Deduction of absence causes

Similar Questions

• Installing Oracle 11 g RAC 2: cannot delete directory under/tmp bootstrap

  People,
  
  Hello. I want to install Oracle 11 g RAC 2 with 2 Virtual Machines (rac1 and rac2 which BONES are Oracle Linux 5.6) VMPlayer and according to the tutorial
  
  http://appsdbaworkshop.blogspot.com/2011/10/11gr2-RAC-on-Linux-56-using-VMware.html
  
  I'm installing network infrastructure. I'm on step 7/10 (check the installation grid environment) and you get this error:
  
  "Free space: Rac2: / tmp '.
  Cause: Could not determine the mounting point for the specified location.
  Action: Check the specified location is available.
  Expected value: n/a
  "Actual value: n/a"
  
  
  In order to correct the above error, I run "cluster verification utility" according to
  http://docs.Oracle.com/CD/E14072_01/RAC.112/e10717/CVU.htm I run the following command:
  
  [ora11g@rac1-] $ /home_grid/runcluvfy.sh pre - crsinst - n rac1, rac2-verbose stage
  
  Output:
  / bin/rm: cannot remove directory ' / tmp/bootstrap ': operation not permitted
  ./runcluvfy.sh:line 99:/tmp/bootstrap/ouibootstrap.log: permission denied
  
  
  The above output, we see that the bootstrap of under/tmp directory is causing the problem. The solution is to remove bootstrap directory. I run the 2 commands:
  
  [ora11g@rac1 tmp] $ rmdir bootstrap
  
  Output: Operation not permitted
  
  bootstrap [ora11g@rac1 tmp] $ rm - rf
  
  Output: cannot remove bootstrap: operation not permitted.
  
  [ora11g@rac2 tmp] $ ls
  
  Output: there is no directory "bootstrap".
  
  My questions are:
  
  First of all, who "cannot remove bootstrap in rac1" cause/tmp in rac2 could not be determine mount point?
  
  Secondly, all folk can help remove bootstrap directory under the directory/tmp?
  
  
  Thank you.

  Change ownership and permission to your home of Oracle mount point will not fix your problems with your directory/tmp. Please see my previous response. The directory/tmp uses a little "sticky", that defines the owner of a file or a directory on the owner of the process, when it was created. You've probably run a previous attempt to install Oracle by another user instead of 'ora11g', in your example, so when you run a later installation as the user 'ora11g' he can't of course cleaning of these files. For security reasons, you cannot create a directory in / tmp, as a single user and use the other to remove it unless you're root or set access permissions. Umask will define access permissions when you create a file or a directory. The value of umask (default 0022) will be deducted from 777, causing e.g. 755 or 775 in your examples. If you need help to understand these codes, Google will be your best friend. Regarding cross access of files between nodes, make sure you have equivalence (ssh key) user installation and functioning. Cluster verification utility will also check if it works.

• Error creating Absence as "APP-COMPENSATION-51271: the assignment is not eligible for the element.

  Hello

  "APP-COMPENSATION-51271: the assignment is not eligible for the item."

  Hi Nelly,

  You can see below the two things that can be the cause of this error:

  1. the definition of the non-recurring item link which is tagged with such an absence, as a best practice that should be an open link. If the definition of link and the eligibility of the assignment does not match then you may receive this error.

  2. If you have defined a regulation for this type of absence plan, then check if the recurring element of the regime of accumulation is was tagged to the assignment for which you receive this error.

  Thank you

  Sanjay

• How to use the balance descending in the management of absences?

  Dear professionals.
  
  I'm in a learning phase exploring the management of absences.
  
  I have a scenario: I have to use the balance of decreasing absence
  
  Eligibility criteria:
  
  1 employee with Grade A will have 32 balance of leave per year at the beginning of the year
  2. employee with class B will have 24 balance of leave per year at the beginning of the year
  
  If an employee trips leave it will be deducted from the balance of leave and will be in the amount of net
  That is, if an employee with the class a student 2 day leave his net payment becomes 30
  
  This plan is expected to be completed at the end of the year, i.e. 31 December
  
  The beginning of each year of leave balances should get re-established.
  that grade A will be 32 and class B will have 24. No calculation necessary deferral.
  
  Y at - it suggestions, how to move forward?
  
  Kind regards
  Kathan

  Hi Kathan,

  Can you be more specific about what is criteria based on which it was decided that the balance of opening is 32 or 24 at the beginning of the year?

  For the requirement mentioned by you in your message. You can always do this by using the type of absence more in nature. but the choice is yours

  In your accrual to set a scale the accrual_value = 32/24 according to the criteria and the report formula that returns zero (as his minimum requirement for defining a plan of accumulation). According to your requirment you can not work report PTO processes because it is not necessary in your case.

  If you do not set an exercise plan, then balances will be not visible in the area of pay for and you will manage validations as someone no more than not the balance of the BG_ABSENCE_DURATION formula.

  As much the creation of link is being considered, it is always recommended that for the absence, you create a link to open. Manage the accumulator value into your formula of accumulation.

  It will be useful. Please do not hesitate to let me know if you need more details.

  Thank you
  Sanjay

• Update modules 10.3 to 10.4 - entities deducted

  I just upgraded from 10.3 to 10.4 OPM. Instead of creating entities on the fly, I deduct entities. The modules contains a large number of attributes and some of them are lance errors after deduction of an entity. The error indicates that I must deduct attributes and relationships since the entity container is deducted.
  
  IE:
  Attribute "item number" must be deducted from the alleged entity "stopped". (OPA-E00346)
  
  or
  
  Relationship 'the elements' should be deducted because of the alleged entity "stopped". (OPA-E00347)
  
  ---
  
  
  I've updated when switching from 10.3 to 10.4, elements
  
  Addition of the 'the name of the command' attribute at the level of the entity 'arrested' and changed "command" identification "gives the name of the order.
  Addition of the 'the name of the element' attribute at the level of the entity of 'element' and "the item changed" id attribute "the name of".
  
  a rule: orders ("order 1") are
  
  If I comment the above rule modules works as before with the creation of entities as you go, so, the rule seems to be the cause of the error, or miss me a step. Or I have to rebuild the modules completely to correct quite a few errors that prevent the modules to boot. I also tried to create a table creation entitiy is compiled, but does not run because of the errors above.
  
  Global
  |
  Order
  |
  The element
  
  Any help is greatly appreciated.

  "NET attributes" is determined automatically based on the question of whether a rule concludes the attribute. For example, if no rule concludes 'age', then the attribute is considered to be an attribute of base level and a value for the attribute must be given as input data (i.e. the user of an interview). However, if a rule concludes 'the age' (perhaps "date of birth of the person") then the attribute "age of the person" will be an attribute inferred.

  In short, all the attributes of an entity that is alleged must themselves such as the conclusion of a settlement or a table of rules.

• How to SELECT the actual credit amount after deduction of payments

  Hello
  I have a table with an account (credits and debits) operations. I try to get the 'real available amount' of each credit. The flows are expected to deduct the amount of their credits (dated before) precedents. It is a remaining amount, it should be deducted from the following credits (dated after) the flow.
  To explain what I want to say that I will use an example.
  
  -1
  create the table testTransactions (accountNo varchar2 (20), tranDate date, tranId varchar2 (10), tranType char(1), tranAmount number (20.2));
  
  -2
  insert into testTransactions (accountNo tranDate tranID, tranType, tranAmount)
  Select acnt, trid, trtype, trdate, tramt of
  (
  Select "AC1" acnt, to_date('01/02/2011','DD/MM/RRRR') trDate, 'A1' trID, would be ' trType, trAmt 5 Union double all the
  Select "AC1", to_date('02/02/2011','DD/MM/RRRR'), "A2", has ', 6 of all the double union
  Select "AC1", to_date('03/02/2011','DD/MM/RRRR'), "A3", "C", 15 double Union all
  Select "AC1", to_date('04/02/2011','DD/MM/RRRR'), "A4", "C", 9 double Union all
  Select "AC1", to_date('05/02/2011','DD/MM/RRRR'), 'A5', had ', 10 of all the double union
  Select "AC1", to_date('06/02/2011','DD/MM/RRRR'), "A6", "C", 7 double Union all
  Select "AC1", to_date('07/02/2011','DD/MM/RRRR'), "A7", 'C', 8 double Union all
  Select "AC1", to_date('08/02/2011','DD/MM/RRRR'), "A8", had ', 3 of all the double union
  Select "AC1", to_date('09/02/2011','DD/MM/RRRR'), 'A9', has ', 5 Union double all the
  Select "AC1", to_date('10/02/2011','DD/MM/RRRR'), "A10", 'C', 6 double Union all
  -----------------------------------------------------------------------------------------------------------------
  Select "AC2", to_date('01/03/2011','DD/MM/RRRR'), 'B1', 'C', 1 double Union all
  Select "AC2", to_date('01/03/2011','DD/MM/RRRR'), "B2", has ', 5 Union double all the
  Select "AC2", to_date('02/03/2011','DD/MM/RRRR'), "B3", has ', 6 Union double all the
  Select "AC2", to_date('03/03/2011','DD/MM/RRRR'), "B4", "C", 7 double Union all
  Select "AC2", to_date('04/03/2011','DD/MM/RRRR'), "B5", "C", 9 double Union all
  Select "AC2", to_date('05/03/2011','DD/MM/RRRR'), "B6", has ', 10 of all the double union
  Select "AC2", to_date('06/03/2011','DD/MM/RRRR'), "B7", 'C', 7 double Union all
  Select "AC2", to_date('07/03/2011','DD/MM/RRRR'), "B8", "C", 8 double Union all
  Select "AC2", to_date('08/03/2011','DD/MM/RRRR'), 'B9', has ', 4 of all the double union
  Select "AC2", to_date('09/03/2011','DD/MM/RRRR'), 'B10', has ', 5 Union double all the
  Select "AC2", to_date('10/03/2011','DD/MM/RRRR'), "B11", 'C', 6 double
  );
  commit;
  
  The results of the query of AC1 account should be
  
  AccountNo - TranID - TranAmount
  ----AC1----------A3-----------3
  ----AC1----------A6-----------7
  -AC1 - A10 - 6
  
  Let's see why:
  (a) the first credit is A3 with an amount of 15 euros, but:
  -There are two flows (A1 and A2) summarizing at 11 euros who have no previous credit, so all the amount is deducted from the following credit. Thus, for A3 is reduced to 15-11 = 4 euros
  -A5 flow is deducted from the A4 remains and 1 euro, which is deducted from the A3, so the actual amount for A3 is 3 euros
  (b) credit A3 does not display because A8 and A9 summing up to 8 flow rates are deducted from the it.
  
  
  The results of the query of account AC2 should be
  
  AccountNo - TranID - TranAmount
  ----AC2------------B7------------2
  -AC2 - B11 - 6
  
  
  
  Let's see why:
  one) first credit is B1 with a $ 1 but B2 is deducted from the it (reset it) and 4 euros remain in B2.
  (b) these 4 the sum of B2 and B3 up to 10 euros, which are deducted from the B4 and 4 + 6-7 = 3 euros remain, which are deducted from the B5.
  (c) now, B5 has 9-3 = 6 euros. B6 has 10, which are deducted from the B5 and the rest 4 (B6) are deducted from the B7 leaving 3 euros as a rest.
  (d) in the same way B9 and B10 are deducted from the B8 (reset it) and the rest 1 is deducted from the B7. The first "found" credit is B7 with a 'real' $ 2
  (e) B11 is not affected
  
  I tried to find a solution using Windowing and are cumulative (without having a very strong knowledge), but I've failed so far. I'll post the - rather
  complicated and inefficient - query in the next post.
  
  Thank you very much
  Theodore

  Hello

  How bizzare! They are certainly in the source, I think that the forum did something a little odd here. Ah, it's not lilke it when I have less than that of the user does not - it removes just to get out them! Reposting the code below with! is instead.

  The core of logic, I think is who is the credit which should be associated with flow rates. If you can understand what credit date they should be associated with, this means that you can add to this reference date. As summarized in figure could cause a flow for one of the two options presented, it must be another passage from the search logic to make sure that all the calculations which resulted in a flow are assigned to a relevant credit.

  WITH first_pass AS
  (
      SELECT
        accountno,
        trandate,
        tranid,
        trantype,
        tranamount,
        tranamount_sign,
        trantype_calc,
        amt
      FROM
        (
          SELECT
            accountno,
            trandate,
            tranid,
            trantype,
            tranamount,
            tranamount_sign,
            credit_date_for_debit,
            amt,
            CASE
              WHEN amt < 0 THEN
                'D'
              ELSE
                'C'
            END trantype_calc
          FROM
            (
            SELECT
              accountno,
              trandate,
              tranid,
              trantype,
              tranamount,
              tranamount_sign,
              credit_date_for_debit,
              sum(tranamount_sign) OVER(PARTITION BY accountno, credit_date_for_debit) amt
            FROM
              (
              SELECT
                accountno,
                trandate,
                tranid,
                trantype,
                tranamount,
                tranamount_sign,
                credit_date_for_debit
              FROM
                ( SELECT
                    t.accountno,
                    t.trandate,
                    t.tranid,
                    t.trantype,
                    t.tranamount,
                    CASE
                      WHEN t.trantype = 'D' THEN
                        -t.tranamount
                      ELSE
                        t.tranamount
                    END tranamount_sign,
                    NVL
                    ( MAX
                      (   CASE
                            WHEN t.trantype = 'C' THEN
                              t.trandate
                          END
                      )
                      OVER(PARTITION BY t.accountno ORDER BY t.trandate ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW),
                      MIN
                      (   CASE
                            WHEN t.trantype = 'C' THEN
                              t.trandate
                          END
                      )
                      OVER(PARTITION BY t.accountno ORDER BY t.trandate ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING)
                    ) credit_date_for_debit
                  FROM
                    testtransactions t
                )
            )
          )
      WHERE
        trantype != 'D'
        )
    ),
  second_pass AS
  (
  SELECT
    accountno,
    trandate,
    tranid,
    trantype,
    tranamount,
    tranamount_sign,
    CASE
      WHEN final_amt < 0 THEN
        'D'
      ELSE
        'C'
    END trantype_calc,
    final_amt amt,
    credit_date_for_debit
  FROM
    (
      SELECT
        accountno,
        trandate,
        tranid,
        trantype,
        tranamount,
        tranamount_sign,
        trantype_calc,
        credit_date_for_debit,
        SUM(amt) OVER(PARTITION BY accountno, credit_date_for_debit) final_amt
      FROM
        (
          SELECT
              accountno,
              trandate,
              tranid,
              trantype,
              tranamount,
              tranamount_sign,
              trantype_calc,
              amt,
              NVL
              ( MAX
                (   CASE
                      WHEN t.trantype_calc = 'C' THEN
                        t.trandate
                    END
                )
                OVER(PARTITION BY t.accountno ORDER BY t.trandate ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW),
                MIN
                (   CASE
                      WHEN t.trantype_calc = 'C' THEN
                        t.trandate
                    END
                )
                OVER(PARTITION BY t.accountno ORDER BY t.trandate ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING)
              ) credit_date_for_debit
          FROM
              first_pass t
          WHERE
              amt != 0
        )
    )
  WHERE
    trantype_calc != 'D'
  )
  SELECT
    accountno,
    trandate,
    tranid,
    trantype,
    tranamount,
    tranamount_sign,
    trantype_calc,
    final_amt,
    credit_date_for_debit
  FROM
    (
      SELECT
        accountno,
        trandate,
        tranid,
        trantype,
        tranamount,
        tranamount_sign,
        trantype_calc,
        credit_date_for_debit,
        SUM(amt) OVER(PARTITION BY accountno, credit_date_for_debit) final_amt
      FROM
        (
          SELECT
              accountno,
              trandate,
              tranid,
              trantype,
              tranamount,
              tranamount_sign,
              trantype_calc,
              amt,
              NVL
              ( MAX
                (   CASE
                      WHEN t.trantype_calc = 'C' THEN
                        t.trandate
                    END
                )
                OVER(PARTITION BY t.accountno ORDER BY t.trandate ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW),
                MIN
                (   CASE
                      WHEN t.trantype_calc = 'C' THEN
                        t.trandate
                    END
                )
                OVER(PARTITION BY t.accountno ORDER BY t.trandate ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING)
              ) credit_date_for_debit
          FROM
              second_pass t
          WHERE
              amt != 0
        )
    )
  WHERE
    trantype_calc != 'D'
  

  Published by: Bravid on June 30, 2011 13:29

• Removes the table causing a lot of disk reads

  Until recently that we hadn't made many deletions on one of our large tables in the comic book. After a recent project has been implemented, system performance has gone downhill a bit. Research in one of the top offenders through v$ sql, we find this:
  
  REMOVE IRQ INSPECTION_REQUEST WHERE WORK_ORDER_SEQ =: B1 AND SEQUENCE_ID IN (SELECT SEQUENCE_ID FROM (SELECT SEQUENCE_ID, CHAR_VALUE FROM INSPECTION_REQUEST_CHAR WHERE WORK_ORDER_SEQ =: B1) X WHERE THE CHAR_VALUE IS NULL).
  
  Here are some stats I see in table v$ sql:
  
  Performances: 4
  Analyze the calls: 4
  Disk reads: 565457
  Gets the buffer: 634626
  Time CPU: 69280000
  Elapsed time: 290015297
  
  If I read this correctly 100 000 disk reads are performed on average whenever this statement is executed. The situation that I am is that the table we are trying to remove from has not been analyzed in almost 2 years and many of the indexes on the table have not been analysed in more than a year. Is my problem here something to do with the fact that this analysis has not been done or is there something else, I'm missing?
  
  We checked the SQL to use the correct index and it is set to perform at its best. We have also tried to run this in our dev environment, and we have the same problem with the slow delete. We even watched the rowid for a row we try to delete and tried to delete by the rowid and the DB is still thousands of readings of the disk to perform this deletion. Our dev table and all the clues have been analyzed recently (last month or almost).
  
  So maybe it takes away the possibility that the absence of analysis of the tables and indices of production contributing to the issue. At this point, I am at a loss. Here is the statistical information for this table in the production.
  
  Parameter, value
  Size in MB, 20464.00
  Numbers Extents, 1279
  Size in bytes, 21458059264
  
  TABLE_NAME, INSPECTION_REQUEST
  NOM_TABLESPACE, DATA_LARGE_2
  CLUSTER_NAME,
  IOT_NAME,
  PCT_FREE, 10
  PCT_USED,
  INI_TRANS, 1
  MAX_TRANS, 255
  INITIAL_EXTENT, 1048576000
  NEXT_EXTENT, 16777216
  MIN_EXTENTS, 1
  MAX_EXTENTS, 2147483645
  PCT_INCREASE, 0
  FREELISTS,
  FREELIST_GROUPS,
  LOGGING, YES
  BACKED_UP, N
  NUM_ROWS, 18095357
  BLOCKS, 1196456
  EMPTY_BLOCKS, 0
  AVG_SPACE, 0
  CHAIN_CNT, 0
  AVG_ROW_LEN, 485
  AVG_SPACE_FREELIST_BLOCKS, 0
  NUM_FREELIST_BLOCKS, 0
  DEGREE, 1
  CASE 1
  MEMORY CACHE, N
  TABLE_LOCK, ENABLED
  SAMPLE_SIZE, 18095357
  LAST_ANALYZED, 2007-04-01 06:41:24
  PARTITIONED, NO.
  IOT_TYPE,
  TEMPORARY, N
  SECONDARY, N
  NESTED, DON'T
  USER_TABLES, DEFAULT
  ROW_MOVEMENT, DISABLED
  GLOBAL_STATS, YES
  USER_STATS, NO.
  DURATION,
  SKIP_CORRUPT, DISABLED
  SURVEILLANCE, NO.
  CLUSTER_OWNER,
  ADDICTIONS, DISABILITIES
  COMPRESSION DISABLED

  user9539428 wrote:

  delete from inspection_request where sequence_id = 9911147198;

  SEQUENCE_ID is the primary key on the table INSPECTION_REQUEST. This only delete statement performs 7 000 disk reads. Is this normal? We have this problem even if it is disable triggers that would fire following this statement.

  To everyone who looks at the thread, the version of db, on that we are is 9.2.0.8.

  If you have verified that all triggers are actually disabled on the table, there are a few potential candidates that could cause this large amount of activity during the removal of a single line:

  * Enabled foreign keys referencing this table
  * Maintenance of Index, your index finger on the table could be degenerate and could benefit from an operation of "merge".
  * Bugs in SAMS if you use a tablespace locally managed with automatic management of the space for indexes

  You can follow this thread that might have similar problems:

  Ellapsed time too tkprof output

  Try to run the simple removal using SQL trace enabled (Event 10046) scopes as described in the above thread. After the release of "tkprof" of the trace file generated here, as described in the following thread: [when your query takes too long | http://forums.oracle.com/forums/thread.jspa?threadID=501834]

  Kind regards
  Randolf

  Oracle related blog stuff:
  http://Oracle-Randolf.blogspot.com/

  SQLTools ++ for Oracle (Open source Oracle GUI for Windows):
  http://www.sqltools-plusplus.org:7676 /.
  http://sourceforge.NET/projects/SQLT-pp/

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  If you use Pages ' 09 on Yosemite or later, the menu share: send by mail-outs are more functional - the price of the older software confronted by changes in operating system.

  For Pages 5.5 and later versions, the loss of the action: send a copy: submenu mail item is caused by a corrupted launch services database.

  Exit Pages and then open the Terminal (Launchpad: other: Terminal). this Apple article, triple - click on the scrolling text to select it, copy it, click on in the Terminal, and then paste. If the command does not run automatically, press return. There will be no end message, other than a new Terminal prompt. Leaving the Terminal.

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  Hello team iTunes,

  I just encountered this problem from my bank account of Commonwealth, found that my funds deducted $1 by iTunes. As far as I remember that I have not made any purchase or a payment account iTunes. Could you please check it and let me know as soon as POSSIBLE? I have attached my bank details on this subject. If you would like more information please do not hesitate to let me know.

  Kind regards

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  We are fellow users on these forums, no Support of iTunes or Apple, we can not check anything on your account.

  But based on the amount, it is likely to be a temporary store maintain charge (you add/change payment on your account details?), which the issuer of your card should automatically delete in a few days or more: on the payment card's authorization in the iTunes Store - Apple Support

• Illegal deductions from my account

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  Don't you say no service at the top?

• Since the upgrade to Sierra MediaLibraryService is causing a memory leak

  Hello.

  I upgraded to Sierra, since as soon as Itunes is launched, the com.apple.medialibraryservice is originally a large memory leak, it keeps in ram more until she takes all (16 GB) and significantly slows down the computer.

  I tried to reset the nvram and smc memory, doesn't change anything.

  Does anyone have an idea on what is causing this leak and is there a solution?

  Yes, I noticed this also. After that I opened iTunes, it's just a matter of time before all the memory gets used up and all departure is wobbly. In particular, bluetooth really gets bug after a certain time, and as soon as I quit iTunes, that's fine.

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  Hello

  I noticed a problem with macOS Sierra running on a Mid 2015 15 "MacBook Pro with the retina display. Sometimes when I press F3 to access presentation and my several computers desktop computer freezes and goes back to the login screen.

  When I log in, it's like I started a new session and the apps I had open start back once again, but with their wiped sessions. This happens to me about 3 times in a day's work, most of the time that exposed works very well. Very strange!

  Did anyone else encounter this problem at all?

  Hi there, stvwlkr!

  Thank you for joining the communities Support from Apple! Looks like you are having problems with the Mission control. I know how important it is to make sure that it works correctly. What you might want to try is then a specific restart. Read this article for trying safe mode if your Mac does not end commissioning. Although this article is about the computer does not start correctly, it can also perform repairs and stop startup items that can cause problems.

  Another option you can try is in this article: How to test a problem in another user on your Mac account. This will allow you to check to see if the problem is specific to the user or the system-wide.

  See you soon!

• iOS default keyboard causes Apps to the freeze on more than 7

  The software keyboard appears to cause random app freezes. It's the APPLE keyboard. The gel seems to occur more frequently in the predictive text or AutoCorrect scenarios. It also occurs when you move the selector text. In addition, the same application / combinations of words seem to trigger the gel several times. More trigger-happy is hashtags in facebook.  In addition, type point 4 below, Frost occurred during after erasing an accidental space after the word "effective" here is what I tried:

  1: turn off predictive text.

  2: more backup on my 6s and the problem was not persistent.

  3: reset and recovered my newest 7s and the problem was persistent.

  4: write notes in Evernote and sticking them in the fields of text on other applications. Of workaround prevents me from losing the entered text before, but does not freeze.

  I have a very similar problem.  It is reproducible even after power off or hard reset (power and set "home" button).

  For example, I found today that it happened all the time when I tried to type "Otley" in a text message.  The keyboard froze as soon as that word was typed.  Normal service has resumed after I close the application.

  I tried the option Dictionary reset without any benefit.

  I'm on an iPhone SE with 10.5.2

• Update of security 2016-001 cause major accident

  I just updated the 2016-001 (Sep 02/16) security update on El Capitan v10.11.6 and it has caused a major system failure, twice.

  All applications are unusable, cannot load system preferences, constantly get "led unexpected resignations" error windows pop up that won't go away.   It wont let me report it to Apple and ignore just made another appear.

  First time I started to the Cmd - R system recovery and reloaded OS - X and spent a few hours fixing all the links of the app, then reloaded the updated security after several own boots and's done it exactly the same again.

  Having just now booted to safe mode and empty the contents of/Users/yourname/Library/Caches in the trash, but it made no difference.  Have a time machine backup of it is 6 weeks, but not yet used.

  Seems that I'm not alone... maybe Apple was too fast it rush out before the big event in next weeks...

  Trash content of/private/var/folders/and restart.