day, date and year back to 2004
Start my computer, the date is Thursday, January 15, 2004. I have to restart the computer and use F2 to correct the date and time. The current date and the computer works well. But as soon as the computer is closed and restarted, the date is Thursday, January 15, 2004. Does anyone have any ideas how can I avoid this?
I am running Windows 7 Ultimate on a Dell Dimension 4600i 32-bit desktop computer. I've updated my Norton 360 software and run it, but that didn't recognize or resolve the problem.
Any help would be welcome!
Nick Bannister
You need to replace the CMOS battery on the motherboard. Open the box and you will see the battery (about the size of a nickel). Model battery is CR2032
I hope this helps.
Tags: Windows
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Hello
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User profile corruption might have caused the problem. As a solution, I suggest to create a new user profile and check if the date format displays the same thing.
To do this, see the link below.
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Hi JeffryBrown,
You can update the BIOS (Basic Input Output System) and drivers from the chipset & check if the problem persists.
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Get the number of days, months and year
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I'm using OBIEE 11 g. I have a line of dash for year (2010, 2011, etc.) and months (Jan, Feb,..., Dec). How can I get the number of days in a given month and year in my report?
For example, if I choose to Jan & 2011, I'd get 31 and 356. And if I choose Feb & 2011, I would get 28 and 356.
Thank you!I have something more good option here... Try to use this
DAYOFMONTH (TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, CURRENT_DATE)))
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I am trying to enter digital variables the same day (format: 1 / 10), month (format: 1 / 10) and year (format: 1900). I tried to use this sample:
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In the Script:
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Pls find the solution of your problem... Let me know if you have any problem.
MainApplication.mxml
layout = "absolute" creationComplete = "onCreationComplete ()" > "
private var actualDate:Date = new Date();
[Bindable]
private var actualDay:String;
[Bindable]
private var actualMonth:String;
[Bindable]
private var actualYear:String;
private function onCreationComplete():void
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actualYear = YYYYformatter.format (actualDate);
}
]]>
with respect,
Mayeul Singh Bartwal
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split with day, month and year in a date
Hi all
I have this point of view
with (id, dt) t (select 1, to_date('02/06/2010','MM/DD/YYYY') of all the double union)
Select 2, to_date('11/29/2001','MM/DD/YYYY') of all the double union
Select 3, to_date('02/06/2011','MM/DD/YYYY') of all the double union
Select option 4, double to_date('10/10/2011','MM/DD/YYYY')
)
--
-end of test data
--
SELECT id, dt
floor (months_between(sysdate,dt)/12) years
, floor (mod (months_between (sysdate, dt), 12)) months
-The day is ambiguous because of the number of days in a different month
-you could design your own algorithm to give the desired results, but it is a good approximation
, floor (sysdate-(add_months (dt, floor (months_between (sysdate, dt))) as dys
t
/
ID DT YEARS MONTHS DYS
---------- ----------- ---------- ---------- ----------
1-6 FEBRUARY 2010 5 8 22
2 29 NOVEMBER 2001 13 10 29
3-6 FEBRUARY 2011 4 8 22
4-10 OCTOBER 2011 4 0 18As a result, 26 years old, 26 months, 91 days.
And subtract years, MONTHS and DYS as format
erase years, from 1 to 12 months and the days of the 1 to 30 as
91 days = 30 x 3 + 1 = > 1 day over 3 months
26 months + 3 months = 29 months = > 24 months + 5 months = 2 years + 5 months
and 26 years + 2 years = 28
desire to result: 28 years, 5 months and 1 day.
Is there a function that give me this result from the query above?
Kind regards
Gordan
Hello Gordan,.
I understand that you are the SUM of all the lines.
Here are two ideas:
-1 - using a date
(a) SUM (TRUNC (sysdate) - dt)
I would give you the total number of days.
(b) adding the number of days to, for example, DATE ' 1900-01-01' would give another date...
(c) simply subtract the years 1900 and it takes several years,
subtract 1 from the month (1-12 from January to December) and you have the number of months
subtract 1 from the day of the month (1-31) and you have the number of days.
It is of course 'approximate' as the months do not have the same number of days...-2 - using only the number of days
Maybe you want something else, for example: the total number of days divided by 365.25 for many years, the recall divided by 30 to get the number of months, the reminder being the number of days.(a) SUM (TRUNC (sysdate) - dt)
I would give you the total number of days.
(b) Division by 365.25 (le.25 is to take leap years into account, but you can choose for example "365")
(c) number of reminder of days (total - years * 365.25): divided by 30 is the number of months
(d) number reminder of days (total - years * 365.25 - months * 30): gives the number of days.
The following two options with your test data (by chance, this gives the same result in this case)
option 1:
with (id, dt) t (select 1, to_date('02/06/2010','MM/DD/YYYY') of all the double union)
Select 2, to_date('11/29/2001','MM/DD/YYYY') of all the double union
Select 3, to_date('02/06/2011','MM/DD/YYYY') of all the double union
Select option 4, double to_date('10/10/2011','MM/DD/YYYY')
)
target_date AS
(SELECT DATE ' 1900-01-01' + SUM (TRUNC (sysdate) - t.dt) FROM t trgt)
in_pieces AS
(SELECT TO_NUMBER (TO_CHAR (td.trgt, 'YYYY')) - 1900 y
, TO_NUMBER (TO_CHAR (td.trgt, 'MM')) - 1 m
, TO_NUMBER (TO_CHAR (td.trgt, 'DD')) - 1 d
Target_date TD
)
SELECT "result: ' |"
TRIM (CASE WHEN ip.y = 0 THEN NULL
WHEN ip.y = 1 THEN "1 year"
Of OTHER TO_CHAR (ip.y) | "years".
END |
CASE WHEN ip.m = 0 THEN NULL
WHEN ip.m = 1 THEN "1 month"
Of OTHER TO_CHAR (ip.m) | 'months '.
END |
CASE WHEN ip.d = 0 THEN NULL
WHEN ip.d = 1 THEN "1 day"
Of OTHER TO_CHAR (ip.d) | 'days '.
END
)
Of in_pieces ip
;
result: 28 years, 4 months and 28 daysoption 2:
with (id, dt) t (select 1, to_date('02/06/2010','MM/DD/YYYY') of all the double union)
Select 2, to_date('11/29/2001','MM/DD/YYYY') of all the double union
Select 3, to_date('02/06/2011','MM/DD/YYYY') of all the double union
Select option 4, double to_date('10/10/2011','MM/DD/YYYY')
)
nb_days AS
(SELECT SUM (TRUNC (sysdate) - t.dt) n t)
, y AS
(SELECT Nb.n, FLOOR (nb.n / 365.25) y nb_days n. b.)
ym AS
(SELECT y.n, y.y, FLOOR ((y.n-y.y * 365,25) / 30) FROM a)
ymd AS
(SELECT ym.y, ym.m, ym.n - ym.y * 365.25 - ym.m * ym FROM 30 d)
SELECT "result: ' |"
TRIM (CASE WHEN ymd.y = 0 THEN NULL
WHEN ymd.y = 1 THEN "1 year"
Of OTHER TO_CHAR (ymd.y) | "years".
END |
CASE WHEN ymd.m = 0 THEN NULL
WHEN ymd.m = 1 THEN "1 month"
Of OTHER TO_CHAR (ymd.m) | 'months '.
END |
CASE WHEN ymd.d = 0 THEN NULL
WHEN ymd.d = 1 THEN "1 day"
Of OTHER TO_CHAR (ymd.d) | 'days '.
END
)
WAN
;
result: 28 years, 4 months and 28 daysBest regards
Bruno Vroman.
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SQL queries for the date and year
Hi friends,
I have a named view - item_sales with 4 columns
Item code
Name of the element
Transaction_YYYYMM (Date stored in a format YYYYMM)
QTY_RECEIVED
QTY_SOLD
Sample data is
ITEM_CODE POINT NAME TRANSACTION_YYYMM QTY_RECD QTY_SOLD
TSHIRT 201307 3000 2000 AX
TSHIRT AX 500 2000 201308
TSHIRT 201309 1000 3000 AX
CX 201307 3000 2000 XLSHIRT
XLSHIRT CX 201308 3000 2500
CX 201309 3000 2500 XLSHIRT
END OF EACH MONTH I'LL RUN THIS QUERY TO FIND OUT THE DETAILS BELOW
1. TO FIND NOM_ELEMENT WISE - QTY_RECEIVED AND QTY_SOLD (FOR THE CURRENT MONTH - EXAMPLE SEP)
2. TO FIND NOM_ELEMENT WISE - QTY_RECEIVED AND QTY_SOLD (EXAMPLE EXERCISE OF JAN TO SEP)
OUTPUT FOR SEPTEMBER MONTH LOOK LIKE THIS
SEVEN MONTHS JAN TO SEP
ITEM_CODE NOM_ELEMENT QTY_RECEIVED QTY_RECEIVED QTY_SOLD QTY_SOLD
TSHIRT 1000, 3000, 6000, 5500 AX
CX 3000 2000 9000 7000 XLSHIRT
Pls advise me how to write queries for this
RDK
Hello
This is called a Pivot, and here's a way to do it:
WITH got_display_yyyymm AS
(
SELECT TO_CHAR (ADD_MONTHS (SYSDATE-1)
, "YYYYMM.
) AS YYYYMM
OF the double
)
SELECT i.item_code
i.item_name
SUM (CASE
WHEN i.transaction_yyyymm = d.yyyymm
THEN i.qty_received
END
) AS month_received
SUM (CASE
WHEN i.transaction_yyyymm = d.yyyymm
THEN i.qty_sold
END
) AS month_sold
SUM (CASE
WHEN SUBSTR (i.transaction_yyyymm, 1, 4)
= SUBSTR (d.yyyymm, 1, 4)
THEN i.qty_received
END
) AS year_received
SUM (CASE
WHEN SUBSTR (i.transaction_yyyymm, 1, 4)
= SUBSTR (d.yyyymm, 1, 4)
THEN i.qty_sold
END
) AS year_sold
Item_sales I have
CROSS JOIN got_display_yyyymm d
I.item_code GROUP, i.item_name
ORDER BY i.item_code, i.item_name
;
If you would care to post a small example of data (CREATE TABLE and INSERT statements) and the results desired from these data, then I could test it.
The subquery got_display_yyyymm digit which is the previous month; It is not to change anything from month to month. If you run the query in October 2013, then YYYYMM Gets the value '201309'. If you run it in January 2014, then YYYYMM will be '201312'.
As posted, it will work in Oracle 9.1 or higher. The SELECT... PIVOT function that was introduced in Oracle 11.1 would not help in this problem, so you do not miss anything using Oracle 10 in this case.
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Hello
Your CMOS battery is probably dead (it's the battery that keeps 'Ticktock' even when the PC is not powered clock of your PC). If you provide your details, the original range model number PC, I might be able to help more to help you locate. It looks like this, if you have a desktop computer...
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Date and time will come back 4 years every time when Vista restarts
whenever I restart my pc, the time and the date was 4 years ago and my updates stop works to start specially my antivirus AVG ver 9, is the virus? settings or, even more I also get an error of checksum on starting and pressing the F1 key, it continues to boot the system.
Please help me ASAP no matter who
Instead of F1, enter the BIOS and then exit it save the changes. Then, the
checksum will be fixed.--
..
--
"Amir Puri" wrote in message news: f87bea8f-4e63-493-b891-54da5cdf0fab...
> every time I restart my pc time and date will come back 4 years and my
> updates to stop working on startup especially my antivirus AVG ver 9, it
> the virus? or other settings, plus I get also a checksum
at startup and pressing the F1 key it still boot the system.
>
> Please help me ASAP no matter who
> -
How to find the next date of the year and day as of today's date and the day
I have a question about date functions, that is to say: how to get one next year (date and day) like today are the date and the day this year?
You mean like this?
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TO_CHAR (ADD_MONTHS (S
--------------------
Friday, August 22, 2014 -
Date and days for the entire year come in the column
Hi all
I have 2 column 1 is the Date and day 2
And I have a button, I need when I press enter then his show all the year date in the date and day column in the column of day for example
Date - day+.
* 1 - jan - 2009 - Thursday *.
* 2 - jan - 2009 - Friday *.
* 3 - jan - 2009 - Saturday *.
And like on
I hope that you guys understand
Concerning
Wasim IsmailHai,
This means, you must fill in the block record multi that has 2 columns (1 is the date, and the other is updated.).
For this try this in the trigger WHEN BUTTON PRESSED the button.
DECLARE Dt_Date DATE; BEGIN GO_BLOCK (''); CLEAR_BLOCK(NO_VALIDATE); FIRST_RECORD; Dt_Date := TO_DATE('01-JAN-2009'); LOOP : .TI_DATE := TO_CHAR(Dt_Date, 'DD-MON-YYYY'); : .TI_DAY := TO_CHAR(Dt_Date, 'DAY'); EXIT WHEN TO_CHAR(Dt_Date, 'YYYY') <> TO_CHAR(Dt_Date + 1, 'YYYY'); -- If next year reaches, exit from the loop. Dt_Date := Dt_Date + 1; NEXT_RECORD; END LOOP; END; Kind regards
Manu.
If this answer is useful or appropriate, please mark. Thank you.
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Hello. I bought Lightroom, paid license 1 year view, did not have serial. And number and then past the 30 day trial and may not use the product or work more hard. I paid has been deducted from my credit card. How I'm going to work now?
Hi Sergior96769872,
I saw your Adobe ID (email address), you used to post on the forums, and I see an active subscription on it.
Please see Help below links: { make sure you use the same Adobe ID (email address) that you used to purchase the subscription }
Connect and disconnect activate Cloud Creative applications
Adobe Creative Cloud apps back in test mode after 2015 set CC to update
* NOTE: Make sure that your firewall of your computer or security software firewall does not block Adobe, if you are not sure of it can just disable the firewall for a while and then log off and log on creative application of cloud and check.
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- Broker CIB Adobe
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2 - right click on the Finder icon, then select the "Go - To" folder. You will get a text box, type in the following command and then press the 'return '. ("Not to be missed ~ symbol")
~/Library (it will open the folder of the user's library.)
3. browse to the Application Support > Adobe > trash OOBE folder and folder AAM Updater
4 - CUT any installed security software with firewall system.
5 - go to: Apple icon > system preferences > Security & Privacy > General > "allow applications downloaded on" change this anywhere (to make these changes click the padlock in the corner at the bottom left of this window and enter your computer password)
These changes are temporary you can restore these changes back to normal once your creative cloud app is running *.
6 - restart the cloud creative app and connect
If you use the WINDOW:
1 complete the process / Task Manager tasks in the same order, as mentioned below the Manager tasks. See, Open the Task Manager
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- Basic timing & sync to basic support
- CC library & process CCX
- Adobe Common Desktop
- Adobe update daemon
- Broker CIB Adobe
- After that, everything that said adobe on it do a force quit for her
2 - C:\Users\
\AppData\Local\Adobe\ MAA UPDATER and two OOBE (App data & Program Data is hidden folder please see, Show files and folders hidden in Windows 7, 8.x, 10, or Vista) 3 - CUT any security software installed with firewall system, also if your having any browser Add On installed for blocking advertising that turn off too.
These changes are temporary you can restore these changes back to normal once your creative cloud app is running *.
4 - raise the cloud creative app and connect
Let us know if that helps.
-
transaction
ID Grp Loc qty type report_days
ABC x 21 101 1 4/1/2009
ABC x 29 101 2 4/1/2009
ABC x 22 101 3 4/1/2009
ABC x 45 101 1 15/6 / 2008
ABC 100 x 102 1 16/11/2008
I have a table called transaction
I want to generate a report like this in an another table generatereport
GenerateReport
GenerateReport
ID Grp Loc qty1 2 days report_days
ABC 101 x 0 0 Sunday, June 1, 2008 adding 7 days
101 abc x 0 0 Sunday ..
ABC 101 x 45 0 Monday, June 15, 2009
ABC 101 x 100 0 Sunday, November 16, 2008
101 abc x 0 0 Sunday …
101 abc x 50 22 Sunday until 01/04/2009 (i.e. ONE year)
Qty1 Generatereport table column is filled with the sum of the quantity of type 1 + type 2
column 2 of table Generatereport is filled with the sum of the quantity of type 3
All day should be Sunday
and we must go a year back from 01/04/09 and generate the timetable up to 2009-04-01 only for Sundays
can you help me pls
Thanks in advance
Published by: user12093849 on November 13, 2009 04:55
Published by: user12093849 on November 13, 2009 04:58This is the query, I came up with that:
WITH transaction_table AS ( SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 21 AS QTY, 1 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 29 AS QTY, 2 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 22 AS QTY, 3 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 45 AS QTY, 1 AS TYPE, TO_DATE('06/15/2008','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL SELECT 102 AS ID, 'abc' AS GRP, 'x' AS LOC, 100 AS QTY, 1 AS TYPE, TO_DATE('11/16/2008','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL ) -- END TEST DATA , sunday_date_range AS ( SELECT NEXT_DAY(TO_DATE(:pStartDate,'MM/DD/YYYY')-1,'SUNDAY') + 7*(LEVEL - 1) AS DT FROM DUAL CONNECT BY LEVEL <= (TO_DATE(:pEndDate,'MM/DD/YYYY') - TO_DATE(:pStartDate,'MM/DD/YYYY'))/7 + 1 ) SELECT ID , GRP , LOC , TO_CHAR(DT,'Day DD/MM/YYYY') AS REPORT_DAYS , SUM(CASE WHEN TYPE IN (1,2) THEN QTY ELSE 0 END) AS QTY1 , SUM(CASE WHEN TYPE = 3 THEN QTY ELSE 0 END) AS QTY2 FROM transaction_table PARTITION BY (ID, GRP, LOC) RIGHT OUTER JOIN sunday_date_range ON transaction_table.REPORT_DAYS BETWEEN sunday_date_range.DT - 7 + INTERVAL '1' SECOND AND sunday_date_range.DT GROUP BY ID , GRP , LOC , DT ORDER BY 1, 2, 3Here's the test scenario:
SQL> var pStartDate VARCHAR2(25); SQL> exec :pStartDate := '04/01/2008'; PL/SQL procedure successfully completed. SQL> var pEndDate VARCHAR2(25); SQL> exec :pEndDate := '04/01/2009'; PL/SQL procedure successfully completed. SQL> WITH transaction_table AS 2 ( 3 SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 21 AS QTY, 1 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL 4 SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 29 AS QTY, 2 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL 5 SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 22 AS QTY, 3 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL 6 SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 45 AS QTY, 1 AS TYPE, TO_DATE('06/15/2008','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL 7 SELECT 102 AS ID, 'abc' AS GRP, 'x' AS LOC, 100 AS QTY, 1 AS TYPE, TO_DATE('11/16/2008','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL 8 ) 9 -- END TEST DATA 10 , sunday_date_range AS 11 ( 12 SELECT NEXT_DAY(TO_DATE(:pStartDate,'MM/DD/YYYY')-1,'SUNDAY') + 7*(LEVEL - 1) AS DT 13 FROM DUAL 14 CONNECT BY LEVEL <= (TO_DATE(:pEndDate,'MM/DD/YYYY') - TO_DATE(:pStartDate,'MM/DD/YYYY'))/7 + 1 15 ) 16 SELECT ID 17 , GRP 18 , LOC 19 , TO_CHAR(DT,'Day DD/MM/YYYY') AS REPORT_DAYS 20 , SUM(CASE WHEN TYPE IN (1,2) THEN QTY ELSE 0 END) AS QTY1 21 , SUM(CASE WHEN TYPE = 3 THEN QTY ELSE 0 END) AS QTY2 22 FROM transaction_table PARTITION BY (ID, GRP, LOC) 23 RIGHT OUTER JOIN sunday_date_range ON transaction_table.REPORT_DAYS BETWEEN sunday_date_range.DT - 7 + INTERVAL '1' SECOND AND sunday_date_range.DT 24 GROUP BY ID 25 , GRP 26 , LOC 27 , DT 28 ORDER BY 1, 2, 3 29 / ID GRP L REPORT_DAYS QTY1 QTY2 ---------- --- - -------------------- ---------- ---------- 101 abc x Sunday 06/04/2008 0 0 101 abc x Sunday 13/04/2008 0 0 101 abc x Sunday 20/04/2008 0 0 101 abc x Sunday 27/04/2008 0 0 101 abc x Sunday 04/05/2008 0 0 101 abc x Sunday 11/05/2008 0 0 101 abc x Sunday 18/05/2008 0 0 101 abc x Sunday 25/05/2008 0 0 101 abc x Sunday 01/06/2008 0 0 101 abc x Sunday 08/06/2008 0 0 101 abc x Sunday 15/06/2008 45 0 101 abc x Sunday 22/06/2008 0 0 101 abc x Sunday 29/06/2008 0 0 101 abc x Sunday 06/07/2008 0 0 101 abc x Sunday 13/07/2008 0 0 101 abc x Sunday 20/07/2008 0 0 101 abc x Sunday 27/07/2008 0 0 101 abc x Sunday 03/08/2008 0 0 101 abc x Sunday 10/08/2008 0 0 101 abc x Sunday 17/08/2008 0 0 101 abc x Sunday 24/08/2008 0 0 101 abc x Sunday 31/08/2008 0 0 101 abc x Sunday 07/09/2008 0 0 101 abc x Sunday 14/09/2008 0 0 101 abc x Sunday 21/09/2008 0 0 101 abc x Sunday 28/09/2008 0 0 101 abc x Sunday 05/10/2008 0 0 101 abc x Sunday 12/10/2008 0 0 101 abc x Sunday 19/10/2008 0 0 101 abc x Sunday 26/10/2008 0 0 101 abc x Sunday 02/11/2008 0 0 101 abc x Sunday 09/11/2008 0 0 101 abc x Sunday 16/11/2008 0 0 101 abc x Sunday 23/11/2008 0 0 101 abc x Sunday 30/11/2008 0 0 101 abc x Sunday 07/12/2008 0 0 101 abc x Sunday 14/12/2008 0 0 101 abc x Sunday 21/12/2008 0 0 101 abc x Sunday 28/12/2008 0 0 101 abc x Sunday 04/01/2009 0 0 101 abc x Sunday 11/01/2009 0 0 101 abc x Sunday 18/01/2009 0 0 101 abc x Sunday 25/01/2009 0 0 101 abc x Sunday 01/02/2009 0 0 101 abc x Sunday 08/02/2009 0 0 101 abc x Sunday 15/02/2009 0 0 101 abc x Sunday 22/02/2009 0 0 101 abc x Sunday 01/03/2009 0 0 101 abc x Sunday 08/03/2009 0 0 101 abc x Sunday 15/03/2009 0 0 101 abc x Sunday 22/03/2009 0 0 101 abc x Sunday 29/03/2009 0 0 101 abc x Sunday 05/04/2009 50 22 102 abc x Sunday 06/04/2008 0 0 102 abc x Sunday 13/04/2008 0 0 102 abc x Sunday 20/04/2008 0 0 102 abc x Sunday 27/04/2008 0 0 102 abc x Sunday 04/05/2008 0 0 102 abc x Sunday 11/05/2008 0 0 102 abc x Sunday 18/05/2008 0 0 102 abc x Sunday 25/05/2008 0 0 102 abc x Sunday 01/06/2008 0 0 102 abc x Sunday 08/06/2008 0 0 102 abc x Sunday 15/06/2008 0 0 102 abc x Sunday 22/06/2008 0 0 102 abc x Sunday 29/06/2008 0 0 102 abc x Sunday 06/07/2008 0 0 102 abc x Sunday 13/07/2008 0 0 102 abc x Sunday 20/07/2008 0 0 102 abc x Sunday 27/07/2008 0 0 102 abc x Sunday 03/08/2008 0 0 102 abc x Sunday 10/08/2008 0 0 102 abc x Sunday 17/08/2008 0 0 102 abc x Sunday 24/08/2008 0 0 102 abc x Sunday 31/08/2008 0 0 102 abc x Sunday 07/09/2008 0 0 102 abc x Sunday 14/09/2008 0 0 102 abc x Sunday 21/09/2008 0 0 102 abc x Sunday 28/09/2008 0 0 102 abc x Sunday 05/10/2008 0 0 102 abc x Sunday 12/10/2008 0 0 102 abc x Sunday 19/10/2008 0 0 102 abc x Sunday 26/10/2008 0 0 102 abc x Sunday 02/11/2008 0 0 102 abc x Sunday 09/11/2008 0 0 102 abc x Sunday 16/11/2008 100 0 102 abc x Sunday 23/11/2008 0 0 102 abc x Sunday 30/11/2008 0 0 102 abc x Sunday 07/12/2008 0 0 102 abc x Sunday 14/12/2008 0 0 102 abc x Sunday 21/12/2008 0 0 102 abc x Sunday 28/12/2008 0 0 102 abc x Sunday 04/01/2009 0 0 102 abc x Sunday 11/01/2009 0 0 102 abc x Sunday 18/01/2009 0 0 102 abc x Sunday 25/01/2009 0 0 102 abc x Sunday 01/02/2009 0 0 102 abc x Sunday 08/02/2009 0 0 102 abc x Sunday 15/02/2009 0 0 102 abc x Sunday 22/02/2009 0 0 102 abc x Sunday 01/03/2009 0 0 102 abc x Sunday 08/03/2009 0 0 102 abc x Sunday 15/03/2009 0 0 102 abc x Sunday 22/03/2009 0 0 102 abc x Sunday 29/03/2009 0 0 102 abc x Sunday 05/04/2009 0 0 106 rows selected.This query performs a number of things.
1. the sunday_date_range generates all the Sunday between the pStartDate and the pEndDate
2. I've made use of a JOIN OUTSIDE of SCORE to generate the date range for EACH ID, GRP and LOC. If you do not have 10g, to implement an alternative workaround.
3. I join on a date range for a little less than 7 days if all report data fall date Sunday by your condition. This is because on 01/04/2009 is not a Sunday.
HTH!
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