Checking roles &; sys privs granted to a user.
Hi all
11.2.0.1
Im still confused in many roles and privileges required a user.
What is the role or sys privs granted to a user, then it can export/import its own table?
Thank you very much
zxy
> so this is something developers and DBA not so it should be granted.
But how a developer will get create a privilege if operator that is not given to DBA. Obviously, operator and PL/SQL are used and written by the developer, but they are maintained by DBA at the database level.
> Unlimited tablespace, what would you say? I did not grant this privilege to HR, but he was able to acquire access unlimited tablespace.
Because HR user resource. which implicitly grant unlimited tablespace privilege to the user, as I already mentioned, do not use resource to the user it is also recommended by Oracle. Create your own role, grant privileges system and object required role and now assign this role to the user.
Concerning
Girish Sharma
Tags: Database
Similar Questions
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Hi all
Can you me the script share how to list EVERYTHING - all roles, objects, privileges granted to a user? say 'HR' to the user.
Thank you.USER_SYS_PRIVS lists all the system privileges granted to a user
SELECT privilege FROM user_sys_privs WHERE username = 'HR'
USER_TAB_PRIVS lists all the privileges granted to a user object
SELECT owner, table_name, privilege FROM user_tab_privs WHERE grantee = 'HR'
And USER_ROLE_PRIVS lists all the roles that have been granted to a user
SELECT granted_role FROM user_role_privs WHERE username = 'HR'
It may become more complex as of here, however, if you want to list all the privileges granted to these roles, the role given to the roles, privileges granted to these roles, etc. recursively. Fortunately, Pete Finnigan has a handy script that implements this logic. You can go down the script of find_all_privs.sql his site.
And it becomes much more complicated if you want to grant privileges that do not follow the normal patterns. Privileges of Java, for example, network ACL, Workspace Manager privileges, etc.
Justin
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How to find the ROLE of all 10 GB DB users
Is there a way to discover the ROLE of all users in the database. Is there any DISPLAY for it.
THXHello
Some scripts:
PROMPT PROMPT PROMPT ******************************************** ROLES AND PRIVILEGES PROMPT PROMPT ******************************************** USER ROLES SELECT grantee user, granted_role, admin_option, default_role FROM dba_role_privs WHERE grantee IN (SELECT username FROM dba_users) AND grantee NOT LIKE '%SYS%' AND grantee NOT IN ('DBSNMP','OUTLN') ORDER BY grantee; PROMPT PROMPT ******************************************** USER PRIVILEGES SELECT grantee user, privilege, admin_option FROM dba_sys_privs WHERE grantee IN (SELECT username FROM dba_users) AND grantee NOT LIKE '%SYS%' AND grantee NOT IN ('DBSNMP','OUTLN') ORDER BY grantee;
set pages 58 column role format a19 heading 'User or Role' column admin_option format a3 heading 'Ad?' column owner format a7 heading 'Owner' column table_name format a26 heading 'Table name' column privilege format a21 heading 'Priv, Grant or Role' column r_ord noprint break on role start titel132 'ORACLE ROLES REPORT' select 2 r_ord, b.role role, b.owner owner, b.table_name, b.privilege privilege, b.grantable admin_option from sys.role_tab_privs b union select 1 r_ord, a.role role, 'N/A' owner, 'N/A' table_name, a.privilege privilege, a.admin_option admin_option from sys.role_sys_privs a union select 3 r_ord, c.role role, 'N/A' owner, 'N/A' table_name, c.granted_role privilege, c.admin_option admin_option from sys.role_role_privs c order by role,r_ord; set flush on term on pagesize 22 linesize 80 clear columns clear breaks ttitle off pause Press enter to continue
I hope this will help you.
See you soon,.
Francisco Munoz Alvarez
http://www.oraclenz.com -
grant select a user to a new user
I know it should be easy, but can't seem to find a way around it.
I can grant roles granted to a user to a new user, but the existing user has loads of select on other tables.
How to get the selection of existing user and give them to the new user?
Thank you
See all the privileges granted to ALICE directly (not through a role)
select * from dba_tab_privs where grantee='ALICE';
With this, you can write a select statement that generates SQL to grant the same privileges to BOB
select 'grant '||privilege||' on '||owner||'.'||table_name||' to BOB;' from dba_tab_privs where grantee='ALICE';
Then, run the output of this statement to make grants.
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Hello
I'm working on oracle10g and HP - UX.
I need to create only one user on reading, how can select data from other users tabels.
One way to do this - is glove instruction to create a srript...
As
Grant select on UserA.Tb1 to UserB;
Grant select on UserA.Tb2 to UserB;
Grant select on UserA.Tb3 to UserB;
and so on...
There are 4000 tables in the schema UserA... .and we need to write a sql script and run it on the database...
Question-
Is there a way to UserB's Select glove on all the obj. for use in a sql statement...?N ° there is no single GRANT command. You can, however, write a small script to PL/SQL, i.e.
FOR x IN (SELECT * FROM dba_tables WHERE owner = 'UserA') LOOP EXECUTE IMMEDIATE 'GRANT SELECT ON UserA.' || x.table_name || ' to UserB'; END LOOP;
Of course, you would usually create a new role, grant this role to UserB and grant the privileges to this role, i.e.
CREATE ROLE UserA_Select; GRANT UserA_Select TO UserB; BEGIN FOR x IN (SELECT * FROM dba_tables WHERE owner = 'UserA') LOOP EXECUTE IMMEDIATE 'GRANT SELECT ON UserA.' || x.table_name || ' to UserA_Select'; END LOOP; END;
In this way, when you need create the next read-only user, you just need to give this user the role of UserA_Select.
Justin
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Hello
Please help me, I'm getting below error when I set up the wizard of Configuration Workflow 2.6.4.0.0 - Linux
Workflow Configuration Assistant 2.6.4.0.0 - Linux
WFCA version: WorkflowCA.java 26.106 29/06/2005-04:33
WorkflowCA:
WorkflowCA: Configuration of current workflow...
WorkflowCA: Kills Feb 16 21:08:57 GMT + 05:30 2010
WorkflowCA:
WorkflowCA: Screen-1024, height-768 screen width-
WorkflowCA:
WorkflowCA: Graphical User Interface Mode
WorkflowCA:
WorkflowCA:
WorkflowCA: Start to test the connection, which takes less than 3 minutes.
WorkflowCA:
WorkflowCA: Test for SYS account login
WorkflowCA: [SYS] ORA-01017: name of user and password invalid. connection refused
WorkflowCA: Unable to connect to jdbc:oracle:thin:@(DESCRIPTION=(ADDRESS=(PROTOCOL=TCP)(HOST=abc.d.com)(PORT=1521))(CONNECT_DATA=(SERVER=DEDICATED)(SERVICE_NAME=PROD)))
java.lang.Exception: invalid connection
at oracle.apps.fnd.wf.install.db.WorkflowCA.createJDBCConnection(WorkflowCA.java:4806)
at oracle.apps.fnd.wf.install.db.WorkflowCA.createSYSConnection(WorkflowCA.java:4902)
at oracle.apps.fnd.wf.install.db.WorkflowCA.schemaCreation(WorkflowCA.java:1039)
at oracle.apps.fnd.wf.install.db.WfFrame.actionPerformed(WfFrame.java:2051)
at oracle.ewt.button.PushButton.processActionEvent (unknown Source)
at oracle.ewt.lwAWT.LWButton.processActionEvent (unknown Source)
at oracle.ewt.button.PushButton.processEventImpl (unknown Source)
at oracle.ewt.lwAWT.LWComponent.redispatchEvent (unknown Source)
at oracle.ewt.lwAWT.LWComponent.processEvent (unknown Source)
at oracle.ewt.button.PushButton.activate (unknown Source)
at oracle.ewt.lwAWT.AbstractButton.processMouseReleased (unknown Source)
at oracle.ewt.lwAWT.AbstractButton.processMouseEvent (unknown Source)
at java.awt.Component.processEvent(Component.java:5266)
at java.awt.Container.processEvent(Container.java:1966)
at oracle.ewt.lwAWT.LWComponent.processEventImpl (unknown Source)
at oracle.ewt.button.PushButton.processEventImpl (unknown Source)
at oracle.ewt.lwAWT.LWComponent.redispatchEvent (unknown Source)
at oracle.ewt.lwAWT.LWComponent.processEvent (unknown Source)
at java.awt.Component.dispatchEventImpl(Component.java:3968)
at java.awt.Container.dispatchEventImpl(Container.java:2024)
at java.awt.Component.dispatchEvent(Component.java:3803)
at java.awt.LightweightDispatcher.retargetMouseEvent(Container.java:4212)
at java.awt.LightweightDispatcher.processMouseEvent(Container.java:3892)
at java.awt.LightweightDispatcher.dispatchEvent(Container.java:3822)
at java.awt.Container.dispatchEventImpl(Container.java:2010)
at java.awt.Window.dispatchEventImpl(Window.java:1778)
at java.awt.Component.dispatchEvent(Component.java:3803)
at java.awt.EventQueue.dispatchEvent(EventQueue.java:463)
at java.awt.EventDispatchThread.pumpOneEventForHierarchy(EventDispatchThread.java:242)
at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:163)
at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:157)
at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:149)
at java.awt.EventDispatchThread.run(EventDispatchThread.java:110)
WorkflowCA: Kills Feb 16 21:09:19 GMT + 05:30 2010
WorkflowCA: java.lang.Exception: invalid connection (0)
WorkflowCA: end...
The respect of
RerryHello
OH, / as sysdba dba using password file
How to check is there any file password and where?
already mentioned in document valid
$ls - ltr $ORACLE_HOME/dbs/orpw *.
After the release
Please check and come back.
Concerning
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Hi team
someone can tell me how we can grant API Oracle user, really appreciate help.
Kind regards
MaheshMahesh,
Are you talking about [url http://docs.oracle.com/cd/E23943_01/portal.1111/e10238/pdg_cm_intro.htm#POBLD478] 9.3 providing access to APIs and Secure views?
In this case, you can use provsyns.sql. Note that the instructions to get the portal password apply to the 10g only. If you want to get on 11g, use the instructions in the Note [url https://support.oracle.com/CSP/main/article?cmd=show&type=NOT&id=843978.1] 843978.1, "How to recover the portal schema Portal 11g password?".
Thank you
EJ -
Can I connect to SQL * more as SYS after connecting as a user and then run a GRANT?
Oracle 11 g 2
Linux RHEL 6.3
SQL * Plus 11.2.0.2 on Windows 7
------------------------------------------------
I am running a script SQL through SQL * more connected as "DOE, JOHN".
In the SQL script, I need to connect as SYS to make a GRANT EXECUTE on a SYS package (e.g. GRANT EXECUTE ON DBMS_CRYPTO to JOHN;).
But it fails with the following error:
GRANT EXECUTE ON TO JOHN DBMS_CRYPTO
*
ERROR on line 1:
ORA-01917: user or role 'JOHN' does not existBut of course, 'JOHN' are. The rest of the SQL script is running "DOE, JOHN" without any problem.
The code segment of SQL script in question is:
connect sys/password as sysdba
GRANT EXECUTE ON DBMS_CRYPTO TO ROYSECITYDATA; <-fails here
to connect/DOEPlease advise on what my being the issue.
tx103108 wrote:
I connect to a remote database. All dbs distance have the same instance name as they are all images. I see where you're going (I think). Should I try
I'll try to connect sys/password@MYDB
Sounds like a plan... (the instance_name returned with what you expected? or something else?)
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Roles really simplify the management of users?
I am trying to establish a role where I can add users to become members of the role to execute select statements on another scheme of.
I cut the code to generate the "Grant Select on table_xxx to < new_role >" and run it. The 1600 various odd given that all appear on the new role. I give membership to a user of vanilla with nothing except create session to this role. And the user can select count (*) by means of a simple test.
However, if I directly grant the same access to a table, the user can make a selection in the schema? What gives.
Can you please explain what is happening here or help with what I'm missing here. See you soon.
PS: If the granting of 1600 odd selects (for each of the objects) for EACH user is the answer, why anyone would use roles? Still reeling from the discovery that after 11 iteration of Oracle, there are still NO grant select on < schema > < user >.You need to activate your role before you start using it.
Run this query and check:
Select * from session_roles;If the output of the above query is 'no rows selected', this means that you don't have any active role.
You have two options in this case:
(1) role playOR
(2) Alter userrole default all; -
Why the SYS is granted the HS_ADMIN_ROLE?
Strangely enough, in my system, SYS is the only user granted the HS_ADMIN_ROLE.
Is this necessary? If I revoke the role of SYS, it will make a difference?All roles are automatically given to SYS SYS is owner of all roles.
Better not follow you the advice of Dinesh Maroo.
---------
Sybrand Bakker
Senior Oracle DBA -
System to grant to the user of the application views
Hi all
11.2.0.1
Batch process Tha night encounter problem blocking where their generations report affected and delayed.
I give this command operators, so that they will kill or stop the process that keeps the lock:
SELECT TO_CHAR ("sysdate, ' HH24:MI:SS of MON-DD-YYYY"). ' The user '. S1. UserName | | » @'|| S1.machine | | "(SID = ' | s1.sid |)
') with the statement: ' | sqlt2.sql_text | |' if it blocks the SQL statement ' | S2. UserName | | » @'|| S2.machine |
' (SID ='|) S2.SID | |') Blocked-> SQL ' | sqlt1.sql_text AS blocking_status
GV $ lock l1, Gv$ session s1, Gv$ lock Gv$ session s2, l2, Gv$ sqlt2, Gv sql $ sql sqlt1
WHERE s1.sid = l1.sid
AND s2.sid = l2.sid
AND sqlt1.sql_id = s2.sql_id
AND sqlt2.sql_id = s1.prev_sql_id
AND l1. BLOCK = 1
AND l2.request > 0
AND l1.id1 = l2.id1
AND l2.id2 = l2.id2;
But this needs system views and you can not run the app user ID.
On the security audit decision or without having violated, what I have to grant select to all system views accessed by this script to the user of the application, then create synonyms it 1 by 1?
Or is it a one-time grant for all views of the system? So I is not need to type a plus creating synonyms so that I can't miss any?
Thank you
Petra k.
f55237a7-2c38-4DB3-a7a3-1d77256f0730 wrote:
Hi all
11.2.0.1
Process batch Tha night meets lock problem where their generations report interrupted.
I give this command operators, so that they will kill or stop the process that keeps the lock:
SELECT TO_CHAR ("sysdate, ' HH24:MI:SS of MON-DD-YYYY"). ' The user '. S1. UserName | | » @'|| S1.machine | | "(SID = ' | s1.sid |)
') with the statement: ' | sqlt2.sql_text | |' if it blocks the SQL statement ' | S2. UserName | | » @'|| S2.machine |
' (SID ='|) S2.SID | |') blocked SQL-> ' | sqlt1.sql_text AS blocking_status
GV $ lock l1, Gv$ session s1, Gv$ lock Gv$ session s2, l2, Gv$ sqlt2, Gv sql $ sql sqlt1
WHERE s1.sid = l1.sid
AND s2.sid = l2.sid
AND sqlt1.sql_id = s2.sql_id
AND sqlt2.sql_id = s1.prev_sql_id
AND l1. BLOCK = 1
AND l2.request > 0
AND l1.id1 = l2.id1
AND l2.id2 = l2.id2;
But this needs system views and you can not run the app user ID.
In view of the security check or without having violated, what I give select all system views accessed by this script to the user of the application, and then create the names it 1 by 1?
Or is it a one-time grant for all views of the system? So I no need to type one by one so that I can't miss any?
Thank you
Petra k.
While approach posted will work subsequently, it's like making three left turns around the block;
instead of making a single term of law.
Place the SQL desired in a procedure (FIND_LOCKER) owned by the extremely privileged schema; then do as below
GRANT EXECUTE ON FIND_LOCKER TO OPERATOR_USER;
-
Political DAP to check the domain name for MAC OS users!
Hi all
How can we configure DAP for Mac OS users, to allow access by the validation of the configuration of the domain name in the MacOS?
I was able able to configure the same for Windows users by using the domain name 'Register' value in the DAP. However, as MacOS do not have to 'Register', I'm trying to find a solution on how would be the authorized user by looking at the entrance to domain somewhere in the MacOS.
I heartily thank you &.
Ameya diabate
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How to hide users (roles and organization) list from a user in IOM
Hello
Admin (xelsysadm) has created a user to IOM. Now, if this user is connected to the IOM Self Service (http:// < url > / identity), he can see other users in his organization, as well as the list of roles, role categories, organizations, etc. I have an obligation to hide all links in the administration of the end-user. At present, it has the role of "All Users" and has no admin role, but can see all these links administration. What should I do to hide these links to the end-user? Should we delete the role of "All Users", or assign another role, or do something in law, or in the access policy?
Thank you.You can write EL condition on visible (or display the component property) Administration menu item: #{oimcontext.currentUser.roles ['SYSTEM ADMINISTRATORS']! = null}
Visit this link on the writing of EL http://docs.oracle.com/cd/E27559_01/dev.1112/e27150/uicust.htm#BABHBFGH
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You can get the roles, but you can get the user's role
You can display or hide items dependant on the roles of the logged in user is affected too.
I know you can do this for the menu using menu.json
'visible': true,
'applyIf': {}
'userHasRoles': ['administrators']
But what about other elements inside the app. Is there a way to get the roles for the logged-on user.
Is this lack as a feature or am I missing some pieces.
Hey,.
Not at the moment.
Talked to the BC guys on this subject with some stuff from varius, they understand the need. Don't know when things will be implemented for us, they're looking to Admin tags or API options etc. for this and a few other bits.
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How to grant resources for users of table
Hello
Security of the ADF, I did it in my application. I created two users and assigned to the newly created application role 'xxx-employees '.
I got my pages to the application role 'xxx-employees '.
If I run my application, using new users I can connect because it works very well.
But, I created SQLAuthenticator and I changed the sql code as per my request.
Now, I should clarify one thing, how can I assign this list of users to the existing application role that created at the application level.
Thank you very much in advance,
SANHello
your database roles are the roles of the user enterprise. So in your application, you have defined a mapping between application roles and the user company roles. If the user enterprise roles are the same as that returned by the table, then that's how it works
Frank
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