split with day, month and year in a date

Similar Questions

• Set the calendar to display day, month and year

  In addition to the time of day, my computer began giving the day of the week (Monday) only instead of day, month and year as it did before. Tried to go back to 29/12/2014 or something similar without success.  Any suggestions?

  Hello

  Sorry for the late reply and I appreciate your patience.

  User profile corruption might have caused the problem. As a solution, I suggest to create a new user profile and check if the date format displays the same thing.

  To do this, see the link below.

  http://Windows.Microsoft.com/en-us/Windows/fix-corrupted-user-profile#1TC=Windows-7.

  It will be useful. Just answer us with the State, and we will be happy to help you.

• I want to collect rain for the day, month and year; Can what formula I use?

  I want to collect rain for the day, month and year; What formula or expression that I can use.

  I use a Rain Wise product that converts impulses to an analog value.  The rain wise device can be

  "the value measure up to 1", 5", or 10".  I will be setting the unit at 10 inches in increments of 0.01 inch.

  What I would do is at each time increments of signal I would consider it as 0.01 then after reaching

  a period of time a day or a month, back to zero.

  Need some advice on this problem.

  How about you, using a counter to count the number of times where the signal is less than 0.01?

  For example,.

  Counter.Count = signal<=>

  The total number of rain is

  Counter * 10 + signal

  Use TimeOfDay or TimeOfWeek to reset the counter.

• Get the number of days, months and year

  Hi all
  
  I'm using OBIEE 11 g. I have a line of dash for year (2010, 2011, etc.) and months (Jan, Feb,..., Dec). How can I get the number of days in a given month and year in my report?
  
  For example, if I choose to Jan & 2011, I'd get 31 and 356. And if I choose Feb & 2011, I would get 28 and 356.
  
  Thank you!

  I have something more good option here... Try to use this

  DAYOFMONTH (TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, CURRENT_DATE)))

  This will give you the days for the month in progress (Oct 2011) after calculating the last day of each month... Similary dynamically pass the value Date or month... You will need to modify this function but shud be simple. Hope this helps :)

• Manage the values of the actual day, month and year

  Hello

  I am trying to enter digital variables the same day (format: 1 / 10), month (format: 1 / 10) and year (format: 1900). I tried to use this sample:

  "< mx:DateFormatter id ="DDformatter"formatString ="DD"/ > "

  "< mx:DateFormatter id ="MMformatter"formatString ="MM"/ >"

  "< mx:DateFormatter id ="YYYYformatter"formatString ="YYYY"/ >"

  In the Script:

  private var actualDate: Date = new Date();

  [Bindable] private var actualDay:String = DDformatter(actualDate) .format.

  [Bindable] private var actualMonth:String = MMformatter(actualDate) .format.

  [Bindable] private var actualYear:String = YYYYformatter(actualDate) .format.

  Part of getting an error when I run my application (am I missing some import?) I would like to have these data in numerical variables:

  #1009 error - cannot access a property or method of a null object reference.

  Pls find the solution of your problem... Let me know if you have any problem.

  MainApplication.mxml

  http://www.Adobe.com/2006/mxml '.

  layout = "absolute" creationComplete = "onCreationComplete ()" > "

  private var actualDate:Date = new Date();

  [Bindable]

  private var actualDay:String;

  [Bindable]

  private var actualMonth:String;

  [Bindable]

  private var actualYear:String;

  private function onCreationComplete():void

  {

  actualDay = DDformatter.format (actualDate);

  actualMonth = MMformatter.format (actualDate);

  actualYear = YYYYformatter.format (actualDate);

  }

  ]]>

  with respect,

  Mayeul Singh Bartwal

• Calculate the age (months and years) of two dates

  Trying to get the (almost exact) age in years and months to fill in 'Age at the time of retirement' (years1) since the date of birth (DOB1) and the date of their departure in retirement (retireDate1). The only examples that I could find are dates "today." If anyone can help with code? And I understand it works better with JavaScript but FormCalc would also work?

  Dates as DD/MM/YYYY

  Field is num {z9}

  Thank you in advance for your help!

  I could do this work with Age1 as a text field. Of course, you can do whatever you want with it, but this method makes the most sense for me because I can say 99 months "99 years". If you need to separate the year and month in different areas, you should be able to do it easily. Finally, it requires that the user does not manually enter dates. (Something on the raw values isn't quite right when they came from the selection.)

  Age1::calculate (or anywhere where you want this event)

  if (!DOB1.isNull && !retireDate1.isNull){
    var d1 = DOB1.rawValue.split('-');
    var d2 = retireDate1.rawValue.split('-');
    var years = parseInt(d2[0]) - parseInt(d1[0]);
    var months = (parseInt(d2[1]) - parseInt(d1[1]));
    if (parseInt(months) < 0){
      months = 12 + months;
      years--;
    }
    Age1.rawValue = years + " years " + months + " months.";
  }
  

• How to find the sum of the month and year of a date

  Hi all
  
  I want to find the sum of the date
  for example, 10 November 2010 I need to find (11-2010).
  
  Please help me

  You can use the extract function...

  SQL> select extract(month from systimestamp)+extract(year from systimestamp) from dual;
              EXTRACT(MONTHFROMSYSTIMESTAMP)+EXTRACT(YEARFROMSYSTIMESTAMP)
                                      ------------------------------------------------------------
                                                          2021
  

  Concerning
  Renjith Malet

• get the month and year of date type

  Hi all
  I need to get the month and year of type date.
  
  For example

  select to_date('2011-01-17', 'yyyy-mm-dd') from dual;

  Required result:

  01-2011

  Any ideas?
  
  Thanks in advance,
  Bahchevanov.

  select to_char(to_date('2011-01-17', 'yyyy-mm-dd'),'mm-yyyy') from dual;
  

  HTH

• Get the number of days in a month based on the month and year of fields

  I have a column in my form which lists the days in a month. I want to configure a hidden field that calculates the total number of days in a month, based on the month and year of the field inputs. The number of days will determine what appears on the column. For example, if I put 4 months, and 2016 in the field of the year, I get 30 in the hidden field. Thus, on the column 'Day', I'll have numbers 1-30. Or if I put 2 months and 2016 in the field of the year, I get the 29 in the hidden field. If the numbers 1-29 appears in the column 'day '.

  Found this on some forum javascript code:

  //Month is 1 based
function daysInMonth(month,year) {
   return new Date(year, month, 0).getDate();
}

//July
daysInMonth(7,2009); //31
//February
daysInMonth(2,2009); //28
daysInMonth(2,2008); //29

  I do not know how to convert this code in JavaScript to adobe and don't really know how to use it. All I know how to do is to configure the field values for the field month and year as variables. I am a novice programmer and would appreciate it really all the help I can get. Thank you in advance!

  The code seems to be JavaScript and runs as needed by using the JavaScript console.

  I would like to consider making more general code, so if you have a date string that includes at least the month and year we could just call the function and get the number of days for that month.

  The following script will calculate the number of days in a month, by using at least the month and year values can display the result on the JavaScript console and all of the value field for the field that has this code as the custom calculation Script.

  function daysInMonth (oDate) {}
  return new Date (oDate.getFullYear (), oDate.getMonth () + 1, 0) .getDate ();
  }

  nMonth var = this.getField("Month").valueAsString; get the value of month;
  nYear var = this.getField("Year").valueAsString; get the value of the year;

  Event.Value = "";

  If (nMonth! = "" & nYear!) = "") {}
  var MyDate = util.scand ("' / mm/yyyy ', nMonth +" / "+ nYear); convert to date object;
  var nDaysInMonth = daysInMonth (MyDate); get the number of days;

  Console.Open (); Open the JavaScript console;

  Console.clear(); clear the console;

  Console.println ("Days in" + nMonth + ":" + nDaysInMonth); show days in month;

  Event.Value = nDaysInMonth; Set the value of the field;

  }

• problem to insert only month and year instead of the full date

  select b.penjara_id, p.penj_lokasi, a.no_daftar, b.episod, b.nama1,to_char(a.trkh_mula_prl,'dd/mm/yyyy') as trkh_mula_prl, to_char(bulan_proses,'mm/yyyy') as bulan_proses,
          b.epd, b.lpd
  from prl_daftar_proses a, senarai_pesalah b, penjara p
  
  where a.no_daftar=b.no_daftar
  and a.episod=b.episod
  and b.penjara_id = p.penjara_id
  and a.setuju_jplp is null
  and a.bulan_proses between to_date(:FROM,'dd/mm/yyyy') and to_date(:TO,'dd/mm/yyyy')
  
  
  order by b.penjara_id, a.bulan_proses,a.no_daftar

  Hi, can someone help me how I can register only the month and year of the value which have full day in the database?
  
  for example, the date is 18/09/2012, but I want to just insert 09/2012 as a parameter. If I want to insert only one setting, I can do... But I have problem when I want to insert two parameters...

  Lina saleh wrote:
  I already try before that and he invites me error like this...
  "name of the invalid host/identification variable.

  Change the name of the connection variable to: from_date and: to_date

  Is a reserved keyword.

• to get the month and year separated

  Hello
  
  I have the entry_date_fin of column (type of data-varchar2 (8))
  
  with values like Apr.-2008
  Feb-2009 etc.
  
  can I get the distinct month and year separated

  i tried select to_date(entry_date_fin,'MM') FROM  xyz  doesnt wrk

  kindly guide me

  Although you are (wrongly, IMO) storage of dates as strings, just use string manipulation...

  SQL> with t as (select 'FEB-2008' as txt from dual)
    2  --
    3  select substr(txt,1,3) as mnth
    4        ,substr(txt,5) as yr
    5  from t
    6  /
  
  MNT YR
  --- ----
  FEB 2008
  
  SQL>
  

• spend months and year in a query

  I created_date in my table... I want to only get the records of a month or a year of records
  
  How we can write a query to spend months and year to a query
  
  example is my name of the x table
  
  Select * from x where trunc (created_date) =?

  Hello

  Rather than convert all DATES in your array to a string and then compare these values to a parameter of sting, it would be more efficient to convert your DATE string parameter and then compare all your DATEs unchanged to her.
  For example, if: year_month is the string "201108', you might say:

  SELECT  *
  FROM    x
  WHERE   created_date >=             TO_DATE (:year_month || '01', 'YYYYMMDD')
  AND     created_date < ADD_MONTHS ( TO_DATE (:year_month || '01', 'YYYYMMDD')
                        , 1
                        )
  ;
  

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and INSERT statements) for table x, some values for: year_month, and the desired results for each value of: year_month from these data.
  Always tell what version of Oracle you are using.

• calculate the day of the year using the date.

  Hi all
  Can calculate us the day of the year using the date form? Is this possible? Please help me thanks in advance
  Like this
  30/08/2009-30/08/2010 after calculation - 365
  
  
  Sarah
  
  Published by: SarahSarahSarah on August 30, 2009 12:49 AM

  Sarah.

  : ins1.noday must be a part of number!

  Create a function in forms like this:

  function get_nodays ( f_dtm_start in date,
                        f_dtm_end   in date ) return number is
  begin
  if
    f_dtm_start is null OR
    f_dtm_end is null
  then
    return ( null );
  end if;
  return ( trunc ( f_dtm_start ) - trunc ( f_dtm_end ) );
  exception when others
  then message ( sqlerrm || ' in function get_nodays occured.' );
  return ( null );
  end;
  

  Call this function in the when-validate-point triggers on ins1. INSPERIOD and: ins1.end love

  :ins1.noday := get_nodays ( :ins1.INSPERIOD, :ins1.end );
  

  It is redundant to have the: noday as a cause of part of database
  the value may by calculated every time using the values INSPERIOD and: end.

• Today's date in the month and year

  Dear experts,
  
  I have a year and the number of the day, I wanted to identify the date
  ex: number of days = 203 year = 2009
  Date: 22/07/2009
  
  Please advice the best way possible to achieve.
  
  Thank you

  Dear user!

  Please try this code.

  SELECT TO_DATE(2032009, 'DDDYYYY') as dateval
  FROM   dual;
  
  DATEVAL
  -------------------
  22.07.2009 00:00:00
  

  This figure first three are the day number and the last four digits are the year. The DDD format will give you the day and the month as JJ.MM. YYYY format join the year your date. To do this, try:

  SELECT TO_DATE(2032008, 'DDDYYYY') as dateval
  FROM   dual;
  
  DATEVAL
  -------------------
  21.07.2008 00:00:00
  

  Yours sincerely

  Florian W.

  Published by: Florian W. the 22.07.2009 08:40

• Month and year Validation

  Hi all!
  
  I want to check if a given date in my form is lower or higher than sysdate...
  
  I used the coding

  if trim(:empaply.fromdate)<trim(sysdate) then
       message('Check the from date you have given !');

  This condition verifies that the date and not the month and the year...
  
  So, how can we check the month and the year is less than the current sysdate in sql?
  
  pls help me with a solution...
  
  Thanks and greetings
  user 10685325

  "Assuming that" fromdate "is the date data type, then it will simply be.

  if :empaply.fromdate < sysdate then
      message('Check the from date you have given !');
  ....