calculate the time difference.

Hello

How to calculate the time difference by using javascript.

Example 15.05 and18.35 difference is 2 h 30 min

BTW: it isn't ~ 2h30min is 3h30min

Maybe something like this works:

// result is 3.300000000000002 ~ 3h 30min
(parseFloat((18.35 - 15.05) / 3600) * 3600)

Tags: BlackBerry Developers

Similar Questions

Is there an easy way to calculate the time difference?

I am trying to find a way to calculate the time difference between
here at a certain time
var settime:Number = 02:35
and
now would be getDate();
I tried something rediculus, but it does not work when I entered a date less than 24 hours, is there a class out there who can just this kind of things
or y at - it something on the internet that could tell me the difference between different time
Thank you
My attempt
var date: Date = new Date();
Set timer to what would I like to call the function
var lastcallH:Number = 22;
var lastcallM:Number = 50;
var lastcallS:Number = 0;
Set up of the 24-hour clock
var tHour:Number = 24;
var tMinute:Number = 60;
var tSecond:Number = 60;
Get the current time
var cHour:Number = date.getHours ();
var cMinutes:Number = date.getMinutes ();
var cSeconds:Number = date.getSeconds ();
Set the first variable
var fH:Number;
var fM:Number;
var fS: Number;
A second set of Variable
var sH: number;
var sM:Number;
var sS:Number;
Final conversion for the Timer
var finalMil:Number;
Time variables that will need to be converted
If (lastcallH < Thur)
{
fH = chorus - Thur;
fM = cMinutes - tMinute;
fS = cSeconds - tSecond.
finalMil = (sH * 60) + (sM * 60) + (sM * 60);
}
ElseIf (cMinutes > 0 | cSeconds > 0) {}
++ Choir;
++ cMinutes;
fH = chorus - Thur;
fM = cMinutes - tMinute;
fS = cSeconds - tSecond.
}
else {}
fH = chorus - Thur;
fM = cMinutes - tMinute;
fS = cSeconds - tSecond.
}
sH = fH + lastcallH;
sM = fM + lastcallM;
sS = fS + lastcallM;
If (< 0 sH: sM < 0 | sS < 0)
{
sH = sH * (-1);
sM = sM * (-1);
sS = sS * (-1);
}
finalMil = (sH * 60) + (sM * 60) + (sM * 60);
Allows you to implement a timer
var yahooTime:Timer = new Timer (finalMil, repeat);
var repeat: Number = 1;
yahooTime.start ();
yahooTime.addEventListener (TimerEvent.TIMER, displayCall);
function displayCall(event:TimerEvent):void
{
trace ("well let's success");
}

your first trace() statement is almost certainly not what you want.

dtDate2 is 08/08/2009

and it's probably not what you want. Flash months are zero-based. That is to say, January corresponding to month 0 and December is the month 11.

How to calculate the time difference

Hi friends,
I want to calculate and the sum of the time difference.
I have two fields in a table. Inside and OUTSIDE. for example.
OUT IN DIFFERENT
01:46 15:30?
01:47 15:45?
02:50 17:30?
I want less above figure and the result will appear in different column.
Help, please
Kind regards

Hello

Assuming that the two columns are the VARCHAR2 data type and "represent" the hours and minutes:

WITH sample_data AS (SELECT ' 01:46 ' in_col, 15:30 ' out_col FROM DUAL)

UNION ALL

SELECT ' 01:47 ' 15:45 ' OF THE DOUBLE

UNION ALL

SELECT ' 02:50 ', 17:30 ' OF THE DOUBLE

)

SELECT in_col,

out_col,

TO_CHAR (TO_DATE ((TO_DATE(out_col, 'HH24:MI')-TO_DATE(in_col, 'HH24:MI')) * 86400, «SSSSS»), "HH24") differ))

OF sample_data;

SQL > WITH sample_data AS (SELECT ' 01:46 ' in_col, 15:30 ' out_col FROM DUAL)

2. ANY TRADE UNION

3. SELECT ' 01:47 ' 15:45 ' OF THE DOUBLE

4 UNION ALL

5. SELECT ' 02:50 ', 17:30 ' OF THE DOUBLE

6 )

7. SELECT in_col,

out_col 8,.

9 to_char (TO_DATE ((TO_DATE(out_col, 'HH24:MI')-TO_DATE(in_col, 'HH24:MI')) * 86400, «SSSSS»), "HH24") differ))

10 FROM sample_data;

IN_COL OUT_COL DIFFER

------ ------- ------

01:46 15:30 13:44

01:47 15:45 13:58

02:50 17:30 14:40

SQL >

calculate the time difference between several lines

Hello

I have a table as below:

create table select TEST_CASETBL (ID, CASE_NUM, CASE_STATUS, CASE_SUB_STATUS, LAST_UPD_DTTM)

112, 123-456', 'open', 'Work', TO_DATE (11 March 2015 13:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

113, 123-456', 'Open', 'pending on the admin', TO_DATE (10 January 2015 15:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

114, 123-456', 'Open', 'client expectation', TO_DATE (10 July 2015 09:00 ',' hh24:mi:ss' of dd/mm/yyyy) of the DUAL union all select them

315, 123-456', 'open', 'Work', TO_DATE (September 15, 2015 10:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

219, 123-456', 'Open', 'pending on the admin', TO_DATE (January 9, 2015 08:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

651, 123-456', 'open', 'Work', TO_DATE (August 20, 2015 10:00 ',' dd/mm/yyyy hh24:mi:ss') from DUAL;

I would like to calculate the duration total (days ideally) to CASE_SUB_STATUS, so have a set of lines:

CASE_NUM of work waiting on admin waiting on customer

-------------------------------------------------------------------------------------------------------------------------------------------------------

123-456 70days 6 hours

Here is the explanation of the pattern:

ex: for everyday business computing (timestamp timestamp of ID:651 - ID:219) +(timestamp of ID:315-timestamp of ID:114) + (ID:112 stamp - current_time) = 11 days + 21 days 22hrs 23hrs 36 days 9 hours

still waiting on admin

(ID:219 timestamp - timestamp of ID:315) + (ID:113 timestamp - timestamp of ID:112)

still waiting on the client

(ID:114 timestamp - timestamp of ID:113)

I would appreciate any idea how to solve this, ideally as an SQL

Thank you

Should he not?...

with test_casetbl (id, case_num, case_status, case_sub_status, last_upd_dttm) as)

Select 112, 123-456', 'Open', 'Work', TO_DATE (11 March 2015 13:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

Select 113, 123-456', 'Open', 'pending on the admin', TO_DATE (10 January 2015 15:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

Select 114, 123-456', 'Open', 'client expectation', TO_DATE (10 July 2015 09:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

Select 315, 123-456', 'Open', 'Work', TO_DATE (September 15, 2015 10:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

Select 219, 123-456', 'Open', 'pending on the admin', TO_DATE (January 9, 2015 08:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

Select 651, 123-456', 'Open', 'Work', TO_DATE (August 20, 2015 10:00 ',' the hh24: mi: ss' dd/mm/yyyy) double

t like)

Select case_num,

case_sub_status,

(last_upd_dttm, 1, sysdate) ahead of diff last_upd_dttm (partition by order of last_upd_dttm case_num).

of test_casetbl

)

Select case_num,

trunc (a) | "day (s). TO_CHAR (date ' 1-1-1' + a, "fmhh24" 'mi' minute (s) "ss" second (s) hour (s)"") "work."

trunc (b) | "day (s). TO_CHAR (day 1-1-1' + b, "fmhh24" 'mi' minute (s) "ss" second (s) hour (s)"") 'Waiting on admin',

trunc (c) | "day (s). TO_CHAR (day 1-1-1' + c, "fmhh24" 'mi' minute (s) "ss" second (s) hour (s)"") "waiting on customer."

pivot)

Sum (diff)

for case_sub_status in)

'Work' is.

B "waiting on admin',

C "customer expectation."

)

CASE_NUM	Working	Waiting on admin	Waiting on customer
123-456	63 day (s) 22 hour (s) (s) 50 minute 49 second (s)	19 day (s) on 20 (s) hour 0 minute 0 second (s)	27 day (s) on 4 hour (s) 0 minute 0 second (s)

How to calculate the time difference in the two date columns time.
Hi Obiee Experts,

I came back new requirement on obiee 10g.

I have two date columns in my table time, data as below.

StartDate: 18/03/2012-04:40:51

Closing date: 18/03/2012-04:50:55

I want to the output as below (Jet lag).

output
04:40:51 (less)-04:50:55 = 00:10:04

I hope you understand my requirement in OBIEE.

Note: I want to show above the output values in another State for OBIEE10g column.

Please share me your valuable contributions. Urgent appeals.

Thank you
Satya
Hi Satya,

Here's another solution. You can try the formula below as it is:

Cast (floor (TIMESTAMPDIFF (sql_tsi_second, '-SNP_SESSION '.))) SESS_BEG, '-SNP_SESSION '. SESS_END) / 3600) as char). ':' ||
Cast (floor (mod (TIMESTAMPDIFF (sql_tsi_second, '-SNP_SESSION '.)))) SESS_BEG, '-SNP_SESSION '. ((SESS_END), 3600) / 60) as char). ':' ||
Cast (mod (TIMESTAMPDIFF (sql_tsi_second, '-SNP_SESSION '.))) SESS_BEG, '-SNP_SESSION '. SESS_END), 60) as char)

I would like to know if that's what you're looking for.

Thank you

Calculate the time (time zones)

Hello

I'm trying to calculate the time (hours and minutes) needs to travel between point a and point b in terms of the time difference between the time zones.

IE: A flight leaves New York at 17:00 and arrives in Frankfurt the next at 07:00

Thanks for your help!

SELECT TZ_OFFSET('America/New_York') new_york, TZ_OFFSET('Europe/Berlin') Frankfurt,

TO_TIMESTAMP_TZ ('20140818170000-04:00 ','yyyymmddhh24misstzh:tzm ') flight_start,

TO_TIMESTAMP_TZ ('20140819070000 + 02:00 ','yyyymmddhh24misstzh:tzm ') flight_end,

TO_TIMESTAMP_TZ ('20140819070000 + 02:00 ','yyyymmddhh24misstzh:tzm ') - to_timestamp_tz ('20140818170000-04:00 ','yyyymmddhh24misstzh:tzm ') flight_duration

OF THE DOUBLE

NEW_YORK	FRANKFURT	FLIGHT_START	FLIGHT_END	FLIGHT_DURATION
-04:00	+ 02:00	18 AUGUST 14 05.00.00.000000000 PM - 04:00	AUGUST 19, 14 07.00.00.000000000 + 02:00 AM	+ 08:00:00.000000000 000000000

Concerning

Etbin

How do the time difference between two dates?
Hi all

I use this query to get the time difference between two dates.

Select to_timestamp ('2012-10-03 12:00 ',' YYYY-MM-DD hh)-to_timestamp ('2012-10-03 11:00 ',' YYYY-MM-DD hh) as double diff;

but do not get the correct result.

Thank you
Left KEY... Left Padding of tanks.

How to calculate the time to SELECT
I want to know how to calculate the time taken by the SELECT query.

For example: I run a select statement in TOAD (oracle version 9i) who takes 40 seconds to run, but in the output window, it displays few records. It says "list 1 of 500 records, more records exist". This table has total 20 million records.

Now my question is: have you my SELECT query took 40 seconds? or it took 40 seconds to SELECT 500 records.

If it took 40 seconds to SELECT 500 records then how to calculate the total amount?

Any help would be much appreciated.
To avoid the exit which is probably not really need you can make
```
begin
  for c in (select * from xy /*your query */)
  loop
    null;
  end loop;
end;
/
```
This gives an estimate of the time to recover all the lines.

How to calculate the time
I want to calculate the time. I want to subtract ' 01:00:00 ' AM currently, but I am getting error.

SQL > /.
Select to_char('01:00:00','HH24:MI:SS')-to_char(sysdate,'HH24:MI:SS') double
*
ERROR on line 1:
ORA-01722: invalid number

can someone help me

Thank you
Not sure what you mean. If you want to subtract an hour from a date, keep in date arithmetic spirit uses day as a unit. To subtract an hour from a date, you need to subtract 1/24:
```
SQL> alter session set nls_date_format = 'MM/DD/YYYY HH24:MI:SS'
  2  /

Session altered.

SQL> select sysdate,sysdate - 1/24 from dual
  2  /

SYSDATE             SYSDATE-1/24
------------------- -------------------
08/09/2009 09:55:28 08/09/2009 08:55:28

SQL> 
```
SY.

QML: calculate the time interval between the touch events

I create a custom button that is activated by a key event, in this way:
```
Container {
    property bool pressed
    signal clicked...
    onTouch: {
        if (enabled && ! event.isMove()) {
            if (event.isUp() && pressed) clicked()
            pressed = event.isDown()
        }
    }
}
```
The problem with this approach is that if the user clicks the custom button several times in a short period of time the click signal is triggered several times too. This does not happen if I use a regular button or an ImageButton.

I was thinking about getting the timestamp of the event and fire the only if clicked event grit touch after at least x milliseconds since the previous event. The DIF is that I couldn't find a way to calculate this difference in QML.

Any suggestions?

You could also follow the time of the last event with the Javascript date.
```
lastTouched = new Date().valueOf();
```
-Check if time has passed...

calculate the time in seconds, the day of the year and year

I have a data file where they record three columns, the seconds elapsed since midnight, day of the year and the year. I am creating a timestamp of LabVIEW from these three numbers. Of seconds elapsed since midnight, I can create seconds, minutes and hours. If I feed in a cluster of time with the day of the year and the year, the timestamp of output is 0. Does not work. Although an input of the day of the year element, the Date and time with seconds function apparently requires day for months and months to work.

The only solution I can imagine at this stage is to calculate the month and the day of the day of the year, which would imply a choice of the month table and a check of the leap year.

Smart solutions, I'm missing?

DaveT

Dave,

I found a Julian Georgian so far.

calculate the time required to perform 100 procedures simultaneously...

roceduresHello,
I wrote a Java program that creates multiple threads, each son establishes a connection, and then each of them calls (simultaneously) a procedure stored in the Oracle database.
I want to know how can I measure the execution time (all) simultaneously stored procedures.
Can I do this using Java or sql, sql developer, maybe?
My idea: in java, difference between time system after discussions started and join in discussions. But which also includes the time to connect to the database... so...?
If each thread calls the stored procedure, where should I call a method called System.getNanoTime ()? Before the call to the procedure? Threads run simultaneously...
Your help would be very appreciated.

> ... Should I start measuring when the son begin to run until they are all nearby?

Yes, if you want to measure the time from start to finish all procedures in the database, you can work this way.

If the creating connection is significant with regard to the duration of the procedure of database, you can use the connection pool.

Kind regards

Zlatko

Calculation of the time differences between several lines

Hello

I have a table as below:

EVENT ID DATE
1. start 05/03/2012-13:00
1. stop the 15:00 05/04/2012
1. start 09:00 05/07/2012
1 stop on 05/09/2012 10:00
Start 2 08/06/2012-08:00
2 stop on 08/07/2012 10:00

I would like to calculate the duration (in hours ideally) between 'Start' and 'Stop' for each ID, so having a set of lines:

ID TimeSpan
---------------------
1 75
26 2

I would appreciate any idea how to solve this, ideally as a SQL solution or maybe a function.

Thank you very much!
Tom

The difference between two dates is a number, where 1 = 1 day. Multiply by 24 to get hours.

Use the LAG, as stated above, to compare the date prior to the current date.

create table T(TID, EVENT, TDATE) as select
1, 'start', TO_DATE('03/05/2012 13:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
1, 'Stop',  TO_DATE('04/05/2012 15:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
1, 'start', TO_DATE('07/05/2012 09:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
1, 'Stop',  TO_DATE('09/05/2012 10:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
2, 'start', TO_DATE('06/08/2012 08:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
2, 'Stop',  TO_DATE('07/08/2012 10:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL;

select tid, round(sum(hours)) hours from (
  select case
    when EVENT = 'Stop' then 24*(TDATE - LAG(TDATE) over(partition by TID order by TDATE))
    else 0 end hours,
  TID from T
)
group by tid;

TID HOURS
--- -----
  1    75
  2    26

Calculate the time period
I want to calculate the date to end date of beginning period, but I have problem
For example, my start date is 'August 21, 2011' and my End Date is "August 21, 2012".
So I want to result as months of the year and days like this is "2 YEARS".
I wrote this command from pl/sql, but I figured it
"TWO YEARS AND SIX DAYS."
Please tell me how to calculate this period
I have enclosed my query

----------------- QUERY ----------------------
Declare
number of mtot_days;
number of mdays;
number of myears;
number of mmonths;
V_Month Varchar2 (10);
V_Year Varchar2 (10);
V_Days Varchar2 (10);
Start
break;
mtot_days: days = (: from_date,: to_date);
myears: = floor(mtot_days/365);
mmonths: = floor(mtot_days/30);
If mmonths = 12 then
mmonths: = 0;
end if;
Mdays: = mod(mtot_days,30);
If mmonths = 1 then
V_Month: = "MONTHS";
on the other
V_Month: = "MONTHS";
End If;

If myears = 1 then
V_Year: = "YEAR";
on the other
V_Year: = "YEARS";
End If;
If mdays = 1 then
V_Days: = "DAY";
on the other
V_Days: = "DAYS";
End If;

If myears = 0 and mmonths! = 0 and mdays! = 0 then
: period: = mmonths | ' ' || V_Month | «AND» | Mdays | ' ' || V_DAYS;
ELSIF
Mdays = 0 and mmonths! = 0 and myears! = 0 then
: period: = myears | ' ' || V_Year | «AND» | mmonths | ' ' || V_Month;
ELSIF
mmonths = 0 and myears! = 0 and mdays! = 0 then
: period: = myears | ' ' || V_Year | «AND» | Mdays | ' ' || V_Days;
ELSIF
myears = 0 and = 0 and mdays mmonths! = 0 then
: period: = mdays | ' ' || V_Days;
ELSIF
Mdays = 0 and = 0 and myears mmonths! = 0 then
: period: = myears | ' ' || V_Year;
ELSIF
Mdays = 0 and = 0 and mmonths myears! = 0 then
: period: = mmonths | ' ' || V_Month;
ELSIF
Mdays! = 0 and myears! = 0 and mdays! = 0 then
: period: = myears | » ' || V_Year | » ' || mmonths | » ' || V_Month | ' AND ' | Mdays | » ' || V_Days;
on the other
: period: not = "ANY TIME."
End If;

end;
not every month has 30 days. Use ADD_MONTHS() instead:
```
SET SERVEROUTPUT ON

DECLARE
   v_start DATE := TO_DATE('21-AUG-2011', 'DD-MON-RRRR');
   v_end DATE := TO_DATE('22-JUN-2014', 'DD-MON-RRRR');
   v_cnt_years NUMBER := 0;
   v_cnt_months NUMBER := 0;
   v_cnt_days NUMBER := 0;
   v_date DATE;
BEGIN
   v_date := v_start;

   WHILE ADD_MONTHS(v_date, 1) <= v_end
   LOOP
       v_date := ADD_MONTHS(v_date, 1);
       v_cnt_months := v_cnt_months + 1;
       IF v_cnt_months = 12 THEN
          v_cnt_years := v_cnt_years + 1;
          v_cnt_months := 0;
       END IF;
   END LOOP;
   v_cnt_days := v_end - v_date;
   --
   DBMS_OUTPUT.PUT_LINE(
       TO_CHAR(v_start, 'DD-MON-RRRR') || ' - ' ||
       TO_CHAR(v_end, 'DD-MON-RRRR') || ': ' ||
       v_cnt_years || ' Years, ' || v_cnt_months || ' Months, ' || v_cnt_days || ' Days');
END;
/
```
outpupt vor several ranges:
```
21-AUG-2011 - 20-AUG-2012: 0 Years, 11 Months, 30 Days

21-AUG-2011 - 21-AUG-2012: 1 Years, 0 Months, 0 Days

21-AUG-2011 - 22-AUG-2012: 1 Years, 0 Months, 1 Days

21-AUG-2011 - 22-JUN-2014: 2 Years, 10 Months, 1 Days
```
Published by: Serge the 25.03.2011 10:46

How to calculate the time interval
Dear Gururs,

I have table of details of the calls as below

Call_Detail DESC;
Name of Type Null
--------- ---------- --------------
Appeal of VARCHAR2 (20)
VARCHAR2 (20) called
Time DATE

in other words table contains each call on a day like this

The call | Called | Time
========================================
A | B | January 1, 2011 00:02:00
A | B | January 1, 2011 00:08:00
A | B | January 1, 2011 00:18:00
A | B | January 1, 2011 00:22:00
A | B | January 1, 2011 00:30:00
A | B | January 1, 2011 00:31:00

I want output like below

The call | Called | Time | Time Difference (sec)
==============================================================
A | B | January 1, 2011 00:02:00 | 360
A | B | January 1, 2011 00:08:00 | 600
A | B | January 1, 2011 00:18:00 | 240
A | B | January 1, 2011 00:22:00 | 480
A | B | January 1, 2011 00:30:00 | 60
A | B | January 1, 2011 00:31:00 | 0

Could someone help to above.

Concerning
Sanjeev
Hello

Use the analytical fucntion of LEAD to get a value on the next line.
For example:
```
SELECT       calling
,       called
,       NVL ( ( LEAD (time) OVER ( PARTITION BY calling
                                            ,               called
                         ORDER BY     time
                       )
             - time
             ) * 24 * 60 * 60
           , 0
           )     AS time_difference_sec
FROM      call_detail
ORDER BY  calling
,            called
,       time
;
```
If you would care to post CREATE TABLE and INSERT statements for your sample data, and then I could test this.

Published by: Frank Kulash, January 11, 2011 10:18

calculate the time difference.

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