Do not use the index
Hi allDB version is 10.2.0.4
Have a query as below
SQL> explain plan for SELECT GS.LOT_NO , GS.LOT_ID , ILI.ITEM_ID ITEM_ID,
2 GR.RESULT_VALUE_CHAR QUALITATIVE_VALUE , ITM.ITEM_NO FROM
GMD_QC_TESTS GQT, GMD_RESULTS GR, GMD_SAMPLES GS , IC_LOCT_INV
3 4 ILI, IC_ITEM_MST_B ITM WHERE GQT.TEST_CODE = 'ISON' AND
5 GR.TEST_ID = GQT.TEST_ID AND GR.RESULT_VALUE_CHAR LIKE :B3
6 ||'-'||:B2 ||'%' AND GR.SAMPLE_ID = GS.SAMPLE_ID AND ITM.ITEM_ID
7 = GS.ITEM_ID AND ILI.WHSE_CODE = UPPER(:B1 ) AND ILI.ITEM_ID =
8 GS.ITEM_ID AND ILI.LOT_ID = GS.LOT_ID AND ILI.LOCT_ONHAND > 0
9 AND ILI.LOT_ID > 0 AND ILI.LOT_STATUS = 'GOOD' AND NOT EXISTS (
10 SELECT 1 FROM IC_TRAN_PND ITP WHERE ITP.LOT_ID = GS.LOT_ID AND
11 ITP.ITEM_ID = GS.ITEM_ID AND ITP.DELETE_MARK = 0 AND
12 ITP.DOC_TYPE = 'OMSO' AND ITP.WHSE_CODE = UPPER(:B1 ) AND LOT_ID
13 <> 0 ) ORDER BY 4
14 /
Explained.
SQL> select * from table(dbms_xplan.display);
PLAN_TABLE_OUTPUT
------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
Plan hash value: 2952119331
---------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
---------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 55 | 7095 | 13614 (1)| 00:02:51 |
| 1 | SORT ORDER BY | | 55 | 7095 | 13614 (1)| 00:02:51 |
| 2 | NESTED LOOPS ANTI | | 55 | 7095 | 13613 (1)| 00:02:51 |
| 3 | NESTED LOOPS | | 55 | 5940 | 13393 (1)| 00:02:49 |
|* 4 | HASH JOIN | | 55 | 4730 | 13283 (1)| 00:02:47 |
|* 5 | TABLE ACCESS BY INDEX ROWID | IC_LOCT_INV | 17498 | 410K| 4056 (1)| 00:00:51 |
|* 6 | INDEX RANGE SCAN | IC_LOCT_INV_I1 | 52570 | | 137 (0)| 00:00:02 |
|* 7 | HASH JOIN | | 14944 | 904K| 9226 (1)| 00:01:56 |
| 8 | NESTED LOOPS | | 14944 | 452K| 212 (0)| 00:00:03 |
| 9 | NESTED LOOPS | | 1 | 19 | 2 (0)| 00:00:01 |
| 10 | TABLE ACCESS BY INDEX ROWID| GMD_QC_TESTS_B | 1 | 12 | 2 (0)| 00:00:01 |
|* 11 | INDEX UNIQUE SCAN | GMD_QC_TESTS_B_U1 | 1 | | 1 (0)| 00:00:01 |
|* 12 | INDEX UNIQUE SCAN | GMD_QC_TESTS_TL_PK | 508 | 3556 | 0 (0)| 00:00:01 |
| 13 | TABLE ACCESS BY INDEX ROWID | GMD_RESULTS | 14944 | 175K| 210 (0)| 00:00:03 |
|* 14 | INDEX RANGE SCAN | GMD_RESULTS_N3 | 228 | | 3 (0)| 00:00:01 |
|* 15 | TABLE ACCESS FULL | GMD_SAMPLES | 1642K| 48M| 9007 (1)| 00:01:54 |
| 16 | TABLE ACCESS BY INDEX ROWID | IC_ITEM_MST_B | 1 | 22 | 2 (0)| 00:00:01 |
|* 17 | INDEX UNIQUE SCAN | IC_ITEM_MST_B_PK | 1 | | 1 (0)| 00:00:01 |
|* 18 | TABLE ACCESS BY INDEX ROWID | IC_TRAN_PND | 1 | 21 | 4 (0)| 00:00:01 |
|* 19 | INDEX RANGE SCAN | IC_TRAN_PNDI1 | 1 | | 3 (0)| 00:00:01 |
---------------------------------------------------------------------------------------------------------
In the table full scan that happens on GMD_SAMPLES. Lot_id is selected in this table. On this column, there are indexes in the table. But this is not used?SQL> select dbms_metadata.get_ddl('INDEX','GMD_SAMPLES_N3','GMD') from dual;
CREATE INDEX "GMD"."GMD_SAMPLES_N3" ON "GMD"."GMD_SAMPLES" ("LOT_ID")
PCTFREE 10 INITRANS 2 MAXTRANS 255 COMPUTE STATISTICS
STORAGE(INITIAL 131072 NEXT 131072 MINEXTENTS 1 MAXEXTENTS 2147483645
PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1 BUFFER_POOL DEFAULT)
TABLESPACE "APPS_TS_TX_DATA"
How can I lower the cost of the query. ?. This query runs for more than two hours in the comic book...Thank you
Baskar.l
The counties to answer your question, now?
LOT_ID returns 99 + % of the lines so Full Table Scan is 100% justified & more efficient execution plan
Tags: Database
Similar Questions
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Hi all
Version of DB: Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Prod
Here is the description of the problem:
(The statistics are up to date for all tables).
The query below does not use the index on ACCOUNTS_LIVE (ID). (Unique index)
Line 23 of the query uses accounts_live.id.SQL> explain plan for 2 select txn.account_number,to_number(txn.amount_lcy) txn_amt,to_date(booking_date,'YYYYMMDD') TXN_DATE, 3 sal.latest_sal,sal.sal_date,customer_name,employer_name, 4 decode(COMMUNICATION_TYPE_1,'MOBILE',COMMUNICATION_NO_1, 5 decode(COMMUNICATION_TYPE_2,'MOBILE',COMMUNICATION_NO_2)) mob, 6 txn.CURRENCY, CHEQUE_NUMBER,trans_dets,trans_reference,target,teller_id,acc.category,acc.inactive_marker, 7 acc.posting_restrict,cus.sector,cus.industry 8 from coreadmin.Gtxn_dtl_v1 txn, 9 (select account_number,round(to_number(nvl(amount_lcy,0)),2) latest_sal,TXN_DATE sal_date,rr 10 from 11 (select to_date(booking_date,'YYYYMMDD') TXN_DATE,batch_id,account_number,amount_lcy 12 ,row_number() over (partition by account_number 13 order by to_date(booking_date,'YYYYMMDD') desc NULLS LAST, 14 batch_id desc nulls last) rr, 15 CURRENCY, CHEQUE_NUMBER,trans_dets,trans_reference 16 from coreadmin.Gtxn_dtl_v1 17 where transaction_code in ('204','938') 18 and to_number(amount_lcy) > 0) 19 where rr = 1 20 ) sal,accounts_live acc,customers_live cus 21 where to_date(booking_date,'YYYYMMDD') between to_date('030109','DDMMRR') and to_date('020209','DDMMRR') 22 and txn.account_number = sal.account_number 23 and txn.account_number = acc.id 24 and txn.CUSTOMER_ID = cus.CUSTOMER_number 25 and target in ('30','31','32') 26 / Explained. SQL> select * from table(dbms_xplan.display); PLAN_TABLE_OUTPUT ------------------------------------------------------------------------------------------------------------------------------------------------------ Plan hash value: 920245766 ----------------------------------------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes |TempSpc| Cost (%CPU)| Time | ----------------------------------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 363M| 121G| | 223K (4)| 00:44:47 | |* 1 | HASH JOIN | | 363M| 121G| 6232K| 223K (4)| 00:44:47 | |* 2 | VIEW | | 34453 | 5820K| | 147K (1)| 00:29:36 | |* 3 | WINDOW SORT PUSHED RANK | | 34453 | 1480K| 4072K| 147K (1)| 00:29:36 | |* 4 | FILTER | | | | | | | | 5 | INLIST ITERATOR | | | | | | | |* 6 | TABLE ACCESS BY INDEX ROWID| GTXN_DTL_V1 | 34453 | 1480K| | 147K (1)| 00:29:31 | |* 7 | INDEX RANGE SCAN | IDX_TXN5 | 707K| | | 1815 (2)| 00:00:22 | |* 8 | HASH JOIN | | 598K| 106M| 20M| 63724 (1)| 00:12:45 | |* 9 | MAT_VIEW ACCESS FULL | CUSTOMERS_LIVE | 227K| 17M| | 2239 (4)| 00:00:27 | |* 10 | HASH JOIN | | 598K| 59M| 9504K| 57157 (1)| 00:11:26 | | 11 | MAT_VIEW ACCESS FULL | ACCOUNTS_LIVE | 249K| 6577K| | 1832 (2)| 00:00:22 | |* 12 | TABLE ACCESS BY INDEX ROWID | GTXN_DTL_V1 | 597K| 43M| | 52319 (1)| 00:10:28 | |* 13 | INDEX RANGE SCAN | IDX_TXN11_V1 | 1204K| | | 3931 (2)| 00:00:48 | ----------------------------------------------------------------------------------------------------------- Predicate Information (identified by operation id): --------------------------------------------------- 1 - access("TXN"."ACCOUNT_NUMBER"="ACCOUNT_NUMBER") 2 - filter("RR"=1) 3 - filter(ROW_NUMBER() OVER ( PARTITION BY "ACCOUNT_NUMBER" ORDER BY TO_DATE("BOOKING_DATE",'YYYYMMDD') DESC NULLS LAST,INTERNAL_FUNCTION("BATCH_ID") DESC NULLS LAST)<=1) 4 - filter(TO_DATE('030109','DDMMRR')<=TO_DATE('020209','DDMMRR')) 6 - filter(TO_NUMBER("AMOUNT_LCY")>0) 7 - access("TRANSACTION_CODE"='204' OR "TRANSACTION_CODE"='938') 8 - access("TXN"."CUSTOMER_ID"="CUS"."CUSTOMER_NUMBER") 9 - filter("TARGET"='30' OR "TARGET"='31' OR "TARGET"='32') 10 - access("TXN"."ACCOUNT_NUMBER"="ACC"."ID") 12 - filter("TXN"."CUSTOMER_ID" IS NOT NULL) 13 - access(TO_DATE("BOOKING_DATE",'YYYYMMDD')>=TO_DATE('030109','DDMMRR') AND TO_DATE("BOOKING_DATE",'YYYYMMDD')<=TO_DATE('020209','DDMMRR')) 38 rows selected. SQL> select index_name 2 from dba_ind_columns 3 where table_name = 'ACCOUNTS_LIVE' 4 and column_name = 'ID'; INDEX_NAME ------------------------------ IDX_ACCLIVE
11 the order ID explain plan shows that the index does not use.
Please suggest.
Thanks in advance,
JacWhat happens when you force the index by using hint and use the hash between txn and acc join?
See you soon
Sarma. -
I have problem with a query as follows. It does not index when I keep a function on the left side of the comparison in which the condition.
But when I remove the function is using the index.
With BLC AS Name Null? Type ----------------------------------------- -------- ---------------------------- ID NOT NULL NUMBER MASTER_VALUE NOT NULL NUMBER(8) DESC_TEXT_ID NUMBER GVM VARCHAR2(50) MASTER_LOOKUP_ID NOT NULL NUMBER WORK_SECTION_ID NUMBER AUDIT_TRAIL_NO NUMBER SQL> SELECT COUNT(*) FROM BLC; COUNT(*) ---------- 7769 SQL> SELECT COUNT(DISTINCT(GVM)) "distinct" FROM BLC; distinct ---------- 1350 SQL> SELECT COUNT(*) "nulls" FROM BLC WHERE GVM IS NULL; nulls ---------- 6419 SQL> SELECT COLUMN_NAME,INDEX_NAME FROM DBA_IND_COLUMNS WHERE TABLE_NAME='BLC'; COLUMN_NAME INDEX_NAME ---------------------------------------- ------------------------------ MASTER_LOOKUP_ID LKPCDE_MSTLKP_FK_I WORK_SECTION_ID LKPCDE_WRKSEC_FK_I GVM LKPCDE_UK MASTER_VALUE LKPCDE_MASTERID_VALUE_UK MASTER_LOOKUP_ID LKPCDE_MASTERID_VALUE_UK ID LKPCDE_PK SQL> EXPLAIN PLAN FOR SELECT ID FROM BLC WHERE UPPER ( GVM) = 'MAIN_ORG'; Explained. SQL> SELECT * FROM TABLE(DBMS_XPLAN.DISPLAY); PLAN_TABLE_OUTPUT -------------------------------------------------------------------------------- Plan hash value: 3196655606 -------------------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time| -------------------------------------------------------------------------------------- PLAN_TABLE_OUTPUT -------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 78 | 624 | 18 (0)| 00:00:01 | |* 1 | TABLE ACCESS FULL| BLC | 78 | 624 | 18 (0)| 00:00:01 | -------------------------------------------------------------------------------------- Predicate Information (identified by operation id): PLAN_TABLE_OUTPUT ----------------------------------------------------------------------------------------------------------------------------------- 1 - filter(UPPER("GVM")='MAIN_ORG') 13 rows selected. SQL> EXPLAIN PLAN FOR SELECT ID FROM BLC WHERE GVM = 'MAIN_ORG'; Explained. SQL> SELECT * FROM TABLE(DBMS_XPLAN.DISPLAY); PLAN_TABLE_OUTPUT -------------------------------------------------------------------------------- Plan hash value: 1620245961 -------------------------------------------------------------------------------- ---------------- | Id | Operation | Name | Rows | Bytes | Cost (% CPU)| Time | -------------------------------------------------------------------------------- ---------------- PLAN_TABLE_OUTPUT -------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 1 | 8 | 2 (0)| 00:00:01 | | 1 | TABLE ACCESS BY INDEX ROWID| BLC | 1 | 8 | 2 (0)| 00:00:01 | |* 2 | INDEX UNIQUE SCAN | LKPCDE_UK | 1 | | 1 (0)| 00:00:01 | -------------------------------------------------------------------------------- ---------------- PLAN_TABLE_OUTPUT -------------------------------------------------------------------------------- Predicate Information (identified by operation id): --------------------------------------------------- 2 - access("GVM"='MAIN_ORG') 14 rows selected. SQL> EXPLAIN PLAN FOR SELECT /* INDEX(LKPCDE_UK) */ ID FROM BLC WHE RE UPPER ( GVM ) = 'MAIN_ORG'; Explained. SQL> SELECT * FROM TABLE(DBMS_XPLAN.DISPLAY); PLAN_TABLE_OUTPUT -------------------------------------------------------------------------------- Plan hash value: 3196655606 -------------------------------------------------------------------------------- ------ | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | -------------------------------------------------------------------------------- ------ PLAN_TABLE_OUTPUT -------------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 78 | 624 | 18 (0)| 00:0 0:01 | |* 1 | TABLE ACCESS FULL| BLC | 78 | 624 | 18 (0)| 00:0 0:01 | -------------------------------------------------------------------------------- ------ Predicate Information (identified by operation id): PLAN_TABLE_OUTPUT -------------------------------------------------------------------------------- --------------------------------------------------- 1 - filter(UPPER("GVM")='MAIN_ORG') 13 rows selected.
Please let me know how I can force it to use an index as it is causing the CPU usage.
I can't change the query in the application it is used in several places.
Thank you
And/or read: ORACLE-BASE - Oracle function index
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If the INSTR function will not use the INDEX o?
Hi all
I have a querry as
Is simple index on column Col1. If we use the index will be used or full table scan will happen in this scenario?Select * from Tab1 Where Instr(Tab1.Col1,'XX') >0 ;
Please give me explanatory answer because I have doubts
DhabasHello
You must use the index function if you want to avoid the full table scan. Check this box
SQL> create table tab1(col1 varchar(20)) 2 / Table created. SQL> insert into tab1 values ('XXAB') 2 / 1 row created. SQL> create index col1_idx on tab1(col1); Index created. SQL> explain plan for Select * from Tab1 Where Instr(Tab1.Col1,'XX') >0; Explained. SQL> set autotrace on SQL> Select * from Tab1 Where Instr(Tab1.Col1,'XX') >0; XXAB Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=ALL_ROWS (Cost=5 Card=1 Bytes=12) 1 0 TABLE ACCESS (FULL) OF 'TAB1' (TABLE) (Cost=5 Card=1 Bytes =12) Statistics ---------------------------------------------------------- 4 recursive calls 0 db block gets 32 consistent gets 0 physical reads 0 redo size 234 bytes sent via SQL*Net to client 280 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed SQL> create index col1_idx2 on tab1(Instr(Col1,'XX')); Index created. SQL> Select * from Tab1 Where Instr(Tab1.Col1,'XX') >0; XXAB Execution Plan ---------------------------------------------------------- 0 SELECT STATEMENT Optimizer=ALL_ROWS (Cost=2 Card=1 Bytes=12) 1 0 TABLE ACCESS (BY INDEX ROWID) OF 'TAB1' (TABLE) (Cost=2 Ca rd=1 Bytes=12) 2 1 INDEX (RANGE SCAN) OF 'COL1_IDX2' (INDEX) (Cost=1 Card=1 ) Statistics ---------------------------------------------------------- 28 recursive calls 0 db block gets 22 consistent gets 0 physical reads 0 redo size 234 bytes sent via SQL*Net to client 280 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 1 rows processed SQL>
Thank you
AJ -
Setting the query: optimizer does not use the index function
Hello
I have a request written by a developer that I can't change.
It is here that the condition:
OÙ ( UPPER(TRIM (CODFSC)) = UPPER (TRIM ( '01923980500'))
OR UPPER(TRIM (CODUIC)) = UPPER (TRIM ( '01923980500')))
There is an index on CODFSC and on CODUIC1.
the plan is:
Plan
INSTRUCTION SELECT ALL_ROWS cost: 9 194 bytes: 3 206 502 cardinality: 15 054
ACCESS FULL ANAGRAFICA cost TABLE TABLE 1: 9 194 bytes: 3 206 502 cardinality: 15 054
So I created two new index on SUPERIOR (TRIM ()CODFSC)) and SUPERIOR (TRIM ()CODUIC)) but the plan
complete analysis of STIL.
Modifing where condition in:
OÙ ( CODFSC = UPPER (TRIM ( '01923980500'))
OR CODUIC = UPPER (TRIM ( '01923980500')))
the plan is:
SELECT STATEMENT ALL_ROWSCost: 157 bytes: 426 cardinality: 2
CONCATENATION OF 5
TABLE ACCESS BY INDEX ROWID ANAGRAFICA cost TABLE 2: cardinality of 5 bytes: 213: 1
1 INDEX RANGE SCAN INDEX ANAGRAFICA_IDX01 cost: cardinality 3: 1
TABLE ACCESS BY INDEX ROWID ANAGRAFICA cost TABLE 4: cardinality 152 bytes: 213: 1
3 INDEX SKIP SCAN INDEX ANAGRAFICA_IDX02 cost: cardinality 1: 151
Why optimizer not use my funct index?
Thank you.
Franck,
I always forget that the default value for the GOLD expansion depends on a path indexed for each branch.
2 in your use of or_predicates (2) depends on the position of complex predicate which must be expanded. If you change the order of predicate 'State = 0' to display AFTER the complex predicate, you must change the indicator of "or_predicates (1).
Outside of the current state of undocumented indicator, it also introduces the disturbing thought that, for a more complex query, a change in the transformation may result in another set of query blocks generated with a different ranking of the predicates. Yet another case to ensure that if you suggest anything suggest you (or create a SQL database).
Concerning
Jonathan Lewis
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query not using the index for some user
Hello
I have a query that is running in less than a second for sys, system, or schema owner. However, another user (test_user) take 30 seconds to run the same query.
I certainly dba and privileges identical to test_user as schmea_user, but the result is the same.
I checked
Select * from V$ SYS_OPTIMIZER_ENV;
Both are the same for both users.
I have check the plan to explain to both users. I noticed that for sys/system/schema_owner, the query uses an index, but not the test_user.
All have experience the issue where a user uses an index, but not the other?
Thank you for any assistance.Thank you for the display of formatting output, this output is much easier to read.
One of the first things you notice about the execution plans that is for the owner non-schema "SQL_ID, 0wcs85uywn72m, number of children 1" appears in the output of DBMS_XPLAN, while "SQL_ID 0wcs85uywn72m, child number 0" (the same SQL_ID but a different number of child) appears for the schema owner. "" Whereas the SQL_ID is the same, which indicates that the client requires exactly the same SQL statement, so it's a good start.
Then, note that in the predicate for the nonschema owner information section the following appears (sometimes with the order of the two conditions switched in position) as a condition placed on each table that is available in the schema:
filter(("SEAL_FLAG" IS NULL OR "SEAL_FLAG"'Y'))
The above suggests the presence of the virtual private database (or a superset of private database virtual) generated the predicates. You should be able to confirm that this is the case by querying V$ VPD_POLICY using the SQL_ID which was displayed in the DBMS_XPLAN output:
SELECT * FROM V$VPD_POLICY WHERE SQL_ID='0wcs85uywn72m';
As a test, I made a few minor adjustments to the example on this page:
http://Antognini.ch/2011/09/optimizer_secure_view_merging-and-VPD/
I changed the name of T to T12 and TESTUSER table specified for the schema names. I then created the function S of this page as follows:CREATE OR REPLACE FUNCTION s (schema IN VARCHAR2, tab IN VARCHAR2) RETURN VARCHAR2 AS BEGIN RETURN 'ID < 10'; END; /
I then added a couple of lines in the T12 test table:
INSERT INTO T12 VALUES (1,1,NULL); INSERT INTO T12 VALUES (4,1,NULL); INSERT INTO T12 VALUES (10,1,NULL); INSERT INTO T12 VALUES (12,1,NULL); COMMIT;
With an active 10053 trace, I executed the following SQL statement:
SELECT id, pad FROM t12 WHERE spy(id, pad) = 1
The SQL_ID (in my case, found in the 10053 trace file) was 6hqw5p9d8g8wf, so I checked V$ VPD_POLICY to this SQL_ID:
SELECT * FROM V$VPD_POLICY WHERE SQL_ID='6hqw5p9d8g8wf'; ADDRESS PARADDR SQL_HASH SQL_ID CHILD_NUMBER OBJECT_OWNER OBJECT_NAME POLICY_GROUP POLICY POLICY_FUNCTION_OWNER PREDICATE ---------------- ---------------- ---------- ------------- ------------ ------------ ------------------------------ ------------------------------ ---------------------- ------------------------------ ------------------------------------------------------------------------------------ 000007FFB7701608 000007FFB7743350 1518838670 6hqw5p9d8g8wf 0 TESTUSER T12 SYS_DEFAULT T_SEC TESTUSER ID < 10
As noted above, the VPD test function named S added the predicate "ID".< 10"="" to="" the="" sql="">
There are not many clues in the 10053 trace file in my test VPD generated additional predicates. Trace the following was found shortly after the beginning of the file (this is the SQL statement initially presented):
----- Current SQL Statement for this session (sql_id=6hqw5p9d8g8wf) ----- SELECT id, pad FROM t12 WHERE spy(id, pad) = 1
I searched then down in the trace for final after changes query file (to be noted that this sentence could be slightly different in different versions of database Oracle). That's what I found:
Final query after transformations: ******* UNPARSED QUERY IS ******* SELECT "T12"."ID" "ID","T12"."PAD" "PAD" FROM "TESTUSER"."T12" "T12" WHERE "TESTUSER"."SPY"("T12"."ID","T12"."PAD")=1 AND "T12"."ID"<10 kkoqbc: optimizing query block SEL$F5BB74E1 (#0)
Note that the final query after transformation shows how the final version of the query that has been rewritten by the query optimizer before the SQL statement has been executed and this version of the query includes AND "T12". "" IDENTITY CARD ".<10. if="" i="" was="" attempting="" to="" determine="" how="" that="">10.><10 predicate="" was="" added="" to="" the="" sql="" statement,="" i="" would="" start="" at="" the="" "current="" sql="" statement="" for"="" line="" in="" the="" trace="" file="" and="" search="" down="" the="" trace="" file="" for="">10><10* -="" in="" this="" case,="" the="" following="" is="" what="" i="" found="" as="" the="" first="" search="" result,="" very="" close="" to="" the="" "current="" sql="" statement="" for"="" line="" in="" the="" trace="">10*>
************************** Predicate Move-Around (PM) ************************** PM: PM bypassed: Outer query contains no views. PM: PM bypassed: Outer query contains no views. query block SEL$F5BB74E1 (#0) unchanged FPD: Considering simple filter push in query block SEL$F5BB74E1 (#0) "TESTUSER"."SPY"("T12"."ID","T12"."PAD")=1 AND "T12"."ID"<10 try to generate transitive predicate from check constraints for query block SEL$F5BB74E1 (#0) finally: "TESTUSER"."SPY"("T12"."ID","T12"."PAD")=1 AND "T12"."ID"<10
As can be seen from the above (because the predicate again appeared before and after the line containing the word "Finally: '), the AND"T12 ". "" IDENTITY CARD ".<10 predicate="" was="" already="" added="" to="" the="" original="" sql="" statement="" by="" the="" time="" the="" predicate="" move-around="" section="" of="" the="" trace="" file="" was="" written,="" and="" that="" is="" the="" first="" mention="" of="">10><10 in="" the="" trace="" file.="" in="" your="" case,="" you="" would="" search="" the="" 10053="" trace="" file="">10>
"SEAL_FLAG" IS NULL
If V$ VPD_POLICY revealed that there are virtual private database (VPD) generated predicates applied to the SQL statement, take a look at the following article in the Oracle documentation library:
http://docs.Oracle.com/CD/B28359_01/network.111/B28531/VPD.htmThis article lists the different points of view, who can be interviewed to learn more about the VPD rules which are in force in the schema. For example, with my SPV test:
SELECT * FROM ALL_POLICIES; OBJECT_OWNER OBJECT_NAME POLICY_GROUP POLICY_NAME PF_OWNER PACKAGE FUNCTION SEL INS UPD DEL IDX CHK ENA STA POLICY_TYPE LON ------------------------------ ------------------------------ ----------------------------- ------------------------------ ------------------------------ ----------------------------- ------------------------------ --- --- --- --- --- --- --- --- ------------------------ --- TESTUSER T12 SYS_DEFAULT T_SEC TESTUSER S YES YES YES YES NO NO YES NO DYNAMIC NO
He knows performance issues related to the use of VPD, some of which are Oracle Database version-dependent, and some have been fixed in recent versions. Take a look at the following articles if you have access to My Oracle Support:
MetaLink (MOS) Doc ID 728292.1 ' known performance problems when you use transparent encryption data and indexes on the encrypted columns.
MetaLink (MOS) Doc ID 967042.1 "How to investigate Query Performance regressions Caused by VPD (FGAC) predicates?"You might find working through the second of the above that the problem is caused by a bug in database Oracle.
On a side note. Execution plans you have published include the 0 value in the column starts many of the operations in the execution plan. 0 indicates that the operation never actually executed. A 0 is included in the column starts on the line that includes the FULL ACCESS of TABLE of PEOPLE_TRANSACTIONS at least to the OPC. Value 123, a full table of PEOPLE_TRANSACTIONS table scan PROPERTY_CONTAINER_ID was not actually performed.
Charles Hooper
http://hoopercharles.WordPress.com/
IT Manager/Oracle DBA
K & M-making Machine, Inc. -
SELECT on a table in the INSERT statement uses the INDEX
Hello world
I have a strange problem with EA Oracle 10 g (64-bit) running on a Linux system. The situation is, I developed a Java program to migrate one client system to another. One of the steps in the migration fills a new table with the data from the old system. Given that the data on the old system structure is fundamentally different from that new, I have to check each time I read a line from the old system, if I have already created an entity on the new table, and if so, update certain attributes. The WHERE clause of this audit uses a key of the company indexed on the new table. The problem is now, that Oracle does not use the index on the key attribute of the company, but it makes table scans complete to select the line. As you can imagine, the lines first thousand or so go fast, but the amount increases, the program becomes slower and slower.
If I do a "scan" when executing the migration program, Oracle change the execution plan and use the index on the attribute key and everything works fast and smooth. However, if I do the analysis on the empty table first, nothing changes (which I understand it perfectly, since there is nothing to analyze, at this point). By integrating a hint of 'INDEX' (table) in the statement SELECT does not change the full implementation plan (also table scans).
Is it possible to change this behavior, in order to SELECT it uses the index of key business from the beginning?
Greetings from Cologne,
Thorsten.
Published by: thkitz on 13.03.2012 18:27thkitz wrote:
SELECT STATEMENT ALL_ROWSCost: 2 Bytes: 76 Cardinality: 2 7 TABLE ACCESS BY INDEX ROWID TABLE AIDATINT.PRVVSSCHADENKORRESPONDENZ Cost: 2 Bytes: 76 Cardinality: 2 6 BITMAP CONVERSION TO ROWIDS 5 BITMAP OR 2 BITMAP CONVERSION FROM ROWIDS 1 INDEX RANGE SCAN INDEX AIDATINT.I_PRVVSSCHADENKORRESPONDENZ_1 Cost: 1 4 BITMAP CONVERSION FROM ROWIDS 3 INDEX RANGE SCAN INDEX AIDATINT.I_PRVVSSCHADENKORRESPONDENZ_2 Cost: 1
I would have thought that as a plan as possible. It is not a concatenation, is a btree/bitmap conversion.
Allude to this plan you need / * + index_combine (table_alias index1 index2) * /.
For 10g and later the index can be specified by name or by descriptionI'm a bit puzzled why the plan changes after truncate - but maybe my comment about not cleared statistics is no longer true. It is easy enough to check if I'm right or wrong on your version of Oracle.
Concerning
Jonathan Lewis
http://jonathanlewis.WordPress.com
Author: core Oracle -
How to monitor the SQL perticuler using the INDEX or not?
I'm running on a long-term quary and the output is coming very late. So, I want to know that the quary sql uses the index or not? How do I know that?Hello
You have not provided your db version?
You can check v $ object_usage in a simple way. Try to check the explanation of your query if you current sql is by using your existing index or not.
Check with dbms_xplan.displayRequest to go through the links of Ask tom and jonathan lewis
http://jonathanlewis.WordPress.com/2007/02/15/index-not-used-10G/
http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:736825544526HTH
-Pounet N
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Performance problem on the SQL query that does not use the primary key index
Hello!
I have some performance issues on a single SQL query (Oracle 10 g).
I could solve the problem by using the INDEX indicator, but I would like to know WHY this is happening.
* Tables *.
create table jobs)
ID number (5) not null,
name varchar2 (100),
primary key constraint Job_PK (id)
)
/
-Record count: 298
create table Comp)
integer ID not null,
name varchar2 (100),
primary key constraint Comp_PK (id)
)
/
-Record count: 193
-Relation m: n
create table JobComp)
integer ID not null,
id_job integer not null,
id_comp integer not null,
primary key constraint JobComp_PK (id),
unique key constraint JobComp_UK (id_job, id_comp),
Constraint JobComp_FK_Job foreign key (id_job) refers to Job (id),
Constraint JobComp_FK_Comp foreign key (id_comp) makes reference Comp (id)
)
/
create index JobComp_IX_Comp on JobComp (Cod_Comp)
/
create index JobComp_IX_Job on JobComp (Cod_Job)
/
-Record count: 6431
* Ask *.
When I run this query, the execution plan shows the index using (JobComp_PK and JobComp_IX_Comp).
No problem.
Select JobComp.*
of JobComp
Join jobs
on Job.id = JobComp.id_job
where JobComp.id_comp = 134
/
-runs in 0.20 sec
But when I add the field 'name' of the work table the plan uses full access table to the table of work
Select JobComp.*, Job.name
of JobComp
Join jobs
on Job.id = JobComp.id_job
where JobComp.id_comp = 134
/
-runs in the 2.70 dry
With the help of the index
Select / * + INDEX (Job Job_PK) * /.
JobComp.*, Job.name
of JobComp
Join jobs
on Job.id = JobComp.id_job
where JobComp.id_comp = 134
/
-runs in 0.20 sec
* Doubt *.
This behavior is correct?
PS. : I tried to recalculate the statistics, but nothing changes:
analyze the job calculation table statistics.
/
change the statistical calculation of index Job_PK reconstruction;
/
Start
dbms_utility.analyze_schema (sys_context ('userenv', 'current_schema'), 'CALCULATE');
end;
/
[of]
Gustavo EhrhardtGus.EHR wrote:
Hello.
I'm sorry for the plan unformatted.
The execution time of the querys "without field name' and 'with the field name with suspicion" are equal.
He has no problem caching, because I get the plans of the sequence different from the querys and repeated the performance. The result is always the same.I don't think that there is no problem with oracle crossing LOOP IMBRIQUEE to the HASH JOIN when you include the field name and this should be the expected behavior. But it seems that your WORKING table has a degree of parallelism set against what is causing the query to run in parallel (as JOB table is now available with full table scan, instead of indexed access earlier). It could be that the parallel execution is contributor to extra Runtime.
(a) do you know why the degree of parallelism on the WORK table has been defined? Do you need it?You can see if the following query provides a better response time?
select /*+ NOPARALLEL(JOB) */ JobComp.*, Job.Name from JobComp join Job on Job.id = JobComp.id_job where JobComp.id_comp = 134
-
Why an amplification of the RAM does not change the index performnance of windows vista?
Why an amplification of the RAM does not change the index performnance of windows Vista?
Hello
I m not very well, but maybe you have more than 3 GB of RAM and Vista 32 bit.
Usually the 32 bit OS is capable to manage and send only 3.2 GB.
The more than 3.2 GB RAM will not operating system used and therefore would not increase the index
In addition the laptop will be not really faster after upgrading RAM. You will notice better performance using applications at the same time, but this does not affect the index of Vista.
But this is only my personal hypothesis.Welcome them
-
Hello
I recently made changes to a site in the latest version (site was the previous version) upgrade of site and went on to publish via FTP not loading the index page. All other pages did. Since then I have used time machine and reloaded the previous site. Any help? is this a bug?
the Web site is cjduncan.com/spacedays
Hello, have you managed to solve the problem
Have you managed to solve the problem?
Your site to load very well to my dissertation
I checked in several browsers as well.
-Catherine
-
SDO_NN cannot be assessed without using the index when put inside subquery
Hi all
I met a problem when you use the function sdo_nn to find the nearest neighbor. Here is my scenario:
_ I have 2 customer and store tables.
Customer table _ a client_ID and a 2D sdo_geom point
_ Store table has store_ID and a 2D polygon sdo_geom.
In the beginning, I have this query to find the nearest store to each customer as below:
Select s.STORE_ID, c.CLIENT_ID
store customer, s c
where sdo_nn (s.MYPOLYGON, c.MYPOINT, 'sdo_num_res = 1', 1) = "TRUE";
_It works as expected when it returns a table showing the nearest store each customer.
_Now I want to count the number of customers who have the same nearest store:
Select / * + INDEX (store store_spatial_idx, client_spatial_idx client) * / count (nearest_store. CLIENT_ID)
from (select s.STORE_ID, c.CLIENT_ID
store customer, s c
where sdo_nn (s.MYPOLYGON, c.MYPOINT, 'sdo_num_res = 1', 1) = "TRUE") nearest_store
Group of nearest_store. STORE_ID;
This query generates the following error:
Error report-
SQL error: ORA-13249: SDO_NN cannot be assessed without using the index
ORA-06512: at the 'MDSYS. MD", line 1723
ORA-06512: at the 'MDSYS. MDERR", line 17
ORA-06512: at the 'MDSYS. PRVT_IDX', line 9
13249 00000 - '%s '.
I'm pretty new to spatial databases and hope get help to go further. Thank you in advance!
Hello Pinball,
Oracle space tends to be a quite complex with many variables and moving parts. We chatted about the group to a sort of FAQ or guidelines to help people like you submit questions that actually answers. First of all, you really have to tell us the version of Oracle you are using. Particularly the problems involving the optimizer, version down to the exact defined patch number is a good idea. Secondly, you took the time to submit the question so I guess you want a response. If you really want to see the answer and then providing an example is one of the most important things that you can do. I'm going to do here for you, but in general people on this forum come and go and are often pushed into lurkitude, so if you want the coax to provide you with an example of work is the key.
DROP TABLE store1 PURGE; CREATE TABLE store1( store_id INTEGER NOT NULL ,shape MDSYS.SDO_GEOMETRY ,PRIMARY KEY(store_id) ); DROP TABLE client2 PURGE; CREATE TABLE client2( client_id INTEGER NOT NULL ,shape MDSYS.SDO_GEOMETRY ,PRIMARY KEY(client_id) ); CREATE OR REPLACE PROCEDURE seeder( p_client_count IN NUMBER ,p_store_count IN NUMBER ) AS sdo_foo MDSYS.SDO_GEOMETRY; int_counter NUMBER; FUNCTION random_point RETURN MDSYS.SDO_GEOMETRY AS num_x1 NUMBER; num_y1 NUMBER; BEGIN num_x1 := dbms_random.value(-179,179); num_y1 := dbms_random.value(-89,89); RETURN MDSYS.SDO_GEOMETRY( 2001 ,8265 ,MDSYS.SDO_POINT_TYPE( num_x1 ,num_y1 ,NULL ) ,NULL ,NULL ); END random_point; BEGIN int_counter := 1; FOR i IN 1 .. p_client_count LOOP -- Create a client point sdo_foo := random_point(); INSERT INTO client2 VALUES ( int_counter ,sdo_foo ); int_counter := int_counter + 1; END LOOP; int_counter := 1; FOR i IN 1 .. p_store_count LOOP -- Create a store polygon of some kind sdo_foo := MDSYS.SDO_GEOM.SDO_ARC_DENSIFY( MDSYS.SDO_GEOM.SDO_BUFFER( random_point() ,5000 ,0.05 ) ,0.05 ,'arc_tolerance=0.05' ); INSERT INTO store1 VALUES ( int_counter ,sdo_foo ); int_counter := int_counter + 1; END LOOP; COMMIT; END seeder; / BEGIN seeder(10000,200); END; / BEGIN INSERT INTO user_sdo_geom_metadata( table_name ,column_name ,diminfo ,srid ) VALUES ( 'STORE1' ,'SHAPE' ,MDSYS.SDO_DIM_ARRAY(MDSYS.SDO_DIM_ELEMENT('X',-180,180,.05),MDSYS.SDO_DIM_ELEMENT('Y',-90,90,.05)) ,8265 ); COMMIT; EXCEPTION WHEN OTHERS THEN NULL; END; / BEGIN INSERT INTO user_sdo_geom_metadata( table_name ,column_name ,diminfo ,srid ) VALUES ( 'CLIENT2' ,'SHAPE' ,MDSYS.SDO_DIM_ARRAY(MDSYS.SDO_DIM_ELEMENT('X',-180,180,.05),MDSYS.SDO_DIM_ELEMENT('Y',-90,90,.05)) ,8265 ); COMMIT; EXCEPTION WHEN OTHERS THEN NULL; END; / CREATE INDEX store1_spx ON store1 (shape) INDEXTYPE IS MDSYS.SPATIAL_INDEX NOPARALLEL; CREATE INDEX client2_spx ON client2 (shape) INDEXTYPE IS MDSYS.SPATIAL_INDEX NOPARALLEL; /* Works as expected */ SELECT s.store_id ,c.client_id ,MDSYS.SDO_NN_DISTANCE(1) FROM store1 s ,client2 c WHERE MDSYS.SDO_NN( s.shape ,c.shape ,'sdo_num_res=1' ,1 ) = 'TRUE'; /* No worky? Works for me */ SELECT ns.store_id ,COUNT(ns.client_id) FROM ( SELECT s.store_id ,c.client_id FROM store1 s ,client2 c WHERE MDSYS.SDO_NN( s.shape ,c.shape ,'sdo_num_res=1' ,1 ) = 'TRUE' ) ns GROUP BY ns.store_id ORDER BY ns.store_id;
So I wrote this about 12 c (12.1.0.2.0) and everything works fine for me. Then I moved back from 11 GR 2 (11.2.0.4.0) and of course, there are questions. So I guess that you don't use flavor of 11g. So at this point we can look at the docs and see for 11g, have you often need to specify which table is the head and that is the one that has the spatial index to use.
http://docs.Oracle.com/CD/E11882_01/AppDev.112/e11830/sdo_operat.htm#SPATL1032Its rather interesting that the optimizer of 12 c knows what you want, when I had to squint myself at your request and to play a little with the refining. Note that SDO_NN is sensitive, because the geometry of the main table should come second in the operator. I did not know that on the top of my head.
SELECT /*+ LEADING(c) INDEX(s store1_spx) */ s.store_id ,c.client_id ,MDSYS.SDO_NN_DISTANCE(1) FROM store1 s ,client2 c WHERE MDSYS.SDO_NN( s.shape ,c.shape ,'sdo_num_res=1' ,1 ) = 'TRUE'; SELECT ns.store_id ,COUNT(ns.client_id) FROM ( SELECT /*+ LEADING(c) INDEX(s store1_spx) */ s.store_id ,c.client_id ,MDSYS.SDO_NN_DISTANCE(1) FROM store1 s ,client2 c WHERE MDSYS.SDO_NN( s.shape ,c.shape ,'sdo_num_res=1' ,1 ) = 'TRUE' ) ns GROUP BY ns.store_id ORDER BY ns.store_id;
So I think that is your answer. Give it a shot and see if this fits the Bill. Of course, moving to 12 c would be useful for such things. It would be interesting to collect more examples of this kind of space thing where 12 c is the answer. Also, would be nice if we could mark somehow this discussion as applying only to 11g and earlier versions.
See you soon,.
Paul
-
Could not use the Brush tool because there is not enough memory (RAM)
Hello, I found is a problem that I can not use the Brush tool error message could not use the Brush tool as there is not enough memory (RAM) I use photoshop cc here is my system information:
Adobe Photoshop Version: 2015.1.1 20151209.r.327 2015/12 / 09:23:59:59 CL 1055659 x 64
Operating system: Windows 64-bit 10
Version: 10 or higher
System architecture: Intel CPU Family: 6, model: 12 Stepping: 3 with MMX, SSE whole, FP SSE, SSE2, SSE3, SSE4.1, SSE4.2, AVX, AVX2, HyperThreading
Physical processor count: 4
Number of logical processors: 8
Processor speed: 2494 MHz
Built-in memory: 16267 MB
Free memory: 8727 MB
Memory available to Photoshop: 14479 MB
Memory used by Photoshop: 55%
Range of modifier: enabled.
Space design: disabled.
Work plans: enabled.
Multi-frequency 3D printing: disabled.
HighBeam: enabled.
Tile image size: 1024K
Image cache level: 4
Overview of fonts: medium
TextComposer: Latin
Display: 1
Limits of the display: top = 0, left = 0, low = 1080, right = 1920
OpenGL drawing: enabled.
OpenGL allows old GPU: not detected.
OpenGL drawing mode: Advanced
OpenGL allows Normal Mode: true.
OpenGL allows Advanced Mode: true.
AIFCoreInitialized = 1
AIFOGLInitialized = 1
OGLContextCreated = 1
NumGLGPUs = 1
NumCLGPUs = 2
glgpu [0]. GLVersion = "3.0".
glgpu [0]. IsIntegratedGLGPU = 1
glgpu [0]. GLMemoryMB = 2048
glgpu [0]. GLName = "Intel(r) HD 4600 graphics card"
glgpu [0]. GLVendor = "Intel."
glgpu [0]. GLVendorID = 32902
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glgpu [0]. GLDriverDate = "20150717000000.000000 - 000.
glgpu [0]. CanCompileProgramGLSL = 1
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glgpu [0] .glGetString [GL_SHADING_LANGUAGE_VERSION] = ' 1.30 - Build 10.18.15.4256.
glgpu [0] .glGetProgramivARB [GL_FRAGMENT_PROGRAM_ARB] [GL_MAX_PROGRAM_INSTRUCTIONS_ARB] = [1447]
glgpu [0] .glGetIntegerv [GL_MAX_TEXTURE_UNITS] = [8]
glgpu [0] .glGetIntegerv [GL_MAX_COMBINED_TEXTURE_IMAGE_UNITS] = [192]
glgpu [0] .glGetIntegerv [GL_MAX_VERTEX_TEXTURE_IMAGE_UNITS] = [32]
glgpu [0] .glGetIntegerv [GL_MAX_TEXTURE_IMAGE_UNITS] = [32]
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glgpu [0] .glGetIntegerv [GL_MAX_FRAGMENT_UNIFORM_COMPONENTS] = [4096]
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clgpu [0]. CLVendor = "Intel(r) Corporation"
clgpu [0]. CLVendorID = 32902
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clgpu [0]. CUDASupported = 0
clgpu [0]. CLBandwidth = 1.68648e + 010
clgpu [0]. CLCompute = 134,55
clgpu [1]. CLPlatformVersion = "1.2".
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clgpu [1]. IsIntegratedCLGPU = 0
clgpu [1]. CLMemoryMB = 4096
clgpu [1]. CLName = 'GeForce GTX 850M.
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clgpu [1]. CLCompute = 354.272
Type of license: subscription
Serial number: 90970505697637150612
Feature::Photoshop / Extended: WE
Feature::Photoshop/standard: WE
Feature::Photoshop/test: OFF
Feature:32 - Bit layers: WE
Feature::CountTool: WE
Feature::Acrobat3D: WE
Feature::measurement: WE
Feature::MATLAB: WE
Feature::VanishingPointMeasurement: WE
Feature::VanishingPoint3DSExport: WE
Feature::VanishingPointDXFExport: WE
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Feature::Timeline: WE
Feature::ExtendedMenuBar: WE
Feature::3DPrint App: WE
Feature::ImageStack creation: WE
Feature::ImageStack edition: WE
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Feature::ACRFilterAllowed: WE
Feature::ACRFilterAvailable: WE
Feature::ExportAssetsQueueFeature: OFF
Feature::creative cloud staged: OFF
Feature::3DMultitonePrinting: OFF
Feature::artboards: WE
Feature::Playground: OFF
Feature::chording range: WE
The application folder: G:\Program Files\Adobe\Adobe Photoshop CC 2015\
Temporary file path: C:\Users\PADREM~1\AppData\Local\Temp\
Zero Photoshop has async I/O active
Scratch the volumes:
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Matlab 16.1.1 operation (2015.1.1 x 001 003 x)
maximum 16.1.1 (2015.1.1 x 001 003 x)
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Median 16.1.1 (2015.1.1 x 001 003 x)
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Plug-ins option and the third: NONE
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Please see the following article: preference file works, names, places | Photoshop CC 2014
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What is the right time to use the index with force?
I have an EMPLOYEE table. I join with the ROLE, and it has only about 200 distinct values on column EMPLOYEE. EMPLOYEE_TYPE_ID.
Select / * + INDEX (an i_employee_type_id) * / b.SID as EMP_NAME, b.role_cd in the ROLE
Of
EMPLOYEE,
B ROLE
where
a.EMPLOYEE_TYPE_ID = b.EMPLOYEE_TYPE_ID
AND a.EFFECTIVE_END_TS > = systimestamp;
Is it a good idea to use the index? .. Or let the full table scan.
SQL > select distinct EMPLOYEE_TYPE_ID of the EMPLOYEE;
238 selected lines.
If you don't know it will help not to use.
Personally, I found several SQLs with index finger tips (written by programmers thinking index access is ALWAYS GOOD) end up harming performance. Oracle made a reading diluvium full table scan, single index reads as follows, according to the % of the returned array it is actually faster to do a full table scan. The optimizer did a great job to determine this.
If you think there are cardinality estimation problems, and the optimizer expects a large number of lines when there are actually few being returned, in THIS case a suspicion was justified. Even so, in this case, I prefer that oracle manages the flag itself.
You can do this by running the SQL tuning advisor. In fact, it will trigger the optimizer checks that the estimates are turned off and it will create a profile for you. (A profile is actually a stored set of advice that set the execution plan for you). If at the point where the underlying data changes significantly and profile ends up hurting performance, you do not need to touch the code like you would with manually added notes, you can just disable or delete the profile and let the optimizer re - analyze the statement.
Concerning
EDIT: In case of small tables, it is preferable to just cache the whole table in the POOL to KEEP and let oracle scan if necessary.
Edit2: With the notable exception of index fast full scans, which are diluvium index readings. But they are only relevant when the request is quite satisfied by the index and has no need to visit the table.
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SDO_NN giving ORA-13249: SDO_NN cannot be assessed without using the index
Hi people,
I do not understand why the SDO_NN gives ORA-13249 in circumstances.
SQL > SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and title like '%' and rownum < 10;
TITLE
--------------------------------------------------------------------------------
MultiPoint_305199
LineString_691779
MultiPolygon_180478
MultiPolygon_358113
MultiPolygon_53008
MultiPolygon_249905
MultiPolygon_204076
MultiPolygon_636994
MultiPoint_464514
9 selected lines.
SQL > SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and timestamp > = to_timestamp (January 6, 2011 ', ' dd/mm/yyyy') and rownum < 10;
SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and timestamp > = to_timestamp (January 6, 2011 ', ' dd/mm/yyyy') and rownum < 10
*
ERROR on line 1:
ORA-13249: SDO_NN cannot be assessed without using the index
ORA-06512: at the 'MDSYS. MD", line 1723
ORA-06512: at the 'MDSYS. MDERR", line 17
ORA-06512: at the 'MDSYS. PRVT_IDX', line 49
The spatial index is created with:
CREATE the INDEX SlavaTest_geometry_idx_spatial ON SlavaTest (geometry) INDEXTYPE IS mdsys.spatial_index;
'Title' and 'timestamp' columns have an index.
Note the query comes from Hibernate and I can't change it's arbitrary.Slava2 wrote:
What this means - there is a bug in Oracle?Well, it could probably be considered a, but [url http://docs.oracle.com/cd/E11882_01/appdev.112/e11830/sdo_operat.htm#i78067] documentation on SDO_NN warns you:
Documentation says:
However, if the column in the WHERE clause predicate specifies a non-space column in the table for geometry1 with an associated index, make sure that this index is not used by specifying the NO_INDEX indicator for this index.See you soon,.
Stefan
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