background of the whole line.

    How to determine the colors, it's you. I used DECODE here, but you can use a field on the DEPT table to hold and use it in your SQL statement.

    Andy

  • comparing string values in the same table

    I have a table with ID (14 digit string values) starting with "A". Ex: A21849B1020792. There may be a different ID with the same substring 'B1020792' in the same table, example: A12349B1020792. If this happens, the ID of the last creation date of must be returned in the result. In other words, comparison is done on the same table. "In the example provided, say A12349B1020792 has the date of 1 January 2015 'and A21849B1020792 has date February 1, 2015", since A21849B1020792 has the most recent date, the result must contain only A21849B1020792.

    ID create_date

    ---                              ------------------

    A21849B1020792 02/01/2015

    A12349 B1020792 01/01/2015

    A12345B1234567 01/03/2015      

    A43567B1234567 01/04/2015      


    Here's the query I used:

    substr (a.id, 7) select sc, max (a.create_date) cd1

    of table a, table b

    where a.id! = b.id

    and substr (a.id, 7) = substr (b.id, 7)

    and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

    and a.id ('A12349B1020792', 'A21849B1020792','A12345B1234567 ','A43567B1234567')

    Group of substr (a.id, 7);

    Result:

    ---------

    sc                    cd1

    ---                    ------

    B1020792 02/01/2015

    B1234567 04/01/2015

    There is one thing that I'm not able to do with my request, that is, be able to get real IDs list and not list of substrings. If I added a.id column in the select clause and the group by clause, the query includes both by substr (a.id, 7) and a.id and as a result, the query returns four lines as below:

    substr (a.id, 7) select sc, max (a.create_date) cd1, a.id ID

    of table a, table b

    where a.id! = b.id

    and substr (a.id, 7) = substr (b.id, 7)

    and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

    and a.id ('A12349B1020792', 'A21849B1020792','A12345B1234567 ','A43567B1234567')

    Group by substr (a.id, 7), a.id.

    Result:

    ---------

    sc                    cd1                      ID

    ---                    ------                   ---------

    01/01/2015 A12349B1020792 B1020792

    B1020792 01/02/2015 A21849B1020792

    B1234567 01/03/2015 A12345B1234567

    B1234567 01/04/2015 A43567B1234567


    My goal is to retrieve a list of all the unique identifiers that have the later dates.


    ID:

    ---

    A21849B1020792

    A43567B1234567


    Thanks for your time in advance!

    Hello

    user11951344 wrote:

    I have a table with ID (14 digit string values) starting with "A". Ex: A21849B1020792. There may be a different ID with the same substring "B1020792" in the same table, example: A12349B1020792. If this is the case, the ID of the last creation date must be returned in the result. In other words, comparison is done on the same table. "In the example provided, say A12349B1020792 updated 1 January 2015 ' and A21849B1020792 a date February 1, 2015", as A21849B1020792 has the most recent date, the result should contain only the A21849B1020792.

    ID create_date

    ---                              ------------------

    A21849B1020792 02/01/2015

    A12349B1020792 01/01/2015

    A12345B1234567 03/01/2015

    A43567B1234567 01/04/2015

    Here's the query I used:

    substr (a.id, 7) select sc, max (a.create_date) cd1

    of table a, table b

    where a.id! = b.id

    and substr (a.id, 7) = substr (b.id, 7)

    and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

    and a.id ('A21849B1020792', 'A12345B1234567', 'A12349B1020792', 'A43567B1234567')

    Group of substr (a.id, 7);

    Result:

    ---------

    sc                    cd1

    ---                    ------

    B1020792 02/01/2015

    B1234567 01/04/2015

    There is one thing that I am not able to do with my request, that is, the ability to retrieve the list of IDs real and not a list of substrings. If I added a.id column in the select clause and the group by clause, the query groups according to the two substr (a.id, 7) and a.id and as a result, the query returns four lines as below:

    substr (a.id, 7) select sc, max (a.create_date) cd1, a.id ID

    of table a, table b

    where a.id! = b.id

    and substr (a.id, 7) = substr (b.id, 7)

    and a.id like 'A %' and b.id like 'A %' / * (I used a % because I am interested only IDs that begin with A) * /.

    and a.id ('A21849B1020792', 'A12345B1234567', 'A12349B1020792', 'A43567B1234567')

    Group by substr (a.id, 7), a.id.

    Result:

    ---------

    sc                    cd1                      ID

    ---                    ------                   ---------

    B1020792 01/01/2015 A12349B1020792

    B1020792 02/01/2015 A21849B1020792

    B1234567 03/01/2015 A12345B1234567

    B1234567 01/04/2015 A43567B1234567

    My goal is to retrieve a list of all the unique identifiers that have the later dates.

    ID:

    ---

    A21849B1020792

    A43567B1234567

    Thanks for your time in advance!

    If it makes sense to treat the first 6 characters of the ID separately from the rest of the id in this problem, maybe it makes sense to store those two parts of the id in two different columns.  Relational databases work best when each column of each row contains 1 single piece of data (at most).  It is so fundamental to the design of table that he called the first normal form.

    Given that the two parts are stored in column 1, so you can something like this Request Top - N:

    WITH got_r_num AS

    (

    SELECT r.id

    r.create_date AS cd1

    , RANK () OVER (PARTITION OF SUBSTR (r.id, 7))

    ORDER BY r.create_date DESC

    ) AS r_num

    FROM table_x g - g for data values

    JOIN table_x r - r for related values

    ON SUBSTR (r.id, 7) = SUBSTR (g.id, 7)

    WHERE g.id IN ('A12349B1020792'

    , "A21849B1020792".

    , "A12345B1234567".

    , "A43567B1234567".

    )

    - AND g.id LIKE 'A %' - if necessary.   The above condition ensures already g.id start with "A".

    AND r.id LIKE 'a % '.

    )

    SELECT id, create_date

    OF got_r_num

    WHERE r_num = 1

    ;

    If you would care to post CREATE TABLE and INSERT instructions for the sample data, and then I could test this.

  • Updated with the values in the same table, for other records corresponding to conditions

    Hi Experts,

    Sorry do not provide the structure of the table (it is a simple structure)

    I have a requirement where I need to update the columns of a table based on the same table with some match empid and date values. If the date and empid match so I have these values to any other folder and update of one who is not having details of Office . I need the Update query

    Before the update my array of values is as below

    Sort_num Emp_id Bureau start_date

    1 101 AUS 01/01/2013
    2 101 01/01/2013
    3 101 15/01/2013
    4 103 USA 01/05/2013
    5 103 01/01/2013
    6 103 05/01/2013
    7 104 FRA 01/10/2013
    8 104 10/01/2013
    9 104 01/01/2013

    After update my table should be as below

    Sort_num Emp_id Bureau start_date

    1 101 AUS 01/01/2013
    2 101 AUS 01/01/2013
    3 101 15/01/2013
    4 103 USA 01/05/2013
    5 103 01/01/2013
    6 103 USA 01/05/2013
    7 104 FRA 01/10/2013
    8 104 FRA 01/10/2013
    9 104 01/01/2013

    Thanks in advance

    I don't have the time to create the table with the data, but basically, you should be able to code the following text

    update one table

    Office set = (select desktop in table b where b.emp_id = a.emp_id)

    and b.start_date = a.start_date

    and b.office is not null

    )

    where is ([as well as overall query])

    and a.office is null

    In my opinion, who will do the trick.

    HTH - Mark D Powell.

  • Tabular presentation - column to turn it off (with picture) based on another value of the column

    Hi all

    I haven't worked much on tabular forms and JS. I'm looking for help in this regard.

    I'm working on a tabular presentation. with several editable fields... I need to disable a column (just for this single line), which contains an image, based on a field of LOV (static) list) (Y/N). The image column must be disabled if the value is N.

    My SQL for the report is something like this: (will keep things simple)

    Select

    emp_id,

    emp_name,

    static_list,

    (case when STATIC_LIST = "Y" THEN ' < a title = "Edit SAMPLE TBL" href = "f?) p = & APP_ID.:10: & APP_SESSION.:NO:P10_EMP_ID, P10_EMP_NAME :'|| EMP_ID | «, » || EMP_NAME | "" "> < img src =" "#IMAGE_PREFIX #SAMPLE.gif" border = '0' (> < /a > ' other ' ' end) as disable_col, "

    dept_name

    of sample_table

    I scoured the topics in this forum. Most of them were made using the table ID f_001, f_002.

    I tried to follow the same path by inspecting the item but the disable_col does not have any ID.  Let's say, f_003 is for the static list and f_004 is assigned to dept_name.

    I tried dynamic actions, but it did not work. Read in a topic that dynamic action does not work on tables. So I chose this approach. Is there a simpler way to solve this?

    need your help on how to proceed with this scenario. Thank you in advance.

    Versions: Apex: 4.2, DB: 11 g

    Thank you

    Daniel

    Hi Daniel_A,

    Daniel_A wrote:

    I did my job in Page 4.

    If the IS_VALID column is select as 'Yes' then the column hyper must be enabled, allowing the user to click on it. If she chose the 'no', then the column Hyper must be disabled for this line.

    The initial question about toggle the hyperlink is resolved. Check your App-> Page 4 35160.

    This is done with the help of two dynamic actions:

    • DA first loading of the Page / after updating of region "tabular":

    Event: After refresh

    Selection type: region

    Region: The other 'tabular '.

    Condition: No strings attached

    Action: Run the JavaScript Code

    Fire on loading the Page: Yes

    Code:

    $( 'select[name="f08"]' ).each(function() {
  if ( $(this).val() === "N" ) {
    $(this).closest("tr").find('td[headers="HYPER"]').find("a").addClass("apex_disabled").unbind("click");
  }
});

    Items concerned: no item affected

    • Second DA on the evolution of the selection list:

    Event: change

    Selection type: jQuery Selector

    jQuery Selector: select [name = "f08"]

    Condition: No strings attached

    Action: Run the JavaScript Code

    Fire on loading the Page: No.

    Code:

    var el = this.triggeringElement;
if ( el.value === "N" ) {
    $(el).closest("tr").find('td[headers="HYPER"]').find("a").addClass("apex_disabled").unbind("click");
} else {
    $(el).closest("tr").find('td[headers="HYPER"]').find("a").removeClass("apex_disabled").bind("click");
}

    Items concerned: no item affected

    NOTE: as the original question/topic related to toggle the image link in the column, for the problem with the Page 5, please create a new thread with the details.

    Kind regards

    Kiran

  • Update the value of the column based on another value of the column to another table

    Hi all

    I have something very confused me and need your help.

    Having two tables A and B.

    Table A have 2 column (+ id + and desc1)

    Table B have column 2 also (+ transnum + and desc2)

    Now, I want to update the column desc2 of table B identical desc1 of table was where transnum of Table B same as the id of the table has.

    I use this SQL

    update of a2 set a2.desc2 = a1.desc1 of a2 on a2.transnum = a1.id inner join a1

    but this error occurs

    Error from line 5 in order:
    update of a2 set a2.desc2 = a1.desc1 of a2 on a2.transnum = a1.id inner join a1
    Error in the command line: 5 column: 35
    Error report:
    SQL error: ORA-00933: SQL not correctly completed command
    * 00933. 00000 - "command not properly ended SQL."
    * Question: *.

    * Action. *

    Hope someone can help me. TQ for help... 
    SQL> create table a1 (id number(2),des varchar2(10));

Table created.

SQL> create table b1 (transnum number(2),des varchar2(10));

Table created.

SQL> insert into a1 values (1,'maran');

1 row created.

SQL> insert into b1 values (1,'ram');

1 row created.

SQL> commit;

Commit complete.

SQL> update b1 set des=(select des from a1 where b1.transnum=a1.id);

1 row updated.

SQL> select * from b1;

  TRANSNUM DES
---------- ----------
         1 maran

  • update of column based on the values of the same table

    I have the T1 table with 4 columns "col1", "col2", "col3", "col4", "col5", "col6" as follows

    Col1 Col2 Col3 Col4 Col5 Col6
    1111 Ville1 C AA DDD A1
    2222 city SD HHH A1 1
    3333 City2 B EE OOO
    4444 City 1 B JJ SSS A1
    5555 City2 C KK VVV
    6666 City2 RR QQQ
    7777 City2 B BBB XX

    I've already updated column value 6 'A1' where the 2 column is 'Ville1 '.

    Now, I want to update Col. 6 where col2 is the of ' with the following conditions
    If Col 3 = 'B', then Col6 should be = col4
    Otherwise, it should be = col5

    SET col6 = DECODE(col3,'B',col4,col5)
    "WHERE col2 = s"

  • Need a script to select the update the row to another row in the same table

    I have a table with the columns and values
    KeyID       EffectiveDate     InactiveDate
1              01/01/2013
1              01/02/2013
1              01/03/2013
2              12/31/2012
2              01/02/2013
2              01/03/2013
    I need to update the InactiveDate of a line with the EffectiveDate of a line with the EffectiveDate newer than the update line and the even KeyID.
    KeyID       EffectiveDate     InactiveDate
1              01/01/2013      01/02/2013
1              01/02/2013      01/03/2013
1              01/03/2013
2              12/31/2012      01/02/2013
2              01/02/2013      01/03/2013
2              01/03/2013
    I want to have a select script that shows
    KeyID       EffectiveDate        InactiveDate    New_InactiveDate
1              01/01/2013                              01/02/2013
1              01/02/2013                              01/03/2013
1              01/03/2013
2              12/31/2012                              01/02/2013
2              01/02/2013                              01/03/2013
2              01/03/2013
    Thanks for any help.

    Published by: 881656 on January 3, 2013 17:57

    Published by: 881656 on January 3, 2013 18:15

    Published by: 881656 on January 3, 2013 18:20

    Hello

    881656 wrote:
    I have a table with the columns and values

    KeyID       EffectiveDate     InactiveDate
1              01/01/2013
1              01/02/2013
1              01/03/2013
2              12/31/2012
2              01/02/2013
2              01/03/2013

I need to update the InactiveDate of a row with the EffectiveDate of a row with the newer EffectiveDate than the row to be updated and with the same KeyID.

KeyID       EffectiveDate     InactiveDate
1              01/01/2013      01/02/2013
1              01/02/2013      01/03/2013
1              01/03/2013
2              12/31/2012      01/02/2013
2              01/02/2013      01/03/2013
2              01/03/2013

    This sounds like a job for the analytical function of LEAD:

    MERGE INTO table_x     dst
USING (
     SELECT  keyid
     ,     effectivedate
     ,     LEAD (effectivedate) OVER ( PARTITION BY  keyid
                                       ORDER BY         activedate
                                     )            AS inactivedate
      )               src
WHEN MATCHED THEN UPDATE
ON    (    src.id          = dst.id
      AND  src.effectivedate     = dst.effectivedate
      )
SET     dst.inactivedate     = src.inactivedate
;

    I want to have a select script which shows

KeyID       EffectiveDate        InactiveDate    New_InactiveDate
1              01/01/2013                              01/02/2013
1              01/02/2013                              01/03/2013
1              01/03/2013
2              12/31/2012                              01/02/2013
2              01/02/2013                              01/03/2013
2              01/03/2013

    Once that you have done the above MERGER, it is simply:

    SELECT    *
FROM      table_x
ORDER BY  keyid
,         effectivedate
;

    If you do not have sthe FUSION, then see the query in the USING clause of the MERGER.

    I hope that answers your question.
    If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements), and the results you want from this data.
    In the case of a DML (UPDATE), for example, the sample data should show what looks like the tables before the DML, and the results will be the content of the table changed after the DML.
    Explain, using specific examples, how you get these results from these data.
    Always say what version of Oracle you are using (for example, 11.2.0.2.0).
    See the FAQ forum {message identifier: = 9360002}

  • Create a query to compare the values in the same table

    Suppose you have the table, below even ID occur for the same month as well as different months

    ID value of months
    --------------------------------------------------------------
    226220 201203 100
    1660 201204 200
    26739 201204 1010
    7750 201205 31.1

    I need a query to determine the results laid below

    The month ID value Prior_month_value Prior_Month
    ----------------------------------------------------------------------------
    1234 201203 10 201201 100
    3456 201206 56.1 201204 78


    Help, please

    Published by: Jaguar on 10 July 2012 03:00

    With the information we have, it's the best we can get to...

    SQL> with t as (select 226220 as ID, 201203 as Month, 100 as Value from dual union all
  2             select 1660, 201204, 200 from dual union all
  3             select 26739, 201204, 1010 from dual union all
  4             select 7750, 201205, 31.1 from dual)
  5  --
  6  -- end of example data
  7  --
  8  select decode(rownum,1,1234,3456) as id
  9        ,decode(rownum,1,201203,201206) as month
 10        ,decode(rownum,1,10,56.1) as prior_month_value
 11        ,decode(rownum,1,201201,201204) as prior_month
 12        ,decode(rownum,1,100,78) as value
 13  from (
 14        select * from t where rownum <= 2
 15       )
 16  /

        ID      MONTH PRIOR_MONTH_VALUE PRIOR_MONTH      VALUE
---------- ---------- ----------------- ----------- ----------
      1234     201203                10      201201        100
      3456     201206              56.1      201204         78

    Waste in... trash out.

  • Looping through the names of columns that are based on a value of the variable

    I have an ArrayCollection collection with a series of columns named price1, price2... through price10

    I try through these columns based on a value of the loop variable, but may not understand the syntax:

    for (var column: int = 1; column < 11; column ++) {}
    testPrice = myGrid.selectedItem.price (column); <-this does not work
    }

    Try testPrice = myGrid.selectedItem ["price" + column];

    Don't forget to test this selectedItem is not null before you try to set the values.

    TS

  • Display list items based on another element of the list

    Hi all

    I want to display the list item based on another element of the list, but his does not work.

    This is my code:


    / * WHEN-NEW-FORM-INSTANCE * /-his work.
    DECLARE

    rg_district recordgroup;

    rg_name VARCHAR2 (40): = "district";

    vtemp NUMBER;

    BEGIN

    rg_district: = FIND_GROUP (rg_name);

    IF ID_NULL (rg_district)

    THEN

    rg_district: =.

    CREATE_GROUP_FROM_QUERY (rg_name,

    'select dist, dist district_mas.

    );

    vtemp: = POPULATE_GROUP (rg_district);

    POPULATE_LIST ('BLOCK3.) Of RIDING ", rg_name);

    END IF;

    END;

    * / CHANGED AFTER a - list * /-does not work. Cannot complete the list based on the list

    DECLARE

    rg_branch recordgroup;

    rg_name1 VARCHAR2 (1000): = "branch";

    vtemp NUMBER;

    BEGIN

    rg_branch: = FIND_GROUP (rg_name1);

    IF this is ID_NULL (rg_branch)

    THEN

    DELETE_GROUP (rg_name1);

    rg_branch: =.

    CREATE_GROUP_FROM_QUERY

    ("rg_branch",

    "SELECT FROM dist_branch WHERE district IN branch (DIST DISTRICT_MAS WHERE DISTRICT = SELECT').

    || : BLOCK3. DISTRICT OF

    );

    vtemp: = POPULATE_GROUP (rg_branch);

    POPULATE_LIST ('BLOCK3.) Branch of THE ', rg_branch);

    END IF;

    END;

    Table:

    CREATE TABLE DISTRICT_MAS

    (

    DIST VARCHAR2 (100 CHAR)

    );

    CREATE TABLE DIST_BRANCH

    (

    NEIGHBORHOOD VARCHAR2 (100 CHAR),

    DIRECTORATE GENERAL OF THE VARCHAR2 (100 CHAR)

    );

    Values:

    insert into district_mas values ('chennai');

    insert into district_mas values ('coimbatore');

    insert into dist_branch values ('chennai', 'chennai_north');

    insert into dist_branch values ('coimbatore', 'Podanur');


    Concerning

    Nassik M

    I tested the code below when the list has changed


    DECLARE

    rg_branch recordgroup;

    rg_name1 VARCHAR2 (1000): = "branch";

    vtemp NUMBER;

    QT VARCHAR2 (10): = "';

    BEGIN

    rg_branch: = FIND_GROUP (rg_name1);

    IF this is ID_NULL (rg_branch)

    THEN

    DELETE_GROUP (rg_name1);

    END IF;

    rg_branch: =.

    CREATE_GROUP_FROM_QUERY

    (rg_name1,

    'SELECT branch, branch OF THE DISTRICT WHERE the dist_branch =' | QT | : BLOCK3. DISTRICT OF | QT);

    vtemp: = POPULATE_GROUP (rg_branch);

    POPULATE_LIST ('BLOCK3.) Branch of THE ', rg_branch);

    END;

    Hope it's work...

    Hamid

  • How to update columns with the value of other lines in the same table

    Hello

    I use Oracle 11.2, I'd use SQL statements to update a column based on values in other rows in the same table. Here are the details:

    create table TB_test (number 4 myId, crtTs date, date of MDPU);

    insert into tb_test (1, to_date ('20110101', 'YYYYMMDD'), null);
    insert into tb_test (1, to_date ('20110201', 'YYYYMMDD'), null);
    insert into tb_test (1, to_date ('20110301', 'YYYYMMDD'), null);
    insert into tb_test (2, to_date ('20110901', 'YYYYMMDD'), null);
    insert into tb_test (2, to_date ('20110902', 'YYYYMMDD'), null);

    After you run the SQL code, I would like to have the following result:

    1, 20110101, 20110201
    1, 20110201, 20110301
    1, 20110301, null
    2, 20110901, 20110902
    2, 20110902, null

    Thanks for your suggestion.

    I guess you need this, otherwise please explain logic correctly:

    SQL> merge into tb_test t
  2  using (
  3    select rowid as rid
  4         , lead(crtts) over(partition by myid order by crtts) as updts
  5    from tb_test
  6  ) v
  7  on (t.rowid = v.rid)
  8  when matched then update
  9   set t.updts = v.updts
 10  ;

5 rows merged.

SQL> select * from tb_test order by 1,2;

      MYID CRTTS     UPDTS
---------- --------- ---------
         1 01-JAN-11 01-FEB-11
         1 01-FEB-11 01-MAR-11
         1 01-MAR-11
         2 01-SEP-11 02-SEP-11
         2 02-SEP-11

  • update to column values (false) in a copy of the same table with the correct values

    Database is 10gr 2 - had a situation last night where someone changed inadvertently values of column on a couple of hundred thousand records with an incorrect value first thing in the morning and never let me know later in the day. My undo retention was not large enough to create a copy of the table as it was 7 hours comes back with a "insert in table_2 select * from table_1 to timestamp...» "query, so I restored the backup previous nights to another machine and it picked up at 07:00 (just before the hour, he made the change), created a dblink since the production database and created a copy of the table of the restored database.

    My first thought was to simply update the table of production with the correct values of the correct copy, using something like this:


    Update mnt.workorders
    Set approvalstat = (select b.approvalstat
    mnt.workorders a, mnt.workorders_copy b
    where a.workordersoi = b.workordersoi)
    where exists (select *)
    mnt.workorders a, mnt.workorders_copy b
    where a.workordersoi = b.workordersoi)

    It wasn't the exact syntax, but you get the idea, I wanted to put the incorrect values in x columns in the tables of production with the correct values of the copy of the table of the restored backup. Anyway, it was (or seem to) works, but I look at the process through OEM it was estimated 100 + hours with full table scans, so I killed him. I found myself just inserting (copy) the lines added to the production since the table copy by doing a select statement of the production table where < col_with_datestamp > is > = 07:00, truncate the table of production, then re insert the rows from now to correct the copy.

    Do a post-mortem today, I replay the scenario on the copy that I restored, trying to figure out a cleaner, a quicker way to do it, if the need arise again. I went and randomly changed some values in a column number (called "comappstat") in a copy of the table of production, and then thought that I would try the following resets the values of the correct table:

    Update (select a.comappstat, b.comappstat
    mnt.workorders a, mnt.workorders_copy b
    where a.workordersoi = b.workordersoi - this is a PK column
    and a.comappstat! = b.comappstat)
    Set b.comappstat = a.comappstat

    Although I thought that the syntax is correct, I get an "ORA-00904: 'A'. '. ' COMAPPSTAT': invalid identifier ' to run this, I was trying to guess where the syntax was wrong here, then thought that perhaps having the subquery returns a single line would be cleaner and faster anyway, so I gave up on that and instead tried this:

    Update mnt.workorders_copy
    Set comappstat = (select distinct)
    a.comappstat
    mnt.workorders a, mnt.workorders_copy b
    where a.workordersoi = b.workordersoi
    and a.comappstat! = b.comappstat)
    where a.comappstat! = b.comappstat
    and a.workordersoi = b.workordersoi

    The subquery executed on its own returns a single value 9, which is the correct value of the column in the table of the prod, and I want to replace the incorrect a '12' (I've updated the copy to change the value of the column comappstat to 12 everywhere where it was 9) However when I run the query again I get this error :

    ERROR on line 8:
    ORA-00904: "B". "" WORKORDERSOI ": invalid identifier

    First of all, I don't see why the update statement does not work (it's probably obvious, but I'm not)

    Secondly, it is the best approach for updating a column (or columns) that are incorrect, with the columns in the same table which are correct, or is there a better way?

    I would sooner update the table rather than delete or truncate then re insert, as it was a trigger for insert/update I had to disable it on the notice re and truncate the table unusable a demand so I was re insert.

    Thank you

    Hello

    First of all, after post 79, you need to know how to format your code.

    Your last request reads as follows:

    UPDATE
  mnt.workorders_copy
SET
  comappstat =
  (
    SELECT DISTINCT
      a.comappstat
    FROM
      mnt.workorders a
    , mnt.workorders_copy b
    WHERE
      a.workordersoi    = b.workordersoi
      AND a.comappstat != b.comappstat
  )
WHERE
  a.comappstat      != b.comappstat
  AND a.workordersoi = b.workordersoi

    This will not work for several reasons:
    The sub query allows you to define a and b and outside the breakets you can't refer to a or b.
    There is no link between the mnt.workorders_copy and the the update and the request of void.

    If you do this you should have something like this:

    UPDATE
  mnt.workorders     A      -- THIS IS THE TABLE YOU WANT TO UPDATE
SET
  A.comappstat =
  (
    SELECT
      B.comappstat
    FROM
      mnt.workorders_copy B   -- THIS IS THE TABLE WITH THE CORRECT (OLD) VALUES
    WHERE
      a.workordersoi    = b.workordersoi      -- THIS MUST BE THE KEY
      AND a.comappstat != b.comappstat
  )
WHERE
  EXISTS
  (
    SELECT
      B.comappstat
    FROM
      mnt.workorders_copy B
    WHERE
      a.workordersoi    = b.workordersoi      -- THIS MUST BE THE KEY
      AND a.comappstat != b.comappstat
  )

    Speed is not so good that you run the query to sub for each row in mnt.workorders
    Note it is condition in where. You need other wise, you will update the unchanged to null values.

    I wouold do it like this:

    UPDATE
  (
    SELECT
      A.workordersoi
      ,A.comappstat
      ,B.comappstat           comappstat_OLD

    FROM
      mnt.workorders        A      -- THIS IS THE TABLE YOU WANT TO UPDATE
      ,mnt.workorders_copy  B      -- THIS IS THE TABLE WITH THE CORRECT (OLD) VALUES

    WHERE
      a.workordersoi    = b.workordersoi      -- THIS MUST BE THE KEY
      AND a.comappstat != b.comappstat
  ) C

SET
  C.comappstat = comappstat_OLD
;

    This way you can test the subquery first and know exectly what will be updated.
    This was not a sub query that is executed for each line preformance should be better.

    Kind regards

    Peter

  • Multiple values for the same column in the columns of diffétent in the same row?

    Hi all
    I wonder how you can display different values for the same column in different columns on the same line. For example, using a CASE statement, I can:

    CASE WHEN CODE IN ('1 ', ' 3') THEN COUNT (ID) AS 'Y '.
    CASE WHEN CODE NOT IN ('1 ', am') THEN COUNT (ID) AS "N".

    Yes, that will produce two columns but will produce null values to empty and also two separate registers.


    Any ideas?

    Thank you

    Are you sure that this code works for you?

    Select ID
         ,CASE WHEN MODE_CODE IN ('1', '3') THEN COUNT( No) END as "Fulltime"
         ,CASE WHEN MODE_CODE NOT IN ('1', '3') THEN COUNT( No ) END  as "Other"
From table
group by ID

    I guess the code above fails because MODE_CODE is not in your group by?

    My suggestion would be to put the CASE in the COUNT:

    Select ID
         ,COUNT(CASE WHEN MODE_CODE IN ('1', '3') THEN No END) as "Fulltime"
         ,COUNT(CASE WHEN MODE_CODE NOT IN ('1', '3') THEN No END)  as "Other"
From table
group by ID

    CASE expressions return no. when the respective conditions are true and NULL otherwise.
    COUNTY will have non-null values.

  • Select literal values in the same column

    Hello
    like the practice:

    Select 'A', 'B', 'C' for double
    will select these values in their own column on the same line, is there a simple way to select these values in the same column on lines without first their insertion into a table?

    Thank you 
    SQL> select 'A' x from dual union
  2  select 'B' x from dual union
  3  select 'C' x from dual ;

X
-
A
B
C

    A bit complicated:

    SQL> select chr(ascii('A')+level-1) x
  2  from dual
  3  connect by level <=3;

X
-
A
B
C

    Other:

    SQL> select regexp_substr('ABC','[[:alpha:]]',1,level) x
  2  from dual
  3  connect by level <= length('ABC');

X
---
A
B
C

    Max
    http://oracleitalia.WordPress.com

    Published by: Massimo Ruocchio, February 12, 2010 17:55
    added a second

    Published by: Massimo Ruocchio, February 12, 2010 17:58
    Added the third

Maybe you are looking for

  • The name on my iMac to start

    When I turn on my machine, I have a small circle in the middle with a picture on and my wife below name. My wife passed away on January 8 this year and I have managed to change his pic, but I would like to change the name under my own name How it's d

  • How to reactivate my tool bar menu?

    I disabled the toolbar menu. Now with no menu, I can't turn it back on.I uninstalled firefox. I downloaded the new version and installed it, but it opens without a toolbar menu. This has happened Each time Firefox opened == I accidentally disabled th

  • XP Pro gives me error message &#60; root windows &#62; \system32\ntoskrnl.exe is damaged and must be replaced. How to replace or fix this problem?

    I tried to reinstall XP Pro, but then I get another error message the file for web printer windows cannot find so it won't let me not finished reinstalling XP.  How can I solve this problem or solve the problem with the ntoskrnl.exe that need to be r

  • Port before 1723 Linksys WRT1900AC (VPN)

    I can't establish a VPN tunnel to my desktop using PPTP (built in vpn windows) machine. I have a Linksys WRT1900AC, latest firmware (1.1.8.164461) I implemented the single port forwarding (this machine has a static ip address below): I can ping the m

  • 5.3 update LR &amp; Adobe CC

    I have Cougar 10.8.5 on my IMac. I use LR 5.3. I intend to go to the Sierra of Mountain Lion. I am also considering buying finally CC although most of my editing (95% +) is done in LR.Should I switch to Sierra first or CC first?