Calculate the absolute Angle with crossover

Similar Questions

• Calculate the % of 'Make with Warp' indication / ARC?

  Hello community,

  I translate a menu German so I hope I get things right.

  I would really like to know how to calculate the percentage of the CRA found in the options function if you choose the command OBJECT > MAKE WITH WARP > ARC of STYLE-> bend /(curve?)

  

  Why?

  I want to print a long line straight line on a piece of paper, cut it out and then paste this line into a simplified conical water glass.

  What is going on?

  The line appears folded due to the deformation / curvature of the object from its tapered.

  What then?

  With the option to MAKE WITH WARP I can compensate for warping/bending of printing in - / decrease the percentage of the warp/curvature.

  So far, I have found the percentage just by trial and error print lines with different curves which is a LOT of work (and paper), with the lines on the glass to see who looks all right.

  I was hoping someone knows how the percentage is calculated... In the photo above: what does the 25% stand for... ?

  Any ideas?

  Best regards and a happy new year!

  Carl

  Carl,

  In a certain vagueness, the % of Warp expresses the angle between the part of initially vertical end in % of 180 °.

  In other words, inspire and keep original width of base, an arc (set) is built where the arc (set) has the width of origin and forms an angle of 180 ° * 100/Warp % of the corresponding circle.

  When you have a line as in this case, it's just the width of the line, and there is no set of arcs.

  25% in an angle of 45 °

  50% is an angle of 90 °

  75% of an angle of 135 °

  100% an angle of 180 °

  So if you know the angle spread, you can easily calculate the % of Warp, dividing the angle of 180 ° and multiplying by 100.

  This angle depends on the angle at the top of the cone, the size of the cone, and the diameter of the line rate.

• Understand and improve the absolute accuracy

  Many sculptures absolute accuracy calculated the computation of absolute precision in the manuals of the user for the use of modules in series C the following entries:

  • TempChangeFromLastExternalCal = 70 * C
  
  
  • TempChangeFromLastInternalCal = 1 * C
  
  
  • Sigma/Std-dev = 3
  
  
  • # of samples = 100

  I have a few questions about these two values listed above TempChange

  1. Why such a low value of only 1 has the TempChangeFromLastInternalCal * C; modules are continually doing internal calibration automatically?
  
  
  2. Regarding TempChangeFromLastExternalCal, I read correctly that NEITHER is the calculation of accuracy, assuming that the material has seen a +/-70 * C delta temperature since the last time it was calibrated externally. that is calibrated to 25 * C, but runs at 95 * C?

  To improve the absolute accuracy, I'm curious to know if the following two statements would improve accuracy:

  1. The material exists in an environment temperature controlled with a + / delta 10 * C ambient temperature. Can I use the value of 10 for TempChangeFromLastExternalCal if it has been calibrated at room temperature outside?
  
  
  2. If I'm short so HAVE them + HAVE terminals and a channel not used by COM and the extent to which results can be subratcted of readings of all other channels, I essentially elimited the error of the formula of absolute precision shifting?

  For completeness, for absolute accuracy formulas are:

  Absolute accuracy = ± (VoltageReading * GainError + VoltageRange * OffsetError + NoiseUncertainity)
  GainError = ResidualAIGainError + GainTempco * TempChangeFromLastInternalCal + ReferenceTempco * TempChangeFromLastExternalCal
  OffsetError = ResidualAIOffsetError + OffsetTempco * TempChangeFromLastInternalCal + INL_Error
  NoiseUncertainity = (RandomNoise * sigma) /(# of samples)

  Hey Sean,

  Change in temperature refers to the temperature difference from the last time that you did these two calibrations and the current temperature unit. So if you did an internal and external calibration at 25 ° C, then you will find the difference between the current temperature and 25 ° C. This is valid for two years for external calibration (according to the data sheet) to answer your questions:

  (1) If you both internal as external calibrated at 25 ° c, and then assign TempChange 1 ° C if the environment is in a summer of 24 or 26 ° C.

  (2) if the room was 10 ° C when the measurement has been taken, both internal and external TempChanges is 15 ° C (because your calibration conducted at 25 ° C).

  (3) If you were doing an internal calibration at 10 ° C, then your internal TempChange would be 0 ° C and your external would be 15 ° C.

  Regarding tips, I do not have too. The best I can suggest is to use a lower range and a device that has a lower production, but I don't think that it would be viable for your application. The best try of course is calibrated as close as possible to the more uniform temperature.

  I found a VI that calculates the absolute accuracy of a device. Must be a lot of values, but it allows you to play with the values to see what you can afford. My calculations show you in your range, but be absolutely sure of these fluctuations.

  https://decibel.NI.com/content/docs/doc-9912

  Attached a photo of the values that I used to get this error. I'm sure that the devices are calibrated at 23 ° C. Here's the manual where I found the numbers that I used.

  http://www.NI.com/PDF/manuals/374231c.PDF

  Sorry for the confusion earlier, I hope that this post clears up a lot of information and if it's not please let me know.

  -KP

• With the mouse to draw the edges of a XY Chart to calculate the perimeter and area of him

  I have signals from a stabilometer... I traced X in terms of y in a XY Chart and I want to know how I can draw with the mouse a circle linking most of the points that is the graph of X on Y and calculate the area of her more perimeter. I joined my program labview with two files X and Y

  LV 2009 Version attached.

• How to get the orientation angle screen with 40 Hz stably without delay to sync?

  Goal: Get orientation angle screen at 40 Hz stably without delay for synchronization.

  Problem with two situations:

  1. When you use the bbutil_swap and navigator_event_get_orientation_angle (event) to get the orientation angle screen with other data such as acceleration sensors and gyroscope data, the sampling frequency will be low grade at 10 Hz randomly. The difference of synchronization will increase from 25 ms to 100 ms.

  2. when the screen orientation angle is collected in the following code to get the angle only, the difference in timing of sampling will be 1, 2 or 5 seconds at random.

  Question: How do I get the orientation angle screen with 40 Hz stably without delay to sync?

  or something wrong in my code?

  Mini code:

  public static void handleNavigatorEvent(bps_event_t *event) {}
  switch (bps_event_get_code (event)) {}
  case NAVIGATOR_ORIENTATION_CHECK:
  navigator_orientation_check_response (event, true); If not the line, no updates on the screen rotation.
  angle = navigator_event_get_orientation_angle (event);
  break;
  case NAVIGATOR_EXIT:
  stop = true;
  break;
  }
  }

  public static void handle_events() {}
  for(; ) {
  bps_event_t * event = NULL;
  If (BPS_SUCCESS! = bps_get_event (& event, 0)) {}
  fprintf (stderr, "bps_get_event failed\n");
  break;
  }
  If {(event)
  If (bps_event_get_domain (event) is {navigator_get_domain()})
  handleNavigatorEvent (event);
  }
  } else {}
  break;
  }
  pthread_create (& t1, NULL, (void *) & rawacceleration, NULL);
  }
  }

  int main (int argc, char * argv []) {}
  screen_create_context (& screen_cxt, 0);
  bps_initialize();

  {If (EXIT_SUCCESS! = {bbutil_init_egl (screen_cxt))}
  fprintf (stderr, "bbutil_init_egl failed\n");
  bbutil_terminate();
  screen_destroy_context (screen_cxt);
  return 0;
  }

  If (BPS_SUCCESS! = screen_request_events (screen_cxt)) {}
  fprintf (stderr, "screen_request_events failed\n");
  bbutil_terminate();
  screen_destroy_context (screen_cxt);
  return 0;
  }

  If (BPS_SUCCESS! = navigator_request_events (0)) {}
  fprintf (stderr, "navigator_request_events failed\n");
  bbutil_terminate();
  screen_destroy_context (screen_cxt);
  return 0;
  }

  Rawlog = fopen (rawfilename, "w"); Save the file in a specific path.
  fprintf (rawlog, "Absorption system, Angle\n");

  navigator_request_events (0);

  While (! shutdown) {}
  handle_events();
  bbutil_swap();
  }

  closeshutdown();

  return 0;
  }

  Thank you for your attention,

  Using SENSOR_TYPE_ORIENTATION of sensor_type_t , you should be able to get > 10 Hz.  Use sensor_set_rate() to get the slower delay to call sensor_info().  Make sure not to enable sensor_set_skip_duplicates().

  However get the orientation at the 40 Hz streaming will not make your application any repsonsive more.  The only way to make your app more would be to manage the orientation change in a short period of time.  This is the time when orientation changes (at the hardware level), to receive you and to deal with it.  It is usually a constraint system and there is not that you can do about it.  What you see using the code above is the same information repeated over and over; FACE_UP, FACE_UP, FACE_UP, which is not really useful.

• Can I mark videos with metadata / the camera angle before creating a multiclip sequence?

  Very well. Apologies... with regard to the first, I'm afraid that I'm a great beginner "Multiclip" so can follow the stupid questions...

  I created sequences multiclip and here to mark the clips from each camera with the appropriate angle label before creating the multiclip sequence (for example tag all clips belong to the CAM A as 'Angle 1', tag all the clips belonging to cam B tag such as "Angle 2"etc.) ... If the generated sequences are created with all of the same clips / camera angle on a specified single track (for example all A cam clips on track 1, all B cam clips on track 2, etc.).

  Is this possible?

  For the moment, it seems to be generating sequences containing hundreds of separate beaches, one for each element, which is a bit of pain to play. All likelihood that I stuffed up some settings somewhere... I don't see the options for 'Assignment of the track' during timecode synchronization, which offers to assign the label of the camera or camera Angle, but for the life of me, I can't find where the actually tag my videos with these data.

  Thanks in advance

  Andy

  Ahhhh... You have enslaved timecode!  Lucky devil!  I'm afraid I have no life experience with this (projects only tutorial).

  This post might help you:

  https://forums.Adobe.com/thread/1871960

  He speaks award camera angle and label the camera in the metadata

• How do you do a straight path any longer with the same angle in Illustrator?

  Let's say I have a straight path, that I need to lie down, and I shot this way very carefully, and I need to extend it with the same angle I turned to. I could use the direct Selection tool and drag the anchor point, but I have to be extremely careful if I want the same exact angle. Is there a way to extend it and keep the angle?

  Ginger,

  With view > guides, you can:

  (1) select the path and Transform in the palette set the relevant reference, then several W or H with a sufficiently high number and Ctrl/CmdEnter to make the desired length or too long if you want to determine by dragging;

  If you want to determine this by dragging:

  (2) with the tool ClickDrag direct Selection the purpose appropriate anchor Point back up until you have the length desired; Smart Guides will keep you on, saying: path.

• How to calculate the Total price based on a rate of m² with different prices?

  Hello

  I'm guessing that it is a script, but I've never done any script so I would like to ask you guys...

  I have a form where I would calculate the total price for some carpet based on the price per sqm.

  -L the user enters the number of carpet needed.

  -There are different price points for 1-20, 21-60, 61 + m² (each with their own hidden field that contains the value of awards).

  -The Total Price field evaluates the relevant quantity and multiply by the square metre rate.

  Is it achievable?

  I guess that all solutions are placed in the "Custom calculation Script" field too?

  Thanks in advance!

  Yes. You can use something like this, as the custom of the price field calculation total (you may need to adjust the domain names):

  var sqm = Number (this.getField("SQM").value);

  rate of var = 0;

  If (sqm > 0 & m²)<=20) rate="">

  ElseIf (> 20 sqm & m²)<=60) rate="">

  ElseIf (> 60 sqm) rate = Number (this.getField("Rate3").value);

  M² = Event.Value * side;

• Can I specify a precise angle with the pen tool?

  I would like to know if I can indicate a specific angle with the pen tool.

  I have info panel to the top when I use it, but the movement is so sensitive that I continue to overrun the angle I want decimals.

  for example, if I want to 60 degrees, I'll get 60,347 degrees, so I bring down a little and then it is 59,641 degrees, etc.. I don't have the accuracy of hand or mouse for exactly 60 degrees.

  Y at - it a field that I can put this in for the pen tool?

  I know that I forced to 45 degrees with the SHIFT key, but what happens if I want to one angle other than 45 degrees?

  David.

  Draw the line with the SHIFT key. Select the rotation tool (or the R key) and Option-click on one of the ends of the line. A dialog box opens where you can enter the exact desired in degrees of rotation. More is clockwise; downside is to the right.

• Calculate the fastest path between 2 nodes with the data model for the Oracle network

  Hi all,
  
  I have Oracle 10 g 2.
  
  My problem is the following:
  
  I created a network named ITALIA_NET in the data model for the Oracle network.
  The table of links of this network is named: ITALIA_NET_LINK$.
  The table of the nodes of this network is named: ITALIA_NET_NODE$.
  
  The table ITALIA_NET_LINK$ contains a field named COST that contains links (in meters) lengths.
  
  I've already calculated the SHORTEST PATH between two nodes of the network, by using the method of shortestPath() (using the Java API) as shown on "Pro Oracle Spatial for Oracle Database 11 g" manual. Infact, this method makes reference to the COST field for $ ITALIA_NET_LINK to make this calculation.
  
  Now, I want to calculate the FASTER PATH between two nodes of the network. I have the links (in hours) travel time to make this calculation.
  
  My idea is to create a new field in ITALIA_NET_LINK$ named Cost2 containing the travel time from the links and then do the math by using the shorthestPath() method, referring to the Cost2 field to $ ITALIA_NET_LINK COST field instead.
  By default, I know that the shorthestPath() method returns the COST field for $ ITALIA_NET_LINK. Is possible to change this setting and do that this method refers to the Cost2 field?
  
  In the alternative, is another way for the calculation of the fastest way?
  I want to leave the creation of another network as last solution, because I will have other costs of field (Cost3, cos4t,...)
  
  Thank you much in advance.

  Your approach is good. You will have two networks and you can read them in memory and analyze of shortest path. The shortestPath method is static for the class of NetworkManager. You can use the same method for both networks, once they are read into memory.

  ...
  read the network with time as cost of link
  NetTime network = NetworkManager.readNetwork (dbConnection, 'ITALIA_NET_TIME');
  read the network length as cost of link
  Network netLength = NetworkManager.readNetwork (dbConnection, 'ITALIA_NET_LENGTH');

  calculate the quickest way
  PathTime path = NetworkManager.shortestPath (netTime, startNodeID, endNodeID);
  calculate the shortest path
  PathLength path = NetworkManager.shortestPath (netLength, startNodeID, endNodeID);
  ...

  In the future, if you upgrade to 11g, network data model provides a load on demand (LOD) API that loads only the scores of necessary network in memory during the analysis. This command removes the restriction of the memory of the 10g (in memory API you use) API. API of LOD can handle very large networks and offers more features analysis and modeling capabilities.

  The following link contains the tutorial of NDM LOD API ready for download. Just for your information.
  https://spatial.SampleCode.Oracle.com/servlets/ProjectProcess?PageID=0Zl7oV

  Kind regards
  Jack

• How to calculate the difference between 2 dates, but with interruptions and stops between

  Hello

  How can I calculate the difference in minutes between 2 dates but taking into account the existence of a table in the Appendix, so if between start_date and end_date arguments, there is no 'work time' then this part of the time will not be included in the total difference.

  Records of the time table example:

  Time_configuration	start_hour	end_day	end_hour
  2	19:00	3	07:00
  3	19:00	4	07:00

  so for example first record said that on Monday you start at 19:00 and leave the next day at 7:00 and then save the same sort of thing.

  There is an event that I want to track how many minutes lasted. for example, this event began the day 2 at 19:00 and ended the day 3 at 21:00

  Theoretically, this event really lasted: 840 minutes. This 840 minutes are within the limits of the annex.

  Thanks in advance.

  The storage of the dates not as data type DATE in most cases is bad design. In addition, how do you know what day of the date is 2 at 19:00? East - Monday 2 November 2015 or Monday, March 7, 2016? It is the same for the event. In any case, assuming that both calendar and events don't extend over several weeks:

  According to schedule)
  Select time_configuration 2, 19:00 ' start_hour, end_day 3,' 07:00 ' end_hour of all the double union
  Select 3, 19:00 ', 4,' 07:00 ' double
  ),
  event like)
  Select event_id 1, time_configuration 2, 19:00 ' start_hour, end_day 3: 21:00 ' end_hour of the double
  )
  Select e.event_id,
  Sum)
  less (e.end_day + to_date (e.end_hour, 'HH24'), s.end_day + to_date (s.end_hour, 'hh24:mi')).
  greater (e.start_day + to_date (e.start_hour, 'HH24'), s.start_day + to_date (s.start_hour,'hh24:mi'))))
  ) * 24 * 60 minutes
  Appendix s,
  e event
  where e.start_day + to_date(e.start_hour,'hh24:mi')< s.end_day="" +="">
  and e.end_day + to_date(e.end_hour,'hh24:mi') > s.start_day + to_date(s.start_hour,'hh24:mi')
  E.event_id group
  /

  EVENT_ID MINUTES
  ---------- ----------
  1 840

  SQL >

  SY.

• Cannot build the site offline with absolute links

  Hello.

  I'm building a site offline before uploading to the server.

  At first I just use relative links, so everything is fine. But now that I've changed the absolute links, I can't get a preview of my work because all of the scripts, style sheets, images, etc. are linking to an online address that does not exist yet.

  In site manager, I put in my local root folder information, and my http address. It seems to me that Dreamweaver must be able to substitute the local root folder for the http address and thus be able to process the links locally. But this doesn't seem to be the case.

  So, how can I work offline but use absolute links in my documents.

  Thank you.

  > I went to absolute links because I have

  > my pages in separate directories and names of

  > these directories may change.

  I'm not. If directory names are changing, you must update the links - you were using absolute and relative root site or document relative links. Of course, if you change the name of the directory in DW, it will update all your links for your - unless you use absolute links. DW does not have absolute links.

• How to calculate the degree of rotation of ticks

  Hello again,

  So with a lot of help I got here, I was able to move all the way to learn how to do my work digitally instead of with an old camera.

  In my last discussion, I learned to make the tick marks with copies and rotation.  Now, my question is, how is the rotation calculated if A) I get the placement right tick brands, especially small ones because there are so many and B) how calculate the degree of rotation so that I have the right amount of space at the bottom of the gauge/dial?

  Here is a picture to show what I'm asking:

  

  I know how to get the tick big brands and small graduations, if I had to place it evenly around the entire circle, I know how to do this too - but since I'm putting around some of the circle (although always evenly) I'm lost.  I can understand only the space of hit and Miss calculations and that takes too much time.  I also need to know how to rotate the whole thing by obtaining space open as shown below.

  Thanks for your help!

  Well let's say you want a gap of 90 °

  and need for 100 points. then: 360 ° - 90 ° (270) / 100 = 2.7 copies up to 100 angle 2.7

  and need 20 points then it will be 270 / 20 = angle 13.5

  G

• I want you to help because the phone asking me to become a frequent and annoying enter a password to calculate the icloud

  Hello

  I want you to help because the phone ask me for becoming a frequent and annoying password to calculate the icloud, and I do not know because I bought a phone from someone else is not new Hama is on the phone (*) No. account. IMEI (*) Please help me soon thank you

  < post branched out by host >

  < personal information under the direction of the host >

  Robert Odamat says:

  Hello

  I want you to help because the phone ask me for becoming a frequent and annoying password to calculate the icloud, and I do not know because I bought a phone from someone else is not new Hama is on the phone (*) No. account. IMEI (*) Please help me soon thank you

  < post branched out by host >

  < personal information under the direction of the host >

  Find my iPhone Activation Lock - Apple Support

  There is nothing you can do to get around activation icloud blocking without recovering the former owners information.

  Communicate with the person that you bought the phone.

• Will the 'flights climbed' work and calculate the altitude of an aircraft?

  I'm going on vacation soon and everything I just want to know my iPhone 6s will calculate the flights climbed when the plane is in the Air?

  You will be on a plane with steps?