Deploy the mapping of sql loader

Similar Questions

• Can I use function defined by the user in the control file Sql Loader?

  Hi Master,

  Can I use fuction user-defined in the sql loader control file? Please advise... !!

  If you can provide an example... It's very kind of you.

  Concerning

  AR

  Here are a few examples that should give you clues: Sql loader

  I seriously wonder if why you use the century previous SQL * Loader instead of a external table:

  ORACLE-BASE - external Tables: querying data from flat files in Oracle

  
  

• Cannot deploy the mapping which is validated fine-problem when debugging

  Hi all
  
  
  I have a complex with almost thirty tables involved mapping.
  I created a mapping with the step by step process of t1 Join t2, t2 join t3... t29 join t30
  Mapping looks very good and has been validated successfully.
  When I try to deploy the same he throws me the warnings below...
  
  
  
  How to solve this problem?
  How to locate the exact problem in pls code region generated during deployment.
  
  Thank you very much!
  SRID
  
  Here is the warning of deployment
  
  
  
  COPY_OF_MAP_PS_2OJAN
  Create
  Warning
  ORA-06550: line 11, column 3:
  PL/SQL: ORA-00923: KEYWORD not found where expected
  COPY_OF_MAP_PS_2OJAN
  Create
  Warning
  ORA-06550: line 11, column 3:
  PL/SQL: SQL statement ignored
  COPY_OF_MAP_PS_2OJAN
  Create
  Warning
  ORA-06550: line 2247, column 3
  PL/SQL: ORA-00923: KEYWORD not found where expected
  COPY_OF_MAP_PS_2OJAN
  Create
  Warning
  ORA-06550: line 2247, column 3:
  PL/SQL: SQL statement ignored
  COPY_OF_MAP_PS_2OJAN
  Create
  Warning
  ORA-06550: line 4738, column 7:
  PL/SQL: ORA-00923: KEYWORD not found where expected
  COPY_OF_MAP_PS_2OJAN
  Create
  Warning
  ORA-06550: line 4738, column 7:
  PL/SQL: SQL statement ignored
  
  
  Summary of the offer
  Update: 2009-01-21 07:38:57.0 job final status: completed WARNING processed job count: 1 number of job errors: 0 Job Alert Count: 6
  
  
  
  
  My mapping has only 18808 lines when I looked the .pls script generated during deployment (surprisingly... the Debug displays message error is on line 22776)
  
  When trying to debug the mapping below is the debug message
  Analysis of card to debug...
  Retrieving the connection of Control Center information...
  Connecting to the Control Center schematic...
  The character set of the Control Center schema checking...
  Configuration of the sources and targets...
  Card validation...
  Correlated Commit is DISABLED.
  Generate debug package...
  Deployment of debug temp tables...
  Deploying debug package...
  ***********************************************
  Messages of debug code deployment:
  LINE 22776, COLUMN 46:
  PLS-00103: encountered the symbol "B_BN_BNI_66_BN_ORIGI$ 2" when expecting one of the following values:
  
  . (* % & = - +; <>/ at mod is still not rem)
  < an exponent (*) > <>or! = or ~ = > = < = <>and or LIKE2_
  LIKE4_ LIKEC_ between | Member of multiset SUBMULTISET_
  The symbol "." was replaced by "B_BN_BNI_66_BN_ORIGI$ 2" to continue. "
  
  End of messages of debug code deployment
  ***********************************************
  Mapping debugger error:
  oracle.wh.service.sdk.mapping.debugger.WBMappingDebuggerException: DBG1012: Debug deployment errors, can't run debug code.

  Hello

  There is only one version of the software. Whether or not you must license depends on the features you use.

  Generates code in the mapping Editor by using the button "generate".
  In the build results window, select style generation = operating mode and middle = 'Set [PL/SQL] founded.
  Now you must select a group entry or exit of some operator in your mapping.

  The build results window then displays a SQL statement that represents the data that would go in the group you selected.
  Run the SQL directly in your target schema (using sql * plus, sql developer, etc.).
  If the SQL code cannot be run, the problem is in this particular part of the mapping.
  You can try to locate further.

  Good luck
  Carsten.

• On the use of SQL * loader program pl/sql command

  Is it possible to develop a PL/SQL program that calls SQL * Loader (sqlldr userid =...) command?

  We want to package a process that loads data from a text file into a table, and we research it is possible to use SQL * Loader to the data loading process.

  You can launch sqlldr like all other orders of operation. There are several methods of cooking OS command, as

  1. external procedure PL/SQL: CHMOD FROM A PLSQL?

  Johan's blog: how to call PL/SQL kernel32.dll.

  2 Java Stored Procedure: Blog of Johan: using JAVA in PL/SQL - PART - I list files with timestamp , Blog of Johan: using JAVA in PL/SQL - PART - II operating system information obtaining

  3. external PREPROCESSOR Table function: no response on java not call windows in oracle command

  Johan's blog: list uses of disk operating system with external feature of the Oracle PREPROCESSOR Table

  Johan's blog: operating system from the list of files with external feature of the Oracle PREPROCESSOR Table

  4. using DBMS_SCHEDULER,job_type => 'executable' and job_action  => '/bin/sh' (may be)

• LRM-00112: multiple values not allowed for the parameter 'control' - SQL Loader

  Hello
  
  Please can someone help me identify why the below SQL test charger does not work and I get the error in the subject header?
  
  file CTL (load.ctl)
  
  load data
  INFILE 'C:\Documents and Documents\loader\TEST.csv c.
  in the XXCPP table. SQL_LOADER_TEST
  fields ended by ',' optionally surrounded "" "
  (PERSON_ID, EMP_NAME, EMP_NUMBER)
  
  command line prompt
  
  sqlldr thompsos/generate control = log "C Documents\loader\load.ctl and Settings" = "C Documents\loader\load.log and Settings"
  
  I obviously miss a key element of the code, but can't locate?
  
  Thank you very much

  SteveCPP wrote:
  Through my PC which is where I realized the question. I need to save the file on the linux server and run it from there I guess

  Well, either you put the file on the server and execute sql * loader from the server OR you place the file on your local client and run sql * server of your local client (assuming you have locally installed Oracle client software).

  ;)

• Cannot deploy the mapping of model code of CDC in OWB 11 GR 2!

  Hi, I have just created a mapping model code of CDC and tried to deployed to the control center. But there is an error like below:
  
  VLD-0006: SEC-10017: you have no privilege of COMPILATION (generate and validate) on the subject: ICT_SQL_TO_SQL_APPEND
  
  How to grant privileges? and who (which user)?
  
  Thank you.

  It looks like only the owner of the workspace initially has privileges on the shared models compilation. If you log on as the owner of the workspace, select the model in the tree, the menu click on view then security, you can either give the privilege to compile ALL or specific users.

  See you soon
  David

• ORA-00923 deployment of mapping

  Hi all
  
  I have a project that contains a match with an expression. This expression uses a function that declares a cursor to extract the values of an intermediate table, as follows:
  
  -initialize variable here
  
  NUMBER OF P_MSISDN;
  V_ROW MAP_PSEUDO_NUMBERS_STG % ROWTYPE;
  
  CURSOR C_MAP_PSEUDO_NUMBERS IS
  SELECT * FROM MAP_PSEUDO_NUMBERS_STG;
  
  -main body
  BEGIN
  OPEN C_MAP_PSEUDO_NUMBERS.
  IF C_MAP_PSEUDO_NUMBERS % ISOPEN THEN
  LOOP
  EXTRACT THE C_MAP_PSEUDO_NUMBERS IN V_ROW;
  WHEN THE OUTPUT C_MAP_PSEUDO_NUMBERS % NOTFOUND;
  IF (INSTR (TO_CHAR (P_MSISDN), V_ROW. PSEUDO_NUMBER_ID) = 1) THEN
  RETURN 4; -Number of nickname
  END IF;
  END LOOP;
  RETURNS A NULL VALUE.
  END IF;
  
  EXCEPTION
  WHILE OTHERS THEN
  NULL; -Enter any code exception here
  RETURNS A NULL VALUE.
  END;
  
  The mapping expression operator uses this function as follows:
  
  IF 'PK_PRJ_LOAD '. «LOAD_ALL_PSEUDO_NUMBERS «(INGRP1.» MSISDN) <>NULL THEN
  'PK_PRJ_LOAD '. «LOAD_ALL_PSEUDO_NUMBERS «(INGRP1.» MSISDN)
  ON THE OTHER
  CASE
  WHEN (INGRP1. PAYMENTTYPE IS NULL) THEN 0 - unknown
  WHEN (INGRP1. PAYMENTTYPE = 'C') THEN 1 - postpaid
  WHEN (INGRP1. PAYMENTTYPE = 'P') THEN 2 - prepaid
  WHEN (INGRP1. PAYMENTTYPE = 'H') THEN 3 - hybrid
  OTHERWISE 0 - Unknown
  END
  
  Where 'PK_PRJ_LOAD '. «LOAD_ALL_PSEUDO_NUMBERS «(INGRP1.» MSISDN) is the above mentioned function.
  
  The sql query is very good, and when I run the script in SQL developer, it works ok. However, when I try to deploy the mapping that uses the function, I get this error:
  
  PL/SQL: ORA-00923: KEYWORD not found where expected
  
  I wonder if I can use the sliders in OWB functions, or elsewhere, where is the problem. Any ideas?
  
  Thanks in advance
  G.

  I think the problem is with
  This part

  IF "PK_PRJ_LOAD"."LOAD_ALL_PSEUDO_NUMBERS"(INGRP1.MSISDN) NULL THEN
  "PK_PRJ_LOAD"."LOAD_ALL_PSEUDO_NUMBERS"(INGRP1.MSISDN)
  ELSE
  CASE
  WHEN (INGRP1.PAYMENTTYPE IS NULL) THEN 0 -- Unknown
  WHEN (INGRP1.PAYMENTTYPE='C') THEN 1 -- Postpaid
  WHEN (INGRP1.PAYMENTTYPE='P') THEN 2 -- Prepaid
  WHEN (INGRP1.PAYMENTTYPE='H') THEN 3 -- Hybrid
  ELSE 0 -- Unknown
  END
  

  instead of 'if' (I never tried 'if' in the expression) try using the avd CASE first try with a simple... as

  Case when "PK_PRJ_LOAD"."LOAD_ALL_PSEUDO_NUMBERS"(INGRP1.MSISDN) IS NULL  THEN
  1
  else  2
  end
  

  and check if it works...

  See you soon
  Katia

  Published by: Katia on October 13, 2009 07:56

• Name of dynamic INFILE SQL loader

  Hi all

  I use oracle 10g on windows server.

  I have a log on a remote server. each line in the log file is as below

  LogIN Mar 02/09/2014 10:10:48 ss18 N419FS40 1

  I create a table for that as below;

  Create table free_pc (log_in varchar2(10),log_day varchar2(10),log_date date,log_time date,log_user varchar2(30),log_Lab varchar2(30),log_pc varchar2(30), log_status char(1));
  

  I have two problems;

  1 N419FS40, the N419 is the name of a student in the lab, while FS40 is the name of the computer in this laboratory. I want only the first four characters to be inserted into the column of Log_lab and the rest of characters iin Log_pc column. my control file is less than

  DOWNLOAD THE DATA

  INFILE '\\remote_location\login02_09_14.txt '.

  ADD

  IN THE TABLE free_pc

  FIELDS FINISHED WITH A WHITE SPACE

  (log_in,

  log_day,

  log_date DATE "DD/MM/YYYY",

  log_time DATE "HH24 MI SS."

  LOG_USER,

  log_Lab,

  log_PC,

  log_status

  )

  How to do this?

  2. the log file is generated on the server, every day with a different name, he cancatenate the current date with Word LOGIN, for example login02_09_14.txt, login03_09_14.txt and login04_09_14 etc. in my INFILE tag, how can I put the name, so that it automatically take the name of the remote location?

  Thank you.

  Kind regards.

  1. you can use the SUBSTR function to separate the two values.  You put the fields in the control file in the same order in the data file, with all the columns that are formulated from data in other areas at the end.

  2. There are different ways to do this.  The file name can be in the control file or the SQL * Loader command line.  You can create either using SQL/SQL * Plus or operating system commands.  I tend to prefer change just the line of SQL * Loader command line, instead of the entire control file.  I prefer to do this in a SQL file instead of a file breaks Windows or * ix shell script or something, so that it is independent of the operating system.

  In addition, it is best to store all of your day, date and time in a column, then you can use to_char to display it as you want, in a column, or two or three.

  Please see the example below, in which I have shown above.

  Scott@ORCL >-data file you provided with the name changed to include today's date:

  Scott@ORCL > HOST TYPE 'c:\remote_location\login27_04_15.txt '.

  Opening on Tuesday, September 2, 2014 ss18 N419FS40 1 10:10:48

  Scott@ORCL >-control file with no infile, fields in the order of the data file, using fill for the unused columns,.

  Scott@ORCL >-with forumulated columns, using boundfiller for filling necessary for columns columns drawn up:

  Scott@ORCL > test.ctl TYPE of HOST

  DOWNLOAD THE DATA

  ADD

  IN THE TABLE free_pc

  FIELDS FINISHED WITH A WHITE SPACE

  TRAILING NULLCOLS

  (log_in,

  log_day FILLING,

  log_date BOUNDFILLER,

  log_time BOUNDFILLER,

  LOG_USER,

  log_Lab ' SUBSTR (: log_lab, 1, 4). "

  log_status,

  log_date_time ' TO_DATE (: log_date |: log_time, "MM/DD / YYYYHH24:MI:SS'"). "

  log_PC ' SUBSTR (: log_lab, 5) ')

  Scott@ORCL >-sql script which now enables to get the data and it concatenates the file name with the path of the directory

  Scott@ORCL >- and loads the data running SQL * Loader of SQL * Plus, using the HOST command:

  Scott@ORCL > test.sql TYPE of HOST

  COLUMN data_file new_value data_file

  SELECT 'c:\remote_location\login ' | TO_CHAR (SYSDATE, 'DD_MM_YY'). ".txt" AS data_file FROM DUAL

  /

  HOST SQLLDR scott/tiger CONTROL = test.ctl DATA = '& data_file' LOG = test.log

  CLEAR COLUMN

  Scott@ORCL >-table which includes the date and time in a column, for the day of the week can be extracted:

  Scott@ORCL > create table free_pc

  2 (log_in varchar2 (10))

  3, date log_date_time

  4, log_user varchar2 (30)

  5, log_Lab varchar2 (30)

  6, log_pc varchar2 (30)

  7, log_status char (1))

  8.

  Table created.

  Scott@ORCL >-load data file sql running running SQL * Loader using the control file:

  Scott@ORCL > test.sql START

  Scott@ORCL > data_file new_value data_file COLUMN

  Scott@ORCL > SELECT 'c:\remote_location\login ' | TO_CHAR (SYSDATE, 'DD_MM_YY'). ".txt" AS data_file FROM DUAL

  2.

  DATA_FILE

  ------------------------------------

  c:\remote_location\login27_04_15.txt

  1 selected line.

  Scott@ORCL > HOST SQLLDR scott/tiger CONTROL = test.ctl DATA = '& data_file' LOG = test.log

  SQL * Loader: release 11.2.0.1.0 - Production on my Apr 27 12:00:53 2015

  Copyright (c) 1982, 2009, Oracle and/or its affiliates.  All rights reserved.

  Commit the point reached - the number of logical records 1

  Scott@ORCL > CLEAR COLUMN

  Scott@ORCL >-results with Date_Time field displayed in the form of day, date and time:

  Scott@ORCL > log_in COLUMN FORMAT A6

  Scott@ORCL > log_day COLUMN FORMAT A7

  Scott@ORCL > log_user COLUMN FORMAT A8

  Scott@ORCL > log_lab COLUMN FORMAT A8

  Scott@ORCL > log_pc COLUMN FORMAT A6

  Scott@ORCL > log_status FORMAT A10 COLUMN

  Scott@ORCL > SELECT log_in,.

  2 TO_CHAR (log_date_time, ' HH24:MI:SS Dy DD-Mon-YYYY ') ' DAY DATE TIME. "

  3 log_user, log_lab, log_pc, log_status

  4 FROM free_pc

  5.

  LOG_IN DAY DATE TIME LOG_USER LOG_LAB LOG_PC LOG_STATUS

  ------ ------------------------------------------ -------- -------- ------ ----------

  LogIN Mar 02 - Sep - 2014 ss18 N419 FS40 1 10:10:48

  1 selected line.

• SQL Loader

  Hello

  I need to load the data into the database using sql loader.

  1. is it possible to change the case of text before you load the data into the table. For example. conversion of names to lowercase before inserting into the database.

  2. why or condition is not in the 'when' control file clause? are there any alternatives that I can use to satisfy conditions similar to the place of use or condition?

  Thanks in advance.

  You can use two condition for your condition... As below...

  WHEN column_2 = '01'

  IN TABLE

  WHEN column_2 = '02'

  IN TABLE

  If you have files on server side, you can use the external table to load the conditional data.

  Thank you

  Ann

• SQL Loader problem

  Hi I'm using version 11.2.0.3.0 version of oracle, and I'm trying to push the file using sql loader utility to my DB table, below is my table structure, two of the column will be constant appears as mentioned below in the table structure. And the File_DATE column must be the combination of two fields (Date and time) of flat file to have the appropriate data column format. I get the error message and not be able to download the data using slot control file, so need help.

  sample data file

  OrderDate, name, size, Records, Date, Time
  06202014, authlogfile06202014.txt, 40777214, 198915, June 21 at 03:51
  06202014, transferfile06202014.txt, 372144, 2255, June 21 at 01:34
  06202014, balancefile06202014.txt, 651075, 10343, June 21 at 03:28

  The table structure

  Create the table file_stats
  (Systemtypecode VARCHAR2 (4000)-this will be a value to hardcode "CBD")
  LETTER Date,
  FILENAME VARCHAR2 (4000).
  Size of the file Number (20.0).
  Noofrecords NUMBER (20.0).
  File_DATE VARCHAR2 (4000).
  CREATED_DATE Date - it will be filled with the value SYSDATE
  );

  Here's my control file

  Options
  (SKIP = 1)
  DOWNLOAD THE DATA
  INFILE 'files.csv '.
  ADD
  IN the file_stats table
  FIELDS TERMINATED BY ', '.
  (Systemtypecode CONSTANT 'CBD',
  LETTER DATE 'MMDDYYYY.
  CHAR FILE NAME,
  Size of the ENTIRE file,
  Noofrecords INTEGER,
  boundfiller TANK file_DATE_DDmon
  , file_DATE ' to_date ('2014':: file_DATE_DDmon:: file_DATE, 'YYYYMON DDHH24:MI').
  , created_date CONSTANT 'sysdate.
  )

  When running under command, all erroneous records on as below

  sqlldr schema1/pwd@db1 control = file_stats.ctl log = file_stats.log file_stats.bad = bad

  ERROR:
  Sheet 1: Rejected - error on the table FILE_STATS, column FILE_DATE.
  ORA-01843: not one month valid

  You must add TRAILING NULLCOLS and use EXTERNAL INTEGER instead of an INTEGER and your file_date column must be of type DATE data.  Please see the demo below with some additional corrections.  Note that since there is no year in the data file for the file_date column, which by default is the current year.  If you want to 2014 so you need to concatenate that and add the date format YYYY.

  Scott@orcl12c > files.csv TYPE of HOST

  OrderDate, name, size, Records, Date, Time

  06202014, authlogfile06202014.txt, 40777214, 198915, June 21 at 03:51

  06202014, transferfile06202014.txt, 372144, 2255, June 21 at 01:34

  06202014, balancefile06202014.txt, 651075, 10343, June 21 at 03:28

  Scott@orcl12c > file_stats.ctl TYPE of HOST

  OPTIONS (SKIP = 1)

  DOWNLOAD THE DATA

  INFILE 'files.csv '.

  ADD IN THE TABLE file_stats

  FIELDS TERMINATED BY ',' TRAILING NULLCOLS

  (systemtypecode CONSTANT "CBD"

  , odate DATE 'MMDDYYYY '.

  filename CHAR

  INTEGER EXTERNAL file size

  noofrecords INTEGER EXTERNAL

  file_date_ddmon BOUNDFILLER TANK

  , file_date DATE 'My DDHH24:MI' ': file_date_ddmon |: file_date '

  , created_date 'SYSDATE.

  )

  Scott@orcl12c > file_stats CREATE TABLE

  2 (systemtypecode VARCHAR2 (14),)

  3 DATE odate,.

  4 name of file VARCHAR2 (24).

  size of the file NUMBER 5 (20.0).

  6 noofrecords NUMBER (20.0).

  7 file_date DATE,

  8 created_date DATE)

  9.

  Table created.

  Scott@orcl12c > HOST SQLLDR scott/tiger CONTROL = file_stats.ctl LOG = file_stats.log file_stats.bad = BAD

  SQL * Loader: release 12.1.0.1.0 - Production on Thu Feb 5 15:26:49 2015

  Copyright (c) 1982, 2013, Oracle and/or its affiliates.  All rights reserved.

  Path used: classics

  Commit the point reached - the number of logical records 3

  Table FILE_STATS:

  3 rows loaded successfully.

  Check the log file:

  file_stats.log

  For more information on the charge.

  Scott@orcl12c > SELECT * FROM file_stats

  2.

  SYSTEMTYPECODE, KAI NOOFRECORDS FILE_DATE CREATED_DATE FILENAME FILE SIZE

  -------------- --------------- ------------------------ ---------- ----------- --------------- ---------------

  Friday, June 20, 2014 authlogfile06202014.txt 40777214 198915 Sunday 21 June 2015 CBD Thursday, February 5, 2015

  Friday, June 20, 2014 transferfile06202014.txt 372144 2255 Sunday 21 June 2015 CBD Thursday, February 5, 2015

  Friday, June 20, 2014 balancefile06202014.txt 651075 10343 Sunday 21 June 2015 CBD Thursday, February 5, 2015

  3 selected lines.

• SQL loader file path control...

  Hi all
  
  I run the query through sql loader client machine below...
  
  saved query in the file loader.ctl, which I kept it in the path "D:\loader.ctl" below...
  
  options (skip = 1)
  load data
  INFILE 'D:\flat.txt '.
  in the GL_INTERFACE table
  fields ended by ',' optionally surrounded "" "
  * (STATUS, LEDGER_ID, USER_JE_SOURCE_NAME, USER_JE_CATEGORY_NAME, ACCOUNTING_DATE, CURRENCY_CODE, DATE_CREATED, CREATED_BY, *)
  SEGMENT1, SEGMENT2 SEGMENT3, SEGMENT4, SEGMENT5, ACTUAL_FLAG, ENTERED_DR, ENTERED_CR, GROUP_ID)
  
  Now my doubt is, to run the above, I need to run the command in sql loader below...
  
  sqlldr USERID = apps/apps CONTROL = loader.ctl
  
  In the control file, we have given the path to the data file, but * how the command (SQLLDR) identifies the path of the control file. ? *
  
  What I have to give or...?
  
  Is it possible to run the loader program above in the customer's computer? or we have to run only one server...
  
  Please clarify my doubt.
  
  Thank you and best regards,
  Muthu

  Hello

  The preferred method is, if you use oracle apps, then a simultaneous recording of type sql * loader
  the ctl yor file in $/bin. Run the program at the same time to load the data.

  I'm just givng you advice, you search on google, that you will get several ways to do the same things.

  There are many ways such as the use of the external table, UTL_FILE or Shell Script to do the same thing.

  Thank you
  Lenora

• SQL * Loader syntax

  DOWNLOAD THE DATA
  INFILE 'c:\folder\sample.txt '.
  DISCARDFILE 'c:\folder\sample.dis '.
  ADD IN THE TABLE user.tmp_tbl
  FIELDS TERMINATED BY ' ~'
  WHEN (1) = "1"
  (record_type,
  Key_ID,
  Key3,
  Key4
  )
  Add THE tmp_tbl2 TABLE
  FIELDS TERMINATED BY ' ~'
  WHEN (1) = "2"
  (rec_type,
  Key_ID,
  Key3,
  Key4,
  region_cd
  )
  
  Get the following error
  SQL * LOADER - 350:SYNTAX IN LINE 6.
  WAITING FOR "(" FIND KEYWORD WHEN
  WHEN (1) = "1"
  ^

  It looks good to me, but it might be the location of your clause 'fields terminated by '.

  See examples here:

  http://www.orafaq.com/Forum/t/63674/0/

  DOWNLOAD THE DATA
  ADD
  IN THE LOGO OF THE TABLE
  WHEN (01) = '1'
  FIELDS TERMINATED BY ' |'
  EVENTUALLY FRAMED BY ' '
  TRAILING NULLCOLS
  (
  INDICATOR FILLING position (1).
  LOGO_CD,
  LOGO_NM,
  LOGO_DESC_TX "decode(:LOGO_DESC_TX,,:LOGO_NM,:LOGO_NM)"
  LOGO_EFF_DT 'trunc (sysdate). "
  LOGO_TRMNT_DT FILLING,
  CRE_USR_ID "USER."
  CRE_TS SYSDATE,
  UPDT_USR_ID "USER."
  UPDT_TS SYSDATE
  )
  IN THE LTR_LOGO TABLE
  WHEN (01) = '2'
  FIELDS TERMINATED BY ' |'
  EVENTUALLY FRAMED BY ' '
  TRAILING NULLCOLS
  (
  FILLING of INDICATOR1 position (1).
  ACCT_ORG_CD "TO_NUMBER(:ACCT_ORG_CD)"
  LOGO_CD,
  LTR_LOGO_EFF_DT 'trunc (sysdate). "
  LTR_LOGO_TRMNT_DT FILLING,
  CRE_USR_ID "USER."
  CRE_TS SYSDATE,
  UPDT_USR_ID "USER."
  UPDT_TS SYSDATE
  )

• Commit point in SQL loader

  Hello
  Using Sqlloader I'm loading data in the table. In the control file, I mentioned after option to commit all rows of 1024.
  
  
  But when actually SQLloader loads the data I'm getting exit follwowing IE its commit all 330 rows.
  
  OPTIONS (LINES = 1024)
  DOWNLOAD THE DATA
  INFILE '$infile '.
  BADFILE "$badfile."
  ADD
  IN the TABLE employee
  .....
  .....
  
  
  SQL * Loader: Release 10.2.0.4.0 - Production on June 22 at 06:13:23 Mar 2010
  
  Copyright (c) 1982, 2007, Oracle. All rights reserved.
  
  Commit the point reached - the number of logical records 330
  Commit the point reached - the number of logical records 660
  Commit the point reached - the number of logical records 990
  
  Can someone help me on this?
  
  Thank you
  Khaldi

  You may need to increase the bindsize.

  Read the reference manual SQL Loader for the implications of the enlargement of these values.

• SQL LOADER vs INSTRUCTION INSERT

  1. What is the difference between Sql loader and insert statement?
  
  2. that will be more effective and better performance?
  
  3 Please give an example and explain.
  
  Please someone share their thoughts...
  
  Thanks in advance

  When you use sql loader you will use a direct path load i.e. you will be set up above the high tide and you will be bypassing undo on the table and it will insert in the index more efficiently.

  When you use insert / * + append * / select then you will be clooning the sqlloader but only if you do not have integrity constraint or insert triggers into your table.

  SQL Loder will be the direct loading path even if you have triggers and referential intergrity

  You see while sql loader seems to be more effective and not in function of the referential integrity or triggers to use a direct path load

  Concerning

  Mohamed Houri

• SQL Loader control file (.ctl) given in table

  Hello
  
  I have a table 'region' in my schema called dss.
  

  SQL > desc region
  R_REGIONKEY
  R_NAME
  R_COMMENT

  I want to LOAD the data into this table of the region in a file called "region.tbl" located at d:\tpch\region.tbl, using a CONTROL file that is also on the the same place is to say d:\tpch\region.ctl.
  
  Region.tbl file contains few records. Recording of a SAMPLE of region.tbl is as follows:
  
  * 1 | AMERICA | HS ironic use, same request. s | *
  
  Region.CTL file contains the following lines to load data using sql loader:
  
  DOWNLOAD THE DATA
  INFILE'd:\tpch\region.tbl'
  IN THE REGION OF THE TABLE
  FIELDS TERMINATED BY ' |'
  * (R_REGIONKEY, R_NAME, R_COMMENT) *.
  
  so I go to the command prompt, navigate to the location of the above files and run the command:
  

  D:\TPCH > sqlldr control = region.ctl dss/dss = userid

  and get the following error:
  
  SQL * Loader-128: unable to start session
  ORA-01017: name of user and password invalid. connection refused
  
  I have the same table under the "system" user creation, but I get a different error with this that is:
  
  SQL * Loader-941: error when the table REGION describe statement
  ORA-04043: object REGION does not exist
  
  Using Oracle 11 g on my Windows XP.
  
  I'll appreciate the valuable suggestion.
  
  Thank you very much.
  
  Best regards
  Kam

  You can connect with dss/dss? For example, what

  sqlplus dss/dss
  

  If no, and you are sure that the name of username/password combination is correct, have you checked things like $ORACLE_SID - i.e. it points to the right database?