calculation of the average using sql
Hi allMy table structure is
--------------------------------------
ID name notes starting_date end_date
--------------------------------------
workingdays = end_date-starting_date
I had a query
Select name, max (case when remarks = remarks then end notes).
Max (case when id = id then end_date-starting_date end),
AVG(end_date-starting_date) average t_action_items
Rollup (name, end_date-starting_date) group;
who's out like that
Name of the average Workingdays remarks
--------------------------------
x 20 20 aaa
BBB 10 20 x
AAA 10 15
y ccc 19
DDD y 8
CCC 8 13.5
CCC 8 14.2
But I need output like this, how can I do that someone please guide me
Name of the remarks Workingdays
------------------------
aaa 20 x
BBB 10 x
15 > x average
y ccc 19
DDD y 8
13.5-> average for y
Forgive me, I can't able to align to the right format, I think that with data you can seggregate
Thanks in advance...
Published by: Paappu on March 20, 2009 09:50
Hello
I have used WITH clause to show the result. You use just SELECT it with your table it will work.
SQL> SELECT * FROM T;
NAME REMARK START_DT END_DT
------ ------------- --------- ---------
Mark Design 15-FEB-09 15-FEB-09
Hendry Coding 08-JUN-08 15-JUN-08
steve Testing 29-OCT-08 04-NOV-08
JAMES POC 01-MAR-09 01-MAR-09
JAMES DOCUMENTATION 01-MAR-09 09-MAR-09
SQL> SELECT Name,Remark, SUM(work_hrs), AVG(work_hrs) FROM (
2 SELECT name,remark ,start_dt,end_dt,SUM(end_dt-start_dt) OVER (PARTITI
N BY name,remark ORDER by Name) work_hrs
3 FROM T)
4 GROUP BY ROLLUP(name,remark);
NAME REMARK SUM(WORK_HRS) AVG(WORK_HRS)
------ ------------- ------------- -------------
Hendry Coding 7 7
Hendry 7 7
JAMES DOCUMENTATION 8 8
JAMES POC 0 0
JAMES 8 4
Mark Design 0 0
Mark 0 0
steve Testing 6 6
steve 6 6
21 4.2
10 rows selected.
SQL>
Kind regards
Tags: Database
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Unfortunately, LISTAGG was created to the Oracle 11.2. About half of the complexity here is the aggregation of chain, i.e. forming the list of the classnumbers, as '1.3', using only functions available in Oracle 10.2.
Here's a solution:
WITH got_gpno_classnumber_cnt AS ( SELECT gpno, classnumber, age_min, age_max, amount , COUNT (*) OVER ( PARTITION BY gpno , classnumber ) AS gpno_classnumber_cnt FROM fortest -- WHERE ... -- If you need any filtering, this is where it goes ) , pairs AS ( SELECT a.gpno , a.classnumber , MIN (b.classnumber) OVER ( PARTITION BY a.gpno , a.classnumber ) AS super_classnumber FROM got_gpno_classnumber_cnt a JOIN got_gpno_classnumber_cnt b ON a.gpno = b.gpno AND a.age_min = b.age_min AND a.age_max = b.age_max AND a.amount = b.amount AND a.gpno_classnumber_cnt = b.gpno_classnumber_cnt GROUP BY a.gpno , a.classnumber , b.classnumber HAVING COUNT (*) = MIN (a.gpno_classnumber_cnt) ) , got_rnk AS ( SELECT DISTINCT gpno, classnumber, super_classnumber , DENSE_RANK () OVER ( PARTITION BY gpno , super_classnumber ORDER BY classnumber ) AS rnk FROM pairs ) , got_classnumbers AS ( SELECT gpno, classnumber, super_classnumber , SUBSTR ( SYS_CONNECT_BY_PATH (classnumber, ',') , 2 ) AS classnumbers FROM got_rnk WHERE CONNECT_BY_ISLEAF = 1 START WITH rnk = 1 CONNECT BY rnk = PRIOR rnk + 1 AND gpno = PRIOR gpno AND super_classnumber = PRIOR super_classnumber ) SELECT DISTINCT g.gpno , c.classnumbers , g.age_min , g.age_max , g.amount FROM got_gpno_classnumber_cnt g JOIN got_classnumbers c ON c.gpno = g.gpno AND c.classnumber = g.classnumber ORDER BY g.gpno , c.classnumbers ;Out (just as you requested):
GPNO CLASSNUMBERS AGE_MIN AGE_MAX AMOUNT ---------- --------------- ---------- ---------- ---------- G123 1,3 0 29 1 G123 1,3 30 35 2 G123 1,3 36 40 3 G123 2 0 29 1 G123 2 30 35 2 G123 2 36 40 5 G124 1 0 29 1 G124 1 30 35 2 G124 1 36 40 3 -
Create the view using SQL DEVELOPER
I'm new to this forum :)
11 GR 2, WIN2008 R2
SQL Developer Version 3.2.09
I am creating the data below view (view existing)
Table: Dovmarker
I try to describe the table and my goal :),MARKERBOREHOLE UWI MARKERSURFACE Z WELLXXX 65372643AAAA Cw -982,985619574516 WELLXXX 65372643AAAA Cn -1891,47401803955 WELLXXX 65372643AAAA J -674,989528816517 WELLXXX 65372643AAAA K3 20,00165000429 WELLXXX 65372643AAAA Tr 125,000317308153 WELLXXX 65372643AAAA K1 -658,989731894024 WELLXXX 65372643AAAA Q 149,999999999549 WELLYYY 56618334AAAA Jkm -715,071442105268 WELLYYY 56618334AAAA K3 36,9013966413975 WELLYYY 56618334AAAA J2 -976,056079257549 WELLYYY 56618334AAAA Tr 106,900507694299
each line describes wells, uwi(uniqe identifier), z (deppth), high (surface marker)
I try to merge all lines with the same MARKERBOREHOLE/UWI and MARKERSURFACE contact coresponding Z (ascending) as MARKERSURFACE = Z.
If it is posibble to reduce the number of decimals to 2.
My idea to solve the problem:
example: ' | ' is the delimiter
or better (not enough knowledge ;))WELLXXX Q=149,999999999549 | Tr=125,000317308153 | K3=20,00165000429 | K1=-658,989731894024 | J =-674,989528816517 | Cw=-982,985619574516 | Cn=-1891,47401803955 WELLYYY Tr=106,900507694299 | K3=36,9013966413975 | Jkm=-715,071442105268 | J2=-976,056079257549
Number of markersurface is different for each wellWELLXXX Q=149,999999999549 Tr=125,000317308153 K3=20,00165000429 K1=-658,989731894024 J =-674,989528816517 Cw=-982,985619574516 Cn=-1891,47401803955 WELLYYY Tr=106,900507694299 K3=36,9013966413975 Jkm=-715,071442105268 J2=-976,056079257549
I try to do it by the listagg function, but I have failled
result:select markerborehole, listagg(z, ' | ') within group (order by z) as new1 from dovmarker group by markerborehole;
When I tried to create new view in sql developer I occurred error;WELLZZZ -2575,95869465411 | -1891,47401803955 | -982,985619574516 | -674,989528816517 | -658,989731894024 | WELLRRR -2376,96975480605 | -2376,96975480605 | -2308,97180590009 | -2308,97180590009 | -2206,47428534641 | -2206,47428534641 | -2163,97522524171
Can you help me with this?Error(s) parsing SQL: unexpected token near *!* in the following: select markerborehole, listagg(z, ' | ') within *!*group (order by z) as new1 unexpected token near *!* in the following: select markerborehole, listagg(z, ' | ') within group *!*(order by z) as new1 missing expression near *!* in the following: select markerborehole, listagg(z, ' | ') within group (*!*order by z) as new1
Concerning
Jaroslaw961148 wrote:
I missed xWell Yes, my apologies, I has not changed all that.
It's a simple way to format the Z value to 2 decimal places?
Yes. It depends on if you want to use rounded, floor, ceiling, truncate or if you like a string always have 2 decimal places etc.
Make your choice and customize according to your needs...SQL> ed Wrote file afiedt.buf 1 with t as (select 'WELLXXX' as MARKERBOREHOLE, '65372643AAAA' as UWI, 'Cw' as MARKERSURFACE, -982.985619574516 as Z from dual union all 2 select 'WELLXXX', '65372643AAAA', 'Cn', -1891.47401803955 from dual union all 3 select 'WELLXXX', '65372643AAAA', 'J', -674.989528816517 from dual union all 4 select 'WELLXXX', '65372643AAAA', 'K3', 20.00165000429 from dual union all 5 select 'WELLXXX', '65372643AAAA', 'Tr', 125.000317308153 from dual union all 6 select 'WELLXXX', '65372643AAAA', 'K1', -658.989731894024 from dual union all 7 select 'WELLXXX', '65372643AAAA', 'Q', 149.999999999549 from dual union all 8 select 'WELLYYY', '56618334AAAA', 'Jkm', -715.071442105268 from dual union all 9 select 'WELLYYY', '56618334AAAA', 'K3', 36.9013966413975 from dual union all 10 select 'WELLYYY', '56618334AAAA', 'J2', -976.056079257549 from dual union all 11 select 'WELLYYY', '56618334AAAA', 'Tr', 106.900507694299 from dual) 12 -- 13 -- END OF TEST DATA - IGNORE ABOVE WITH CLAUSE 14 -- 15 select z 16 ,round(z,2) as round_z_2 17 ,floor(z*100)/100 as floor_z_2 18 ,ceil(z*100)/100 as ceil_z_2 19 ,trunc(z,2) as trunc_z_2 20 ,to_char(round(z,2),'fm9990.00') as string_z_2 21* from t SQL> / Z ROUND_Z_2 FLOOR_Z_2 CEIL_Z_2 TRUNC_Z_2 STRING_Z ------------------- ---------- ---------- ---------- ---------- -------- -982.9856195745160 -982.99 -982.99 -982.98 -982.98 -982.99 -1891.4740180395500 -1891.47 -1891.48 -1891.47 -1891.47 -1891.47 -674.9895288165170 -674.99 -674.99 -674.98 -674.98 -674.99 20.0016500042900 20 20 20.01 20 20.00 125.0003173081530 125 125 125.01 125 125.00 -658.9897318940240 -658.99 -658.99 -658.98 -658.98 -658.99 149.9999999995490 150 149.99 150 149.99 150.00 -715.0714421052680 -715.07 -715.08 -715.07 -715.07 -715.07 36.9013966413975 36.9 36.9 36.91 36.9 36.90 -976.0560792575490 -976.06 -976.06 -976.05 -976.05 -976.06 106.9005076942990 106.9 106.9 106.91 106.9 106.90 11 rows selected.with above code I try to create a new view in SQL Developer, but I have error:
Error(s) parsing SQL: Unexpected token near *!* in the following: select markerborehole, listagg(z,chr(10)) within *!*group(order by rn) as z Unexpected token near *!* in the following: select markerborehole, listagg(z,chr(10)) within group*!*(order by rn) as z Missing expression near *!* in the following: select markerborehole, listagg(z,chr(10)) within group(*!*order by rn) as zWhat are all the {noformat}! * * {noformat} in the code? Delete them.
Edit: or maybe your version of SQL Developer is not up-to-date and does not know the new LISTAGG function in 11g?
Published by: BluShadow on 26-Sep-2012 09:41
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Version
My querySQL> select * 2 from v$version; BANNER ---------------------------------------------------------------- Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi PL/SQL Release 10.2.0.4.0 - Production CORE 10.2.0.4.0 Production TNS for IBM/AIX RISC System/6000: Version 10.2.0.4.0 - Productio NLSRTL Version 10.2.0.4.0 - Production
Desired output:with tmp AS ( select 1 as num, 'karthik' as txt from dual UNION select 2 as num, 'john' as txt from dual UNION select 3 as num, '' as txt from dual UNION select 4 as num, '' as txt from dual UNION select 14 as num, 'tom' as txt from dual UNION select 15 as num, '' as txt from dual UNION select 26 as num, 'sam' as txt from dual UNION select 27 as num, '' as txt from dual UNION select 28 as num, '' as txt from dual ) select * from ( select num,txt,rw,'G'||dense_rank() over(order by (num-rw)) grp_id from ( select num, txt,row_number() over(order by num) rw from tmp ) ) model partition by(grp_id) dimension by(num) measures(txt,cast(null as varchar2(4000)) as last_row_col) rules (last_row_col[(num)] = max(txt)[num < cv()]) GRP_ID NUM TXT LAST_ROW_COL ----------------------------------------- ---------- ------- -------------------------------------------------------------------------------- G1 1 karthik G1 2 john karthik G1 3 karthik G1 4 karthik G3 26 sam G3 27 sam G3 28 sam G2 14 tom G2 15 tom
i.e.within Group (GRP_ID) the LAST_ROW_COL column must have the most recent (order by num desc) not null not the value that is displayed in the last line of this group in particular.GRP_ID NUM TXT LAST_ROW_COL G1 1 karthik karthik G1 2 john G1 3 G1 4 john G3 26 sam G3 27 G3 28 sam G2 14 tom G2 15 tom
So, it should be 'john' for the rest of the null values in the group G1 (Kiss will remain as for num = 1) which should appear on the final line of this group in particular.
Thanks in advance.
Published by: RUSSO on January 2, 2012 04:18RUSSO says:
I thought that this could be done easily using the power of the sql model clause
with tmp AS ( select 1 as num, 'karthik' as txt from dual UNION ALL select 2 as num, 'john' as txt from dual UNION ALL select 3 as num, '' as txt from dual UNION ALL select 4 as num, '' as txt from dual UNION ALL select 14 as num, 'tom' as txt from dual UNION ALL select 15 as num, '' as txt from dual UNION ALL select 26 as num, 'sam' as txt from dual UNION ALL select 27 as num, '' as txt from dual UNION ALL select 28 as num, '' as txt from dual ) select grp_id, num, txt, last_row_col from tmp model dimension by(row_number() over(order by num) rw) measures(num,txt,txt last_row_col,cast(null as varchar2(5)) grp_id) rules( grp_id[any] = 'G' || dense_rank() over(order by num[cv()] - cv(rw)), last_row_col[rw > 1] order by rw = case when last_row_col[cv()] is null then last_row_col[cv() - 1] else last_row_col[cv()] end, last_row_col[rw > 1] order by rw = case last_row_col[cv() + 1] when last_row_col[cv()] then null else last_row_col[cv()] end ) / GRP_I NUM TXT LAST_RO ----- ---------- ------- ------- G1 1 karthik karthik G1 2 john G1 3 G1 4 john G2 14 tom G2 15 tom G3 26 sam G3 27 G3 28 sam 9 rows selected. SQL>SY.
Published by: Solomon Yakobson January 2, 2012 09:35
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How can I write an SQL to generate a square for a period of time? Using only the SQL (not PL SQL).
Assumption - two characters in the horizontal line is equal to a character vertically.
Example of
Suppose that if the length of the square is 7, then there will be a character in horizontal line 14 and 7 in vertical line.
Help, please.************** * * * * * * * * * * **************
Published by: user10681556 on 10 Sep, 2009 01:26Alex Nuijten wrote:
... but I don't know Rob could come up with a more elegant solution ;)Not really.
Only one rule less:
SQL> select s square 2 from dual 3 model 4 dimension by (0 i) 5 measures (cast(null as varchar2(100)) s) 6 rules 7 ( s[for i from 1 to :sz increment 1] = '*' || rpad (' ',2*:sz - 2) || '*' 8 , s[i in (1,:sz)] = replace(s[cv()],' ','*') 9 ) 10 / SQUARE ------------------------------------------------------------------------------------- ******************** * * * * * * * * * * * * * * * * ******************** 11 rijen zijn geselecteerd.Kind regards
Rob.
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