Declarations of function call

If I call a function and pass it a variable, and this function performs a calculation with this variable, the variable in the main function should be changed.  Let me give an example below.  In this example, the Message box displays 1, 2 and 3.  I always have my code the only way to get the variables of a function was explicitly return a value, for example ReturnVariable = Function (PassedVar).  In this case, only ReturnVariable would receive all changes.    So for the example below, my hypothesis is that Msgbox should print 1, 1 and 1.

In any case, this has caused a few problems with my programs, but I fear other issues that I have not yet found.  Is there a decleration that I can call to stop the evolution of a variable, passed to a function? Or is it something that I missed in VB programming, and I need to go through all my code to make sure that I do not do this?

Option Explicit  ' force explicit declaration of all variables in a script.
Dim MainVar, I have
MainVar = 1
For i = 1 to 3
MsgBox (MainVar)
Call Exchange (MainVar)
next

Function Exchange (MyVar)
MyVar = MyVar + 1
End Function

This is a feature very currious in vbscript

MSDN ByRef and ByVal

Option Explicit

Void Increment (param)
Param = param + 1
End Sub

Void IncrementByRef (ByRef param)
Param = param + 1
End Sub

Void IncrementByVal (ByVal param)
Param = param + 1
End Sub

Dim Num
Dim txt: txt = "number:"& Num ".
Num = 0: IncrementByRef (Num): txt = txt & + "\n" & "IncrementByRef (Num):"& Num ".
Num = 0: IncrementByRef Num: txt = txt & + "\n" & "IncrementByRef Num:"& Num ".
Num = 0: IncrementByRef ((Num)): txt = txt & + "\n" & "IncrementByRef ((Num)): «& Num»»
Num = 0: call IncrementByRef (Num): txt = txt & + "\n" & "call IncrementByRef (Num):"& Num ".
Num = 0: dial IncrementByRef ((Num)): txt = txt & + "\n" & "call IncrementByRef ((Num)): «& Num»»

Num = 0: IncrementByVal (Num): txt = txt & + "\n" & "IncrementByVal (Num):"& Num ".
Num = 0: IncrementByVal Num: txt = txt & + "\n" & "IncrementByVal Num:"& Num ".
Num = 0: IncrementByVal ((Num)): txt = txt & + "\n" & "IncrementByVal ((Num)): «& Num»»
Num = 0: call IncrementByVal (Num): txt = txt & + "\n" & "call IncrementByVal (Num):"& Num ".
Num = 0: dial IncrementByVal ((Num)): txt = txt & + "\n" & "call IncrementByVal ((Num)): «& Num»»

Num = 0: Increment (Num): txt = txt & + "\n" & "Increment (Num):"& Num ".
Num = 0: increment Num: txt = txt & + "\n" & "increment Num:"& Num ".
Num = 0: increment ((Num)): txt = txt & + "\n" & "increment ((Num)): «& Num»»
Num = 0: call Increment (Num): txt = txt & + "\n" & "call Increment (Num):"& Num ".
Num = 0: call Increment ((Num)): txt = txt & + "\n" & "call Increment ((Num)): «& Num»»

MsgBox txt

So, as you can see by the output, it's a trap. The only course is to write ByVal and make sure that ByRef works for you.

Maybe you can get a smile while reading this blog.

Greetings

Andreas

Tags: NI Software

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