compare and replace the value

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• Find and replace the delimited string value by the

  Hi all

  I have a requirement where I need to find and replace the delimited string values.

  For example, the string is "GL ~ 1001 ~ 157747 ~FEB-13~ CREDIT ~ A ~ N ~ US ~ NULL ~". The 4th column gives the month and year. I need to replace it with the name of the previous month. For example: "GL ~ 1001 ~ 157747 ~JAN-13~ CREDIT ~ A ~ N ~ US ~ NULL ~". I need to do the same thing for the past 12 months.

  I thought initially divide the values and store it in a variable and then after him substituting the value required, join the return.

  I just wanted to know if there is a better way to do it?

  Like this:

  with a model like

  (select "GL ~ 1001 ~ 157747 ~ FEB-13 ~ CREDIT ~ A ~ N ~ $ ~ NULL ~' double UNION ALL data")

  Select ' GL ~ 1001 ~ 157747 ~ JAN-13 ~ CREDIT ~ A ~ N ~ US ~ NULL ~' double data)

  Select

  REPLACE (DATA, TO_CHAR (to_date (substr (data, 16.6), "MON-RRRR"), 'MON - RR'), TO_CHAR (to_date (substr (data, 16.6), "MON-RRRR")-1, 'MON - RR'))

  modeling;

  GL ~ 1001 ~ 157747 ~ JAN-13 ~ CREDITS ~ HAS ~ N ~ US ~ NOTHING ~

  GL ~ 1001 ~ 157747 ~ DEC-12 ~ CREDITS ~ HAS ~ N ~ US ~ NOTHING ~

  Ishan

• replace some symbols and converts the value to a number

  Hi all. I've got bp_link table with 'avalue' column VARCHAR2 (200). If I can find a different version of p here:
  
  (a) 100%
  (b) 100
  (c) 100.00
  (d) 100.00
  (e) null
  (f) symbol of space
  (I hope that all versions are mentioned).
  
  So I try to replace some symbols and convert the value to a number using the following steps:
  
  NVL(Avalue,0) - removes the null value
  Replace (NVL(Avalue,0), '%', ")-removes the symbol '% '.
  Replace (Replace (NVL(Avalue,0), '%', "), ',','. ')-remove a symbol «,»
  Trim (Replace (Replace (NVL(Avalue,0),'%',''),',','.')) - removes the symbol space)))
  TO_CHAR (Trim (Replace (Replace (NVL(Avalue,0), '%', "), ', '.'")), "FM999999999999.90")-converts format "100.00".
  
  But it still does not, maybe I don't see anything else.
  
  When I just "select * from...". "it works:
  
  Select to_char (trim (replace (replace (nvl(avalue,0), '%', "), ', '.'")), "FM999999999999.90")
  as avalue of JJ bp_link where roletypeid = 9
  
  But when I try "order by avalue" ends with error - ORA-01722: invalid number
  
  Select to_char (trim (replace (replace (nvl(avalue,0), '%', "), ', '.'")), "FM999999999999.90")
  as avalue of JJ bp_link where roletypeid = 9
  order of dd.avalue
  
  What can I do else?

  Maybe this will help you
  http://nimishgarg.blogspot.com/2010/04/Oracle-SQL-extract-numbers-from-string.html

• Need help to compare and replace

  Hi all
  
  I have a cumulative file that is added at the end of the month. The Table contains information about customers, like:
  
  customer_id, name, address, phone, notes, DATE_STAMP
  
  In addition, I have other Tables that are divided into monthly Tables and information for these monthly tables are obtained from this cumulative one table. When I collect the information at the end of the month (which is added to the summary table that grows in size), I put the name of the MONTH in the column DATE_STAMP. MARCH, APRIL, MAY, JUNE, etc...
  
  So I select all of MARCH (from the cumulative Table) and then who is put in the MARKET Table. These Tables are compared with others a month control Tables for analysis.
  
  The challenge is what to say in APRIL or MAY, a value important column changes in the summary table so I need to update the monthly tables to reflect this.
  
  Then... I will concentrate on the key columns.
  
  customer_id, DATE_STAMP, Sales_Person_Assigned
  
  In the cumulative table (which has many months), say I select all of MARCH and move customers to a MARCH_TABLE. I'll use a customer as an example:
  
  customer_id, DATE_STAMP, Sales_Person_Assigned
  12345, MARCH, NULL
  
  Then in APRIL, most data enters the cumulative file, and those who are stamped APRIL for DATE_STAMP column.
  
  So, when I check the client who was in MARCH, now in this file, they could be like this: (update of the record sales person)
  
  customer_id, DATE_STAMP, Sales_Person_Assigned
  12345, MARCH, Frank Smith
  
  I need a way to take the CUMULATIVE table and compare it with the corresponding MONTH_Table and update that Null for Frank Smith.
  
  So say what: September today and we have 9 separate Tables Jan - September and ONE cumulative Tables Jan - September, I need only a summary table to check all individual Tables and based on:
  
  customer_id AND DATE_STAMP - a JOIN match here and if the value is null before in the field of the Sales_Person_assigned, if is no longer null, updated as the new value of cumulative for the monthly tables.
  
  Any help would be appreciated, sorry if this sounds too complicated.

  user621335 wrote:
  AND (NVL (your. GTP, 'X'). = NVL (tt. GTP, 'Y');

  I know NVL is a function that will replace a value if it is NULL with X or Y. But I wanted to make sure I understand this line. Table your if value is NULL it puts an X (temporarily?) and Y for table tt temporarily?

  So if both are NULL, they will get an X and Y, then they could not equal each other. You can specify that? So that means, if they equal each other, there is no update and to what update? or am I confused?

  Sorry, my mistake - I would have had the same share values and else equal (I've corrected that now).

  If a table your or table tt has a NULL value in a column, no equality will return UNKNOWN, that is, even if we could have a value and the other NULL, it would not be picked up because NULL is the absence of a value and therefore cannot return true or false. NVL will set a value here for the purposes of the motion only, so that either TRUE or FALSE will be returned. Here, the key is that the NVL value must be a value that can never legitimately exist in the column, i.e., 'X' could never be a value in the Sales_Person_Asisgned column. If it's a numeric column, we use-1, or something just as impossible for a legitimate column value.

  If both are NULL, 'X' is equivalent to 'X', so the file will not be updated on this column, if it is NULL, 'X' will not match a legitimate value, so the record will be updated on this column.

• How to replace the value of a column in a table based on the value in the second column?

  Hi, I would like to find in a table 2D for values that meet certain criteria (for example, a column< 0.98).=""  based="" on="" which="" rows="" meet="" this="" criteria,="" i="" want="" to="" replace="" the="" values="" in="" a="" different="" column="" of="" the="" array="" (change="" to="" 'nan'="" so="" that="" the="" values="" will="" not="" be="" included="" in="" any="" calculations="" on="" that="" column,="" for="" example="" the="" finding="" the="" mean).=""  i've="" attached="" a="" sample="" .csv="" file.=""  if="" the="" values="" in="" column="" 3="" (index="" 2)="" are="" less="" than="" 0.980="" (or="" some="" other="" user="" defined="" value),="" then="" the="" value="" in="" column="" 2="" (index="" 1)="" should="" be="" replaced="" with="" nan.=""  can="" someone="" help="" out="" with="" this="" search="" and="" replace="">

  Thank you

  Keith

  (using LV 2009 SP1)

  A few quick hits.

  You can merge the two for loops

  You have not need one of the constants 1 and 2 in the index table.  They will solve automatically when you expand on the index picture, once you have wired to 0 in the column index.

  It seems a lot of handling additional table spent unnecessarily.

  See below.  I did not try to duplicate your code to see how it actually works, but I believe that I have attached will give the same result with less steps.

  

• How can I replace the value of the column with a particular value in SQL

  Hi all
  
  Is someone can you please tell me how can I format my output with the replacement of a column value with a specific value that really depends on the current value of the column
  
  I am executing the following SQL statement
  
  Select state, count (id) from < table_name > where composite_dn = < composite_dn_name > Group by State;
  My current performance is:
  
  State Instance number
  1 3
  3 28
  
  I want to replace the value in the State column as follows
  
  No.OfInstances State
  3 filled
  28 faulted
  
  I want '1' to be reppaced of 'Done' and '3' is replaced by 'Faulted. '
  
  Is is possible with SQL or PL/SQL, if it is then how I can achieve this required. Help, please!
  
  Thanks in advance!
  
  Published by: Roshni Shankar on October 27, 2012 12:38 AM

  Hi Claude,.

  I guess this CASE clause can be simulated by a DECODE and also it is very easy to use.
  See - http://www.techonthenet.com/oracle/functions/decode.php

  select decode(t1.state,t2.state_id,t2.state_name), t1.count_id
  from  t2, (select state,count(id) count_id
   from 
   where composite_dn= 
  group by state) t1
  where t1.state = t2.state_id;
  

  HTH
  Vanessa B.

  Published by: Vanessa B on October 27, 2012 14:02
  -link added

  Published by: Vanessa B on October 27, 2012 14:19
  -added code sample

• A Script to find and replace the layer names

  Is there scripts to find and replace the names of layers?

  There is an excellent script available for Photoshop that allows you not only to replace words in layer names, but also insert words as prefixes, Suffixes and sequential numbers.

  The version of the illustrator of this script allows only sequential numbering: it does not offer search and replace words.

  Ideally, it would be great if there were something that could find multiple and replaces in a go:

  (for example

  You have layers like this car, the dog, the bat

  You enter: because (Option1), dog (Option2), Bat (Option3)

  Your layers become then: option 1, option 2, Option3).

  )

  Big_SmiLe, which is a very good start! Step 1 of learning how to Script is indeed, by adjusting an existing simple script to make things more complicated. (And usually then "break something", which is also a necessary part of the process.)

  You are right your comment, it comes to repetitive things. For one or two different articles that wouldn't be a problem, but in the longer lists you are soon lost.

  As usual to work with lists of search - replace is to build a table:

  var layernames = [
  [ 'FHairBowlBoy *Hair', 'Hairboy1' ],
  [ 'FHairCurlyafroBoy *Hair', 'Hairboy2' ],
  [ 'FHairSpikyBoy *Hair', 'Hairboy3' ],
  ];
  

  The general idea is to loop through all the names, check if the current layer name is "layernames [i] [0]" (the left column) and if so, rename it "layernames [i] [1]" (the right column). If you know how to write a loop in Javascript, then you can implement this immediately.

  However...

  A more advanced method to do this didn't need even loop on all layernames - instead you can immediately 'get' the correct name by layer! It's magic! Almost!

  The trick is to use a Javascript object rather than a table. JavaScript objects are nothing special; "Layers" of Illustrator are an array of objects, and each object 'sex' has a 'name' property, which you can read and set the value. What I do here, is to create a new object, where the part 'name' is the name of the original layer and its value is the name of the new layer. All you need to check each layer is if there is a "object.originalLayerName" property and if so, assign its value to this layer name.

  It looks a bit like the table above, except that (1) you use {.} instead of [..] to create an object and (2) you add pairs "name: value" instead of 'value' only (in fact, the 'name' of a value in a table is simply her number).

  So here's what it looks like:

  // JavaScript Document
  var doc = app.activeDocument;
  // name indexed object
  var layernames = {
   'FHairBowlBoy *Hair':'Hairboy1',
   'FHairCurlyafroBoy *Hair':'Hairboy2',
   'FHairSpikyBoy *Hair':'Hairboy3'
  };
  // loop through all layers
  for (var i = 0; i < doc.layers.length; i++)
  {
   //Set up Variable to access layer name
   var currentLayer = app.activeDocument.layers[i];
   if (layernames[currentLayer.name])
   {
    currentLayer.name = layernames[currentLayer.name];
   }
  }
  

  Enjoy!

• ODI can load data into the planning and REPLACE the existing data?

  Hello
  ODI (9.3.1.1) can load data into the planning and REPLACE the existing data?
  Currently of our ODI by "ADD" load to existing data data - so that is I accidentally run the load twice, it would be double planning numbers. I don't know how to do it to REPLACE so that running more than twice has no effect.

  With the help of the essbase adapter you would use a rule of load, in the State of charge, you can set whether to replace or add to existing values. It is not difficult to pass.

  See you soon

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  http://John-Goodwin.blogspot.com/

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  I hope that clarifies the doubts...

• Satellite A30 921: how to remove and replace the memory?

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  Thank you in advance.

  Hello

  There is not much to explain. On the low side in the Middle it is placed to cover memory (fixed with two screws). Remove the cover and you will see 2 slots there. I put t know how much memory you here but like Stefan says you can use max 2 GB of RAM (2 x 1024Mo PC2700 - PA3313U-1M1G). How to remove the memory modules, which you can see on http://www.hardwaresecrets.com/article/189/5

  Good bye

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• How to acquire and store the values of DAQmx analog voltage (I do not want the graphic, but strings and values in a chart)?

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  Thank you very much.

  
  

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• Search and replace the string formatting

  Hello

  I try to do a search and replace the formatting of a string.

  In the example, I'm looking for the string 'SUCCESSFUL', but it must also begin by usbflash and some number + PASSED.

  I can't get the format to have a number between 1 and 99. The number of replacements should add up to 6 in this case. I tried with \d for any number, and I also tried [1-99].

  Make a right-click on the function search and replace the string.  There is an option to use regular Expressions.  Then give it a try.

  

  EDIT: You need to set the entry replace all to TRUE.