cloumn on the emp table online

Similar Questions

• How to insert 10,000 records test data into the emp table

  Hi I am new to oracle can someone please help me write a program so that I can insert the test data into the emp table

  SELECT       LEVEL empno,
               DBMS_RANDOM.string ('U', 20) emp_name,
               TRUNC (DBMS_RANDOM.VALUE (10000, 100000), 2) sal,
               DBMS_RANDOM.string ('U', 10) job,
               TO_DATE ('1990-01-01', 'yyyy-mm-dd')
               + TRUNC (DBMS_RANDOM.VALUE (1, 6000), 0)
                 hiredate,
               CASE
                 WHEN LEVEL > 10 THEN TRUNC (DBMS_RANDOM.VALUE (1, 11), 0)
                 ELSE NULL
               END
                 mgr,
               TRUNC (DBMS_RANDOM.VALUE (1, 5), 0) deptno
  FROM         DUAL
  CONNECT BY   LEVEL <= 10000
  

• How can I get the second and third highest salary from the emp table

  How can I get the second and third highest salary from the emp table in the ecah Department

  SQL> ed
  Wrote file afiedt.buf
  
    1  select empno, ename, sal, deptno
    2  from (
    3    select empno, ename, sal, deptno, dense_rank() over (partition by deptno order by sal desc) as rn
    4    from emp
    5    )
    6* where rn in (2,3)
  SQL> /
  
       EMPNO ENAME             SAL     DEPTNO
  ---------- ---------- ---------- ----------
        7782 CLARK            2450         10
        7934 MILLER           1300         10
        7566 JONES            2975         20
        7876 ADAMS            1100         20
        7499 ALLEN            1600         30
        7844 TURNER           1500         30
  
  6 rows selected.
  
  SQL>
  

• selecting max 5 salaries in the emp table

  Hi I tried the following query to obtain the emp table max 5 salaries...

  SQL> select sal
    2  from (select sal,empno from emp order by sal desc
    3  where rownum<6;
  
         SAL
  ----------
        5000
        3000
        3000
        2975
        2850

  But here in the output of the duplicate rows are there... I need to remove this and number total should be equal to only 5...
  If I put the distinct clause, then I'll take 4 rows only... but I need the salaries of the top 5...
  
  Thank you

  select *
    from (
  select distinct sal
    from emp
   order by sal desc
   ) where rownum <= 5
  ;
  

• SELECT on the emp table query

  Hello
  
  
  How to find the display the o/p as a manager name under employees dependent child parent like relation ship on the noraml emp table:
  
  sample o/p:
  
  use of name
  Nativity scene XX
  sales of yy
  YY1 sales
  Manager of the AA
  marketing of RR
  RR1 marketing
  
  
  Thank you

  921306 wrote:

  So I need, like that, child-parent relationship between the Manager under employees...

  Then join the parent with the child entity entity to create the parent-child relationship.

  The two entities are in the same table, it means to join the table to itself. For example

  SQL> select
    2          child.ename                     as CHILD,
    3          child.job                       as CHILD_JOB,
    4          nvl(parent.ename,'')      as PARENT,
    5          parent.job                      as PARENT_JOB
    6  from emp parent,
    7       emp child
    8  where child.mgr = parent.empno (+)
    9  /
  
  CHILD      CHILD_JOB PARENT     PARENT_JO
  ---------- --------- ---------- ---------
  FORD       ANALYST   JONES      MANAGER
  SCOTT      ANALYST   JONES      MANAGER
  JAMES      CLERK     BLAKE      MANAGER
  TURNER     SALESMAN  BLAKE      MANAGER
  MARTIN     SALESMAN  BLAKE      MANAGER
  WARD       SALESMAN  BLAKE      MANAGER
  ALLEN      SALESMAN  BLAKE      MANAGER
  MILLER     CLERK     CLARK      MANAGER
  ADAMS      CLERK     SCOTT      ANALYST
  CLARK      MANAGER   KING       PRESIDENT
  BLAKE      MANAGER   KING       PRESIDENT
  JONES      MANAGER   KING       PRESIDENT
  SMITH      CLERK     FORD       ANALYST
  KING       PRESIDENT 
  
  14 rows selected.
  
  SQL> 
  

  The basic concept is easy - set the parent entity, set the child entity, join the parent to the child.

  If some entities will not have parents (root entities), then an outer join is required of the child entity to the parent entity.

  Everything simply because the two entities are in the same table, does not change the logic or the approach. It's perfectly valid for a join table.

• sum of sal and comm in the emp table

  Hi all
  
  for the table emp with enam, eno, dept, sal and comm fields
  
  I want to display a field in oracle forms 6i, who will show me the sum of sal and comm
  
  I've created a field of no database
  and wrote this code in the formula

  declare
  summ number(10);
  begin
  
  summ=:sal + :comm
  end;

  but I get the compilation failed
  
  kindly Guide
  
  thanking in advance

  Hello

  your code

  declare
  summ number(10);
  begin
  
  summ =:sal + :comm  --this line must be  summ :=  nvl(:sal,0) + nvl(:comm ,0)
  end;
  

  Try this code to a trigger
  change after exp.

  declare
  summ number(10);
  begin
  
  summ := nvl(:sal,0) + nvl(:comm,0)
  end;
  

  or send me your complete code.
  Thank you

• How to display data from the emp table?

  Hi everyone, this is my first post in this portal. I want to display the details of the table emp... for this I use this SQL statement.
  
  Select * from emp where mgr = nvl(:mgr,mgr);
  
  When I give the entry as 7698 it shows the matching records... and also when I don't give any input then it shows all the records except the Archbishop with null values.
  
  (1) I want to display all the records when I do not give any input, including null values
  (2) I want to display all the records that a Bishop is null
  
  Is it possible to integrate in order to include all these in a single query.

  Hello

  937440 wrote:
  Hi everyone, this is my first post in this portal.

  Welcome to the forum!
  Don't forget to read the forum FAQ {message identifier: = 9360002}

  I want to display the details of the table emp... for this I use this SQL statement.

  Select * from emp where mgr = nvl(:mgr,mgr);

  When I give the entry as 7698 it shows the matching records... and also when I don't give any input then it shows all the records except the Archbishop with null values.

  (1) I want to display all the records when I do not give any input, including null values
  (2) I want to display all the records that a Bishop is null

  Is it possible to integrate in order to include all these in a single query.

  It's a little unsure what you're asking.
  The following query always includes the lines where mgr is NULL and when the binding variable: mgr is NULL, it displays all the lines:

  SELECT  *
  FROM     emp
  WHERE     LNNVL (mgr != :mgr)
  ;
  

  In other words, when: 7698 = mgr, it displays 6 rows and when: mgr is NULL, it displays 14 rows (assuming you are using the table provided by Oracle scott.emp).

  The following query includes lines where Bishop is ZERO only when the binding variable: mgr is NULL, in which case it shows all lines:

  SELECT     *
  FROM     emp
  WHERE     :mgr     = mgr
  OR       :mgr       IS NULL
  ;
  

  When: mgr = 7698, this will display 5 rows and when: mgr is NULL, it displays 14 rows.

  The following query includes lines where Bishop is ZERO only when the link variab; e: mgr is NULL, in which case it shows only those rows where mgr is NULL. In other words, it treats NULL as a value:

  SELECT     *
  FROM     emp
  WHERE     DECODE ( mgr
              , :mgr, 'OK'
              )     = 'OK'
  ;
  

  When: mgr = 7698, this will display 5 rows and when: mgr is NULL, it displays 1 row.

• minimum hiredate from the emp table

  Hello
  
  There is a table EMP, hiredate column (date). I want to get the record with minimum hiredate and using this query.
  

  SQL> select * from v$version;
  
  BANNER
  ----------------------------------------------------------------
  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
  PL/SQL Release 10.2.0.4.0 - Production
  CORE    10.2.0.4.0      Production
  TNS for Solaris: Version 10.2.0.4.0 - Production
  NLSRTL Version 10.2.0.4.0 - Production
  
  SQL> with t as
    2  (select 'A' ename, 1 enum, '1-Oct-2008' hiredate from dual union all
    3  select 'B', 2, '1-Jan-2002' from dual union all
    4  select 'C', 3, '1-Mar-2008' from dual)
    5  select * from t
    6  where hiredate = (select min(hiredate) from t);
  
  E       ENUM HIREDATE
  - ---------- ----------
  B          2 1-Jan-2002
  
  SQL> 

  Is there another way to do it, without using subquery?
  
  Kind regards
  Ritesh

  Another option:

  SELECT  MIN(ENUM)       KEEP (DENSE_RANK FIRST ORDER BY HIREDATE)       AS ENUM
  ,       MIN(HIREDATE)   KEEP (DENSE_RANK FIRST ORDER BY HIREDATE)       AS HIREDATE
  FROM    t
  

  EDIT: See the post of John Spencer as it has a more in-depth explanation. This will only return the FIRST record oracle meets with minimal hiredate. It will not return more records if more than one employee has the same minimum hiredate.

  Published by: Centinul on October 23, 2009 09:38

• get the cumulative sum of the salaries of the employees of emp table

  Hi gurus,
  
  Can any body tell me how to get the cumulative sum of the salaries of the employees in the emp table using analytical functions.
  
  Thanks in advance...

  Please read the document

  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/functions163.htm#sthref2186

  Look for example at the bottom of the document.

• EMP table query

  Hi friends,
  
  Please help me get the following output from the EMP table:
  

  DEPTNO     EMPNO     ENAME     SAL      HIREDATE
  ------------------------------------------------------------------------------------
  10             7521        Arun         1000    01-Jan-2005
                  7522       Bala           2000    01-Feb-2005 
                  7523        Chitra         3000    01-Mar-2005
  20             7524        Divya         4000    01-Apr-2005
                  7525        Elango        5000    01-May-2005 
  30             7526        Fathima      6000    01-Jun-2005
                  7527        Gopal         7000     01-Jul-2005
                  7528        Hari            8000    01-Aug-2005

  Published by: BluShadow on February 15, 2012 08:29
  addition of {noformat}

  {noformat} tags for improved (not perfect, due to OP's source) readability.  Please read {message:id=9360002} and learn to do this yourself.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                        

  According to my understanding, you could require something like this:

       DEPTNO      EMPNO ENAME             SAL HIREDATE
  ---------- ---------- ---------- ---------- ---------
          10       7934 MILLER           1300 23-JAN-82
                   7839 KING             5000 17-NOV-81
                   7782 CLARK            2450 09-JUN-81
          20       7876 ADAMS            6200 12-JAN-83
                   7369 SMITH             800 17-DEC-80
                   7788 SCOTT            3000 09-DEC-82
                   7566 JONES            2975 02-APR-81
                   7902 FORD             3000 03-DEC-81
          30       7844 TURNER           1500 08-SEP-81
                   7698 BLAKE            2850 01-MAY-81
                   7521 WARD             1250 22-FEB-81
                   7499 ALLEN            1600 20-FEB-81
                   7521 WARD             6500 22-FEB-81
          40       7900 JAMES            5900 03-DEC-81
                   7654 MARTIN           6500 28-SEP-81
  
  Then, the query you could use is:
  
  SELECT (CASE WHEN rn = 1 THEN deptno ELSE NULL END) Deptno, empno, ename, sal, hiredate
  FROM (
  SELECT deptno, ROW_NUMBER() OVER (PARTITION BY deptno ORDER BY empno) rn ,empno, ename, sal, hiredate
  FROM emp); 
  

  Published by: claire on February 14, 2012 23:17

• XML from the Oracle Table data

  Hi all
  
  I'm new to this network. I'm also new to oracle XML package. I want a help with the query below.
  
  CREATE TABLE EMP (ID NUMBER PRIMARY KEY, NAME VARCHAR2 (10), TELEPHONE NUMBER);
  
  INSERT INTO EMP (ID, NAME, PHONE) VALUES (11, 'Joy', 1234);
  INSERT INTO EMP (ID, NAME, PHONE) VALUES (22, 'Mike', 5678).
  INSERT INTO EMP (ID, NAME, PHONE) VALUES (33, "Jason", NULL);
  COMMIT;
  
  I want to export data from the EMP table in an XML file with the format below.
  
  Power required:
  
  <? XML version = "1.0" encoding = "UTF-8"? > < Joy STATICDATA > < EMP > < ID > 11 < /ID > < NAME > < / NAME > < / EMP > < / STATICDATA >
  <? XML version = "1.0" encoding = "UTF-8"? > < Mike STATICDATA > < EMP > < ID > 22 < /ID > < NAME > < / NAME > < / EMP > < / STATICDATA >
  <? XML version = "1.0" encoding = "UTF-8"? > < Jason STATICDATA > < EMP > < ID > 33 < /ID > < NAME > < / NAME > < / EMP > < / STATICDATA >
  
  I used some XML functions and you wrote the following query.
  
  Select XMLROOT (XMLELEMENT (staticdata, XMLELEMENT (EMP, XMLELEMENT(ID,ID), XMLELEMENT(NAME,NAME))), version "1.0" encoding = "UTF - 8') xml EMP;
  
  my query output:
  
  <? XML version = "1.0" encoding = "UTF-8"? >
  < STATICDATA >
  < EMP >
  < ID > 11 / < ID >
  Joy of < NAME > < / NAME >
  < / EMP >
  < / STATICDATA >
  <? XML version = "1.0" encoding = "UTF-8"? >
  < STATICDATA >
  < EMP >
  < ID > 22 / < ID >
  < NAME > Mike < / NAME >
  < / EMP >
  < / STATICDATA >
  <? XML version = "1.0" encoding = "UTF-8"? >
  < STATICDATA >
  < EMP >
  < ID > 33 / < ID >
  Jason < NAME > < / NAME >
  < / EMP >
  < / STATICDATA >
  
  
  But I want the out as the power required above. all records in a single line. can someone help me achieve the desired output. also can I export all columns of the table with something like select * from the table in the XML file?
  
  Thank you
  Delobelle

  Don't know why you need it on a single line, but you could:

  Select XMLTYPE (REGEXP_REPLACE (XMLROOT (XMLELEMENT (staticdata, XMLELEMENT (EMP, XMLELEMENT(ID,ID), XMLELEMENT(NAME,NAME))), version "1.0" encoding = "UTF - 8'), CHR (10) |)) ' *<><'))>
  FROM EMP;

  SY.

• steps to create the new table using existing metadata

  Hi all
  
  
  That's what I want to achieve,
  
  I want to create a procedure that will take an input parameter as a table name lets say 'EMP ',.
  This procedure checks if this table exists or not?
  If they don't exist
  It will create a new table with the name _dummy join the existing table name (ex: new table will be EMP_DUMMY).
  and new table should have the same structure of the table, indexes, and constraints on the EMP table.
  
  
  NB: It should not be created using select as create table EMP_DUMMY select * from EMP where = condition false;
  
  
  
  Can someone help me please how to achieve this?

  Please, don't post duplicate discussions.

  Check your thread previous stored procedure to create a new table with the existing table structure to further discussions

• How to load the child table by using a simple slider...?

  How can I loa the child table by using a PL/SQL block cursor...
  
  for example, I have a table of the source called method
  
  EmpNo, empname, deptid deptname
  
  and I have 2 tables of taget... EMP and Dept.
  
  EMP
  ===
  EmpNo, empname, deptid
  
  Dept
  ====
  deptID, deptname
  
  
  Here, I want to load method for emp data and... Dept where dept does not contain data in double...
  
  For now... I used the cursor and in the same cursor, I'm loading data first dept table and then to the emp table.
  I use for dept, exceptional setting, which will manage a PK constraint violation error by doing nothing...
  
  in this way, there will be no duplicates... but it is not advisable because I 15,00,000 lines in the method table.
  
  Is there another way to do it?

  OK, I'd probably go with the method two insert, but as an alternative, here's a way to do it in a single insert:

  create table emp_info as
  select 1 empno, 'a' empname, 101 deptid, 'aaa' deptname from dual union all
  select 2, 'b' empname, 201 deptid, 'bbb' deptname from dual union all
  select 3, 'c' empname, 101 deptid, 'aaa' deptname from dual union all
  select 4, 'd' empname, 101 deptid, 'aaa' deptname from dual union all
  select 5, 'e' empname, 301 deptid, 'ccc' deptname from dual;
  
  create table emp (empno number primary key, empname varchar2(3), deptid number);
  
  create table dept (deptid number primary key, deptname varchar2(3));
  
  insert all
    WHEN rn = 1 THEN
         into dept (deptid, deptname)
         values (deptid, deptname)
    WHEN rn > 0 THEN
         into emp (empno, empname, deptid)
         values (empno, empname, deptid)
  select empno, empname, deptid, deptname, rn
  from   (select empno,
                 empname,
                 deptid,
                 deptname,
                 row_number() over (partition by deptid order by empno) rn
          from   emp_info);
  
    8 rows inserted
  
  commit;
  
  select * from emp;
  
       EMPNO EMP     DEPTID
  ---------- --- ----------
           1 a          101
           3 c          101
           4 d          101
           2 b          201
           5 e          301
  
  select * from dept;
  
      DEPTID DEP
  ---------- ---
         101 aaa
         201 bbb
         301 ccc
  

  You must test these two methods to see which is more efficient.

• separate account using the lookup table

  How can I get a separate count of column values by using another table?
  
  Let's say I want to get a separate account of all 'company_name' files in the 'emp' table that corespond (soccer match) with table of 'research', 'State' category.
  
  What I want is to find charges for all businesses that have a value of 'california' in the 'Status' column of the 'search' Table. I want the output to look like:
  
  Sears 17
  Pennys 22
  Marshalls 6
  Macys 9
  
  I want the result to show me the company names dynamically as I don't know what they are, just that they are part of the group 'State' in the lookup Table object. Does make sense?
  
  M

  If you want a counter for each value of rfs_category, but instead of rfs_category you want to display, it's translated value lookup_value_desc.

  This should do it for you:

  select lookup_value_desc, the_count
    from lookup
    join (select rfs_category, count(*) the_count
            from RFS group by rfs_category)
      on rfs_category = lookup_type;
  

• Remove the same instance of two separate tables online

  Hi all

  I have two tables that each repeatable lines. Both tables must display almost the same information in each case of the line (I managed to code to link the values in specific cases of the lines). However, I added a button in the repeatable row, which allows the user to remove from the current instance of the line, so will they look back and realize that they do not need a line, they can take directly from the table. However, I can't seem to get the deletion affects the same instance of row of the second table. Is it possible to do this? I'm not terribly familiar with the instance Manager.

  Any help would be greatly appreciated. I just can't understand how to identify a specific instance of the repeatable row in table 2.

  Hello

  Removing instances in the event of an object that is inside the instance, you must ensure that you remove this particular instance at the end of the event.

  For example:

  If you delete the instance that the button is on the inside before finishing the entire event, the program will not recognize what event is to finish because you have removed it from the object that is triggered...

  You try here at the end of the code that no longer exists...

  I suggest that you still need to delete the instance (this) object at the end of any event to make sure to complete all your actions before deleting the object.

  I hope this helps!