Create an Instance of the entity that is conditional on a screen

Similar Questions

• Impossible to find a solution to control the next dates on multiple instances of the entity.

  Hello

  I have a simple scenario. I have two instances of an entity that match two records of a component of bussiness in Siebel. I need to put a validation that the date of the end of an instance is the eve of the start date of the other.

  Using the functions Nextdate() etc. can be useful within the same instance, but the way to check on multiple instances?

  Any suggestion is welcome.

  If you want to exclude from the last instance, there are two options. You can set a Global attribute to the start date of the last session, for example

  the date of beginning of last session = InstanceMaximum (sessions, the start date of the session)

  ... then use this attribute as a filter in your other rules. If there are some things where you want to run the logic on the same subset of instances (e.g., the subset that excludes the last instance), then it might be useful to create an inferred relationship:

  1. in the properties file, create one-to-many relationship overall to the session. (Relationships that will be deducted must always be on many-to-many.)

  2. give the new relationship a unique and descriptive name for example 'the sessions (excluding the last session) '.

  3. write a membership rule to determine which instances of the entity are part of the new relationship, for example

  the session is a member of the sessions (excluding the last session), if

  start date of the session< the="" start="" date="" of="" the="" latest="">

  4. When you want to redo the subset of instances of logic, use the relationship 'the sessions (excluding the last session)' rather than 'the sessions', for example

  the end dates of the sessions are valid if

  ForAll (sessions (excluding the last session), the session end date is certain)

  Using the cross-entity argument version of my example above, the following rule could be set to TRUE:

  the end dates of the sessions are valid if

  ForAll (sessions (excluding the last session), the session end date is certain)

  Whereas this rule would have the value FALSE:

  the end dates of the sessions are valid if

  ForAll (sessions, the closing date of the session is certain)

  I hope that gives you enough to continue their career with your specific scenario!

  See you soon,.

  Jasmine

• Cannot create an instance of the java virtual machine

  Hi when I try to launch my sql developer get this error

  Cannot create an instance of the java virtual machine located in the path C:\Program Files\Java\jdk1.6.0_38\jre\bin\client\jvm.dll, but I do not have the file in the location

  I'm trying to do

  BI CHAOS: SQL Developer: cannot create an instance of the Virtual Machine Java

  Cannot create an instance of the Virtual Machine Java

  but am not able to locate file product.conf in my machine
  

  OK, we lost time because you said never explicitly release of SQL Developer in use, and then, when I deduced this wrong, you went right with it, rather than correct me.  Remember the line from Blade Runner when Harrison Ford hits Rutger Hauer in the head with a pipe?  Than hurt!

  Anyway, since the last post (because of the osgi references in the file ide.conf) I see that you are using a version 4.0.x of SQL Developer.  You must update the file product.conf with the smallest Xmx value in order to create an instance of the JVM.  If you have not yet found the product.conf file on your system, this might help: http://www.thatjeffsmith.com/archive/2013/12/oracle-sql-developer-4-windows-and-the-jdk/

  Otherwise, ask someone in your organization COMPUTER help - keep in mind that AppData is one of those hidden Windows directories, so you'll have to tell explore to make it visible by the organize > Folder Options > view > hidden files and folders parameters.  In addition, you should use Java 7, not Java 6 - try to get that upgrade to the latest version of jdk1.7.0_xx (currently 60, I think).  Since you never said if your JDK is 32-bit or 64-bit, I can not say to use an AddVMOption, Add32VMOption or Add64VMOption.

  Best wishes

  Gary

  Post edited by: Gary Graham

• Re-evaluate the relationships after adding a new instance of the entity

  Hi all

  I have an 'X' entity for which global > X 1:M relations are evaluated on the screens. For example, after we collect the instances of 'X', the next screen ask you, out of all the X, which is a member of the relationship there. The interview continues.

  The question we now face is that if the user decides to add an additional instance of 'X' after having answered the relationship screen, screen relationship there does not appear once more.

  Ideally, we would like this screen once more, now that the extra 'X' was added, since it is theoretically 'unknown', they are also in the relationship Y or not. Instead, the debugger shows the relationship there is known and empty for the new 'X' entity instance.

  Is it possible to have this screen once more, once the new instance of the entity?

  Thanks for your help,

  -Julien

  Julien,

  The solution for this is not quite easy. Once the relationship is known to 'Y', the screen will be visited not unless the user chooses explicitly (usually data review screen).

  Event Manager solution

  A solution is to implement an event handler that sets the relationship 'Y' Unknown when the user adds a new 'X' entity. This requires custom code. See 'Events and event handlers' in the Guide of the developer of automation Oracle policy

  The entity implied solution

  Another (perhaps easier) solution is to infer the relationship 'Y' and collect information on the same screen that 'X' entities are added. This is best illustrated by an example.

  For the entity 'X', I'll use "person" global to the containment relationship no one is 'the people '.

  For relationship 'Y' I will use the global relationship person '' the special people. ''

  On the person entity, I have 2 attributes "name of person" (text) and 'the person is special' (Boolean)

  I have the following rule to infer the relationship '' the special people. ''

  the person is a member of the special people if

  the person is special

  The next step is to ensure that when you add features of person, they state "name of person" and "person is special."

  It will have 2 effects:

  1. the relationship "the special people" will be deducted, that there will be no screen to associate the relationship.

  2. for the collection of instances of the person, the extraordinary selection (or not) will determine members

  I think that the solution infers entity could be your best option. It requires no code and simplifies the interview.

  Hope this helps

  See you soon

  Frank

• Create an instance of the component with CLSID {0002DF01-0000-0000-C000-000000000046} COM IClassFactory failed due to the following error: 80004005.

  I have IE 9 installed on my machine. When I try to create objects of IE using SHDocVw. Its version is 6.1.7601.17514. When I run my windows service it runs fine but when I create an installer and then run, it displays the error message: creating an instance of the component with CLSID {0002DF01-0000-0000-C000-000000000046} COM IClassFactory failed due to the following error: 80004005.

  IE = new SHDocVw.InternetExplorer ();
  IE = new SHDocVw.InternetExplorer (true);

  I tried the two lines.

  Please give me a solution.

  Hi Patrick,

  The problem you are having is more complex than what is generally answered in the Microsoft Answers forums. It is better suited to the MSDN forums.

  Please post your question in the MSDN Forums.

  You can follow this link to ask your question:

  http://msdn.Microsoft.com/en-us/library/aa752084%28V=vs.85%29.aspx

  I hope this helps. If you have problems of Windows in the future, let us know and we would be happy to help you.

• Cannot create an instance of the Virtual Machine Java

  Hi all

  I try to install and test the Jdev OAF for R12.2.4 in patch 19170592

  After installation, when I run the page you arest_fwktutorial.jsp and click on Hello world or any other link, it gives me an error saying: failed to create an instance of the java virtual machine...

  Here is the part of the Jdev log file:

  URL - target http://***/:8988/OA_HTML/test_fwktutorial.jsp

  March 9, 2015 17:06:47 oracle.jsp.logger.JspMessages infoCannotDispatchJspPage

  INFO: Failed to send the JSP Page: oracle.jsp.provider.JspCompileException: < H3 > errors compiling:C:\Users\XXX\OAFR12\jdevhome\jdev\myclasses\.jsps\\_OA.java < / H3 > < pre > WARNING: cannot find default VM 'ojvm' to...... \jdk

  help the client instead.

  Error occurred during initialization of VM

  Could not reserve enough space for lots of things

  I use a desktop computer of Windows 7 with 64 bit OS and 4 GB of RAM

  Can anyone help please if you know of a fix for this error.

  Thank you

  -John.

  for the record, the procedure below solves the problem:

  1. Open the control panel
  2. Go to system
  3. Go to the properties of advanced systems
  4. Environment variables can
  5. In System Variables, click Add
  6. New name of the Variable: _JAVA_OPTIONS
  7. New value of the Variable:-Xmx512M
  8. Click OK

  Thank you

  -John.

• How to programmatically create an instance of the target

  Is there a way to create an instance of the target programmatically. Basically, I have a goal which, in the addition of the target manually, create and instantiate a subtarget including metrics gives the availability. Is there a way in which I can programmatically create an instance of the target.

  I felt the portions of automatic detection of the chapter helped me to meet my needs. Instances of targets could be created as part of the discovery process and thus made available during the process of guided discovery.

• Cannot create an instance on the Virtual Machine Java

  Hello world
  
  I installed 11.1.2.3.0 Jdeveloper.
  And tried to run the Jdeveloper but got error below:
  
  "Failed to create an instance on the Virtual Machine Java located at c:\oracle\Middleware\jdk160_24\jre\bin\client\jvm.dll road.
  I tried several options but nothing has worked for me.
  
  Please suggest solutions for this.
  
  Thank you.

  Hello
  Check

  http://no-con-fusion.blogspot.com/2011/06/unable-to-create-instance-of-Java.html
  http://pisceansheart.WordPress.com/2009/08/06/solution-to-unable-to-create-an-instance-of-the-Java-virtual-machine-for-JDeveloper/

• Create a concatenated string of attributes on Multiple Instances of the entity

  Hello world

  I wonder if someone has met this challenge, or ideas. We have been asked if OPA could produce a string containing the concatenation of the values of an attribute of text stored on multiple instances of an entity. The number of instances is variable, generally.

  Example: Assume that the attribute is "DayOfWeek", and we have an entity called "Appointment", with the authorities:

  appointment_1 (DayOfWeek = 'Monday')

  appointment_2 (DayOfWeek = 'Thursday')

  appointment_3 (DayOfWeek = 'Sunday')

  ... we need produce a string "AllAppointmentDays" = "on Monday, Thursday, Sunday.

  We don't think that this is possible without either: (a) an external system to generate the resulting concatenated string of the output, or (b) modules with the command of the approach to read the white paper Oracle in Nov 2012 (approaches to limits, thresholds and preferences), combined with hard-coding and the constraints on the length of the string.

  
  

  I was wondering if there was a better way to do it without external script or forced / hardcode.

  Thank you

  -Patrick

  I don' t know that an external implementation would be easier, but it could be more effective if well written.  Internal or external, you must decide how you want to classify or ordering entities before concatenation.  The order must be absolute (i.e. without fasteners).  Policies to 'solve' the first entity out of string and the string output of the policy to concatenate a string to produce this entity = the entity 'before' + ', ' + attribute of the entity are fairly simple.

  I guess the answer is: it is not necessarily a better way to do it in OPM and I don't think that there are constraints, or a more effective solution is necessary unless you already know you will work with a very large number of entities or very long strings.

• Why Windows XP Pro creates another instance of the printer when I connect my USB printer,

  I am running Windows XP Pro SP3. I have a HP LaserJet 1100 printer (parallel) through a parallel to USB adapter. It seems that whenever I connect the printer to my laptop, another instance of the printer is created, so I have HP LaserJet 1100 (MS), HP LaserJet 1100 (MS) (1 copy), HP LaserJet 1100 (MS) (copy 2). Only one of these printers may also appear online at the same time. Sometimes I use the laptop in a dock and connect the printer to one of the 2 station USB ports, and sometimes I connect the printer to one of the 2 USB ports on the laptop.

  How can I consolidate all of these instances in a single printer so that I can have a consistent default printer? Or, how can I prevent this from happening at all?

  Bruce B, Massachusetts

  This happens because you have connected the printer to different USB ports.  The same thing happens when you connect any device (e.g., a mouse) on different USB ports, but unlike "Printers and faxes," Device Manager shows only the devices not present ("ghost") if deliberately do you.

  If having the extra icons printers and faxes you, right-click on it and select "Delete" - and then always connect your printer to the USB port.

• How to avoid creating multiple instances of the application?

  Hello

  We have a user interface Application. The application has been set to Auto run at startup and as a Module system.

  The application has a file listener that checks all new emails.

  When we start the application from the user interface by clicking on the application icon, it seems that the multiple instance of the application is created. For this reason when send us an email to request it is receiving emails several times. Sometimes simple, double and sometimes even five times.

  public class MyApplication  extends UiApplication implements FolderListener,
          SystemListener, GlobalEventListener {
  
      // Boot
      public static void main(String[] args) {
          if (args != null && args.length > 0 && args[0].equals("gui")) {
              // code to initialize the app
              fromService = false;
              // register the notification
              Notification n = new Notification();
              n.registerNotificationObjects();
  
              Utilities.writeLog(GUID, "MyApplication GUI Starting up");
              MyApplication service = new MyApplication();
              service.enterEventDispatcher();
          } else {
              Utilities.writeLog(GUID, "OnBoardV2 Service Starting up");
              MyApplication service = new MyApplication();
              service.enterEventDispatcher();
          }
      }
  
      public void messagesAdded(FolderEvent e) {
          /// Receive messages
          }   
  
  }
  

  In this regard, any help will be apreciated!

  Thank you

  I don't know if it's your entire code, but if you register your application as a file time listener never, it is called, then you save several headphones. The listener does not cause deleted your app closes, you must explicitly remove the listener. You must either put the listener in its own class and only sign up to start or find a way to check if the listener is already registered whenever the application is called.

• IOM SysAdmin does not create an instance of the application

  Hey guys,.

  I created a connector ICF personalized according to the guide to the resources page for Oracle dev (icf-connector-development-1868156). I have completed the coding and have created the appropriate metadata integration via the Console Design and am stuck in one of the tasks that must be done through the Console of SysAdmin IOM. I managed to create both the resource and the instance of the application for my connector, but after that I saved the instance of the application, the user interface does not show the button to create a form - only inactive "Edit" and the "Refresh" button on the button which has no effect.

  If the user interface behaves as if a form has already been created, but no entry appears in the drop-down list of 'form '.

  I just finished this process several times before but I have never seen this behavior.

  Can you help me with this problem?

  The more in advance thank you!

  Best regards

  Hello

  I believe that similar kinds of problems with one user.

  Re: Not able to choose the form in the instance of the application

  Not sure if it has been resolved or not. You can also check with any other env as well?

  ~ J

• Compare the instances of the entity

  Hello

  I want to compare two entity instance and to deduce whether or not they are same...

  Considered a person and he has two instance of person. Now, how can I get just the terms of this comparison of the name, age and sex.

  Thank you

  Fox

  See the help topic

  Examples of functions of rule of the entity and relationship

  Specifically the examples:

  the product is if duplicate

  ExistsScope (products, other product)

  product code = code for other products and

  InstanceEquals (product, other product)

  the employee has a conflicting identification if

  ExistsScope (employees, other employees)

  the employee identification code = code identification of the other employee and

  InstanceNotEquals (employee, the other employee)

  Hope that helps,

  Fiona

• Error-could not create an instance of the custom function

  Hello
  
  I'm trying to implement an extension of the simple custom function OPM 10.2. Here is the code:
  package com.oracle.determinations.examples;
  
  import com.oracle.determinations.engine.CustomFunction;
  import com.oracle.determinations.engine.EntityInstance;
  import java.util.Random;
  
  SerializableAttribute public class RandomFunction extends CustomFunction {}
  public Object evaluate (EntityInstance entityInstance, Object [] items) {}
  
  If (items [0] == null) {}
  return 0;
  } else {}
  -Code to generate a random number
  }
  }
  }
  
  The xml extension is the following:
  -< extension >
  -< features >
  -name of the function = "RandomFunction" type return = 'number' >
  < name arg = "enterednumber" type = "number" / >
  < Manager platform = 'java' class = "com.oracle.determinations.examples.RandomFunction" / > "
  < Manager platform = "dotnet" class = "com.oracle.determinations.examples.RandomFunction" / > "
  < / feature >
  < / functions >
  < / extension >
  
  I placed the code extension xml under the Development\Extensions\Examples folder and the jar file named "JavaLibrary1" containing only the above mentioned code is under Development\Extensions\Examples\lib.
  
  The rule that calls the custom function is as follows:
  the random number = RandomFunction (figure)
  
  I get the error "Unable to create year instance of com.oracle.determinations.examples.RandomFunction" when I debug the project.
  
  Please tell me how to solve this problem.
  
  Thank you
  JAS

  Received your email and found the problem. The problem is the custom .NET, function definition is invalid, and must be (or must be removed).

  When you are debugging with screens, it uses a combination of dosages of Web for Java and the host of the debugger, which takes place in .NET. Although the modules runs into reality in the determinations of web, the debugger needs always to be able to open the modules locally for purposes of reflection (eg. obtaining a list of all possible attributes and the type of data). Even if the modules is not actually executed in .NET, it must therefore be loadable, which means that if you do not provide a custom function .NET Manager, it must be valid. This:

  >
  
  >

  Does not appoint a .NET class, that's why the debugger complains. Delete this line (only the Manager of java leaving intact) and your example works.

  >
  You also mentioned that the random function is not a good choice, that means that the engine of dosage will not work with the random function?
  >

  Yes, a random function will not work because the engine must be (and is optimized to be) deterministic - same entry should always produce the same result.

  It is difficult to imagine what you can in theory of random numbers for (otherwise), but if you don't need, you may either) front of seeds new sessions with random inputs as attributes of basic (requires customization of your host application, for example, web determinations) or b) generate the random number from other values in your modules such as the customer, name and date of birth. This should ensure that the same combination of inputs will result in the same number of 'random' each time.

• How to access the BitmapData instance on the class that extends the charger?

  Hello. I use Flash CS6 to create an AIR application that loads an image from the computer, and then a pixel counts using its bitmap data.

  MyImg is a class that represents the loaded image.

  package com.utils {}

  import flash.display.Loader;

  SerializableAttribute public class extends {charger MyImg

  public void MyImg (): void {}

  }

  }

  }

  In my main class I manage the selection of files and loading.

  private var _myImage:MyImg = new MyImg();

  private var _file:FileReference;

  private var _fileTypes:FileFilter = new FileFilter ("Imagens: (*.jpeg, *.jpg, *.gif, *.png)", "*.jpeg;") *.jpg; *.gif; *.png");

  When the user clicks on a "load image" button on the stage, it calls loadMyImg().

  public void loadMyImg($e:MouseEvent):void {}

  chooseFile();

  }

  The user then selects the file he wants to do.

  private function chooseFile (): void {}

  Inasmuch = new FileReference();

  _File.addEventListener (Event.SELECT, fileSelected);

  _File.browse ([_fileTypes]);

  }

  Once you have selected the file, it is loaded as a byte array.

  private void fileSelected($e:Event):void {}

  _File.removeEventListener (Event.SELECT, fileSelected);

  _File.addEventListener (Event.COMPLETE, fileLoaded);

  _File.load ();

  }

  When it finishes loading it loads the byte array in _myImage.

  private void fileLoaded($e:Event):void {}

  _File.removeEventListener (Event.COMPLETE, fileLoaded);

  _myImage.contentLoaderInfo.addEventListener (Event.COMPLETE, dataReady);

  _myImage.loadBytes (_File.Data);

  }

  Once it's done I try to use the _myImage BitmapData, but cannot...

  private void dataReady($e:Event):void {}

  $e.target.loader.contentLoaderInfo.removeEventListener (Event.COMPLETE, dataReady);

  trace ($e.target + $e.target.content + $e.target.content.name + $e.target.content.bitmapData); Returns [object LoaderInfo] [object Bitmap] instance 155 [BitmapData object]

  trace (_myImage + _myImage.content + _myImage.content.name + _myImage.contentLoaderInfo + _myImage.contentLoaderInfo.content.name); instance of [object LoaderInfo] 155 155 instance [object Bitmap] returns [object MyImg]

  trace (_myImage.content.bitmapData) //compiler error: 1119 of bitmapData property possibly access not defined through a reference with static type flash.flashDisplay:DisplayObject.

  error //same trace (_myImage.contentLoaderInfo.content.bitmapData)

  }

  I don't understand what I'm doing wrong. Instances have the same name so that they are identical. They both trace as bitmaps, yet when I didn't access it from the event I do not get the bitmapData. Can someone tell me what I am doing wrong? I need to use the bitmapData of the classroom MyImg. I guess I could create a BitmapData variable in the class and give it the value of $e.target.content.bitmapData, but I still want to know why it can't be simpler.

  Thank you!

  Cast _myImage.content as bitmap:

  Bitmap (_myImage.Content)