Describe Popup on objects for other schemas

Similar Questions

• What are the implications of the definition of the db_4k_cache_size and db_16k_cache_size for other schemas?

  Hi all

  I have a node Oracle RAC 5 system. It's pretty tough, RAM, cpu, etc. Running on RHEL5 64 bit. I have a block size of 8K.

  I have a COTS application that is wanting to pay 128 M for 4K and 16K cache sizes...

  I have never before worked with databases of the combination block size... setting of these parameters, are there any impacts or implications on I need to study, especially considering that there are a number of other schemes for many other applications that already use this system of database?

  Links for reading and suggestions would be helpful.

  I found this: http://docs.oracle.com/cd/B12037_01/server.101/b10755/initparams035.htm but it is hardly useful to know what impact this could have other applications that use the database.

  Thank you in advance,

  Cayenne

  I have never before worked with databases of the combination block size... setting of these parameters, are there any impacts or implications on I need to study, especially considering that there are a number of other schemes for many other applications that already use this system of database?

  .

  My understanding is that objects of tablespaces with different block sizes will succeed only if you have already configured the db_cache_size and at least one

  DB_nK_CACHE_SIZEinitialization parameter.  As jgarry says there would be performance-related.  Oracle documentation "large cache sizes usually reduces the number of disk reads and writes. However, a large cache can take too much memory and induce memory paging or Exchange"

• How to operate all invalid objects for a schema?

  Dear team,
  
  There is a lot of invalid objects in my diagram.
  Is it possible to compile/Run the invalid objects to the schema?
  
  Kind regards
  Augustine

  Yes, there is: DBMS_UTILITY.COMPILE_SCHEMA

  HTH!

• With the help of the TYPE operator % on objects in another schema

  Suppose I have the following architecture:
  * A schema called APP_SCHEMA (for example), which contains all applications level PL/SQL packages that contain a business application logic
  * A data schema, called DATA_SCHEMA (for example), that contains the schema objects that are referenced by the PL/SQL in APP_SCHEMA
  Suppose I create a simple procedure like this in the APP_SCHEMA:

  CREATE OR REPLACE PROCEDURE test_proc(pVar IN DATA_SCHEMA.TABLENAME.TABLECOLUMN%TYPE)
  AS
  BEGIN
       DBMS_OUTPUT.PUT_LINE(pVar);
  END;
  /{code}
  For this simplified procedure I get the following error:
  {code:java}1/25     PLS-00201: identifier 'DATA_SCHEMA.TABLENAME' must be declared{code}So, my basic question is how do I use the %TYPE operator to reference objects in another schema?
  
  Other Pertinent info:
  * Windows Server 2003
  * Oracle Database 10gR2 (10.2.0.3)
  Thanks!                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                

  Its almost certainly a problem of privileges.

  I can create a test procedure based on the same script that compiles successfully.

  Verify that your user can access the table. Might need to have to grant access directly, rather than in a role.

  Published by: Keith Jamieson on August 25, 2008 17:51
  typo fixed

• Cannot start the services of ICF error 1079: the account specified for this service is different from the account specified for other services running in the same process

  Original title: I'm trying to start the Windows Firewall.

  I'm trying to start Windows Firewall services, (administrative control / tools/services/windowsfirewall Panel) and error 1079: the account specified for this service is different from the account specified for other services running in the same process, rises.  What should I do?

  Hello

  ·         You will remember to do recent changes on the computer before this problem?

  ·         Logged in as an administrator on the computer?

  I suggest you follow the steps mentioned below:

  Method 1:

  Follow the steps described in the following link and check if the problem persists:

  http://support.Microsoft.com/kb/2478117

  Method 2:

  If the previous step fails, run the System File Checker tool to troubleshoot missing or corrupted, system files proceed to the following link:

  http://support.Microsoft.com/kb/929833

  Method 3:

  If the previous step fails, set the center of security and its dependencies services to run under the Local Service account. Follow these steps:

  a. Click Start, type services.msc and press to enter.

  b. double-click Security Center, click on tab log.

  c. Select "this account", click on the Browse button, type Local Service and click ok.

  Type the password and confirm the password and click ok.

• expdp of objects in a schema

  Hi all

  Can we use expdp to export objects in a scheme starting with a particular letter.

  for example, I would like to export objects from a diagram of the test, the names of objects from S %

  Thank you

  You can play around something as

  "expdp scott/tiger include = table:" % like'FOO ".

  Kind regards

  --

  Bertrand

• Not covered by the course objectives for VCP5

  Hello world

  Followed the course of the ICM this week and although it is very broad, I am aware that the course only covers almost 80% of the objectives of the review for VCP5-VTC

  Now, I'm trying to highlight of the bits on the action plan that I need to read up on the last 20%.

  Can someone with experience advise all the extra bits to make sure I don't miss anything.

  Paranoid I'll miss something so that references to the course book for the action plan.

  Any other advice would be appreciated.

  Thank you

  Karl

  You will do it by Karl,

  Here is a link to VMware VMwarehands-we-labs. Its a free laboratory offered by VMware for CIM. You will have the same scenarios that was given in the course of the ICM. You can practice and learn.

  If you feel its not enough you can always build your own lab helping not only for this but for other certifications advances

  Review the allocation of points by choosing the right answer if you found it useful

• using a style object for "mouse"?

  I use 8 Captivate:

  Anyone know if it is possible to create an object style to the "mouse". I want to avoid having to manually change on each slide. I try to use the blue click circle of mouse.

  Is it possible to create a style as if it were possible for other objects?

  Or, is it possible to change the default style?

  Thanks a bunch

  Sanna

  Mouse Properties Panel has a menu top right corner that lets you apply a

  Replace all items of this type. The icon has 4 horizontal lines to open

  menu. Try it?

• JDeveloper do not establish association for HR schema

  Hi, I just started learning JDeveloper and Oracle and I'm trying to follow this tutorial:

  http://docs.Oracle.com/CD/E37547_01/tutorials/tut_rich_app/tut_rich_app.html

  I got to step 19, and everything was working fine until I tried to run the AppModule. I get not all associations (for example. I do not have EmpDeptFkLink1 )

  All I have is

  AppModule

  -DepartmentsView1

  -EmployeesView1

  -JobsView1

  In my view, that ADF should automatically create associations for me based on the foreign keys of the tables, I checked to work properly.

  I looked at this thread https://community.oracle.com/thread/2411302

  but I don't think it applies to me I chose the HR schema when you move through the wizard.

  Can anyone suggest what the problem? I really want to learn this.

  Thanks for your reply. I understand that you wanted to say but as I am a total beginner even what is hard for me (tried and did not turn to the right).

  After a day scouring the Internet I thought about it so I'll post it here for others (and I'm surprised that nobody publishes this problem, happens by default when you install oracle 12 c!).

  Basically, your PDB is RESTRICTED the first time install you it. Trying to grant the user SESSION is RESTRICTED for some reason any does not have full access. Tables appear, but do not have points of view.

  To verify if your PDB (remember not CBD) is restricted or not (and make sure that you are logged on as user SYS):

  SQL > show files PDB;

  CON_ID CON_NAME RESTRICTED OPENING MODE

  ---------- ------------------------------ ---------- ----------

  2 SEEDS OF $ PDB READ ONLY NO.

  3 PDBTVTS READ WRITE YES

  As you can see, mine was. We could think about rating is a simple command that forums will tell you:

  SQL > DISABLE THE ALTER SESSION SYSTEM RESTRICTED;

  DISABLE RESTRICTED SESSION ALTER SYSTEM

  *

  ERROR on line 1:

  ORA-65144: ALTER SYSTEM DISABLE RESTRICTED SESSION is not allowed

  Took me hours before I realized there's no point to find a way to get this command works. Then I saw that you can start an instance using the RESTRICTED, then why not start up * without * this mode.

  To put it simply, stop the instance and start it again.

  SQL > shutdown immediate

  Connectable to closed database.

  (don't care which change the order now while the instance is closed.) I tried, still did not haha)

  SQL > startup

  Connectable to open database.

  SQL > show PDB files

  CON_ID CON_NAME RESTRICTED OPENING MODE

  ---------- ------------------------------ ---------- ----------

  2 SEEDS OF $ PDB READ ONLY NO.

  PDBTVTS READING ENTRY NO. 3

  And now it works! My God, so difficult just start learning with a tutorial. Basically the tutorial currently works perfectly. Auto-created associations.

• How to choose the object that others will line up to?

  Hi I'm attacking with Illustrator, having been familiar with CorelDRAW X 5, and some of the fundamental things in artificial intelligence are just weird!

  A common operation is to have a bunch of stuff I want to align, where I spent the time of positioning on the particular object so I want that everything stays aligned him to this object. I can do it in artificial intelligence?

  For example, I have two rectangles A and B, separated horizontally with a greater than B. I want that the upper edge of the B to align to the top edge. I select A, then B and align top. It works - B moves upward.

  However if I want albums edge to align the top edge of the B, it does not work how I expect. B always moves. It doesn't matter if I choose first or second, B is the one who moves, when A is above B.

  It's frustrating when I have a lot of objects that are carefully aligned, and I want to align a new object with them. What often happens is that all of my objects placed move to align with the Unplaced object, so I spend a lot of time.

  Y at - it a simple way to choose the object that others in the choice of align on? In CorelDraw, it's the last selected object that determines how many others will be moved.

  Thank you

  Rob

  Select all the objects you want to align, and then click again on the object of the selection you want that all the others will match (object key).

  the key of the object will appear thicker than others.

• Reference to the other schema

  Hello
  
  I want to model the following situation in SQLD DM:
  -Diagram 2
  -1 schema, I define a view
  -of the other schema I want to refer to this point of view in a view
  
  Issues related to the:
  -Create each drawing as a drawing or a relational model in a drawing?
  -How can I refer to the other schema view in the query designer?
  
  SQLD DM version 3.3.0.734
  
  Thanks in advance,
  
  Joop

  Hi Joop,

  Create each drawing as a drawing or a relational model in a drawing?

  As a relationship in a drawing model.

  How can I refer to the other schema view in the query designer

  You have a set a display scheme that you create. If the objects used in the view definition belong to another scheme they are included with the schema name in a generated select statement. By default the objects in the same schema (such as the view) are not prefixed with schema name - if you want that the schema name to include, then check the box 'Schema to include in the query name' on the view dialog box.

  Philippe

• The list of roles with subsidies for specified schemas...

  How can I find recipients roles for each schema in my list? For example, I have about 5 patterns that each have a role of admin and user assigned to them. What I would like is a table which shows who is assigned to the roles for each schema.
  
  For example:
  
  USERS OF THE SCHEMA ROLE
  ======= =============== ==========================
  
  FIGURE 1 ADMIN_ROLE_SCHEMA_1 USER_1 USER_2 USER_3 USER_4
  
  USER_ROLE_SCHEMA_1 USER_5 USER_6 USER_7 USER_8...
  ......... .......... .......... ..........
  USER_45 USER_46 USER_47 USER 48
  
  
  FIGURE 2 ADMIN_ROLE_SCHEMA_2 USER_1 USER_2 USER_3 USER_4
  
  USER_ROLE_SCHEMA_2 USER_5 USER_6 USER_7 USER_8...
  ......... .......... .......... ..........
  USER_45 USER_46 USER_47 USER 48
  
  
  FIGURE 1 ADMIN_ROLE_SCHEMA_3 USER_1 USER_2 USER_3 USER_4
  
  USER_ROLE_SCHEMA_3 USER_5 USER_6 USER_7 USER_8...
  ......... .......... .......... ..........
  USER_45 USER_46 USER_47 USER 48
  
  
  (SORRY, I can't seem to get this to format correctly! This should be displayed in three columns, but is all stuck together when I post?)
  Thank you
  
  KSL
  
  Published by: leonhardtk on Sep 17, 2012 15:35
  
  Published by: leonhardtk on Sep 17, 2012 15:35
  
  Published by: leonhardtk on Sep 17, 2012 15:37

  Hello

  leonhardtk wrote:
  Thanks for the help; I can't quite understand your example runs... I'm running into a TOAD Editor window.

  I get an error: ORA-00923: KEYWORD not found or provided. In your example, I see a few extraneous apostrophes (second and third online and also in front of the name of the licensor. These are different than single quotes used everywhere else--is that a different symbol?

  I don't see anything like that. I used single quotes ancient Plains. Maybe your browser displays a kind of cute quotes, I used normal, straight single quotes.
  If you get a few other symbols like quote, change them to single quotes. If you get the error, your postal code.

  I just noticed that I initially failed the 2nd single in quote

  ...   OR      granted_role  LIKE ('USER\_ROLE\_%')       ESCAPE '\'
  

  now corrected. However, in your post, it seems that the error occurred earlier, because the quotes in

  ,       SYS_CONNECT_BY_PATH  (grantee, '/')     AS path          -- for debugging
  

  are not read correctly.

  Published by: Frank Kulash, Sep 18, 2012 11:00

• End Insight table list includes other schema Tables (without alias)

  I noticed this problem in the last few editions, including the 3.2.09.30 latest version:
  
  If, say, there are User1 who is the owner of a table named TABLE1 and also a USER2 who is the owner of TABLE2 and granted select access on it to User1.
  
  If I have a spreadsheet where I'm logged on as User1 and I type "Select * tab" and then the list of AutoComplete overview will contain 'TABLE1' both 'TABLE2 '. If I select TABLE2, then it fills the declaration as "select * from TABLE2", that won't work because it lacks the reference of the schema. I expect that TABLE1 to appear in these circumstances.
  
  In other words, the list of tables for completion insight contains the name table form other schemas without a prefixed schema reference. It of basically useless and only serves the background image to the top of the list of seizure semi-automatic insight and give you a false idea of the tables/views/synonyms, which are present in the current schema.
  
  (Note: if I type "select * from USER2.tab" then entry list semi-automatic insight correctly contains "user2.) TABLE2', which is the behavior I expect. "USER2. TABLE2"should be there, but never just"TABLE2")
  
  
  So, is there any configuration option to turn this off, or it's just a bug?
  
  Published by: IvanG, Sep 17, 2012 15:50
  
  Published by: IvanG on 17 sept 2012 16:29, removed reference to this work properly in 3.0.04, which was incorrect.

  Buggy as 14638078; fixed

• ReadOnly user can access the other schema and change them

  Hello everyone,
  
  I created a readonly as this user in oracle 11g r2
  
  SQL > CREATE USER IDENTIFIED BY readonly readonly;
  SQL > GRANT CREATE SESSION, CREATE a SYNONYM to readonly.
  SQL > GRANT SELECT ON SA.vCustomerService TO readonly.
  
  But when I connect to the database and do a select like:
  SQL > SELECT * FROM ACC;
  I get the data in this table, even if I do an update on that table it works.
  
  What I am doing wrong that my readonly user always has full access to the other schema?
  
  Thank you in advance for your help!
  
  Best regards
  GIL GOMES Dany

  Dan_lu wrote:
  Hello everyone,

  I created a readonly as this user in oracle 11g r2

  SQL > CREATE USER IDENTIFIED BY readonly readonly;
  SQL > GRANT CREATE SESSION, CREATE a SYNONYM to readonly.
  SQL > GRANT SELECT ON SA.vCustomerService TO readonly.

  But when I connect to the database and do a select like:
  SQL > SELECT * FROM ACC;
  I get the data in this table, even if I do an update on that table it works.

  Check the permissions for this table - maybe some operations on this table are granted to the publc?

• Data type of the other schema reference

  Hello
  
  I want to reference the data type on the other schema, inv.customer, 1st schema table, 2nd table tran.order.
  
  then, when I declare my package.
  
  
  Procedure p_insertOrder
  (
  p_empid in customer.customerid%type
  p_orderid in tran.order.orderid%type
  );
  
  
  However, it gives me this error message
  
  PLS-00201: identifier 'tran.orde' must be declared.
  
  the following package is located in inv schema. so when I make reference to the customer table, I do not have the diagram for it.
  
  So what is the cause of this?
  
  
  
  ~ vincent.

  what grants do you have enabled on the table?

  Log in as tran or a dba and try:

  grant select on tran.order to inv;
  

  You can also create a public synonym so you don't have to precede the table with the schema name. Beware of the tables of the same name in your current schema if you do it well.