Big v running small compositions containing only vector files

Hey all, make both of these approaches have different impacts on the performance in AE?

Situation 1:

A composition is 19 200 x 10 800 pixels in AE (which may be greater than the size, but for the sake of discussion, this is a large size model).

It contains three complex shape layers that are purely vector images, they have a few transformations.

Situation 2:

A composition is 192 x 108 pixels in AE

It contains the same three complex layers, just smaller in the relative scale.

If these two compositions are placed in a standard composition of 1080 p...

The composition of the largest will have an impact more on performance given the rasterization of vectors, or AE will recognize the different vectors and scales and interpret them as they require the same exact amount of processing power / ram? Are there warnings here or times when performance is affected differently? Thanks for the help!

> within this secondary model, they required the same amount of rendering time

Be careful when testing like this. The second (and third and fourth...) that you use and return the same element, the result will be pulled from the cache, you can not use these subsequent runs to measure rendering time except if you purge the cache at each stage.

Tags: After Effects

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 * and open the template in the editor.
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package myname.project.pkg6;

import java.util.Scanner;
import java.util.regex.Pattern;

/**
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* To change this template, choose Tools | Templates
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import java.util.Scanner;
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for (int counter = 0; counter < romNum.length(); counter++) {
characters[counter] = romNum.charAt(counter);
//System.out.println(characters[counter]);
}

for (int sCounter = 0; sCounter < romNum.length(); sCounter++) {
if (characters[sCounter] == 'M'  || characters[sCounter] == 'm') {
charValue += 1000;
} else if (characters[sCounter] == 'D' || characters[sCounter] == 'd') {
charValue += 500;
} else if (characters[sCounter] == 'C' || characters[sCounter] == 'c') {
charValue += 100;
} else if (characters[sCounter] == 'L' || characters[sCounter] == 'l') {
charValue += 50;
} else if (characters[sCounter] == 'X' || characters[sCounter] == 'x') {
charValue += 10;
} else if (characters[sCounter] == 'V' || characters[sCounter] == 'v') {
charValue += 5;
} else if (characters[sCounter] == 'I' || characters[sCounter] == 'i') {
charValue += 1;
}

}
decNumber = charValue;
return charValue;
}

// Converts a decomal number to a roman number
public String setDec2Roman(int decNum) {
String newRoman = "";

while (decNum >= 1000) {
newRoman += "M";
decNum -= 1000;
//System.out.println(decNum);
//System.out.println(newRoman);
}

while (decNum >= 500) {
newRoman += "D";
decNum -= 500;
//System.out.println(decNum);
//System.out.println(newRoman);
}

while (decNum >= 100) {
newRoman += "C";
decNum -= 100;
//System.out.println(decNum);
//System.out.println(newRoman);
}

while (decNum >= 50) {
newRoman += "L";
decNum -= 50;
//System.out.println(decNum);
//System.out.println(newRoman);
}

while (decNum >= 10) {
newRoman += "X";
decNum -= 10;
//System.out.println(decNum);
//System.out.println(newRoman);
}

while (decNum >= 5) {
newRoman += "V";
decNum -= 5;
//System.out.println(decNum);
//System.out.println(newRoman);
}

while (decNum > 0) {
newRoman += "I";
decNum -= 1;
//System.out.println(decNum);
//System.out.println(newRoman);
}
return newRoman;
}

public Roman addRoman(Roman newRom) {
int totRom = newRom.setDecimal(newRom.romNumber) + decNumber;
romNumber = newRom.setDec2Roman(totRom);
return new Roman(romNumber);
}

public Roman subRoman(Roman subRom) {
int totRom = decNumber - subRom.setDecimal(subRom.romNumber);
romNumber = subRom.setDec2Roman(totRom);
return new Roman(romNumber);
}

}

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