Doubt to_char

Could someone explain to me the meaning of:

To_char(hire_date-1,'d')

The question is:

Create a query that displays the emp surname, hire_date and the day began. The label for the Date column.
Sort the results by the day of the week from Monday.

Soln:

Select last_name, hire_date, TO_CHAR (hire_date, 'DAY') DAY
employees
order by TO_CHAR (hire_date-1, 'd');

How does the order of?

Hello

Try to view the expression did you place your order BY and see:

select        last_name
,       hire_date
,       TO_CHAR (hire_date, 'DAY')      AS DAY
,       TO_CHAR (hire_date - 1, 'd')     AS order_by_exp          -- For testing only
from        employees
order by  TO_CHAR (hire_date - 1, 'd');

To_char ("dt," d ") returns '1' if dt is a Sunday,"2"If dt is a Monday,...,"7"If dt is a Saturday (depending on your settings for NLS_TERRITORY).
If you would be perfect for ORDER BY Sunday come first, but you want the first come Monday (1 day later). So if you subtract 1 day from dt and use
To_char (dt - 1, '), then you'll have an expression that returns the value '1' if dt is a Monday (and therefore, dt-1 is a Sunday), "2" If dt is a Tuesday (and dt-1 is a Monday),..., "7" If dt is a Sunday (dt-1 Saturday) and (depending on your settings for NLS_TERRITORY).

Tags: Database

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Doubt function to_char (date, 'month')

Hello
Hope you have a great day.
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```
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```
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The database version is 11.2.0.3 64 bit.
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Concerning
Carlos

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doubt, querying with dates

Hi all, I have a doubt, a sql statement that includes the date of the interrogation.

  1  SELECT rsh.shipment_num "File#"
  2        ,mmt.transaction_date "Transaction Date"
  3  FROM rcv_shipment_headers rsh,
  4       ap_suppliers aps,
  5    po_headers_all pha,
  6    po_lines_all pla,
  7    mtl_system_items_kfv msi,
  8    rcv_shipment_lines rsl,
  9    rcv_transactions rcv,
 10    mtl_material_transactions mmt,
 11    mtl_transaction_types mtt
 12  WHERE rsh.vendor_id = aps.vendor_id
 13  AND pha.po_header_id = pla.po_header_id
 14  AND pla.item_id = msi.inventory_item_id
 15  AND pha.po_header_id = rsl.po_header_id
 16  and pla.po_line_id = rsl.po_line_id
 17  AND rsl.shipment_header_id = rsh.shipment_header_id
 18  AND rsl.item_id = msi.inventory_item_id
 19  AND rsl.to_organization_id = msi.organization_id
 20  AND rcv.shipment_header_id = rsh.shipment_header_id
 21  AND rcv.organization_id = msi.organization_id
 22  AND rcv.po_header_id = pha.po_header_id
 23  AND rcv.po_line_id = pla.po_line_id
 24  --and pla.org_id = msi.organization_id
 25  AND rsh.SHIPMENT_NUM = 'AP1005'
 26  --AND mmt.transaction_date = TO_CHAR(TO_DATE('14-SEP-2012','DD-MON-YYYY'))
 27  AND rcv.transaction_type = 'DELIVER'
 28  AND rcv.source_document_code = 'PO'
 29  --AND rcv.subinventory = 'Vessel'
 30  AND mmt.rcv_transaction_id = rcv.transaction_id
 31  AND mmt.transaction_type_id = mtt.transaction_type_id
 32* AND rcv.organization_id = 81
SQL> /

File#                          Transacti
------------------------------ ---------
AP1005                         14-SEP-12
AP1005                         14-SEP-12

Now the date of passage

  1  SELECT rsh.shipment_num "File#"
  2        ,mmt.transaction_date "Transaction Date"
  3  FROM rcv_shipment_headers rsh,
  4       ap_suppliers aps,
  5    po_headers_all pha,
  6    po_lines_all pla,
  7    mtl_system_items_kfv msi,
  8    rcv_shipment_lines rsl,
  9    rcv_transactions rcv,
 10    mtl_material_transactions mmt,
 11    mtl_transaction_types mtt
 12  WHERE rsh.vendor_id = aps.vendor_id
 13  AND pha.po_header_id = pla.po_header_id
 14  AND pla.item_id = msi.inventory_item_id
 15  AND pha.po_header_id = rsl.po_header_id
 16  and pla.po_line_id = rsl.po_line_id
 17  AND rsl.shipment_header_id = rsh.shipment_header_id
 18  AND rsl.item_id = msi.inventory_item_id
 19  AND rsl.to_organization_id = msi.organization_id
 20  AND rcv.shipment_header_id = rsh.shipment_header_id
 21  AND rcv.organization_id = msi.organization_id
 22  AND rcv.po_header_id = pha.po_header_id
 23  AND rcv.po_line_id = pla.po_line_id
 24  --and pla.org_id = msi.organization_id
 25  --AND rsh.SHIPMENT_NUM = 'AP1005'
 26  AND mmt.transaction_date = TO_CHAR(TO_DATE('14-SEP-2012','DD-MON-YYYY'))
 27  AND rcv.transaction_type = 'DELIVER'
 28  AND rcv.source_document_code = 'PO'
 29  --AND rcv.subinventory = 'Vessel'
 30  AND mmt.rcv_transaction_id = rcv.transaction_id
 31  AND mmt.transaction_type_id = mtt.transaction_type_id
 32* AND rcv.organization_id = 81
SQL> /

no rows selected

Can someone pls suggest me where I am doing wrong.

Any help is appreciated,
Thanks in advance

You can try the below

AND trunc(mmt.transaction_date) = TO_DATE('14-SEP-2012','DD-MON-YYYY')

I hope that your column is DATE data type. You need not use to_char. When you use a STRING comparison will happen.

More on the date of your field is assigned a part of the TIME. You must trucate the time part.

Or if you plan to use the index on the DATE column, you can write it as

AND mmt.transaction_date between TO_DATE('14-SEP-2012','DD-MON-YYYY') and TO_DATE('14-SEP-2012 23:59:59','DD-MON-YYYY hh24:mi:ss')

Edited by: jeneesh on Sep 14, 2012 5:19 PM

To_Number doubt
Hi once again, EMSI,
I have this doubt, always on implicit conversions... (!!!!)
I read the book SQL Fundamentals 1 corrected to prepare for the exam, at the end of each chapter there are a few questions to prove your understanding and a few pages later he has the answers. There is this question:

What value is returned after executing the next statement?

SELECT TO_NUMBER (1234.49, '999999.9') FROM DUAL;

This query generates an error because "education is trying to convert a number using a mask of incompatible format. "If the expression was TO_NUMBER (1234,49, '999999.99') number would return.
My question is: WHY?
TO_NUMBER function gets a string as the first parameter, then it implicitly converts 1234.49 to '1234.49', shouldn't around it up to the first decimal digit and 1234.5 back?
just as would a to_char?

Thank you

Paolo
Hi, Paolo.

955202 wrote:
... This query generates an error because "education is trying to convert a number using a mask of incompatible format. "If the expression was TO_NUMBER (1234,49, '999999.99') number would return.
My question is: WHY?
TO_NUMBER function gets a string as the first parameter, then it implicitly converts 1234.49 to "1234.49."

Exactly! If you use the wrong data type, Oracle will do an implicit conversion, when possible.

shouldn't it round to the first decimal digit and 1234.5 back?
just as would a to_char?

To_char rounds the number, as you said, but only if you explicitly tell him how much of numbers that you want after the comma, like this:
```
SELECT     TO_CHAR (1234.49, '999999.9')     AS explicit_result
FROM     dual;
```
Output:
```
EXPLICIT_RESULT
---------------
   1234.5
```
But you're not explictly tell how many digits you want. You're not explictly calling TO_CHAR at all; you call it implictly, as if your were doing that:
```
SELECT     TO_CHAR ('1234.49')          AS implicit_result
FROM     dual;
```
Output:
```
IMPLICIT_RESULT
---------------
1234.49
```

Behavior of $ facsimile in function TO_CHAR
Hello
```
SELECT status_cid,
           LENGTH (status_cid) len, 
           TO_CHAR (status_cid, '$99') status_cid_1,
           LENGTH (TO_CHAR (status_cid, '$99')) len_1
  FROM status

Result 

STATUS_CID     LEN     STATUS_CID_1     LEN_1
1     1       $1     4
15     2      $15     4
```
Length of the column in the table number iis-status_cid (3).

My doubt is why there are spaces in the alias column status_cid_1 while $ facsimile is used in the function to_char top of the query.

Thanks in advance.

Kind regards
Prakash
That's the negative symbol

a number can be negative...

http://Nuijten.blogspot.com/2011/09/quick-how-long-is-this-string.html

Published by: Alex Nuijten on March 19, 2012 13:21

some doubts in the conversion of oracle query
I have to convert the following query in ms access to oracle.

INSERT INTO the Bill (Reffacture, InvoiceDesc)
Select a_Invoices! [Ref provider] & "-" & Trim (a_Invoices! [invoice No.]) & "Q" & DatePart ("q", [invDate]) & "-" & DatePart("yyyy",[invDate]) & "SB" as Reffacture.
Trim (a_Invoice_Desc! [Invoice line Description]) AS a Expr4
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AND (a_Invoices. [Invoice No.] is a_Invoice_Desc. [Invoice No.)]
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Hello

882431 wrote:
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For example: ' 18/4/2011 0:0:0.0' varchar field is, I tried with "' 2011/4/18 as yyyy/mm/dd ', I can add hh: mm: for the moment (I wasn't looking this), but there is one.0, can someone please tell me how shud convert it..." Sorry if asking a basic question, I already searched but to no avail.

DATEs do not include fractions of a second. If you don't mind losing fractions of a second, you can simply remove them before pass the string to TO_DATE, like this
```
TO_DATE ( REGEXP_REPLACE ( varchar2_column
                , '\.[0-9]*$'
                )
     , 'YYYY/MM/DD HH24:MI:SS'
     )
```
REGEXP_REPLACE will remove the decimal point and any numbers after him. If the string does not contain a decimial, it is correct: REGEXP_REPLACE returns the immutable string in this case.

If the fraction of a second is important, use a TIMESTAMP instead of a DATE column (and use the TO_TIMESTAMP instead of TO_DATE function).

Error that using TO_CHAR (TRUNC (SYSDATE), 'DAY') FROM DUAL
Hello everyone.

I have a pl/sql procedure that contains TO_CHAR (TRUNC (SYSDATE), 'DAY') FROM DUAL to capture the DAY in a variable. Now when I access this procedure of someother application (Workflow), I get the error ORA-01841: (full) year must be understood between-4713 and 9999 and not be 0.

If I do not use TO_CHAR (TRUNC (SYSDATE), 'DAY') and hardcode the value, it throws no error.

Any ideas on this error?

Is this something to do with the NLS_DATE?

Thank you

Kind regards

Pavan K
>
...

IF (TRIM (SAT_DAY) = 'SATURDAY')
THEN
L_DAYS: = L_DAYS + 2;
ELSIF (TRIM (SAT_DAY) = "SUNDAY")
THEN
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ON THE OTHER
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END IF;
L_DAYS: = L_DAYS * 24 * 60;

First, you add two days if it's a Sunday.
Then you multiply by 24 * 60.
Are you sure that this logic is ok?

I guess you just use bad values for the L_days parameter.

The difference between last Friday and today, without doubt is:

last Friday, the variable L_days has been VERY VERY VERY big, for example 20000000 = (x + 2) * 24 * 60)

Today, it's only 1 * 24 * 60 = 1440.

Published by: W. Sven on September 21, 2009 18:01

Looking at the error message...

ORA-01841: (full) year must be between-4713 and 9999

My current guess is that you have created a date that goes beyond the year 9999.

Published by: W. Sven on September 21, 2009 18:05

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