CF9 - sort order of change for the recordset of db (Oracle)

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  Hi all
  
  This issue was raised before also, but still not able to find the real cause of this.
  
  Thread1:
  Re: Research of fragmentation of the table in Oracle 8.1.6.3.0
  
  Thread2:
  CBC latch and buffer busy await you on the same table.
  
  It comes, sometimes hammers server 100% CPU utilization with free latch and buffer busy wait events.
  
  We found a single query consumes high CPU usage that is run by different sessions.
  
  This query have two types of execution plans, where one is accurate and is not (its primary key hit index index no appropriate means present on the table)
  
  Because its primary key index hit repeatedly at various sessions, some sessions are powerful db file sequential read and a few sessions waiting buffer busy waits for event. Also during this time a few sessions waiting for latch free event.
  
  My doubt is how to sql even with different literal values execution plan changes and causes a prob.
  

  select count(*),event from v$session_wait group by event;
    COUNT(*) EVENT
  ---------- ----------------------------------------------------------------
         165 SQL*Net message from client
           1 SQL*Net message to client
           3 buffer busy waits
           2 db file parallel read
          18 db file sequential read
          10 latch free
           5 log file sync
           1 pmon timer
           6 rdbms ipc message
           1 smon timer
  
  SQL> select sid from v$session_wait where event='db file sequential read';
         SID
  ----------
          26
          58
          82
         107
         116
         223
         212
         203
         192
         173
         161
         157
         150
         147
         254
         238
         229
         112
         101
          81
          68
  
  SQL> select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID;
  Enter value for sid: 161
  old   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID
  new   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=161
  
  SPID             SID    SERIAL# PROGRAM
  --------- ---------- ---------- ------------------------------------------------
  4231             161      49569 oracle@tfrdb3 (TNS V1-V3)
  
  
  SQL> select sql_text
  from v$process a,
       v$session b,  2    3
       v$sql c
  where a.addr = b.paddr and
       b.sql_hash_value = c.hash_value and
      a.spid = &PID;  4    5    6    7
  Enter value for pid: 4231
  old   7:     a.spid = &PID
  new   7:     a.spid = 4231
  
  SQL_TEXT
  --------------------------------------------------------------------------------
  SELECT ERROR,TIME_STAMP,O_RESOURCE,QUEUE,NEW_QUEUE FROM LOG WHERE ID = '09292AMR
  10B41FE' AND TYPE IN (11, 28, 25, 18, 60, 13) AND (LOG_SEQ>'234225222' OR TYPE =
   18 AND LOG_SEQ='234225222') ORDER BY TIME_STAMP ASC
  
  SQL> set autotrace traceonly exp
  SQL> SELECT ERROR,TIME_STAMP,O_RESOURCE,QUEUE,NEW_QUEUE FROM amrwf1.LOG WHERE ID = '09292AMR10B41FE' AND TYPE IN (11, 28, 25, 18, 60, 13) AND (LOG_SEQ>'234225222' OR TYPE =18 AND LOG_SEQ='234225222') ORDER BY TIME_STAMP ASC;
  
  Execution Plan
  ----------------------------------------------------------
     0      SELECT STATEMENT Optimizer=CHOOSE (Cost=11 Card=2 Bytes=126)
     1    0   SORT (ORDER BY) (Cost=11 Card=2 Bytes=126)
     2    1     CONCATENATION
     3    2       TABLE ACCESS (BY INDEX ROWID) OF 'LOG' (Cost=4 Card=1
            Bytes=63)
  
     4    3         INDEX (UNIQUE SCAN) OF 'PK_LOG_LOG_SEQ' (UNIQUE) (Co
            st=3 Card=1)
  
     5    2       TABLE ACCESS (BY INDEX ROWID) OF 'LOG' (Cost=4 Card=1
            Bytes=63)
  
     6    5         INDEX (RANGE SCAN) OF 'PK_LOG_LOG_SEQ' (UNIQUE) (Cos
            t=3 Card=1)
  
  
  SQL> select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID;
  Enter value for sid: 147
  old   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID
  new   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=147
  
  SPID             SID    SERIAL# PROGRAM
  --------- ---------- ---------- ------------------------------------------------
  6255             147      38306 oracle@tfrdb3 (TNS V1-V3)
  
  SQL> select sql_text
  from v$process a,
       v$session b,
       v$sql c  2    3
  where a.addr = b.paddr and
       b.sql_hash_value = c.hash_value and
      a.spid = &PID;  4    5    6    7
  Enter value for pid: 6255
  old   7:     a.spid = &PID
  new   7:     a.spid = 6255
  
  SQL_TEXT
  --------------------------------------------------------------------------------
  SELECT ERROR,TIME_STAMP,O_RESOURCE,QUEUE,NEW_QUEUE FROM LOG WHERE ID = '09273AMR
  62B4894' AND TYPE IN (11, 28, 25, 18, 60, 13) AND (LOG_SEQ>'223324996' OR TYPE =
   18 AND LOG_SEQ='223324996') ORDER BY TIME_STAMP ASC
  
  
  SQL> set autotrace traceonly exp
  SQL> SELECT ERROR,TIME_STAMP,O_RESOURCE,QUEUE,NEW_QUEUE FROM amrwf1.LOG WHERE ID = '09273AMR62B4894' AND TYPE IN (11, 28, 25, 18, 60, 13) AND (LOG_SEQ>'223324996' OR TYPE =18 AND LOG_SEQ='223324996') ORDER BY TIME_STAMP ASC;
  
  Execution Plan
  ----------------------------------------------------------
     0      SELECT STATEMENT Optimizer=CHOOSE (Cost=1538 Card=736 Bytes=
            46368)
  
     1    0   SORT (ORDER BY) (Cost=1538 Card=736 Bytes=46368)
     2    1     TABLE ACCESS (BY INDEX ROWID) OF 'LOG' (Cost=1527 Card=7
            36 Bytes=46368)
  
     3    2       INDEX (RANGE SCAN) OF 'LOG_ID' (NON-UNIQUE) (Cost=32 C
            ard=736)
  
  
  
  SQL> select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID;
  Enter value for sid: 82
  old   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=&SID
  new   1: select spid, sid, s.serial#, p.program from v$session s, v$process p where paddr=addr and sid=82
  
  SPID             SID    SERIAL# PROGRAM
  --------- ---------- ---------- ------------------------------------------------
  6172              82      45378 oracle@tfrdb3 (TNS V1-V3)
  
  
  SQL> select sql_text
  from v$process a,
       v$session b,
       v$sql c
  where a.addr = b.paddr and
       b.sql_hash_value = c.hash_value and  2
    3      a.spid = &PID;  4    5    6    7
  Enter value for pid: 6172
  old   7:     a.spid = &PID
  new   7:     a.spid = 6172
  
  SQL_TEXT
  --------------------------------------------------------------------------------
  INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
  LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
  002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)
  
  INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
  LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
  002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)
  
  INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
  LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
  002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)
  
  SQL_TEXT
  --------------------------------------------------------------------------------
  
  INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
  LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
  002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)
  
  INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
  LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
  002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)
  
  INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
  LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
  
  SQL_TEXT
  --------------------------------------------------------------------------------
  002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)
  
  INSERT INTO LOG (ID,TIME_STAMP,TYPE,ERROR,INSTANCE,RULE_NUM,RULE_TYPE,PRIORITY,F
  LAGS,NAME,BATCH,O_RESOURCE,QUEUE,NEW_QUEUE,SERVER,FORM,WORKSET) VALUES (:V001,:V
  002,11,0,0,3,1,0,1,:V003,:V004,:V005,:V006,:V007,:V008,:V009,:V010)

  How to avoid this... why its different execution plan using (I mean bad index PK)
  
  Is it possible to avoid this?
  
  If any details please check out some of my previous post on this specific URL (above)
  
  -Yasser

  My doubt is how to sql even with different literal values execution plan changes and causes a prob.

  Different literal values cause analysis difficult.
  Hard analysis includes the re-evaluation of the best path.
  Literal value is included in the assessment of the selectivity for the scan interval (log_seq >...)

  See
  http://www.centrexcc.com/A%20Look%20under%20The%20Hood%20Of%20CBO%20-%20The%2010053%20Event.ppt.PDF
  http://www.centrexcc.com/fallacies%20Of%20The%20Cost%20Based%20Optimizer.PDF
  more the book of Jonathan Lewis which other threads, I believe that you already have.

  You must lower your CPU.
  Previous discussions, if the situation is still the same, it sounded like hard analysis particularly with this SELECTION against the NEWSPAPER plays an important role in that.

  How to avoid this... why its different execution plan using (I mean bad index PK)

  The points raised in the previous discussion remain valid.
  -Do you have access to this SQL to change?
  for example using bind variable or trick it if necessary due to problems caused by data as discussed in the previous thread.
  - Or you could it repoint the view to a view and a hint?
  -If a particular user makes this sql, could affect you cursor_sharing just for this user. If not, you should consider implementing pan-Canadian database.

  Oracle 8.1.6 still?

• Sort order by default of the rows returned by a query

  Hello

  We have a query that returns rows sorted by ascending order on an Oracle 9i server. Example of returned rows.

  879

  Billing account number

  Team account

  ACCT No.

  The action code

  ADMIRE

  Alternative Service instance

  Circuit #.

  Associate Circuit #-2

  Automatic return action

  See BMO Auto

  APR

  We have the same query that returns rows with a random order when ran on an Oracle 11 g database that we plan to upgrade at. example of lines.

  PAIR1 - L02

  Secondary XSLAM of the Board

  The identifier of the current command

  Right stick DSL wholesale

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  For the DSL Service provider contact

  Secondary XSLAM CLLI

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  MTTR7Indicator

  PAIR2 - L04

  ADMIRE

  Need help

  We demand that the lines to be pre-sorted as 9i to avoid external sort in order by clause. Why is the difference in query returned lines differ between them when tables and indexes that are affected by the query have been matching exactly the other environment.

  Additional information:

  Oracle 9i database character set: AL32UTF8

  Oracle 11 g database character set: WE8MSWIN1252

  Please let me know if you need additional information.

  Thank you!

  If your query is a group, 9i, the Group of the operation has been done as a SORT operation the returned results are sorted.

  10g, the default behavior for the group by being a HASH AGGREGATION, which means that the results are not sorted.

  Support.oracle.com or search google for "_gby_hash_aggregation_enabled", which is a parameter that controls this behavior.

  Hemant K Collette

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  3. Select Acrord32.exe, then click on end process.

  Try to restart the computer and check.

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  Can someone tell me please a link that contains information about how to change my BB Bold 9930 brand OS to another other than Verizon's CDMA network. I'm new to the BB but have COMPUTER experience and a familiar with Android. I know there are a lot of sites with information on the release and OS unbranding inds and changing. A legitimate site exists where one might find the tools and instructions that can help the owner of a BB change its device without having to rely on a team of Technical Support of network providers who charge for a service that can be done by the owner? Sarcastic or useful comments will be greatly appreciated.

  Remove information staff to comply with theCommunity guidelinesand theterms and Conditions of use.

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  What network are you moving to?