DATE in TIMESTAMP data type conversion

Similar Questions

• Create another data base of Liquibase changelog: automatic data type conversion

  I need to convert the structure of PostgreSQL databases to Oracle. In PostgreSQL, I a postgres database.

  In Oracle, I have an empty database in which I want to write to postgres database in PostgreSQL.

  Actually, I didn't need the data, only the structure (relationships).

  For this, I use Liquibase. I get the changelog of PostgreSQL with the command:

  Liquibase.

  -driver = org.postgresql.Driver.

  --classpath="C:\db_drivers\postgresql-9.3-1102.jdbc3.jar------.

  --changeLogFile="./postgresql_changelog.Xml------.

  -url = "" jdbc:postgresql://localhost:5432 / postgres "\"

  -username = schema_name_here.

  -password = *.

  -logLevel = debug.

  -defaultSchemaName = Ms.

  generateChangeLog

  After that, I try to create objects in the Oracle database:

  
  

  Liquibase

  -driver oracle.jdbc.OracleDriver =

  --classpath="C:\db_drivers\ojdbc14.jar".

  --changeLogFile="./postgresql_changelog.xml".

  --URL="JDBC:Oracle:thin:@ip_here:orabeta".

  -username = *.

  -password = *.

  Update

  Does not work: ORA-00902

  Here is a fragment of postgresql_changelog.xml:

  ...

  < changeSet author = '(generated) Alexey' id = "1409146335011-53" >

  < create table tableName = "TABLE1A" >

  < column name = "total_pk" type = 'INT8' >

  < forced nullable = "false" / >

  < / column >

  < column name = "form_fk" type = 'INT8' >

  < forced nullable = "false" / >

  < / column >

  ...

  I also generate a pure SQL file:

  
  

  Liquibase

  -driver oracle.jdbc.OracleDriver =

  --classpath="C:\db_drivers\ojdbc14.jar".

  --changeLogFile="./postgresql_changelog.xml".

  --URL="JDBC:Oracle:thin:@ip_here:orabeta".

  -username = *.

  -password = *.

  updateSQL > update.sql

  Here is a fragment of update.sql:

  
  

  ...

  CREATE THE TABLE SCHEMA_HERE. TABLE1A (total_pk form_fk INT8 INT8 NOT NULL,.. .etc);

  INSERT INTO SCHEMA_HERE. TABLE1A (ID, $form_id,... etc.)

  ...

  I want to generate the file, in which all the data types correspond to the target database, that is to say I want to create. I can write a simple parser that replace the data types, but this isn't the right solution - can be a lot of data.

  It is possible to get changelog from a database and update another database on a different server this changelog RDBMS? I need to get the automatic and Automatic data type conversion generate XML data / SQL output with the data types of target database.

  Or maybe there is an option to generate output data types with "abstract"? That is to say with data types that are not in the actual databases, for example, instead of INT8 - whole, etc.

  I would be very grateful for the information. Thank you all.

  Why not to use pg_dump to extract the schema in a file of script that you can then 'change '?

• Problems with the Long data type conversion

  With the help of Oracle 11 G.
  
  I have a vision where one of the name of the column is of type long, I need to convert in varchar2. I tried using the to_Lob() function, but this error:
  
  ORA-00932: inconsistent data types: expected - got LONG
  
  I followed this article (step 1), which suggests to use to_lob()
  
  My query is:
  

  select
  item1, -- this is of type LONG
  item_vat, 
  price_pc_tot,
  from xd_item_price_view 

  I tried to convert it into:
  

  select
  to_lob(item1) as item1_x, -- this is of type LONG
  item_vat, 
  price_pc_tot,
  from xd_item_price_view 

  I am confused about the "-", why he would expect that? Thanks for watching it.

  >
  Sorry mate, just realized that. Yep, this is the one I followed (step 1 using to_lob())
  >
  It's a case of 'use' along in a query or search.

  But you can use to_lob as part of creating a new table.

  Response to see Dom Brooks in this thread
  Re: Conversion long to varchar2

  And he directly answered your original question
  >
  But you can't use TO_LOB in a statement SELECT right:

• Control data type conversion

  Topology Manager only allows me the conversion to data type of technology to another. SQL Server has a data type BIT. Default is to convert to a CHAR in Oracle. However, it coverts TANK (1) and the interface fails because the data contains "True" or "False" as values. This forces me to change manually (5) tank & then run again. How can I adjust the settings so that the BIT converts char (5) instead of char (1)?
  
  Thank you
  Dinesh.

  Hi dieng

  Go to the topology, under Oracle and create a new data type, name char5 for example.

  In the text box NAME and CODE OPPOSITE the word "TANK" in the CODE, let's CHAR5 text box

  in the text box: CREATE the TABLE SYNTAX and SYNTAX of DATA WRITEBLE of writing type: char (5)

  In the tab "Convet to", you can associate the SQL BIT for this new data type.

  This help you?

• Variant data type conversion

  Hi all

  I use VI Scripting in LabVIEW 2010. I need to know the data type of the wire connected to a Terminal. Terminal wire reference gives a property called "Datatype". I thought that this will help me. But he is a variant and how do I actually convert the data to find out the data type. Specifically, I want to make use of data type of cluster. How do I know if the wire is of type cluster?

  Thanks for any help.

  You want to use the 'GetTypeInfo.vi' VI "LabVIEW 20xx\vi.lib\Utility\VariantDataType\" folder for this!

  I would recommend installation of this Package of VI because it adds these features to pallets:

  https://decibel.NI.com/content/groups/hidden-gems-in-vilib

  Here's what it looks like:

  

• data type conversion error

  Hello
  I have the insert under certain conditions
  

  insert into temp1(no number) 
   SELECT (CASE WHEN TO_NUMBER(TO_CHAR(SYSDATE,'DDMMYYYY')) BETWEEN                                 TO_NUMBER(TO_CHAR(START_DATE,'DDMMYYYY')) AND
           TO_NUMBER(TO_CHAR(END_DATE,'DDMMYYYY'))
          THEN NVL(ORG_ID,0) ELSE 0 END)
  FROM temp2;

  but get the following error:
  
  ERROR at line 3:
  ORA-00932: inconsistent data types: expected TANK got the NUMBER
  
  
  could you please give hint to resolve this error:
  
  Josh

  If your arguments start_date and end_date DATE data type, then you can simply use TRUNC

  INSERT INTO temp1(no)
  SELECT CASE WHEN TRUNC(sysdate) BETWEEN TRUNC(start_date) AND TRUNC(end_date)
               THEN NVL(TO_NUMBER(org_id),0)
              ELSE 0
         END
    FROM temp2
  

• MSSQL gateway nvarchar data type conversion

  Hello
  
  is there a way how to configure the MSSQL gateway to convert the data type nvarchar MSSQL in varchar2 Oracle instead of nchar? Because when converted to nchar, extra spaces are added as nchar is fixed-length, even if I load the data in varchar2 columns.
  
  Thanks for help
  Petra

  Not sure, but it looks like you're talking about Oracle TG4MSQL V10.

  Please be aware that all versions of TG4MSQL until V10.2 were desupported by March 15. Thus no additional code changes is made for V10 and frees up the bridge earlier. Customers have to migrate their gateway to the V11 DG4MSQL product that is now available for many platforms of follow-up.
  This DG4MSQL also has a mapping to change nchar/nvarchar/ntext data types, the extract of the manual here:
  -> NCHAR NCHAR
  NTEXT-> LONG (if the Oracle DB character set = Unicode. Otherwise, it is not supported)
  NVARCHAR-> NVARCHAR
  Nvarchar (max)-> LONG (if the Oracle DB character set = Unicode)

  Thos V11 gateways are certified with Oracle V9.2.0.8 database versions, 10.1.0.5 and 10.2.0.3 with a compatibility patch but in most applied to the database. This patch is already included in the 10.2.0.4 patches group.
  Database v11 works right out of the box.

• Data type conversion

  Hi experts,

  Try to convert the varchar2 systimestamp date

  EX:

  Entry (varchar2) - 26-FEB-14 02.22.45.231073 PM

  output should be (column format - systimestamp)-HH24:MI:SS MM/DD/YYYY

  Thanks in advance

  R

  Hello

  7688438 wrote:

  ... Target table:

  T1

  (C2 timestamp

  );

  OUTPUT SHOULD BE:

  I need the output to the format MM/DD/YYYY HH24:MI:SS

  sample:

  26/02/2014 02:22:45

  26/02/2014 02:19:11

  This is contradictory.

  The timestamps have no any format.  (Or, to be excruciatingly correct, they all have the same format, which is nothing like ' MM/DD/YYYY HH24:MI:SS' or ' LUN-JJ-AA HH.MI.) SS. AM FF ' or something else that you use to display the values.) Only those channels have formats like ' MM/DD/YYYY HH24:MI:SS' and you certainly do not want to store information about the dates and times of a string column.

  TO_CHAR display a TIMESTAMP in a given format.  You can also use ALTER SESSION to change the default format, so that the timestamps are displayed in a given format (unless you are using TO_CHAR to convert them to strings).

  For example:

  ALTER SESSION SET NLS_TIMESTAMP_FORMAT = "DD/MM/YYYY HH24:MI:SS";

  NLS_TIMESTAMP_TZ_FORMAT allows to do the programming for the TIMESTAMP WITH time ZONE SCHEDULE thing.

  Your DBA can do something similar to change your system's default format.

  See:

  http://edstevensdba.WordPress.com/2011/04/07/NLS_DATE_FORMAT/

  What it says on the DATEs apply to parking meters as well.

• Table data type conversion

  I have a simple problem.

  I have a string type 2D chart. The array is an array with the column names and the lines which are numbers.

  I want to extract the lines, but I want them out in the form of numbers that I can make a mount for them online.

  I have to select each item and convert the string to a number?

  Is there a function that converts a string number (orange line) (pink line)?

  Is there a smarter way?

  murchak wrote:

  Thank you. Your solution works but element-wise.

  But is there a VI that applies to the whole range 2D to change its type?

  ??

  He works on a table in its entirety both in my version of LabVIEW.

  

• Problem with the data type date

  Hi team
  
  
  I'm very confused in the associated date coversion
  
  for example if I have question
  Select name, hire_date from employee
  
  the o/p looks like this
  
  Suresh 24/05/1999, but if I need to display as 24-May-1999, should I use
  and please help me understand
  
  Function TO_NUMBER to_char TO_DATE, I bit confused in this? Please you can get a few suggestion to laymensterm
  
  Thank you
  Suresh

  If you want to present a DATE data type in a specific format, you will use TO_CHAR.
  If you want to transform a (varchar2) STRING to a DATE data type in a specific format, you will use TO_DATE.
  Never compare strings to dates
  Never compare strings to numbers
  You never rely on implicit data type conversions
  Long version:
  http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:2858890655722

• Timestamp data type is wrong

  The code attached is supposed to focus on a cluster and read the name and the data type of each control of the cluster.  When I put a timestamp control in the cluster it returns its data in the form of wave type, I thought timestamp has its own data type.  I need to get the type of correct data I use this to a database.  I need to be able to tell the difference between a timestamp data type and a waveform, because I do not want to insert a data with waveform data type in the database in the form of stamp and I do not want to insert a time stamp in a place where the waveform data must be.  Any ideas?

  

  One of the subVIs is password protected, and it is the one that generates the error.

  Using the properties class ID and the name class seems to work OK, producing ID = 60 and the class name = AbsTime for the timestamp and ID = 47 and name = WaveformData for waveform control.

  Lynn

• timestamp data type column

  Hi guys,.

  I want to extract information from a column that contains the timestamp data type.

  something like that

  loged_date between the 09/03/2015 09/03/2015 and 09:00 20:00

  and it does not work.

  Would be very happy to help.

  Hello

  SQL lover wrote:

  Hi guys,.

  I want to extract information from a column that contains the timestamp data type.

  something like that

  loged_date between the 09/03/2015 09/03/2015 and 09:00 20:00

  and it does not work.

  Would be very happy to help.

  Whenever you have a question, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and the exact results you want from this data, so that people who want to help you can recreate the problem and test their ideas.

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: Re: 2. How can I ask a question on the forums?

  Maybe you want something like:

  loged_date between TO_TIMESTAMP (' March 9, 2015 09:00 ")

  , ' DD/MM/YYYY HH24:MI:SS.

  )

  and TO_TIMESTAMP (March 9, 2015 20:00 ')

  , ' DD/MM/YYYY HH24:MI:SS.

  )

• ADF table filter - date column - in the table data type is timestamp

  Hello

  I want to filter adf table based on the time stamp column, but unable to do so.

  Details.

  1. The data type of the column (dateAdded) in the database is timestamp.
  2. the type of this column in the mode attribute is oracle.jbo.domain.Timestamp. and the format is DD/MM/YYYY
  3. the part of the code in my page jspx is

  < af:column sortProperty = filterable "DateAdded" = "true" width = '80' sortable = "true" headerText = "creation Date" id = "c6" >

  < f: facet = name 'filter' >

  < af:inputDate value = "#{vs.filterCriteria.DateAdded}" id = "id1" > "

  < af:convertDateTime pattern = "dd/MM/yyyy" / >

  < / af:inputDate >

  < / f: facet >

  < af:outputText value = "#{rank." DateAdded}"id ="ot5">

  < af:convertDateTime pattern = "#{bindings." MYCASE_CONS_VO1.hints.DateAdded.format}"/ >

  < / af:outputText >

  < / af:column >

  4. everything by filtering this field giving entered in the format DD/Mm/yyyy, the query runs but no change in the result (the value of this field in the table lavel is 10.54.16.000000000 18 June 14 h)

  Note: In the interface user, the value of the field is display in the format DD/MM/YYYY.

  Please feel free to ask me questions. Enjoy for little help.

  Thank you

  ASIS

  You can try with that mentioned in the link:

  http://dkleppinger.blogspot.in/2011/09/how-to-ignore-time-component-of-date.html

  Date query shows no results for the date of the day

• partition interval on the data type TIMESTAMP PrimaryKey

  question:
  Need example of Oracle Interval partitioning on the TIMESTAMP data type of primary key, including the LOCAL INDEX generated by partitioned interval key functional
  
  Published by: oracletune on April 17, 2013 07:51

  >
  * It seems that interval of time STAMP partitioning is not supported:
  >
  This is not correct.
  >
  Partitioning interval is limited to a partition key unique to a numeric or date range.
  >
  The above is YOUR text and is NOT what the doc.

  The VLDB and partitioning Guide
  http://docs.Oracle.com/CD/E18283_01/server.112/e16541/part_admin001.htm#BAJHFFBE
  >
  For the partitioning of the interval, the partitioning key can be a single column of the table name, and it must be the number or DATE type.
  >
  Which must be read carefully. It is said should be "NUMBER or DATE type. Note that 'DATE type' does NOT mean 'Type of DATE data. A TIMESTAMP (but not TIMESTAMP WITH TIMEZONE) are a type of DATE. It's confusing and the doc must could be formulated differently.

  This code is very well:

  drop table test_part_timestamp
  
  CREATE TABLE TEST_PART_TIMESTAMP
  (
  PRODUCT_ID NUMBER,
  DESCRIPTION VARCHAR2(20 BYTE),
  CREATE_DATE TIMESTAMP(6)
  )
  PARTITION BY RANGE (CREATE_DATE)
  INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
  (
  PARTITION OLD_DATA VALUES LESS THAN (TIMESTAMP' 2013-01-01 00:00:00'),
  PARTITION P_2013_JAN VALUES LESS THAN (TIMESTAMP' 2013-02-01 00:00:00')
  )
  

• date and timestamp data type lengths

  Hello
  
  Documentation, says the following:
  
  : Date parameter valid [...]. The size is fixed to 7 bytes. This data type contains the datetime fields YEAR, MONTH, DAY, HOUR, MINUTE, and SECOND. There can be no fractions of a second or a zone.
  
  TIMESTAMP [(fractional_seconds_precision)]
  Year, [...] setting. The size is 7 or 11 bytes, depending on the precision. This data type contains the datetime fields YEAR, MONTH, DAY, HOUR, MINUTE, and SECOND. It contains fractions of a second, but does not have a time zone.
  
  However, if I create a table as follows:
  
  create table t9 (timestamp (3) c1, c2 date);
  
  and do:
  
  insert into values t9 (systimestamp, sysdate);
  commit;
  
  Select length (c1), (c2) length, lengthb (c1), (c2) lengthb of t9.
  
  I get
  
  
  LENGTH (C1) (C2) LENGTH LENGTHB (C1) (C2) LENGTHB
  ---------- ---------- ----------- -----------
  21 8 21 8
  
  Can someone please explain this to me?
  
  Thank you

  I think you want to do this to check the time.

  ME_XE?select dump(c1) as c1, dump(c2) as c2 from t9;
  
  C1                             C2
  ------------------------------ ------------------------------
  Typ=180 Len=11: 120,110,4,19,1 Typ=12 Len=7: 120,110,4,19,16,
  6,30,31,13,105,58,64           30,31
  
  1 row selected.
  
  Elapsed: 00:00:00.17
  ME_XE?