Count the number of records between two values of keys (BTREE)

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• Dynamic calculation of the number of days between two dates in a table

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  Hi BO123,

  BO123 wrote:

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  one of the way to do this by calling ajax on change of end_date.

  See the sample code given below to fetch the resulting duration and making the field read only after calculation

  Step 1: Change your page

  under CSS-> Inline, put the code below

  .row_item_disabled {
    cursor: default;
    opacity: 0.5;
    filter: alpha(opacity=50);
    pointer-events: none;
  }
  

  Step 2: Create on demand Ajax process I say CALC_DURATION

  Please check Procces Ajax, see line 6.7 How to assign a value to the variable sent by ajax call

  Declare
    p_start_date  date;
    p_end_date    date;
    p_duration number;
  Begin
    p_start_date  := to_date(apex_application.g_x01);
    p_end_date    := to_date(apex_application.g_x02);
  
     --do your calculation and assign the output to the variable p_duration
    select p_end_date - p_start_date into p_duration
      from dual;
  
    -- return calculated duration
    sys.htp.p(p_duration);
  End;
  

  Step 3: Create the javascript function

  Change your page-> the function and the declaration of the Global Variable-> put the javascript function

  You must extract the rowid in the first place, for which you want to set the time, see line 2

  assuming f06, f07 and f08 is the id of the start date, and end date columns respectively, and duration

  See no line no 8 how set the value returned by the process of ajax at the duration column

  Replace your column to the respective column identifiers in the code below

  function f_calulate_duration(pThis) {
    var row_id  = pThis.id.substr(4);
    var start_date = $('#f06_'+row_id).val();
    apex.server.process ( "CALC_DURATION", {
    x01: start_date,x02: $(pThis).val()
  }, { success: function( pData ) {
  // set duration to duration column
  $('#f08_'+row_id).val(pData);
  // disable duration column
  $("#f08_" + row_id).attr("readonly", true).addClass('row_item_disabled'); }
  });
  }
  

  Step 4: choose the end date call the javascript function

  Go to report attributes-> edit your Date column end-> column-> Attrbiutes element attributes-> put the code below

  onchange="javascript:f_calulate_duration(this);"
  

  
  

  hope this helps you,

  Kind regards

  Jitendra
  

• JavaScript anomaly on the number of days between two dates

  Use ApEx 4.0, I found an anomaly in a javascript code that calculates the number of days between two dates, the current_date and the past_date. If the past and present is the or before March 10, 2013, and the current_date lies between 10 March 2013 and November 3, 2013, the number of days will be from 1 day to less than the actual number. Between November 3, 2013 and on 4 November 2013, the increments of number by 2, then the count will be accurate from this date forward.
  
  Here are some examples:
  
  March 10, 2013 = 69 days of December 31, 2012
  March 11, 2013 = 69 days of December 31, 2012
  March 12, 2013 = 70 days of December 31, 2012
  
  November 3, 2013 = 306 days in December 31, 2012
  November 4, 2013 = 308 days in December 31, 2012
  
  11 March should be 70 and 12 March should be 71. November 3 is 307 and 4 November corrects the number of fake, which began March 11.
  
  Change the past_date to March 10, 2013 produces the following:
  
  March 10, 2013 = 0 days of March 10, 2013
  March 11, 2013 = 0 days of March 10, 2013
  March 12, 2013 = 1 days of March 10, 2013
  
  But change the past_date to 11 March 2013, product of the correct numbers:
  
  March 11, 2013 = 0 days of March 11, 2013
  March 12, 2013 = 1 days of March 11, 2013
  March 13, 2013 = 2 days of March 11, 2013
  
  I would certainly all help to determine the cause of this anomaly. Here's the javascript code:
  
  var w1 = ($v ("P48_PAST_DATE"));
  W1 = (w1.toString ());
  vmon var = (w1.substr (3.3));
  vyr var = (w1.substr (7));
  var r = (vyr.length);
  If (r == 2)
  vyr. = (parseFloat (vyr) + 2000);
  vday var = (w1.substr (0.2));
  var y = (vmon.concat ("", vday, ",", vyr));
  y = Date.parse (y);
  
  var w2 = ($v ("P48_CURRENT_DATE"));
  var vmon2 = (w2.substr (3.3));
  var vyr2 = (w2.substr (7));
  var vday2 = (w2.substr (0.2));
  var x = (vmon2.concat ("", vday2, ",", vyr2));
  x = Date.parse (x);
  
  var numdays = (x - y);
  numdays = (Math.floor(numdays / 86400000));
  $s ("P48_NUMBEROFDAYS", numdays);

  Did you google for something like "javascript number of days between two dates. I think you will find the explanation to this observation:

  This method does not work correctly if there is an advanced economies jump between the two dates.

  There are examples available to calculate the difference between two dates.

• count the number of records

  I have a control block View1 with some fields, YEAR, MONTH, STAFF and button SEARCH with the trigger button when pressed with the pl/sql code 'go_block (view2); execute_query; »
  View2 is the block of data showing 10 records on canvas with the fields NAME, STAFF, WAGES...
  in the palette view2, property
  Insert allowed the value or not, update enabled is set to no and in which I put a code of clause.
  After pressing the View1 SEARCH get all the required documents output.
  I want to count the number of records of my outings.
  How do I do that... ???
  
  
  thnx. (I use 10g)

  ManiKanchan wrote:
  I have a control block View1 with some fields, YEAR, MONTH, STAFF and button SEARCH with the trigger button when pressed with the pl/sql code 'go_block (view2); execute_query; »
  View2 is the block of data showing 10 records on canvas with the fields NAME, STAFF, WAGES...
  in the palette view2, property
  Insert allowed the value or not, update enabled is set to no and in which I put a code of clause.
  After pressing the View1 SEARCH get all the required documents output.
  I want to count the number of records of my outings.
  How do I do that... ???

  thnx. (I use 10g)

  You can use a column with data type number and not the database.
  Set

  calculation mode :summary
  summary function:count
  summarized block:your_block_name
  summarized item:name_column
  

  Hope this helps...

• Count the number of hours between the dates off holiday/weekend

  Hi all
  
  I've not worked with dates and was recently asked to create a report where I am looking for the number of hours between two dates only count business days.
  
  So for example I have given as follows
  
  Created on 2011-03-30 15:00
  Treaty of 2011-03-30 15:03:46
  Filled 2011-04-01 17:25:02
  Posted 2011-04-01 17:45
  
  For a total of looking for the CREATION and dates
  
  50 hours and 45 minutes
  
  IM also trying to exclude weekends and holidays, I read around and was able to also find an array of dates where I main date, the HOLIDAY_IND column, and the column WEEKDAY_IND
  
  If the calendar table I have looks like
  
  CALENDER_DATE HOLIDAY_IND WEEKDAY_IND
  2011-03-31 YY
  2011-04-01 N Y
  2011-04-02 N N
  
  IM really very puzzled to know where to start
  
  I thought I'd try to write with PL/SQL, but I don't have access of the user to create procedures/functions, so looks like right up to SQL
  
  Any help is appreciated!

  Hello

  Depeneding on your data and your needs, you can do something like this:

  SELECT     created_DATE,
  ,     mailed_date
  ,     24 * ( (mailed_date - created_date)
            - (
              SELECT  COUNT (*)
              FROM        table_o_dates
              WHERE    main_date > created_date
              AND        main_date < TRUNC (mailed_date)
              AND        (   holiday_ind = 'Y'
                       OR  weekday_ind = 'N'
                    )
            )
             )               AS hours_between
  FROM     table_x
  ;
  

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all tables and also post the results desired from these data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

  What do you do if created_date or mailed_date is not a working day? Examples in you data and results.

• Try to count the number of records where some columns are met

  Using SQL in Toad against an Oracle table, I'm trying to count the number of records in a table where some columns are filled. For
  example, I need to know the total number of records from a table where
  
  ln_stop_cd is not null - 65000 records
  ln_process_cd is <>- 25000 0 records
  ln_opt_cd is not null - 7500 records
  
  and the record_type = "A".
  
  I know that the total individual records as described above. However, I do not know how
  the SQL to show for record_type = 'A' the total count is 97500 records. Any help would be
  appreciated.

  Hello

  It seems that the problem is that the indictment may overlap; You can count the same rank 0, 1, 2 or 3 times, depending on whether 0, 1, 2 or 3 of these 3 independent conditions are met.

  Try something like this:

  SELECT     COUNT (in_stop_cd)
        + COUNT (CASE WHEN in_process_cd  != 0        THEN 1 END)     -- this site doesn't like the other inequality operator
        + COUNT (in_opt_cd)        AS grand_total
  FROM    table1
  WHERE     dt          >= TO_DATE ('01-JUN-2011', 'DD-MON-YYYY')
  AND     dt          <  TO_DATE ('02-JUN-2011', 'DD-MON-YYYY')
  AND     record_type       = 'A'
  ;
  

  You want to make charges without making 3 assists separated through the table. The problem is the 3 original requests had slightly different WHERE clauses.
  Put these conditions in the WHERE clause and make other conditions apply only to the individual counties, either with a column instead of *, or using a CASE statement that contains the condition that applies only to the column.

  Also, the date is not a column name good. Do not compare the DATEs to strings. If your column is really a DATE and you want to ignore the hours, the minutes and seconds, then the best way is to compare the column with 2 other DATES, as shown above. It's more coding, but it is more efficient and more reliable.

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  You don't have to display a large amount of data. You can probably give an excellent example of this problem with only 5 or 10 rows of sample data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

  Published by: Frank Kulash, August 4, 2011 11:27

• How to count the number of Sundays between the two dates

  Hello
  
  I want the number of Sundays between the two dates
  
  example of
  
  number of number of Sundays between 4 January 2013 ' and April 30, 2013 "in a select query, I have to include this as a sub query in my select statement.

  nordine B wrote:
  Hi Frank,.
  Have 1 doubt...

  In many countries the week could me "Monday". How the application handles it?
  Or did I get something wrong?

  Help, please!

  For ' IW'(ISO week) early in the day is always Monday...

  It's so simple - calculate the weeks between two dates based on Monday... This is the number of Sundays...

  NEXT_DAY is another option...

  SQL> with dd as
    2  (
    3      select TO_DATE('01-04-2013','dd-mm-yyyy') fdt, TO_DATE('30-04-2013','dd-mm-yyyy') ldt from dual
    4  )
    5  SELECT       fdt,ldt,
    6            (next_day(ldt,'sunday')-next_day(fdt-1,'sunday'))/7 sdays
    7  FROM         dd;
  
  FDT       LDT            SDAYS
  --------- --------- ----------
  01-APR-13 30-APR-13          4
  

  Published by: JAC on May 2, 2013 12:20

• Number of records between two dates which lasted more than a minute

  I need to count the number of events/records in a single table with the dates of appointment and for how long the appointments in another table, I have two cells to hold dated (start and end dates) give a range. I want to count the number of appointments that lasted more than a minute falling into the test range.

  I am sure that this is COUNTIFS and I tried to make it work.

  Hope you can help.

  Thank you

  You could do something like that

  

  The data table on the left and are named "Data."

  Data in the table on the right.  Enter the Start Date, end Date and time Min.

  D2 = COUNTIF (Data::B, "> =" & C2, Data::A, "> =" & A2, Data::A,")<>

  It's abbreviation dethrone select cell D2, and then type (or Coptic and paste here) the formula:

  = COUNTIFS(Data::B, ">="&C2, Data::A, ">="&A2, Data::A, ")<>

• Calculate the number of days between two dates

  Hello

  Can someone help please change my formcalc script to calculate the number of working days between two date fields.  My script currently calculates the total number of days between two dates, including the weekends which must be excluded from the total.

  If

  (HasValue (Start_Date1) & HasValue (End_Date1)) then

  $

  = Date2Num (End_Date1, "YYYY-MM-DD" "en_IE") - Date2Num (Start_Date1, "YYYY-MM-DD" "en_IE") + 1

  on the other

  ""

  endif

  Any help will be most appreciated.

  Thank you.

  Check...

  (1) you said that you put the script on the event «days1» calculate My sample imitates the variable names used in the original message, "Start_Date1" and "End_Date1". If the names of variables for the start and end dates are different, you will need to modify the script to account for these names.

  (2) the Date2Num functions in the calculation of the "totalDays" use the date format "YYYY-MM-DD". If your date habits differ from "YYYY-MM-DD" FormCalc will complain.

  Steve

• Dynamically calculate the number of days between two dates and amounts of split

  Hello
  
  I have searched for a solution for this, but had no success.
  I need to show the amounts broken down by days.
  
  I have a table that has an amount column and start and end dates.
  
  I need to write a query so that the amounts will be broken evenly based on the number of days between the start date and end date.
  
  For example, for this line.
  insert into my_test values (' 1, '' 3-mar-2010, ' 7 - mar - 2010 ", 1000);
  
  the query returns this (split $1,000 over 5 days)
  
  
  ID Date amount
  1 ' 3-mar-2010' 200,00
  1 ' 4-mar-2010' 200,00
  1 ' 5-mar-2010' 200,00
  1 ' 6-mar-2010' 200,00
  1 ' 7-mar-2010' 200,00
  
  
  
  create table my_test)
  ID number (10),
  start_date date,
  End_date date,
  amount number (10.2)
  );
  
  
  Select * from my_test
  
  insert into my_test values (' 1, '' 3-mar-2010, ' 7 - mar - 2010 ", 1000);
  insert into my_test values (2, 10-mar-2010 ", 19-mar-2010", 2000);
  insert into my_test values (3, 20-mar-2010 ',' 21-mar-2010, 5000);
  
  
  
  Thanks in advance.

  Hello

  One way is to join a Meter of Table , a table, or (more often) a set of results includes a line for eery number 1, 2, 3,... until the maximum number of times you need to divide a line.
  For example:

  WITH     cntr     AS
  (
       SELECT     LEVEL - 1     AS n
       FROM     (  SELECT  MAX (end_date - start_date)     AS max_day_cnt
               FROM        my_test
            )
       CONNECT BY     LEVEL <= 1 + max_day_cnt
  )
  SELECT       t.id
  ,       t.start_date + c.n                    AS dt
  ,       t.amount / (t.end_date + 1 - t.start_date)     AS amt
  FROM       my_test      t
  JOIN       cntr            c     ON     c.n <= t.end_date - t.start_date
  ORDER BY  id
  ,            dt
  ;
  

  This assumes that all dates have the same number of hours, minutes, and seconds, as is the case in your sample data.
  If this isn't the case, then use TRUNC (start_date) and TRUNC (end_date) instead of start_date and end_date or post some sample data and results if some lines do not represent a whole number of days.

• Count the number of records in all tables with a querry URGENT please...

  I downloaded ORACLE 9I DATA DUMP in my computer. There are number of tables. I need to know the tables with records more of say 100 or on the go. Is it possible... If so kindly let me know.
  
  Second, the database that I downloaded, I discovered that Audit_ trial was not activated by cooking
  ' select name, value of v$ parameter.
  where name like '% verification' and it turned out to be false.
  Can we assume that the database in the server as the audit_trial has been disabled...
  
  Published by: user1287492 on October 21, 2009 09:07

  Hello

  Place the table name with quotes. Maybe that's the problem.

  Try this code

  select table_name,
   to_number(
   extractvalue(
   xmltype(
   dbms_xmlgen.getxml('select count (*) c from "'||table_name||'"' ))
   ,'/ROWSET/ROW/C')) COUNT
   FROM USER_TABLES
   where iot_type IS NULL
  /
  

  SS

• Calculation of the number of rows between two rows

  Hello
  
  For a query I want to connect two tables with an outer join, and the external joined table instead of display NULL values display the value of the last row containg data. I try it using the LAG function, but I need the number of lines from which to extract the data to be dynamic, as the gap between the current line (NULL) and the last line displays data.
  
  For example:
  
  SELECT NVL (fadd.deprn_reserve,
  LAG (fadd.deprn_reserve, "XXX") OVER (ORDER BY fadp.period_counter)
  ),
  fadp.period_counter
  OF fa_deprn_detail fadd, fa_deprn_periods naturally
  WHERE fadd.period_counter (+) = fadp.period_counter
  
  , where 'fadd' contains amounts and accounting periods 'naturally '. For example, there would be a balance in NOV - 08 with the next transaction is made in MAY - 09. Periods DEC-08 Apr-09 all shall display the balance of NOV - 08. The "XXX" would be the difference of the position of each line to the ' NOV-08' containing the amount to use.»
  Is there a way to calculate the difference in positions of line like this, or this approach is not feasible?
  
  Concerning

  Hello

  I think LAST_VALUE is better for this task.

  As Salim said, it is always useful to post a small example of data and the results desired from these data. Your version of Oracle can be important.

  Using the table scott.emp, here is an example of using LAST_VALUE:

  SELECT       ename
  ,       comm
  ,       LAST_VALUE (comm IGNORE NULLS)
                   OVER ( ORDER BY       ename
                        ROWS BETWEEN  UNBOUNDED PRECEDING
                       AND       1         PRECEDING
                   )  AS prev_comm
  FROM       scott.emp
  ORDER BY  ename
  ;
  

  Output:

  ENAME            COMM  PREV_COMM
  ---------- ---------- ----------
  ADAMS
  ALLEN             300
  BLAKE                        300
  CLARK                        300
  FORD                         300
  JAMES                        300
  JONES                        300
  KING                         300
  MARTIN           1400        300
  MILLER                      1400
  SCOTT                       1400
  SMITH                       1400
  TURNER              0       1400
  WARD              500          0
  

• How to count the number of data records?

  Hey guys, how to count the number of records, I had on a data object variable?

  Im having a result of sql query in a variable like this:

  oDB.resolveNode("#command").query.select.value = "SELECT * FROM Customers WHERE CliNombre LIKE ' % ' + input1 +" %' ";

  oDB.open ();

  oDB.first ();

  So I need to count the number of records retrieved by this SQL query at the moment. Help please

  Then move the cursor back to the first record after you have your account.

  There is a keyword count in SQL that will allow you to get the account of your request. You can run that first - get your account, and then run the actual query to get the Recordset. This would require a separate data connection. Some examples of code.

  var xfa.event.newText = inName;
  If (inName == "") {}
  App.Alert ("you must enter a name--try again!")
  }
  var nIndex = 0;
  While (xfa.sourceSet.nodes.item (nIndex) .name! = "DataConnection2")
  {
  nIndex ++;
  }

  oDB = xfa.sourceSet.nodes.item (nIndex) .racing var (1); pertaining to the specified data connection node
  App.Alert (ODB.saveXML ("Pretty"));

  var nIndex = 0;
  While (xfa.sourceSet.nodes.item (nIndex) .name! = "DataConnection3")
  {
  nIndex ++;
  }
  var oDBCount = xfa.sourceSet.nodes.item (nIndex) .racing (1); pertaining to the specified data connection node
  Configure sql call DB to get the number of records that match the criteria

  oDBCount.nodes.item (1).query.setAttribute ("text", "commandType");
  oDBCount.nodes.item (1).query.select.nodes.item (0) .value = "Select count (*) from table1 where AcctNumber = '" + inName + "'";
  oDBCount.open)
  oDBCount.close)

  Configure sql call DB to get the specified employee number

  oDB.nodes.item (1).query.setAttribute ("text", "commandType");
  oDB.nodes.item (1).query.select.nodes.item (0) .value = "Select * from table1 where AcctNumber = '" + inName + "'";
  App.Alert (ODB. Nodes.Item (1) .saveXML ("Pretty"));

  now connect to the DB and get a recording
  oDB.open)
  oDB.close ();

  Note the SQL command use the keyword count (take a look at the oDBCount section). This will return a number of return to the cllaer. When I set up the data connection, a node count (*) that appeared there. I dragged to the form and it has created a field called count that the onus at this node. When the query is executed, the number of resulting records returns to this field. You can have hidden it so that your users can not see it and also to change the binding votes to zero, so it is not included in the data file that is submitted when the form is complete.

  Paul

• Number of weeks between two dates that are in the same or different year

  Hello

  How to calculate the number of weeks between two dates?

  for example. "" "17-mar-2013' and June 27, 2013" or June 15, 2013 "and" 25-mar-2014
  

  
  

  Thanks in advance.

  lukx
  

  Hello

  Looks like your date range is incorrect.

  Please try the below.

  SQL >-front right

  SQL > select D2 - D1 "days."

  2 round ((D2-D1)/7.0) "weeks."

  3 round (Months_between (d1, d2), 0) 'months '.

  (select 4

  5 TO_DATE ('20121201', 'YYYYMMDD') D1, D2 TO_DATE ('20130116', 'YYYYMMDD')

  6 from two

  (7) date_range;

  Elapsed days weeks months

  ------------ --------- ---------

  46         7         1

• Find the number of days between the dates...

  Hi friends,

  I am new to this development of blackberry applications so I do not know how to find the number of days between two days. Y at - there any API is avilable otherwise we have to write our own code. In fact, I tried GregorianCalendar but I get error that cannot find the symbol but I already imported net.rim.device.api.util and package java.util also... Please give an idea how to solve this problem.

  with respect,

  s.Kumaran.

  Use DateField class instances to represent dates on the screen.

  And your code will be as follows:

  long date1 = date1DateField.getDate ();

  long date2 = date2DateField.getDate ();