Calculate the difference of date in milliseconds

Similar Questions

• How to calculate the difference between 2 dates, but with interruptions and stops between

  Hello

  How can I calculate the difference in minutes between 2 dates but taking into account the existence of a table in the Appendix, so if between start_date and end_date arguments, there is no 'work time' then this part of the time will not be included in the total difference.

  Records of the time table example:

  Time_configuration	start_hour	end_day	end_hour
  2	19:00	3	07:00
  3	19:00	4	07:00

  so for example first record said that on Monday you start at 19:00 and leave the next day at 7:00 and then save the same sort of thing.

  There is an event that I want to track how many minutes lasted. for example, this event began the day 2 at 19:00 and ended the day 3 at 21:00

  Theoretically, this event really lasted: 840 minutes. This 840 minutes are within the limits of the annex.

  Thanks in advance.

  The storage of the dates not as data type DATE in most cases is bad design. In addition, how do you know what day of the date is 2 at 19:00? East - Monday 2 November 2015 or Monday, March 7, 2016? It is the same for the event. In any case, assuming that both calendar and events don't extend over several weeks:

  According to schedule)
  Select time_configuration 2, 19:00 ' start_hour, end_day 3,' 07:00 ' end_hour of all the double union
  Select 3, 19:00 ', 4,' 07:00 ' double
  ),
  event like)
  Select event_id 1, time_configuration 2, 19:00 ' start_hour, end_day 3: 21:00 ' end_hour of the double
  )
  Select e.event_id,
  Sum)
  less (e.end_day + to_date (e.end_hour, 'HH24'), s.end_day + to_date (s.end_hour, 'hh24:mi')).
  greater (e.start_day + to_date (e.start_hour, 'HH24'), s.start_day + to_date (s.start_hour,'hh24:mi'))))
  ) * 24 * 60 minutes
  Appendix s,
  e event
  where e.start_day + to_date(e.start_hour,'hh24:mi')< s.end_day="" +="">
  and e.end_day + to_date(e.end_hour,'hh24:mi') > s.start_day + to_date(s.start_hour,'hh24:mi')
  E.event_id group
  /

  EVENT_ID MINUTES
  ---------- ----------
  1 840

  SQL >

  SY.

• How to calculate the difference between a Date column and the Date yesterday in the analysis (in the formula in the column)

  . For example, I need to calculate the difference between a date column, 'Table_Name '. "' Column_Name ' and (Current_Date-1). I tried different ways to do this. But nothing seems to work.

  Try the below formula.

  Replace "Time". "" Date "with your column.

  TIMESTAMPDIFF (SQL_TSI_DAY, "Time". "Date", TIMESTAMPADD (SQL_TSI_DAY-1, CURRENT_DATE))

  Thank you!

• Calculate the difference in days between two Dates

  Hello

  I'm trying to understand how to calculate the difference in days between two dates using JavaScript in LiveCycle. (Minimum = JavaScript knowledge)

  Where 'Start_Date' and 'Current_Date' are the names of the two dates in the palette of the hierarchy. (the two Date/time field)

  * Current date is using the object > value > execution property > current Date/time

  I need a text or number field showing the difference in days. (Difference_in_Days)

  I noticed the following code is pretty standard among other responses:

  var

  Start_date = new Date (Start_Date);

  var

  Current_Date = new Date (Current_Date);

  var

  nAgeMilliseconds = Current_Date.getTime) - Start_date.getTime ();

  var

  nMilliSecondsPerYear = 365 * 24 * 60 * 60 * 1000 ;

  I know there is lack of code and code above are may not be not correct.

  Please notify.

  OK, that's because of the way that javascript and works of the calculate event.  The field will be filled with whatever the script resolves at the end of execution. Technically, your script does not have a value because the last thing you do is an assignment to a variable.  Change the last line as follows:

  Math.ABS ((firstDate.getTime)

  ((- secondDate.getTime (()) / (oneDay));

  (eliminate the variable assignment) and get rid of the app.alert.  Your script will "return" (have) regardless of the value of calculation from the East and which will be stored in the field.

• How to calculate the difference between two times by the NUMBERS

  I'm so bothered by the fact that I can't understand that.

  Cell B2 - 08:00

  Cell C2 - 10:50

  (How can cell D2 - I get this cell to calculate the difference and say 02:50?)

  I know it's probably one of the most basic operations, but for the life of me I can't understand it. The cells B2 and C2 are formatted for a 24-hour clock. But if I tell the system to just subtract the two, I get "0,118. Everything I find on the forum search goes beyond what I need. Can someone help me?

  Thank you

  Hi sapirs,

  Departure and arrival of the cells are in Date and time with Date format: no and time: 24-hour clock.

  

  Formula in D2 (fill down)

  = C2−B2

  

  The results become a duration format, but under automatic (numbers automatically worth this format)

  

  If you wish, you can change the cells of lasting results.

  What Data Format have your result cells?

  Kind regards

  Ian.

• How to calculate the difference in lines

  Hi, the case is:

  Column1 Column2 Column3 column4

  C114 00301152 20/07/2010?

  C114 00301152 10/20/2009?

  C114 00301152 16/06/2009?

  I want to calculate the difference of Column3 in 1st place with the second row and second row to the third row column4 unlike

  Thank you very much

  Luca

  Hi, Luca,

  user12880276 wrote:

  Hi, the case is:

  Column1 Column2 Column3 column4

  C114 00301152 20/07/2010?

  C114 00301152 10/20/2009?

  C114 00301152 16/06/2009?

  I want to calculate the difference of Column3 in 1st place with the second row and second row to the third row column4 unlike

  Thank you very much

  Luca

  You can use the analytical function of LAG (or LEAD).

  For example, if Column3 is a DATE:

  SELECT column1, Column2, Column3

  , Column3 - (Column3) in ADVANCE ON (ORDER BY Column3) AS days_diff

  FROM table_x

  ORDER BY DESC - optionally Column3

  ;

  If you would care to post CREATE TABLE and INSERT instructions for the sample data, and then I could test this.

  Check out the Forum FAQ: Re: 2. How can I ask a question on the forums?

  Column1 and column2 play no role in this problem (except that appear in the output)?  If so, you will need to PARTITION BY in the analytical clause.

• Calculate the difference between the subtotals

  I'm working on a simple report that looks like this:
  
  EmployeeID EmployeeName Date salary wages
  1234 Tom June 1, 2009 $2000.00
  2345 harry $2400,00 June 1, 2009
  3456 sally $3000.00 June 4, 2009
  Partial total salary: $7400,00
  
  Advances of salary Date EmployeeID EmployeeName
  2345 harry $1000.00 may 15, 2009
  3456 sally $750.00 may 15, 2009
  Advances subtotal: $1750,00
  Total: $5650,00
  
  Is there any function in Discoverer, which calculates the difference between subtotals and the poster as a total. Please advise if you can create a named for this sum calculation?
  
  Published by: user1049091 on August 6, 2009 11:33
  
  Published by: user1049091 on August 6, 2009 12:38

  Hello

  Not really possible. You the best approach is probably to create a named calculation that contains the difference: for example

  Decode (salary_type, 'Pay', 'Progress', - wages)

  Then create a total on this calculation. You can often hide the calculation itself in terms of formatting and white text on white background.

  Rod West

• Need help to calculate the difference between times

  Hi all
  
  I have two fields that stores just the hour in 24-hour ex: 08:00 and 20:00 now I want to calculate the difference between two times
  
  Kindle help me
  
  Thanks for your help
  
  Thank you
  Ravi

  Hello

  diiference in hours

  SQL> WITH T AS (SELECT '08:00' ST_TIME, '20:00' END_TIME FROM DUAL)
    2  SELECT (TO_DATE (END_TIME, 'HH24:MI') - TO_DATE (ST_TIME, 'HH24:MI')) * 24 DIFF_HOURS
    3    FROM T;
  
  DIFF_HOURS
  ----------
          12
  
  SQL> 
  

  G.

• FormCalc - how to calculate the difference between the two fields datetime in hh: mm?

  Hello!

  I am building a form of time sheet in which I need to calculate the difference between the start and end times and present the result.

  I'm trying to do with FormCalc but if it is easier with JS is ok too.

  So that's what I did on the total field, by using the calculate on a NUMERIC field called decimalValue event:

  elapsed = Time2Num (endTime.formattedValue, "HH: mm")-Time2Num (startTime.formattedValue, "HH: mm")

  And then I tried to convert a time field:

  Total = decimalValue.rawValue;

  $.formattedValue = Num2Time (total, "HH: mm")

  Well, it doesn't work, it gives me crazy results in the datetime (total) field. If I type 09:00 and 09:30, the final result is... 22:30. Huh?

  Please, could someone help me understand how this thing works?

  Thanks a lot for the tips!

  Marcos

  Hi Marcos,

  Here are some examples:

  https://Acrobat.com/#d=kCPIgVkd09qrx6h-WRXxbQ

  https://Acrobat.com/#d=EsWqBMBt3sgEXnMSsK5pRA

  Hope that helps,

  Niall

• How to find the difference in date in years, months and days

  Hello
  I need to find the difference between 2 dates in the following way "years months days". "
  Please can help me, how can I achieve this.
  
  for example, in the scott schema emp table, I need to find the difference in date between sysdate and hiredate for an employee in the following way.
  
  12 years 7 months 4 days.

  Hello

  Please, see this post to AskTom [difference between 2 dates | http://asktom.oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:96012348060]. There is good information in this forum, for example you can also see this thread [calculation of years, months & days | http://forums.oracle.com/forums/thread.jspa?messageID=3115216�]

  Kind regards

  Published by: Walter Fernández on November 30, 2008 08:58 - adding another link

• calculate the difference of unique column values

  I tried the info and the website to learn how to perform a "calculation difference" function on a single column (channel) of data.  For example if my data channel is a period of time to say the following: 100, 101, 99, 102, 100, 99...  I would like to calculate 100-101 101 - 99 then then 99-102 and so on for all the values.  How can I do this?

  Hi ranger,

  Looks like you're looking for the standard function "Calculate the disparity" ANALYSIS > basic math.

  Hope this helps,
  Ralf

• Average of the difference in date in minutes

  Hi friends
  
  I have a table called attendance with 3 columns
  

  eid  number
  in   date
  out  date 

  two columns (in, out) of date are stored with date and time. The table will have multiple entries
  Is it possible that I can calculate the average of the difference in minutes between in and out of all the records
  using a single query or don't we have the right to use the loop.
  

  For Example
  
  eid         in                      out             difference in minutes
  1    01-01-2012 09:00:00   01-01-2012 10:00:00              60
  2    01-01-2012 09:05:00   01-01-2012 10:10:00              65  
  3    01-01-2012 09:10:00   01-01-2012 10:20:00              80  

  The result should be the average difference of minutes IE (60 + 65 + 80) / 3 which would be 68.33
  
  Thanks in advance
  Concerning
  Park

  Hello

  Use

  select avg((out - in) * 24 * 60)
  from 
  

• calculate the difference in last hour?

  Hi all
  
  I have a sql like query below...
  
  SELECT sn.snap_time, st.value
  OF PERFSTAT. STATS$ SYSSTAT st, PERFSTAT. STATS$ SNAPSHOT sn
  WHERE st.snap_id = sn.snap_id
  and st.NAME = "user request".
  and sn.snap_time > to_date (March 1, 2011 10:00 ',' mm/dd/yyyy hh24:ss:mi "")
  order by 1 desc
  
  and output is inferior to...
  
  SNAP_TIME VALUE
  -------------------- ----------
  DECEMBER 19, 11 08:0:00 123501120
  19 DECEMBER 11 07:0:00 121336929
  DECEMBER 19, 11 06:0:01 119910473
  DECEMBER 19, 11 05:0:01 118900726
  DECEMBER 19, 11 04:0:07 118244503
  DECEMBER 19, 11 03:0:01 117202971
  DECEMBER 19, 11 02:0:01 115791474
  DECEMBER 19, 11 01:0:03 114008304
  19 DECEMBER 11 00:0:02 111347506
  18 DEC 11 23:0:01 108291559
  DECEMBER 18, 11 22:0:02 104340139
  18 DEC 11 21:0:01 99255636
  18 DEC 11 20:0:02 92775319
  DECEMBER 18, 11 19:0:01 85262323
  DECEMBER 18, 11 18:0:01 76262794
  DECEMBER 18, 11 17:0:01 68381704
  DECEMBER 18, 11 16:0:01 60100822
  DECEMBER 18, 11 15:0:01 51855773
  18 DEC 11 14:43733973 0:01
  DECEMBER 18, 11 13:0:01 35903397
  DECEMBER 18, 11 12:0:01 28494465
  18 DECEMBER 11 11:0:01 21724443
  DECEMBER 18, 11 10:0:02 15667617
  DECEMBER 18, 11 09:0:01 10526163
  DECEMBER 18, 11 08:0:01 6741565
  18 DECEMBER 11 07:0:00 3622640
  DECEMBER 18, 11 06:0:01 1623214
  DECEMBER 18, 11 05:0:03 207054
  
  But how can I write my query in a way if I can get the real value/difference of time before
  .. all the above value is cumulative and I want to calculate the value of the actual hours... lets say from
  DECEMBER 18, 11 05:0:03...
  
  He hopes to make sense... I'm on 9.2.0.5

  Hello

  To show the difference from the previous row (where "previous" is based on snap_time, ASCendcing order):

  SELECT    sn.snap_time
  ,        st.value
  ,       st.value - LAG (st.value) OVER (ORDER BY snap_time)     AS value_change
  FROM        PERFSTAT.STATS$SYSSTAT     st
  ,        PERFSTAT.STATS$SNAPSHOT     sn
  WHERE        st.snap_id     = sn.snap_id
  AND       st.NAME     = 'user calls'
  AND       sn.snap_time     > TO_DATE ( '03/01/2011 10:00:00'
                            , 'mm/dd/yyyy hh24:ss:mi'
                        )
  ORDER BY  snap_time     DESC
  ;
  

  In yopur sample data, it seems that each row is about an hour from its neighbours. If you missed an hour, or if you sometimes had two (or more) line in the same time, what wouold results you want? Post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all the tables and also post the results desired from these data.

• How to calculate the difference in response times

  Hello
  I need to calculate the time difference of BI answers and I don't have access to the repository. I have the data in the following format
  
  2005-10-12 19:24:19 12/10/2005 19:32:04
  2005-10-12 19:50:47 2005-10-12 20:52:36
  2005-10-12 19:54:23 04/11/2005 22:47:32
  2005-10-12 21:05:51 12/10/2005 21:08:58
  2005-10-12 21:07:42 12/10/2005 21:14:47
  2005-10-12 21:09:02 12/10/2005 21:10:57
  I need to get the hours of elapased between these two columns. Please help me
  
  Thank you

  TimeStampDiff (SQL_TSI_HOUR, table.column1, table.column2)

• Create lines based on the difference in date

  Hello

  I would like to create lines based on the difference between the start and end dates (per year).

  for example

  ID1  Start_time                                             End_time                                                      ID2
  07/01/2003 1, 12.00.00.000000000 2005-01-07 12.00.00.000000000 123

  07/01/1999 1, 12.00.00.000000000 07/01/2003 12.00.00.000000000 345

  I need:

  ID1  Start_time                                             End_time                                                      ID2
  07/01/2004 1, 12.00.00.000000000 2005-01-07 12.00.00.000000000 123

  07/01/2003 1 12.00.00.000000000 07/01/2004 12.00.00.000000000 123

  1 01/07/2002 12.00.00.000000000 07/01/2003 12.00.00.000000000 345

  07/01/2001 1, 12.00.00.000000000 01/07/2002 12.00.00.000000000 345

  07/01/2000 1, 12.00.00.000000000 01/07/2001 12.00.00.000000000 345

  07/01/1999 1, 12.00.00.000000000 07/01/2000 12.00.00.000000000 345

  Thank you

  Hello

  Here's one way:

  SELECT ID1

  , ADD_MONTHS (start_time, 12 * (LEVEL - 1)) AS start_time value

  , ADD_MONTHS (start_time, 12 * LEVEL) AS end_time

  id2

  FROM table_x

  CONNECT BY LEVEL<= months_between="" (end_time,="" start_time)="">

  AND PRIOR id2 = id2

  AND PRIOR SYS_GUID () IS NOT NULL

  ;

  I'm assuming that id2 is unique.

  Would what results you if end_time wasn't exactly N years after start_time?