By comparing the matrix elements

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• Extract the matrix element

  I am trying to make the detection of peaks on a waveform. I use the waveform peak detection VI for that. One of the outputs of this VI is a picture of the 'locations' of each peak.

  The table of locations is displayed on the front panel, and it displays each item. I want to be able to extract a specific element of the array, however, say the third element (value = 226). I tried to do by using the table of index function, but I think that my understanding of this feature was incorrect. It seems that this can only isolate an ultrasensitive table 1 d array of?

  I'm sure that the answer is pretty simple, but I'm scratching my head trying to find. Thanks in advance.

  Your contribution is an array of waveforms, so you will get a table of the peaks for each waveform. You check out the first elements, which is a cluster that contains a table of the peaks for the first waveform. (Given that LabVIEW can not have arrays of arrays, you will get an array of clusters, each containing a table 1 d).

  If you have only a waveform in the input array, you must use table index before the detection of peaks and feed only a waveform to get a simple output of table 1 d.

  If you want to analyze an array of waveforms, simply dig a little deeper to the output you get. Array index to get the result of one of the waveforms (that is what you are currently doing!), and then ungroup to get the table of the results of this waveform, then the array index to access the first Ridge.

• Compare the table and out of the common elements

  Hello

  Can you help me to compare the two tables in the attached file in VI and out the elements common to the two tables?

  Thank you

  hiNi

  There is no wire table through the False State in the structure of your business.  Use the default value if unwired is selected for this tunnel. the default value for this tunnel is an array of empty strings.  Run the wire straight through, and Bob's your father's brother.

  

• compare the two array element and ignore the undesirable element of the array

  Hello

  Here I attached the vi. In this vi I compare table with ideal picture of A to z. normally in an entry, that we get a data with noise, as is show in this vi normally I just need to compare the value has Cwith c D with D with A & B with B, and so on. now the problem is I have to compare ideal picture with input .and string array if the input string is not in series from A to Z the whole comparion is .i false hope you understand my problem and give some suggestion thank you

  Please take a look at this modified version of your code and I would like to know if that's what you are trying to achieve.

  Please, ask questions and make sure you are comfortable and understand what I coded.

• Using ListView with ArrayDataModel displays only the first element in each QVariantMap within the matrix

  I have this QML who have a ListView with datasource to a full ArrayDataModel from the CPP file for creationcompleted, I loop in the table to add the hour together to appear as a label on the page, what works. However, when I want to view these items in the list, it will display only the first element of the QVariantMap within the table, no error on the log of the device. Also, triggered more does not work, but when I click it, it will have a blue border surrounding it, but the onTriggered does not fire.

  Here is an excerpt of the CPP on the table fill

  This-> eventsModel = new ArrayDataModel();

  QVariantMap event;

  event ['EventName'] = "Event1";

  event ["EventHour"] = "00";

  event ["EventMinute"] = "01";

  event ["EventSecond"] = '02 ";

  QML-> setContextProperty ("eventsModel", it-> eventsModel);

  Here's the QML

  {Of container

  ID: eventListContainer

  {To ListView

  ID: eventList

  dataModel: eventsModel

  Use a ListItemComponent to customize the appearance of the list view

  listItemComponents:]

  {ListItemComponent}

  type: 'point '.

  {StandardListItem}

  Title: 'Event' + ListItemData.EventName;

  Description: "time:" + ListItemData.EventHour + ":" + ListItemData.EventMinute + ":" + ListItemData.EventSecond; "»

  }

  }

  ]

  onTriggered: {}

  var selectedEvent = dataModel.data (row);

  var eventDetailPage = eventDetailDefinition.createObject ();

  eventDetailPage.txtEventName.text = selectedEvent ['EventName'];

  eventDetailPage.pickEventTime.value = picker.dateFromTime(selectedEvent["EventHour"]+":"+selectedEvent["EventMinute"]+":"+selectedEvent["EventSecond"]);

  eventDetailPage.open ();

  }

  }

  Any help would be appreciated.

  Thank you.

  ListView determines ItemType of the element by calling the function itemType of the dataModel. By default, an ArrayDataModel returns an empty string for this call (see https://developer.blackberry.com/cascades/reference/bb__cascades__arraydatamodel.html).

  This leaves you with a few options:

  (1) If you have no header and all the elements are the same, you can make

  ListItemComponent {
       type: ""
       ...
  

  (2) If you have headers or different elements, you can extend ArrayDataModel and implement your own function of itemType

  (3) you can define a function of ItemType on your ListView in QML. Documentation:

  ListView called DataModel::itemType() for each item in order to know the type. QML, this can be overridden by declaring the itemType function (data, row) on the ListView element. ListView then call this function instead of the function DataModel.

  Here's how to create a list in QML which creates a header for all items on the high level and aStandardListItem for each item below the top level:

• Dynamic action - compare the elements in Date - Show Alert

  This is my first attempt to create a dynamic Action. I am creating a dynamic Action that displays an alert if a user enters a date in an article in date picker (P1_DATE1), which is less then another date in a different element (P1_DATE2).
  
  Event = change
  Select Type = item (s)
  product (s) = P1_DATE1
  Condition = less than
  Value = <? >
  
  If the condition is true, it must trigger an action type 'alert '. The alert text should read something like "Date1 precedes Date2.
  
  I'm not sure what syntax to use in the value element. It seems not that I element values in the element of reference value.
  
  
  How can I create a dynamic Action that will assess if P1_DATE1 < P1_DATE2 when P1_DATE1 is changed and show a warning if this is true?
  
  Kind regards
  Todd

  Change the status of "javascript expression", and then assign the expression $v ('P1_DATE1')<$v('P1_DATE2'). then="" add="" a="" true="" action="" in="" which="" you="" do="" the="">

• Integration of the matrix

  I have an X matrix and a vector b:

  X = 1/4 * exp(x/2) [x 3 + 4, 3 x,-3, 4-3 x] b = (x, exp (x))

  now I should calc: X * int (Inv(x) * b)

  Inv (X) * b fine.

  Application INTVX on a simple matrix also works. But if I apply on the resulting vector (inv (X) * b)

  -((3x^2-4X) exp (x) + 3 x)) / (4exp (x) exp(x/2))

  (3 x ^ 2 exp (x) + 3 x + 4) / (4exp (x) exp(x/2))

  my 50g puts INT before the two elements and adds a few t

  How can I get the solution that suits (travel 200) be something like:

  ((3(x+8) exp (x) + 1) exp (x)) / 3

  -(3(x+4) exp (x) + 1) exp (x)

  Are you sure your original formula?

  [["3 * X + 4', ' 3 * X'"], ["-3 * X', 4-3 * X'"]]
  X 2 / EXP 4 / * INV
  
  ['X' "EXP (X)"] *.
  
  SIMPLIFY

  Returns a partial result (inv (X) * b)) who seems different (?)  than the one that you give

  ['((3 * X * EXP(-X/2) ^ 3 +(3*X^2-4*X) * EXP(-X/2)) / 4)']

  "((X + 3 * 4) * EXP (X/2) ^ 3 + 3 * X ^ 2 * EXP (X/2)) [/ 4']."

  INTVX then gives

  [' ((X + 3 * 2) * EXP (X/2) ^ 3 + (9 * X ^ 2 + X + 24 * 48) * EXP (X/2)) / 6']

  ['-(((X+2) * EXP(-X/2) ^ 3 +(3*X^2+12*X+24) * EXP(-X/2)) / 2)']

• Find the table if element have the same element in all indexes

  Hello

  I need to check if a table have the same element in all its indexes. (Example: an array of size 4, should have index 0... 3 1 and during the next iteration index whether no. 2 overall indexes...) How can I check if all indexes have same number)

  Attached to the VI I did.

  Anyone can offer better than this.

  

  get the first element, compare it with the hole dashboard, AND all items

• Resize the array element programmatically

  Hi, I need to programmatically resize the element of a matrix. The external framework of the matrix control must take the same size, but the internal element should chang size programmatically.

  

  I have found no property/method to do this. Wait using Xcontrol I guess.

  Any idea?

  Thank you.

  Of your image that you inserted, I guess your "matrix" is a display of 2D LED array.

  In order to resize these elements all in now the 'original size of the matrix", you must implement two steps:

  1 resize LEDs:

  • Get ArrayElement reference
  
  
  • Convert the reference to Boolean
  
  
  • Set the width and height for the Boolean value of the new value

  Please note that now change the size of all THE LEDs. This is because all items in a table share the same properties (including size) with the exception of the "Value" property

  In addition, the table shell is resized as it still shows the same amount of LEDs (columns, rows)

  2. calculate the new number of columns/rows to keep the table shell roughly the same size

  • Calculate the multiplier for resizing in each direction (led to half size smaller multiplier of 2 to the number of lines/columns each)
  
  
  • Multiply the number of rows/columns of this multiplier (rounded)?
  
  
  • Set the size property of dimension to the hull of the array to the new values

  Please note that this will be 'resize the table to about the same size as it did before. Resizes rounding issues very likely (it has no LED 0.5 available!)

  Norbert

• compare the mixed data clusters which include some floats

  Did someone come up with what they consider to be a slick way to compare groups of mixed (including floats) data for functional equality (close enough)? Are all I have manged to come with specific-the-cluster screws using a while loop with a case statement internal focus on the index to scroll the cluster element by element to make comparisons, using an appropriate method to compare the floats that can accept a tolerance.  I thought that maybe someone can already built a more generic solution based on clusters of variant data conversion and then direction each piece of data to a correct comparison for its data type.

  The attached Zip file has versions v7.1.1, v8.0 and v2014 my VI for this comparison. I need to rework the managed case RefNum objects to the fact that they will be digital or ASCII (e.g.: VISA). I also added an error output to make it easier to tell when the process runs off the rails. At this point, I'll say I'm done with this, because what I created, this is what I need to do and the elves of the forum NOR are harassing me to mark something on this topic as a response. Enjoy!

• Index of the matrix

  I use the reading of spreadsheet files VI to read a text file that contains a matrix of 52 x 49 with numbers from 1 to 100. I want to find the index of rows and columns where the number 5. How can I do this?

  hannesostergren wrote:

  Stops 'picture 1 d of research' search for the desired item as soon as the first element is found?

  This is why I said that it would be a bit more complicated. You need continue to search for each found clue, until the end is reached.

  It is easier to simply browse all the items as follows (change the case enabled to use your file).

• Invert the table to the Add element to the front of the performance of Bay

  Hi all

  I read in a few places that reverse an array to add the element to the front of it will give the best performance since no new allocation of memory is necessary.

  I have 2 questions about this process:

  1. "reverse a table on requires pointers change.»

  Is that mean that a table in Labview is like a linked list? who has pointers that point to the next element.

  So when this inverse process occurs, the head of the linked list will be the last element of the array, and all links in the linked list will require a change.

  

  Step 1: table of moose with one extra space at the end

  Step 2: Matrix inverse

  Step 3: Add a new item at the end of the table opposite

  Step 4: Reverse again.

  2. the exercise of reverse Add then reverse is even worse in fact. Why is this?

  

  

  "Overhead" is the need for new buffer allocations, which indireclly affects runtime but also memory.

  Yes, often the paintings have an additional memory beyond the end of the table to avoid the resizing with each adding an item...

  Your FAQ quotes says nothing about any reversal trick. To do this, the elements of the array need reverse look up, then inserted using the space soft (if it exists!), then the need even to reverse ber alements in place. Seems like a lot of work to do over and over again. Yes, it might be slightly more efficient that have to be allocated to each prefix operation but we do not really know what the compiler does. Maybe if soft is available, it would be to move all the items up and insert the element first, make a new allowance that occasionally necessary. Who knows? I have the greatest respect for Darren, the author of the "source". Perhaps he can clarify what he writes.

  Benchmarking valid what is quite difficult.

  In all cases, you often know the final size, so it can be distributed in one shot and the items replaced with valid data that you will. It's always orders if magnutide more effective than any other solution.  If you need to grow an element of a table at a time, add at the end, never at the begginning.

• compare the screws

  With the help of labView 2009, I compared the 2 vi. Under added or replaced/removed, a majority of the son and of many terminals are highlighted, although they look identical. I unchecked cosmetic changes, so I'm not sure why identical looking for elements are highlighted.

  Thank you

  JVH

  Sorry, I made changes, original is no longer available. I had uncontrolled cosmetics. Were more likely after focusing on the circles instead of son highlighted.

  Thanks for posting.

  JVH

• Stopping everything in a loop after the last element of a 2D array

  How to stop a while loop after the last element of a 2d array.  I tried an uninitialized matrix wiring constant and comparison with table 2d, which has been indexed to a 1 d table, but that did not work.

  Hahaha, Hey, it's true what they say, a picture is worth a thousand words

  

• How to compare the original value of table size and the changed value

  juice I took a table and then took the function of the size of the array so that it shows me the number of the elements present in it. so it'll be the original table size value. If the items in the table even changes another value, then I want to compare the original table size value and the value of table size has changed. How to compare... Please help me. you are looking for a possible solution. Thank you

  Hi stara,

  the attached picture shows the ony solution.

  It will be useful.

  Mike