Calculate the fastest path between 2 nodes with the data model for the Oracle network

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  http://download.Oracle.com/docs/CD/B19306_01/network.102/b14212/TOC.htm

  Published by: CKPT on July 19, 2010 19:58

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• All paths between 2 nodes

  Hello
  
  Can you get it someone please let me know how can I achieve this?
  
  I want to know all the paths between A Source node and the node of Destination B.
  
  I donot want the shortest way but all paths between the 2 nodes.
  
  Also I donot have no weight/cost by any path. (The graph is a directed graph)
  
  Kind regards
  Pantxo

  Hello

  Maybe this:

  Scott@my11g SQL>l
    1  with links(n1,n2) as (
    2  select 'A','B' from dual
    3  union all select 'A','C' from dual
    4  union all select 'B','C' from dual
    5  union all select 'B','D' from dual
    6  union all select 'D','G' from dual
    7  union all select 'C','G' from dual
    8  union all select 'D','I' from dual
    9  union all select 'C','E' from dual
   10  union all select 'E','F' from dual
   11  union all select 'F','G' from dual
   12  union all select 'F','H' from dual
   13  )
   14  select pth
   15  from (
   16  select connect_by_root(n1) || sys_connect_by_path(n2,'>') pth ,n2
   17  from links
   18  start with n1='A'
   19  connect by nocycle prior n2=n1
   20  )
   21* where n2='G'
  Scott@my11g SQL>/
  
  PTH
  ----------------------------------------
  A>B>C>E>F>G
  A>B>C>G
  A>B>D>G
  A>C>E>F>G
  A>C>G
  

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• Find paths between two nodes using SQL sort by cost

  Hi gurus,
  
  I want to find all paths from the source node to the target node that will be sorted by the cost. I don't know if it was possible with the SQL statement. How to start with this query? The script to create the tables and data are given below:
  
  ------------------------------------------------------------------------------------------------------------------
  create table of nodes (nodeId int Primary Key, nodeName varchar (50));
  
  create paths of table (pathId int Primary Key, int fromNodeId, int toNodeId, int cost);
  
  insert into a values (1, 'ISL') nodes;
  insert into a values (2, "LHR") nodes;
  insert into a values (3, 'HYD') nodes;
  insert into a values (4, 'FLS') nodes;
  insert into a values (5, 'MUL') nodes;
  insert into a values (6, "KHI") nodes;
  insert into a values (7, 'QT') nodes;
  
  insert into values of paths (1,1,3,20);
  insert into values of paths (2,1,5,10);
  insert into values of paths (3,1,7,80);
  insert into values of paths (4,2,4,10);
  insert into values of paths (5,3,4,40);
  insert into values of paths (6,3,5,20);
  insert into values of paths (7,3,6,10);
  insert into values of paths (8,6,7,30);
  insert into values of paths (9,6,5,30);
  insert into values of paths (10,6,3,10);
  insert into values of paths (11,7,2,20);
  insert into values of paths (12,5,4,40);
  insert into values of paths (13,5,7,40);
  
  ----------------------------------------------------------------------------------------------------------------------------------
  Assume that the source = ISL and QT= target, there are different paths to QT ISL:
  
  Path relative cost DSB #.
  ==== ================================= =================
  1 ISL-> Multimedia-> QT 50
  2 ISL->->-> QT 60 KHI HYD
  3 ISL-> QT 80
  4 ISL-> HYD-> Multimedia-> QT 80
  5 ISL-> HYD at KHI-> Multimedia-> QT 100
  
  This gives us all possible paths, sorted by price.
  
  No indication or help will be appreciated.
  
  Thanks in advance and best regards
  
  Bilal
  
  Published by: naive2Oracle on February 11, 2011 09:59

  select  ltrim(sys_connect_by_path(nodeName,'->'),'->') path,
          extractvalue(dbms_xmlgen.getXMLtype('select '|| sys_connect_by_path(cost,'+') ||' cost from dual'),'/ROWSET/ROW/COST') - cost cost
    from  paths p,
          nodes n
    where p.fromNodeId = n.nodeId
      and nodeName = 'QT'
    start with nodeName = 'ISL'
    connect by nocycle fromNodeId = prior toNodeId
                   and prior nodeName != 'QT'
      order by cost
  /
  
  PATH                                                              COST
  -------------------------------------------------- -------------------
  ISL->MUL->QT                                                        50
  ISL->HYD->KHI->QT                                                   60
  ISL->HYD->MUL->QT                                                   80
  ISL->QT                                                             80
  ISL->HYD->KHI->HYD->MUL->QT                                        100
  ISL->HYD->KHI->MUL->QT                                             100
  
  6 rows selected.
  
  SQL> 
  

  SY.

• Hierarchical Oracle query help needed - path between the crux of two brothers and sisters

  I want to find the path between two nodes of oracle hierarchical Table.
  
  Consider the following case-
  NodeId - ParentId
  =============
  1 > > > > > > 0
  2 > > > > > > 1
  3 > > > > > > 2
  4 > > > > > > 3
  5 > > > > > > 0
  6 > > > > > > 5
  Here I want to query the database table that if there is a path between nodes 3 and 5?
  The previous query you provided work upwards to the root node.
  
  Here is my expected result, 3-> 2-> 1-> 0-> 5
  
  Yet once if I have a query in the table to get the path between 1 and 3, I want to get out of the way - next
  1-> 2-> 3
  
  Therefore, the query works in both cases. Where ADI root can act as an intermediate or no node.
  
  Can you please guide me how I can get it?
  
  Thank you.

  Hello

  user13276471 wrote:
  I want to find the path between two nodes of oracle hierarchical Table.

  Consider the following case-
  NodeId - ParentId
  =============
  1 >>>>>> 0
  2 >>>>>> 1
  3 >>>>>> 2
  4 >>>>>> 3
  5 >>>>>> 0
  6 >>>>>> 5
  Here I want to query the database table that if there is a path between nodes 3 and 5?
  The previous query

  What application is this? If you're referering to another thread, then post a link, such as {message identifier: = 10769125}

  you provided work upwards to the root node.

  Here is my expected result, 3--> 2--> 1--> 0--> 5

  Yet once if I have a query in the table to get the path between 1 and 3, I want to get out of the way - next
  1--> 2--> 3

  Therefore, the query works in both cases. Where ADI root can act as an intermediate or no node.

  Can you please guide me how I can get it?

  I think you want something like this:

  WITH     bottom_up_from_src    AS
  (
       SELECT     nodeid
       ,     parentid
       FROM     table_x
       START WITH     nodeid      = :src_nodeid
       CONNECT BY     nodeid   = PRIOR parentid
  )
  ,     bottom_up_from_dst     AS
  (
       SELECT     *
       FROM     bottom_up_from_src
      UNION ALL
       SELECT     parentid     AS nodeid
       ,     nodeid          AS parentid
       FROM     table_x
       WHERE     nodeid     NOT IN (
                                        SELECT  nodeid
                                 FROM    bottom_up_from_src
                                    )
       START WITH     nodeid        = :dst_nodeid
       CONNECT BY     nodeid        = PRIOR parentid
  )
  SELECT      :src_nodeid || SYS_CONNECT_BY_PATH (parentid, '-->')     AS display_path
  FROM       bottom_up_from_dst
  WHERE       parentid     = :dst_nodeid
  START WITH  nodeid     = :src_nodeid
  CONNECT BY  nodeid     = PRIOR parentid
  ;
  

  This will show how you can get it from: src_nodeid at dst_nodeid, moving to the top or to the bottom of a hierarchy at a time step. This will work regardless of the fact that
  

  
  
  • : src_nodeid is the ancestor of the: dst_nodeid, or
    
  • : src_nodeid is a descendant of: dst_nodeid, or
    
  • both: src_nodeid and: dst_nodeid are the descendants of another node (e.g. 0).
    

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0). It is always important, but particularly so with CONNECT BY queries, because each version since Oracle 7 had significant improvements in this area.
  See the FAQ forum {message identifier: = 9360002}

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• SCHEMAVALIDATE() fails only in the oracle database.

  I have this function that performs a simple XML validation against a XSD upload in the database.

  
  [code]

  PROCEDURE do_xml_validation (xmlRequest IN XMLTYPE, xsdToValidate IN VARCHAR2, OUT VARCHAR2 returnStatus)

  IS

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  It is linked with the attribute 'encapsulationEnumeration '...

  Anyone with similar problems? I can't explain why this fails in Oracle only.

  XML is:

  < SSLI class = "FLOW_POINT" name = "dasfasfd" transaction = "crΘer" >

  <>attributes

  < name > sdfsafd < / name >

  < port_name > < / port_name >

  < encapsulation > dot1q 4090 < / encapsulation >

  < / attribute >

  < / SSLI >

  Download XSD in the database

  <? XML version = "1.0" encoding = "UTF-8"? >

  <!--

  XSD schema for the active catalog entry

  Seller: IOS_XE

  RFS: EthernetFlowPoint

  ->

  " < xs: schema xmlns: XS =" http://www.w3.org/2001/XMLSchema "elementFormDefault ="unqualified"> "

  <! - TYPE SIMPLE DEFINITIONS - >

  < xs:simpleType name = "encapsulationEnumeration" >

  < values basic memberTypes = "stringEnum dot1qString seconddot1qString" / >

  < / xs:simpleType >

  < xs:simpleType name = "stringEnum" >

  < xs:restriction base = "XS: String" >

  < xs:enumeration value = "default" / >

  < xs:enumeration value = "any" / >

  < xs:enumeration value = 'priority-tag' / >

  < xs:enumeration value = 'unidentified' / >

  < / xs:restriction >

  < / xs:simpleType >

  < xs:simpleType name = "dot1qString" >

  < xs:restriction base = "XS: String" >

  < value pattern = "dot1q\s ([1-9] |)" [0-9] [0-9] | [1-9] [0-9] [0-9] | ([1-3] [0-9] [0-9] [0-9]|40[0-8][0-9]|409[0-4]) "/ >

  < / xs:restriction >

  < / xs:simpleType >

  < xs:simpleType name = "seconddot1qString" >

  < xs:restriction base = "XS: String" >

  < value pattern = "dot1q\s ([1-9] |)" [0-9] [0-9] | [1-9] [0-9] [0-9] | [1-3] [0-9] [0-9] [0-9]|40[0-8][0-9]|409[0-4])\ssecond-dot1q\s ([1-9] |) [0-9] [0-9] | [1-9] [0-9] [0-9] | ([1-3] [0-9] [0-9] [0-9]|40[0-8][0-9]|409[0-4]) "/ >

  < / xs:restriction >

  < / xs:simpleType >

  <! - GROUPS DEFINITIONS - >

  < name XS: Group = "AttributesGroup" >

  < xs: SEQUENCE >

  < xs: element name = "name" type = "xs: String" minOccurs = "1" maxOccurs = "1" / >

  < xs: element name = "port_name" type = "xs: String" minOccurs = "0" maxOccurs = "1" / >

  < xs: element name = "encapsulation" type = "encapsulationEnumeration" minOccurs = "0" maxOccurs = "1" / >

  < / xs: SEQUENCE >

  < / xs: Group >

  <! - BASIC DEFINITIONS of COMPLEX TYPES - >

  < name XS: complexType 'SSLI' = >

  < xs: SEQUENCE >

  < xs: element name = "attributes" minOccurs = "1" maxOccurs = "unbounded" >

  < xs: complexType >

  < xs: Choice minOccurs = "1" maxOccurs = "unbounded" >

  < xs: Group ref = "AttributesGroup" / >

  < / xs: Choice >

  < / xs: complexType >

  < / xs: element >

  < / xs: SEQUENCE >

  < name XS: attribute = "class" type = "xs: String" use = "required" / >

  < name XS: attribute = "name" type = "xs: String" use = "required" / >

  < name XS: attribute = "transaction" type = "xs: String" use = "required" / >

  < / xs: complexType >

  <! - ROOT ELEMENT - >

  < xs: element name = "SSLI" type = "SSLI" / >

  < / xs: Schema >

  Anyone with similar problems? I can't explain why this fails in Oracle only.

  This is a bug.

  I can reproduce it on 12.1.0.2 too, even during the recording of binary XML schema.

  There have been some problems with validation of model for a while now pending, and they are not yet fixed.

  You must open a SR with Oracle's Support.

  BTW, in the future, to the right place for these issues would be the XML DB forum.

• How to recover data from plsql table in the BI publisher data model

  Hi all
  
  I created a data model for XML editor report. In the data model I m get plsql table data. for this I created a package with a function in the pipeline. I am able to run sql in sql developer. But if I run the program at the same time, then I got error like "java.sql.SQLSyntaxErrorException: ORA-00904:"XXXXX": invalid identifier.
  
  I used the same settings in the data model and simultaneous program...
  
  Please tell me what to do...
  
  Thanks in advance...
  
  Kind regards
  Doss

  I think P_ORG_ID is the parameter
  so use

  :P_ORG_ID
  

  -Add
  also why not use simple sql query?

  Published by: Alexandr Sep 14, 2012 04:48

• Comment of tables and columns are included in the Data Modeler

  Hi all
  I used Oracle SQL Developer Data Modeler (Version 3.0.0.665) and created a data model for my project. I sent an email a PDF version of the data model to our systems analyst. She asked if I could re - create the data model and include table and column comments. Is this possible and if so how this work is it?
  
  Thank you for your comments,
  
  Seyed

  Seyed salvation,

  I used the Data Modeler and create a report. The report included 36 .csv files

  What is the purpose of this 'report' task, because 36 files csv does not sound like report to me. Watch "files > reports" feature - you can generate reports for your model. -for any model, single table or tables belonging to specific subview. The report of the complete table contains additional details, so if you need these comments, then only you can create a template and select column comments appear only. So some general information table will be also included.

  Philippe