Discovered lines with column names where the cell contains a value

Similar Questions

• Return all column names of the cells that match a value in a single cell

  

  I want to be able to scan all the cells in column 1 in column 3 (there could be several) which belong to the same line and check if they all have a value y (X). If they have no value, I want all columns to display all the names of the matching columns as follows: "column 1, column 2" for Elemento.

  This can be a good start:

  

  B2 = if (counta (C2) > 0, C$ 1, "" ") & IF (COUNTA (D2) > 0', ' & D$ 1," ") & IF (COUNTA (E2) > 0', ' & E$ 1," "") & IF (COUNTA (F2) > 0', '& F$ 1,' ')

  It's shorthand dethrone select cell C2, then type (or copy and paste it here) the formula:

  = IF (counta (C2) > 0, C$ 1, "" ") & IF (COUNTA (D2) > 0', ' & D$ 1," ") & IF (COUNTA (E2) > 0', ' & E$ 1," "") & IF (COUNTA (F2) > 0', '& F$ 1,' ')

  Select cell B2, copy

  Select the cells B2 the bottom of column D, dough

  To add additional columns, you copy the atomic unit:

  & IF (COUNTA (D2) > 0', '& D$ 1,' ')

  and update D2 with the new column and D$ 1 with the new column.

  then... If you add a new column (G, for example) that you want to change it:

  and IF (COUNTA (D2) > 0', '&D$1,' ')

  TO

  and IF (COUNTA (G2) > 0', "&G$1," ")

  and the updated formula would be:

  = IF (counta (C2) > 0, C$ 1, "" ") & IF (COUNTA (D2) > 0', ' & D$ 1," ") & IF (COUNTA (E2) > 0', ' & E$ 1," "") & IF (COUNTA (F2) > 0', ' & F$ 1,"") & IF (COUNTA (G2) > 0', '& G$ 1,' ')

  fill down like before

• DROP table and CREATE with column name and ORA: 00904

  Hello
  I created a table with an attribute date CRTD_ON and two other attributes. Successfully created. I can see the data tab and the window empty data with column names in the header...
  Now, I had to change the name of field attribute date on OPNG_DATE so I don't bother to change, instead, I deleted and created with the name of the column has changed. Then I restart the ddl. Once again managed to create. But this time I am not able to see the data tab or the column headings. And I see the error of the log of the data Publisher ORA-00904: "CRTD_ON": invalid identifier
  Is this a bug?

  There is a current bug where you will get the data if you have a public synonym with the same table name pointing to another table with another structure. Can you confirm that in your environment?

  K.

• I want to get only year sysdate with my name of the defined column. but not able to get it.

  I want to get only year sysdate with my name of the defined column. but not able to get it.

  SQL > select to_char (sysdate, 'yyyy') as 'mahesh tyagi' from dual;

  Mahé

  ----

  2015

  SQL > select to_char (sysdate, 'yy') as 'Manu' from dual;

  my

  --

  15

  So I couldn't do 'Manu' or "mahesh tyagi" as the column name.

  The column name is "mahesh tyagi" is simply displayed it shortened to sqlplus due to the known values in the column length.

  create table year_test select to_char (sysdate, 'yyyy') "mahesh tyagi" double;

  year_test / / DESC

  You can change the way sqlplus displays the header of column with something like

  column "mahesh tyagi" format a15

• Anyway, to remove the column names in the result of the query of SQLPLUS

  Hello
  
  I am using sqlplus to run a script that returns results with the column names.
  
  Anyway is to omit the names of columns in the result of the sqlplus query?
  
  I would like to have only results with their column names in the output.
  
  Thanks in advance!

  Hello

  Maybe your LINES (IZE) is not defined?

  SCOTT>set lines 130
  SCOTT>select status, machine, module
    2    from v$session
    3   where upper(username) = 'SCOTT';
  
  STATUS   MACHINE                                                          MODULE
  -------- ---------------------------------------------------------------- ------------------------------------------------
  INACTIVE PFAE3\VPC4894-03                                                 TOAD 9.7.2.5
  ACTIVE   PFAE3\VPC4894-03                                                 SQL*Plus
  
  2 rows selected.
  
  SCOTT>
  

  As an alternative to the linesize parameter, you can format the columns:

  SCOTT>set lines 80
  SCOTT>col status for a8
  SCOTT>col machine for a30
  SCOTT>col module for a30
  SCOTT>select status, machine, module
    2    from v$session
    3   where upper(username) = 'SCOTT';
  
  STATUS   MACHINE                        MODULE
  -------- ------------------------------ ------------------------------
  INACTIVE PFAE3\VPC4894-03               TOAD 9.7.2.5
  ACTIVE   PFAE3\VPC4894-03               SQL*Plus
  
  2 rows selected.
  
  SCOTT>
  

  Concerning
  Peter

• Display the name of the tag as the column name and the value in the tag as a row of data from the input string.

  Hi Forum members,

  I am looking for a query display the name of the tag as the column name and the value in the tag as a row of data.

  I have to print the values within the tag to a file by choosing the value of the flags. the sequence of the tags will vary each time, as the tag name will change dynamically.

  So here is the example of input data and the expected output. The string in the text column must be separated as the column names and values.

  Input data
  Select 1 as seqno,' < > 0210A 50 4f < / 4f > < 5f20 > TEST CARD 16 < / 5f20 > < 5f2a > < / 5f2a > < 82 > 1 c 00 < / 82 > ' double text

  
  Output:

  Seqno 4f 5f20 5f2a 82
  0210A 50 16 1 00 TEST CARD 1

  Please help me by providing your entries on this.

  We use the version of Oracle 11.2.

  Note: This is not the XML string

  Thank you

  Shree

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  )

  Select d.seqno, x.*

  d the data,

  XMLTable ('/ root')

  by the way xmltransform (xmltype ('': replace (replace (text,'<><>'),)))

  XmlType (q'~http://www.w3.org/1999/XSL/Transform "version ="1.0"> ")

                                                   

                                                     

                                                       

                                                     

                                                   

                                                   

                                                     

                                                       

                                                     

                                                   

  ~'

  )

  )

  path of columns '4f' varchar2 (10) "tag4f."

  path of "5f20' varchar2 (30)"tag5f20. "

  path of '5f2a' varchar2 (10) "tag5f2a."

  path of varchar2 (10) "82" "tag82.

  ) x

  
  

  SEQNO	4f	5f20	5f2a	82
  1	0210A 50	16 TEST CARD	-	1 00
  2	0210A 50	16 TEST CARD	-	1 00
  3	0210A 50	16 TEST CARD	-	1 00
  4	0210A 50	16 TEST CARD	-	1 00

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  ),

  Chopper (seqno, Key, value, String) as

  (select seqno,

  regexp_substr (text,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (Text,'>(.*?))

  regexp_substr (text,'<.+?>. *? ) (.*) $', 1, 1, null, 1). » <>'

  from the data

  Union of all the

  Select seqno,

  regexp_substr (String,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (String,'>(.*?))

  regexp_substr (String,'<.+?>. *? ) (.*) $', 1, 1, null, 1)

  Chopper

  where regexp_substr (string,'<(.*?)>', 1, 1, null, 1) is not null

  )

  Select '4f', seqno, '5f2a', '82', '5f20.

  of (seqno, lower (key) select key, value)

  Chopper

  )

  Pivot (max (value) for key in ('4f' as '4f', '5f20' as '5f20', '5f2a' as '5f2a', "82" as "82"))

  Concerning

  Etbin
  

• Select the column name when the value = something

  Is there a way to select the column name when there is a specific value in it?

  As follows:

  create table (abc123)

  COLUMN1 VARCHAR2 (50).

  COLUMN2 VARCHAR2 (50).

  Column3 varchar2 (50)

  );

  insert into abc123 values ('yes', 'Yes', 'No');

  insert into abc123 values ('no', 'Yes', 'No');

  INSERT INTO ABC123 VALUES ('no ',' no', 'No');

  insert into abc123 values ('yes', 'Yes', 'Yes');

  SELECT CASE WHEN COLUMN1 = 'Yes' THEN - the name of the column would be here somehow?

  WHEN COLUMN2 = 'Yes' THEN - the name of the column would be here somehow?

  WHERE Column3 = 'Yes' THEN - the name of the column would be here somehow?

  Another null

  finish as abc123 columnname

  final results for the just Column1 would be:

  COLUMN1

  NULL VALUE

  NULL VALUE

  COLUMN1

  I'm not sure what I use to get the name of column in there

  Thank you.

  Hello

  708631 wrote:

  Is there a way to select the column name when there is a specific value in it?

  As follows:

  create table (abc123)

  COLUMN1 VARCHAR2 (50).

  COLUMN2 VARCHAR2 (50).

  Column3 varchar2 (50)

  );

  insert into abc123 values ('yes', 'Yes', 'No');

  insert into abc123 values ('no', 'Yes', 'No');

  INSERT INTO ABC123 VALUES ('no ',' no', 'No');

  insert into abc123 values ('yes', 'Yes', 'Yes');

  SELECT CASE WHEN COLUMN1 = 'Yes' THEN - the name of the column would be here somehow?

  WHEN COLUMN2 = 'Yes' THEN - the name of the column would be here somehow?

  WHERE Column3 = 'Yes' THEN - the name of the column would be here somehow?

  Another null

  finish as abc123 columnname

  final results for the just Column1 would be:

  COLUMN1

  NULL VALUE

  NULL VALUE

  COLUMN1

  I'm not sure what I use to get the name of column in there

  Thank you.

  Thanks for posting the CREATE TABLE and INSERT for the sample data.

  Don't forget to post the exact results you want from these sample data.  If the results depend on the parameters you want to pass a run time, then give a few different examples, with the the desired results of each.

  You can hardcode the values you want, such as the column names in a query.  For example:

  SELECT CASE WHEN column1 = 'Yes' THEN 'Column1' END like y1

  CASE WHEN column2 = 'Yes' THEN 'Column2' END like y2

  CASE WHEN Column3 = 'Yes' THEN 'Column2' END like y3

  , a. *-If wanted

  Of abc123 one

  ;

• Display the column name of the column more recently updated

  I wonder if it is possible to display the name of the column in the column most recently updated in a table.

  Example:

  Emp table

  Name

  Height

  Weight

  Age

  Update_Date

  Update_Column

  Original record (03/20/14)

  Name size weight Age Update_date Update_Column

  John                                                 03/20/14          Name

  Then someone comes and update the height on 22/03/14:

  Name size weight Age Update_date Update_Column

  John 5'9 03/22/14 height

  And the Update_date and the Update_column would change again if someone came and put a value for the age. And so on.

  Is this possible?

  Also, if the above is possible, would it be possible to display the name of extreme right column if a user updated several columns at the same time?

  Example:

  User updates the sub-folder:

  Name size weight Age Update_date Update_Column

  John 5'9 03/22/14 height

  And adds weight and age at the same time on 24-03-14:

  Name size weight Age Update_date Update_Column

  John 5'9 150 31 03/24 / 14

  The Update_Column would display age because it is the furthest to the right. (Think by reading from left to right, the column that has been updated if the extreme right)

  So to sum things, I need to be able to display Updated_date (which will be the date of the day when the record is the last updated) and Updated_Col (which is the column name of the column was last updated, and if multiple columns are updated then display that value has been updated last in)

  I hope that the examples help to clarify things.

  Thank you

  Steven

  I think I found a solution.

  delimiter //
create table a (
  id int (10) unsigned auto_increment,
  a int(10),
  b int(10),
  update_date datetime NULL,
  update_column varchar(16) NULL,
  primary key (id)
)//

  create trigger bu_a before update on a for each row begin
  set NEW.update_date = NOW();
  set NEW.update_column = NULL;
  -- you need to start with the rightmost column if you want
  -- that matched with the highest priority
  if OLD.b != NEW.b then
   set NEW.update_column = "b";
  elseif OLD.a != NEW.a then
   set NEW.update_column = "a";
  end if;
end //

  TEST

  insert into a (id,a,b) values (1,1,1), (2,1,1), (3,1,1), (4,1,1)[
update a set b = 2 where id = 2;
update a set a = 2 where id = 3;
update a set a = 2 where id = 4;
update a set b = 2 where id = 4;
select * from a;

  DISPLAY

  ID  A   B   UPDATE_DATE                    UPDATE_COLUMN
1   1   1   (null)                          (null)
2   1   2   March, 24 2014 23:22:33+0000      b
3   2   1   March, 24 2014 23:22:33+0000      a
4   2   2   March, 24 2014 23:22:33+0000      b

• How to view the line of columns without using the pivot keyword

  Hello
  could someone help me how to display lines in columns without using the keyword pivot and actuall is my scenario, iam having two tables with names and examples of data is shown below
  
  MIDDLE MINAME TASKID TASKNAME IDENTIFICATION PROJECT
  
  1 PROJ1 1 AA 100 PR1_TASK1
  1 PROJ1 3 CC PR1_TASK3 102
  1 PROJ1 DD 4 103 PR1_TASK4
  1 PROJ1 EE 5 104 PR1_TASK5
  1 PROJ1 6 105 FF PR1_TASK6
  2 PROJ2 EE 5 114 PR2_TASK1
  2 PROJ2 6 115 FF PR2_TASK2
  2 PROJ2 GG 7 116 PR2_TASK3
  2 PROJ2 HH 8 117 PR2_TASK4
  2 PROJ2 9 118 PR2_TASK5 JJ
  2 PROJ2 KK 10 119 PR2_TASK6
  2 PROJ2 1 AA PR2_TASK7 120
  
  
  The output should show the project and County of tasks at a given stage as shown below
  
  project AA BB CC DD EE FF GG HH JJ KK
  1 2 0 1 5 3 2 0 2 1 0
  2 1 2 0 2 1 0 2 4 3 1
  
  
  Thanks in advance,
  VVR

  CREATE TABLE pivot_test (
  ID           NUMBER,
  PROJECT      VARCHAR2(10),
  MID          NUMBER,
  MINAME       VARCHAR2(5),
  TASKID       NUMBER,
  TASKNAME     VARCHAR2(10)
  );
  
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 1,  'AA', 100, 'PR1_TASK1');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 3,  'CC', 102, 'PR1_TASK3');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 4,  'DD', 103, 'PR1_TASK4');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 5,  'EE', 104, 'PR1_TASK5');
  INSERT INTO pivot_test VALUES (1, 'PROJ1', 6,  'FF', 105, 'PR1_TASK6');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 5,  'EE', 114, 'PR2_TASK1');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 6,  'FF', 115, 'PR2_TASK2');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 7,  'GG', 116, 'PR2_TASK3');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 8,  'HH', 117, 'PR2_TASK4');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 9,  'JJ', 118, 'PR2_TASK5');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 10, 'KK', 119, 'PR2_TASK6');
  INSERT INTO pivot_test VALUES (2, 'PROJ2', 1,  'AA', 120, 'PR2_TASK7');
  
  SELECT ID as PROJECT,
         SUM(DECODE(miname, 'AA', 1, 0)) AS AA,
         SUM(DECODE(miname, 'BB', 1, 0)) AS BB,
         SUM(DECODE(miname, 'CC', 1, 0)) AS CC,
         SUM(DECODE(miname, 'DD', 1, 0)) AS DD,
         SUM(DECODE(miname, 'EE', 1, 0)) AS EE,
         SUM(DECODE(miname, 'FF', 1, 0)) AS FF,
         SUM(DECODE(miname, 'GG', 1, 0)) AS GG,
         SUM(DECODE(miname, 'HH', 1, 0)) AS HH,
         SUM(DECODE(miname, 'JJ', 1, 0)) AS JJ,
         SUM(DECODE(miname, 'KK', 1, 0)) AS KK
  FROM   pivot_test
  GROUP BY ID;
  
  PROJECT AA BB CC DD EE FF GG HH JJ KK
  ------- -- -- -- -- -- -- -- -- -- --
        1  1  0  1  1  1  1  0  0  0  0
        2  1  0  0  0  1  1  1  1  1  1 
  

• new to 4.02, no grid or column names in the query results

  It is a bit strange, I have SQL Developer 4.02 just installed, and I don't see grid or column names in the query results.  Don't see anything useful in tools > Preferences, what don't get me?

  The worksheet gives you a couple of different ways to run a query...

  1. instruction execute sheet icon toolbar (large green arrow, or Ctrl + Enter).

  This produces a results tab of the query with the data displayed in a grid.

  2. worksheet icon toolbar Execute the Script (the small tip of the green arrow on lined paper, or F5).

  This produces a tab out of the Script with the data displayed on the printer.

  If execution of the statement to Execute the Script, using some SQL * most orders will remove the column headers:

  1. set the position

  2. set the pagesize 0 (or 1 or 2).

  Pagesize and linesize default is - 1.  By default, the spreadsheet is free for formatting output script as he wishes.  If you have not changed these settings in the spreadsheet, then see if you point to a startup script in Tools > Preferences > Database > name of the connection startup script file

  Kind regards

  Gary

  SQL DeveloperTeam

• How to make reference to a column name in the form report

  Hello
  How can I make reference to a column name in the form report. My problem is that "I have a form report that I have the column name when using click on the column name, it must get to the next page with the corresponding values of the column".
  
  Here, I realized that when I click on the name of the column (in page 1) it brings me to the next page (page 2). but in the next page (P2) I want to display (display only) the corresponding values of the column (page 1) selected, but the values are not editable and shouldn't be in the text box must be in display area.
  
  So, how can I write a SQL to display single source field. That is to say, how can I consult report form (page 1) in name column.

  Hello

  If you use the link in the column when you click on the need of the column value, you need to navigate to the next page and all the data accordingly select value here.

  Modify the report form and see the top of the page and click on report attribute.

  So now you have the attributes of the columns is to say what are the columns are available in the reports form.

  Click on change column what you need Ie the column when you click on its passage to the next page this column, for example, as mentioned in the previous post "Empname".

  Check the link column and give perspective of values according to your need and click on apply chages.

  Thank you & best regards
  Srikkanth.M

• include the column name in the results

  How can I include my column names in the first line of my results?

  Do not press the "Execute" button negative
  Press the button 'Run as script'

• My deskjet 3522 print horizontal lines with no printing on the lines

  My deskjet 3522 print horizontal lines with no printing on the lines

  I solved prolem with horizontal lines with no printing on the printer cleaning lines and lining up and will leave no paper in the tray to dust cllect

• Why I get two files with different names but the same image when I save in 2015 CC Photoshop?

  Why I get two files with different names but the same image when I save in 2015 CC Photoshop?

  Try resetting the PS preferences - Preferences in Photoshop

  ~ Rohit

• How to make reference to a column name in the domain constraint

  When specify us a constraint check (for SQL Server) in a field, we need to enter an expression in the syntax, for example
  
  Len (Phone) > 7
  
  Later, the Modeler will exactly this expression in the SQL code. But it would be wrong as a constraint to refer to a column name in the table (which would not be 'phone').
  So, how to make the data name Modeler to a real column in the constraint domain?

  Hello

  Use the % COLUMN as a placeholder column name - len (%COLUMN%) > 7

  Philippe