Compare the result of a query with a number and return a message
HelloI have the following query in oracle 9i:
SELECT COUNT (*)
OF hourly_files
WHERE date_received = TO_DATE ((SELECT TO_CHAR (SYSDATE - INTERVAL '1' DAY, 'DDMMYYYY')
(THE DOUBLE), 'DDMMYYYY');
This will produce a number of lines required
I need to compare the number of output with another number hardcoded (threshold) and print an appropriate example message
If the result of the query above is 18000 and the number of threshold is fixed at 20000, then output a meesage:
Number of files received less than 2000
Any help will be very appreciated!
Thank you.
SQL> ed
Wrote file afiedt.buf
1 SELECT CASE WHEN COUNT(*) >5 THEN 'Number is > than 5'
2 WHEN COUNT(*) <1 THEN 'Its less than 1'
3 ELSE 'Its in between'
4 END
5 FROM emp
6* WHERE deptno=20
SQL> /
CASEWHENCOUNT(*)>5
------------------
Its in between
SQL> SELECT COUNT(*) FROM emp
2 WHERE deptno=10;
COUNT(*)
----------
3
Tags: Database
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