Create the subtables based on the index positions in an array of distinct index?
I have a table 1 d of index values and a table 1 d of the measured values. For example:
Picture index: 1, 2, 4, 7, 126, 127 129, 214, 215
Measuring range: 5, 6, 8, 4, 4, 9, 8, 7, 5
Alice12 wrote:
I tried to build your program, but there is a problem (I don't know the case of false).
And I want to find the maxima of each sub-table and then find their average (this should be the end result).
You got it mostly right. I explained in my post, which is in the case of false: register to offset an increment (+ 1) for the top. The other son directly through. The picture I posted an "excerpt" - it is actual code. You can drag in a block diagram (with some browsers, you will need to drag your first office and from there to the block diagram). There is a bug in the creation of the extract where it does not always show properly cluster content, and that's what happened here. The constant matrix cable on the left side of the underpass registry contains a cluster that contains an array of numeric values. You will see this if you load the code snippet. I hope that you were able to understand the logic of this code as you were building it, but if not, please ask for explanations.
From there, it is trivial to find the max and average. Connect the output of my code for a loop for. Inside the loop for example, ungroup the table and calculate the maximum and medium. Functions to perform these operations on a digital table already exist (see table Max & minimum and average).
Tags: NI Software
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Asif Kabir -
How can I create the subtables based on the index positions in an array of distinct index?
Please forgive me if this question is fundamental or obvious. I'm relatively new to LabVIEW and I'm learning as I go along.
I have a table 1 d of the values of the index (the number of possible index values is not fixed, but varies between the uses of the application, it could be just {0, 1} on a day and {1, 5, 11 678} on another) and a table 1 d of the measured values (doubles). I would like to analyze measured in sub-tables for each index value, so that if my board index was:
[0 1 1 1 1 5 5 0 5 5 1 0 1 1 5]
and my table of measurement was:
[0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.11 0.10 0.12 0.13 0.15 0.14]
I would like to return 3 sub-tables:
[0.1 0.12 0.8]
[0.2 0.3 0.4 0.5 0.11 0.13 0.14]
[0.6 0.9 0.7 0.15 0.10]
I know that there must be a simple way to do this, I guess I'm stuck just too matlab-table thinking to understand... Please help!
-jph
One of the problems is that your subsets are not of equal length and you also do not know the number of subsets in advance, you will need to decide on a suitable output structure. I suggest a picture of clusters, each element that contains the subset and, possibly, the tag.
Here's a very quick example (LabVIEW 8.0). See if it makes sense. Please check the correct operation. There could be bugs, but the concept should be clear.
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How to create the index suitable for my xml...
Hi all... I have an xml attachment saved in an XMLType column in a table that is stored in binary xml secure.
I want to use XQuery to navigate the xml code and push the results in a normal table.
All of this works, I have a question if all the xmlindex I want to create.
I want to create a xmlindex so that the plan of the explain command would be cheaper.
If I remove the where XQuery bit the explain command comes with a cost of 32, but if I use the where the bits of the cost are 223000!
Removal of the index makes no difference if the index is not used here.
What index to use here and especially how he specify?
I read something on the structured and unstructured indexes, but I did not understand what and how to use them.
If someone could help that would be great.
A point, however: the xml used for the explain command is much longer; It contains 48385 lines instead of the rows listed here.
Ad al of them would make the post a little longer...
table and index:
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Drop and re-create the index on the current table
Hello
I just have a few questions about the removal and creating indexes on a table that activates a lot.
Let me explain first:
The table is used by the application with the DML statements every 3 seconds and I want to do is to drop the indexes and re-create them.
But Im worried about the consequences - what happens when I try to recreate the indexes and the table has an option rowlock/used by the application?
P.S
It's production environment - so I can't stop the application.
BR / AnderA reconstructed index either Online or Offline.
Online index rebuild features:
ALTER INDEX REBUILD ONLINE;
LMD is allowed on the base table
It's relatively slow
Base table is targeted for the new index
Base table is locked in shared mode and DOF is not possible
Intermediate table stores changes to data in the base table, during the rebuilding of indexes to update the new index laterOffline index rebuild features:
ALTER INDEX REBUILD. (Default)
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Not possible DML and DDL on the base table
Relatively faster -
I like to read
http://www.DBA-Oracle.com/concepts/grant_user_privileges.htm
and there
grant create index
but I thought that it was not this privilege, such as index creation. I tried and got:
ERROR on line 1:
ORA-00990: missing or not valid privilege
So the site is bad?
Thank youOracleguy,
I'm not sure what is the context of the cited site but in the Oracle docs, there is a small reference that says this,
http://download.Oracle.com/docs/CD/B19306_01/server.102/b14231/indexes.htm#sthref2475
>
Creating indexesThis section describes how to create indexes. To create an index in your own schema, one or more of the following conditions must apply:
The table or cluster to be indexed is in your own schema.
You have the privilege of the INDEXES on the table to be indexed.
You have the CREATE ANY INDEX system privilege. >
The irony is that there is no privilege as such who called Index priv. Once you get a create table, you get automatically create index above. As others have mentioned, there is a creation of an index , but this is something totally different.
The answer to the question you asked, there are no such priv, AFAIK.
HTH
Aman... -
Error creating the Spatial Index for SRID 8307 on newly hardened database
Oracle 11g Rel2, Windows 2003 platform
Help, please...
Meeting with error message:
ERROR on line 1:
ORA-29855: an error has occurred in the execution of routine ODCIINDEXCREATE
ORA-13249: internal error in the Spatial index: [mdidxrbd]
ORA-13249: geodetic initialization error turn
ORA-13249: SRID 8307 does not exist in the table MDSYS.CS_SRS
ORA-29400: data cartridge error
ORA-04063: package body 'MDSYS. SDO_CS"contains errors
ORA-06512: at the 'MDSYS. SDO_INDEX_METHOD_10I', line 10
After running the command
INSERT INTO USER_SDO_GEOM_METADATA VALUES
("PointGeometry",
"pointGeom,"
MDSYS.sdo_dim_array (mdsys.sdo_dim_element ('Longitude',-180, 180, 1),
mdsys.sdo_dim_element('Latitude',-90,90,1)),
8307
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CREATE the INDEX IDX_POINTGEOMETRY on PointGeometry (pointGeom) indextype is mdsys.spatial_index parameters('LAYER_GTYPE=POINT');
When I ask mdsys.sdo_cs I see that there are actually SRID 8307. This index was created in this schema without problem. The problem only arises once the hardened customer database and we tried to recreate the schema (and index).
Probably not coincidentally, I also get error:
ORA-29855: an error has occurred in the execution of routine ODCIINDEXCREATE
ORA-04063: package body "CTXSYS. DRIXMD' has errors
ORA-06508: PL/SQL: called program unit is not found: 'CTXSYS. DRIXMD ".
ORA-06512: at "CTXSYS. DRUE", line 145
ORA-06512: at "CTXSYS. TEXTINDEXMETHODS', line 366
ORA-04063: package body "CTXSYS. DRIXMD' has errors
ORA-06508: PL/SQL: called program unit is not found: 'CTXSYS. DRIXMD ".
When attempting to create and index Oracle Text context.
Your help is greatly appreciated.Then, that's the problem.
MDSYS user now has not run, and select privileges on the dbms_lob package.
You must grant privileges on this package in MDSYS.
Note that you can run into other issues of privilege package like this, so you must correct all by the granting of the
required privileges for MDSYS.Siva
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Cannot create the spatial index
It's a little bit of the puzzle for me this one, I made this little time on different system and I do not understand why it's here
Oracle 11.1.0.7 Windows 64-bit
We have simple following table:
CREATE TABLE DASHBOARD. DSGEOEXCEPTION
(
GEOIDE NUMBER NOT NULL,
ZORDER INTEGER DEFAULT 0 NOT NULL.
HOUSENO VARCHAR2 (100),
STREET VARCHAR2 (100),
VARCHAR2 (100) SUBURBAN,.
CITY VARCHAR2 (100),
COUNTY OF VARCHAR2 (100),
DESCRIPTION VARCHAR2 (200),
MDSYS FORM. SDO_GEOMETRY
)
LOGGING
NOCOMPRESS
NOCACHE
NOPARALLEL
NOMONITORING;
ALTER TABLE DASH. (ADD) DSGEOEXCEPTION
CONSTRAINT DSGEOEXCEPTION_PK
KEY ELEMENTARY SCHOOL
(GEOIDE)) ;
Insert values (user_sdo_geom_metadata)
"DASHBOARD. DSGEOEXCEPTION',.
"FORM."
MDSYS. () SDO_DIM_ARRAY
MDSYS. SDO_DIM_ELEMENT ('LONGITUDE',-180, 180, 0.00005),
MDSYS. SDO_DIM_ELEMENT ('LATITUDE',-90, 90, 0.00005)
),
8307);
until then, everything is good.
I run the two sql suite to ensure that everything is fine
Select * from USER_SDO_GEOM_METADATA;
Dashboard. DSGEOEXCEPTION, shape, ((LONGITUDE,-180, 180, 5E-5), (LATITUDE, -90, 90, 5th-5),), 8307
select * from mdsys.sdo_geom_metadata_table
DASHBOARD, dashboard. DSGEOEXCEPTION, shape, ((LONGITUDE,-180, 180, 5E-5), (LATITUDE, -90, 90, 5th-5),), 8307
select * from ALL_SDO_GEOM_METADATA;
first 2 return one row as planned last returns nothing
creating the index
CREATE INDEXES DASH. DSGEOEXCEPTION_SIDX ON DASHBOARD. DSGEOEXCEPTION
(FORM)
INDEXTYPE IS MDSYS. SPATIAL_INDEX
NOPARALLEL;
or
CREATE INDEXES DASH. DSGEOEXCEPTION_SIDX ON DASHBOARD. DSGEOEXCEPTION
(FORM)
INDEXTYPE IS MDSYS. SPATIAL_INDEX;
fails with the error:
ORA-29855: an error has occurred in the execution of routine ODCIINDEXCREATE
ORA-13203: cannot read the notice USER_SDO_GEOM_METADATA
ORA-13203: cannot read the notice USER_SDO_GEOM_METADATA
ORA-06512: at the 'MDSYS. SDO_INDEX_METHOD_10I', line 10
According to one of the posts, I run this
ALTER session set current_schema = MDSYS;
@$ORACLE_HOME/md/admin/prvtgmd.plb
but no difference I can always create index
Any suggestions?Please, try the following:
Insert values (user_sdo_geom_metadata)
"DSGEOEXCEPTION,"
"FORM."
MDSYS. () SDO_DIM_ARRAY
MDSYS. SDO_DIM_ELEMENT ('LONGITUDE',-180, 180, 0.00005),
MDSYS. SDO_DIM_ELEMENT ('LATITUDE',-90, 90, 0.00005)
),
8307); -
create index index_lib on BOOK_DETAIL (ID);
I want to change the index.drop and re-create the index.
Drop index index_lib1;
create index index_lib1 on TB_USER (lower (USERID));
Rebuild will rebuild just the index based on the existing settings. If necessary you can change storage settings
-
SDO_NN giving ORA-13249: SDO_NN cannot be assessed without using the index
Hi people,
I do not understand why the SDO_NN gives ORA-13249 in circumstances.
SQL > SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and title like '%' and rownum < 10;
TITLE
--------------------------------------------------------------------------------
MultiPoint_305199
LineString_691779
MultiPolygon_180478
MultiPolygon_358113
MultiPolygon_53008
MultiPolygon_249905
MultiPolygon_204076
MultiPolygon_636994
MultiPoint_464514
9 selected lines.
SQL > SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and timestamp > = to_timestamp (January 6, 2011 ', ' dd/mm/yyyy') and rownum < 10;
SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and timestamp > = to_timestamp (January 6, 2011 ', ' dd/mm/yyyy') and rownum < 10
*
ERROR on line 1:
ORA-13249: SDO_NN cannot be assessed without using the index
ORA-06512: at the 'MDSYS. MD", line 1723
ORA-06512: at the 'MDSYS. MDERR", line 17
ORA-06512: at the 'MDSYS. PRVT_IDX', line 49
The spatial index is created with:
CREATE the INDEX SlavaTest_geometry_idx_spatial ON SlavaTest (geometry) INDEXTYPE IS mdsys.spatial_index;
'Title' and 'timestamp' columns have an index.
Note the query comes from Hibernate and I can't change it's arbitrary.Slava2 wrote:
What this means - there is a bug in Oracle?Well, it could probably be considered a, but [url http://docs.oracle.com/cd/E11882_01/appdev.112/e11830/sdo_operat.htm#i78067] documentation on SDO_NN warns you:
Documentation says:
However, if the column in the WHERE clause predicate specifies a non-space column in the table for geometry1 with an associated index, make sure that this index is not used by specifying the NO_INDEX indicator for this index.See you soon,.
Stefan -
by specifying the index tablespace in to disable the primary key constraint
Hello
during the ETL I want to disable constraints PK/UK to speed up the load;
on activation of the constraint, the corresponding indices are created in a different tablespace while they were initially on the creation of the table itself
I tried to disable PK / UK with the option 'keep the index', the index value corresponding to the status of "unusable" and use ' alter session set skip_unusable_indexes = true', but then I can't insert rows with the error.
can anyone tell if there is a way to allow the PK/UK constraint and specify the storage space for the corresponding indices, or keep the index and inserts works?Error: ORA-01502: index 'xxx' or partition of such index is in unusable state
I'd like to avoid to drop constraints / indexes and re-create them both from scratch after the load
Thank you for the advice
Thank you
Rgds>
can anyone tell if there is a way to allow the PK/UK constraint and specify the storage space for the corresponding indices, or keep the index and inserts works?
I'd like to avoid to drop constraints / indexes and re-create them both from scratch after the load
>
Have you tried specifying the table space in the USING clause when you activate the constraint?ALTER TABLE emp ENABLE PRIMARY KEY USING INDEX TABLESPACE myTS;See DBA guide
http://docs.Oracle.com/CD/B28359_01/server.111/b28310/indexes003.htm
>
Creating an Index associated with a constraintOracle database applies a UNIQUE key or a constraint integrity PRIMARY KEY on a table by creating a unique index on the unique key or primary key. This index is created automatically by the database when the constraint is enabled. No action is required by you when you run the CREATE TABLE or ALTER TABLE statement to create the index, but you can optionally specify an ESCALATION using clause to exercise control over his creation. This includes them when a constraint is defined and enabled, and when a constraint defined but disabled is selected.
>
Note the last sentence two sentences:
>
You can optionally specify an ESCALATION using clause to exercise control over his creation. This includes them when a constraint is defined and enabled, and when a constraint defined but disabled is selected.
>
You realize, I hope, that the only way can Oracle KNOWS that the index contains valid values is to rebuild? -
How the index data are managed within the cluster?
Hello
We are evaluating the consistency.
Regarding indexes, am I right in thinking that the data in the index are stored in a (managed internally) cache on the same node that the attendant at the following indexed values? I'm not interested in getting the data in the index, but rather just to understand how the data in the index itself are stored or processed within the cluster.
So in a 2 cluster node where an index is applied to a distributed cache that has only 2 entries, will there be a key cache on each node 1 {binary,} to enter key where the key points to the value that is stored on this same node? In other words, I'm sure that the index data to be spread out in the cluster in the case of a partitioned topology?
Concerning
Peteruser11279467 wrote:
HelloWe are evaluating the consistency.
Regarding indexes, am I right in thinking that the data in the index are stored in a (managed internally) cache on the same node that the attendant at the following indexed values? I'm not interested in getting the data in the index, but rather just to understand how the data in the index itself are stored or processed within the cluster.
So in a 2 cluster node where an index is applied to a distributed cache that has only 2 entries, will there be a key cache on each node 1 {binary,} to enter key where the key points to the value that is stored on this same node? In other words, I'm sure that the index data to be spread out in the cluster in the case of a partitioned topology?
Concerning
PeterHi Peter,.
up to 3.4.x index have been supported only on partitioned topology, and Yes, the index on each node contain only the data corresponding to the entries that have their main copy on this node (referred to as entered local subsequently).
The indexes are not stored in a cache, but they are managed under the information that maintains consistency in terms of backup (the map that contains local entries).
The indexes are in 2 parts:
-index to the front: this is a mapping of the cache key in an internal representation (Playback key card in the future) the value extracted with the extractor used to create the index of the entry to membership of the cache key (value extracted later)
-reverse index (aka. reversed card): this is a map of the value extracted from a backup set of the keys of the map of entries which we extract the index key reversed with the extractor used to create the index
The index can be sorted, which means that the index reversed a SortedMap (sort order is the order of the extracted values)
Let's see an example. Assuming you have the contents of the following cache within a particular extension storage node:
A--> Object (PositionX = 5,...)
B--> object (getA = 3,...)
C--> object (getA = 3,...)
D--> object (getA = 4,...)The index forward in this node will contain:
Binary (A)--> 5
Binary (B)--> 3
Binary (C)--> 3
Binary (D)--> 4The reverse index will contain:
3--> {Binary (B), Binary (C)}
4--> {Binary (D)}
5--> {Binary (A)}Where Binary (...) designates the internal representation (binary) of the... object.
If the index is not ordered, then the order of iteration over the entries in the index reversed are not deterministic.
If the index is ordered, the iteration of the entries into the inverted index will be as stated above. Also, you can convert the SortedMap inverted index in order to have the very useful headMap and tailMap and firstKey and lastKey methods.
I hope this helps.
Best regards
Robert
-
Invalidation of the index based on a function because the recompilation
Hello
one of our customers has two indices according to the functions that fall under the State "off" in some situations. After looking more closely at the situation, there are some things that my opinion are different from what I expected of a function-based index. Because I am unable to find anything about either on metalink (or I'm not asking the right question) I would appreciate a second opinion of you.
To keep things simple, I gave an example to illustrate the behavior. I use Oracle 12.1.0.2, although it can also be reproduced on versions 10.2 and 11.2.
It's my environment and three parameters that I find relevant to the discussion:
SQL> select banner from v$version; BANNER ---------------------------------------------------------------------------- Oracle Database 12c Enterprise Edition Release 12.1.0.2.0 - 64bit Production PL/SQL Release 12.1.0.2.0 - Production CORE 12.1.0.2.0 Production TNS for Linux: Version 12.1.0.2.0 - Production NLSRTL Version 12.1.0.2.0 - Production SQL> show parameter remote_dependencies NAME TYPE VALUE ------------------------------------ ----------- ---------- remote_dependencies_mode string TIMESTAMP SQL> show parameter query_rewrite NAME TYPE VALUE ------------------------------------ ----------- ------------- query_rewrite_enabled string TRUE query_rewrite_integrity string enforced
Test case:
SQL> CREATE OR REPLACE FUNCTION f1 (p_string IN VARCHAR2) 2 RETURN VARCHAR2 3 DETERMINISTIC 4 IS 5 BEGIN 6 RETURN lower(p_string); 7 END f1; 8 / Function created. SQL> CREATE TABLE tmp_t1 (a_string VARCHAR2(10)); Table created. SQL> INSERT INTO tmp_t1 VALUES ('a'); 1 row created. SQL> COMMIT; Commit complete. SQL> CREATE INDEX x1_tmp_t1 ON tmp_t1(f1(a_string)); Index created. SQL> set linesize 80; SQL> column index_name format a10; SQL> SELECT index_name, index_type, status, funcidx_status 2 FROM user_indexes; INDEX_NAME INDEX_TYPE STATUS FUNCIDX_ ---------- --------------------------- -------- -------- X1_TMP_T1 FUNCTION-BASED NORMAL VALID ENABLEDWe have our table and our based on an index function which basically converts the values to lowercase. From here on things, download a little weird. What happens with the index based on a function if the underlying function is recompiled? I always thought (and which is also stated in the Concepts and the use of function index (Doc ID 66277.1)) that the index would change its status to "disabled". Here is an excerpt of the said Doc ID:
The index depends on the State of the PL/SQL function. The index can be
struck down or rendered useless by changes to the function. The index is marked
People with DISABILITIES, if he is brought to the function or function is re-created.
The timestamp of the function is used to validate the index.
To allow the index after it is created, the function if the signature of the
the function is identical to the front:
ALTER INDEX ENABLE;
If the signature of functions is changed, to make the changes effective
in the index, the index must be renewed to make it valid.
ALTER INDEX REBUILD.
It seems that this is not the case, as the index remains valid and activate.
SQL> alter function f1 compile; Function altered. SQL> SELECT index_name, index_type, status, funcidx_status 2 FROM user_indexes; INDEX_NAME INDEX_TYPE STATUS FUNCIDX_ ---------- --------------------------- -------- -------- X1_TMP_T1 FUNCTION-BASED NORMAL VALID ENABLED
OK, explicitly recompiling function F1 single timestamp changed. What if we replace the function completely and we change the output of the function - for example we will switch from a LOWER function to SUPERIOR function in the body of the F1. Again, it is change that I thought would be not only to disable the index based on a function, but also force its reconstruction. At least that is my understanding of the explanation in Doc ID).
SQL> CREATE OR REPLACE FUNCTION f1 (p_string IN VARCHAR2) 2 RETURN VARCHAR2 3 DETERMINISTIC 4 IS 5 BEGIN 6 RETURN UPPER(p_string); 7 END f1; 8 / Function created. SQL> SELECT index_name, index_type, status, funcidx_status 2 FROM user_indexes; INDEX_NAME INDEX_TYPE STATUS FUNCIDX_ ---------- --------------------------- -------- -------- X1_TMP_T1 FUNCTION-BASED NORMAL VALID ENABLED
Should not be. Because of the function "create or replace" F1 never go through a "invalid" phase which may be necessary for index becomes unusable? What about queries on the TMP_T1 table? Does optimizer always uses access index or not? What about the results?
SQL> EXPLAIN PLAN SET statement_id='s1' FOR 2 SELECT a_string, f1(a_string) as f1_a_string, f1('a') as f1_literal 3 FROM tmp_t1 4 WHERE f1(a_string) = 'a'; Explained. SQL> SELECT * from table(dbms_xplan.display(statement_id=>'s1')); PLAN_TABLE_OUTPUT ------------------------------------------------------------------------------------------------------------------------ Plan hash value: 3133804460 ------------------------------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ------------------------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 1 | 2024 | 2 (0)| 00:00:01 | | 1 | TABLE ACCESS BY INDEX ROWID BATCHED| TMP_T1 | 1 | 2024 | 2 (0)| 00:00:01 | |* 2 | INDEX RANGE SCAN | X1_TMP_T1 | 1 | | 1 (0)| 00:00:01 | -------------------------------------------------------------------------------------------------The index is used by the optimizer, see the results.
SQL> column f1_a_string format a15; SQL> column f1_literal format a15; SQL> SELECT a_string, f1(a_string) as f1_a_string, f1('a') as f1_literal 2 FROM tmp_t1 3 WHERE f1(a_string) = 'a'; A_STRING F1_A_STRING F1_LITERAL ---------- --------------- --------------- a a AA_STRING = value in the table
F1_A_STRING = value of f1 (a_string) but the value is not evaluated because it comes from an index, so tiny value (remember, at the time index created the function returned small values)
F1_LITERAL = value of the function f1 newly evaluated, using literal instead of the value in the table.
Predicate f1 (a_string) = 'a' should return no rows because no character uppercase is equivalent to "a". Query with f1 (a_string) = 'A' should return a line, but it doesn't.
SQL> SELECT a_string, f1(a_string) as f1_a_string, f1('a') as f1_literal 2 FROM tmp_t1 3 WHERE f1(a_string) = 'A'; no rows selectedAnyone know if this is an expected behavior? And, is it possible to disable the index based on a function whenever the underlying function signature is changed? The parameter query_rewrite_integrity = applied from
DOC-ID 66277.1 does not seem to do the trick:
(c) session variables
~~~~~~~~~~~~~~~~~~~~
QUERY_REWRITE_ENABLED (true, false),
QUERY_REWRITE_INTEGRITY (confidence, forced, stale_tolerated)
determines the optimizer to use index based on a function with
expressions using SQL, user defined functions functions.
TRUST: Oracle allows rewrites using relationships that have
was declared.
APPLIED: Oracle ensures and guarantees consistency and integrity.
STALE_TOLERATED: Oracle allows rewrites using vessels of the relationship not applied.
Used in the case of materialized views.
Set session variable cost function optimizer to choose the
a function-based index
Kind regards
SAMO
From the Manual 11.2 ( https://docs.oracle.com/cd/E11882_01/appdev.112/e41502/adfns_indexes.htm#ADFNS254 )
"If you change the semantics of a
DETERMINISTICrun and recompile, then you must manually rebuild all addicts depending on index and materialized views." Otherwise, they report results for the previous version of the function. »This note is not that I made my initial comment well - which was based on an incorrect memory the relationship between function-oriented and autonomous pl/sql functions, so I won't try to explain it. In fact, I went back to Oracle 8i practice to see if something had changed between yesterday and today and found that I had described exactly the behavior that the OP has been seeing. It's the way it is supposed to be.
Concerning
Jonathan Lewis
-
Why a method to create a constraint would allow the index to be used, but not another.
Hi all
With the help of:
Oracle Database 11 g Enterprise Edition Release 11.2.0.4.0 - 64 bit Production
SQL Developer Version 4.0.2.15
I had to do the following query on a table.
Select distinct chdrnum, tranno
of ractpf_pgr;
I ran the setup of SQL in SQL Developer, who told me that he was doing a full table scan,
(It's what you get using SEPARATE!)
After some research, I discovered that if I put in question on columns not null check constraints
and then recreated the index based on these columns, I'd get a full index scan instead of a table scan.
Good news - off, I went and tried using the following method (I think it's call a constraint of out-of-line)
and created one for each colmn using snytax below.
ALTER table RACTPF_PGR add constraint CS_CHDRNUM_NN check (CHDRNUM is not null) validate;
Ran my SQL Tuning Advisor again - no joy - a full table scan that was happening.
Did some more research and recreated the constraints with the help of an online method
ALTER TABLE RACTPF_PGR CHANGE (CHDRNUM CONSTRAINT CS_CHDRNUM_NN NOT NULL);
My SQL Tuning Advisor is represented - and yes the index was used.
But what I want to know why a method would cause the index to use another does not
Thanks in advance.
The second is a NOT NULL constraint.
The a ('is not null') is technically not a NOT NULL constraint.
Give me a moment to start my database, and I will demonstrate.
Edit: Here's the demo:
SQL> create table x (a number null, b number null); Table created. SQL> alter table x add constraint a_nn check(a is not null) validate; Table altered. SQL> alter table x modify (b constraint b_nn not null); Table altered. SQL> select column_name, nullable 2 from user_tab_cols 3 where table_name = 'X'; COLUMN_NAME ---------------------------------------------------------------------- N - B N A Y
The index does not store registrations for the lines where all components of the index are null, then the optimizer needs to see that the columns are not nullable to be able to use an index scan.
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