Drive the analytic function

Similar Questions

• SQL using the analytic function

  
  Hi all

  I want a help in the creation of my SQL query to retrieve the data described below:

  I have a test of sample table containing data as below:

  State ID Desc

  MICHAEL 1 T1

  ACTIVE 2 T2

  T3 3 SUCCESS

  DISABLE THE T4 4

  The thing I want to do is to select all the lines with an ACTIVE status in the table but is there is no ACTIVE status, my request will give me the last line with MICHAEL status.

  I can do this in a single request by using the analytical function for example, if yes can yiu help me on the request of unpacking.

  Kind regards

  Raluce

  Something like that?

  I had to fix it.

  with testdata until)
  Select 1 id, "T1" dsc "DISABLED" status of Union double all the
  Select 2 id, 'T2' dsc, the status "ACTIVE" of all the double union
  Select id 3, "T3" dsc, the status of 'SUCCESS' of all the double union
  Select 4 id, "T4" dsc "DISABLED" status of double
  )

  Select
  ID
  dsc
  status
  of testdata
  where
  status =
  -case when (select count (*) in testdata where status = 'ACTIVE') > 0
  then 'ACTIVE '.
  Another 'DISABLED '.
  end
  and)
  ID in (select id from testdata where status = ' ACTIVE')
  or
  ID = (select max (id) in testdata when status = 'DISABLED')
  )

  STATE ID DSC

  '2' 'T2' 'ACTIVE '.

  Maybe it's more efficient

  Select
  ID
  dsc
  status
  of testdata
  where
  status =
  -case when (select count (*) in testdata where status = 'ACTIVE') > 0
  then 'ACTIVE '.
  Another 'DISABLED '.
  end
  and
  ID =)
  -case when (select count (*) in testdata where status = 'ACTIVE') > 0
  then id
  on the other
  (select max (id) in testdata when status = 'DISABLED')
  end
  )

  Post edited by: correction of chris227

  Post edited by: chris227
  extended

• A question about the analytical function used with the GROUP BY clause in SHORT

  Hi all
  
  I created the following table named myenterprise
  

  CITY       STOREID    MONTH_NAME TOTAL_SALES            
  ---------- ---------- ---------- ---------------------- 
  paris      id1        January    1000                   
  paris      id1        March      7000                   
  paris      id1        April      2000                   
  paris      id2        November   2000                   
  paris      id3        January    5000                   
  london     id4        Janaury    3000                   
  london     id4        August     6000                   
  london     id5        September  500                    
  london     id5        November   1000

  If I want to find which is the total sales by city? I'll run the following query

  SELECT city, SUM(total_sales) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  that works very well and produces the expected result, i.e.

  CITY       TOTAL_SALES_PER_CITY   
  ---------- ---------------------- 
  london     10500                  
  paris      17000            

  Now in one of my books SQL (Mastering Oracle SQL) I found another method by using the SUM, but this time as an analytic function. Here's what the method of the book suggests as an alternative to the problem:

  SELECT city, 
         SUM(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  I know that the analytic functions are executed after the GROUP BY clause has been transformed completely and Unlike regular aggregate functions, they return their result for each line belonging to the partitions specified in the partition clause (if there is a defined partition clause).
  
  Now my problem is that I do not understand what we have to use two functions SUM? If we only use one only, i.e.

  SELECT city, 
         SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  This generates the following error:

  Error starting at line 2 in command:
  SELECT city, 
         SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY
  Error at Command Line:2 Column:11
  Error report:
  SQL Error: ORA-00979: not a GROUP BY expression
  00979. 00000 -  "not a GROUP BY expression"
  *Cause:    
  *Action:

  The error is generated for the line 2 column 11 which is, for the expression SUM (total_sales), well it's true that total_sales does not appear in the GROUP BY clause, but this should not be a problem, it has been used in an analytical function, so it is evaluated after the GROUP BY clause.
  
  So here's my question:
  
  Why use SUM (SUM (total_sales)) instead of SUM (total_sales)?
  
  
  Thanks in advance!
  :)
  
  
  
  
  
  In case you are interested, that's my definition of the table:

  DROP TABLE myenterprise;
  CREATE TABLE myenterprise(
  city VARCHAR2(10), 
  storeid VARCHAR2(10),
  month_name VARCHAR2(10),
  total_sales NUMBER);
  
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'January', 1000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'March', 7000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'April', 2000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id2', 'November', 2000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id3', 'January', 5000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id4', 'Janaury', 3000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id4', 'August', 6000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id5', 'September', 500);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id5', 'November', 1000);

  Edited by: dariyoosh on April 9, 2009 04:51

  It is clear that thet Analytics is reduntant here...
  You can even use AVG or any analytic function...

  SQL> SELECT city,
    2         avg(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
    3  FROM myenterprise
    4  GROUP BY city
    5  ORDER BY city, TOTAL_SALES_PER_CITY;
  
  CITY       TOTAL_SALES_PER_CITY
  ---------- --------------------
  london                    10500
  paris                     17000
  

• Report Builder 6i do not recognize the analytical functions

  Hi all, in an attempt to speed up a slow query, I applied the analytical function to it. I can save the query in the generator without any problem, however, I can't create data between this request and other links. After I have comment on the analytical function, data bindings can be made. My colleague says Report Builder 6i is too old so he can recognize only the ANSI SQL syntax. Since our server DB uses Oracle 10 g 2, is there a way for the generator of reports to identify and compile syntax of Oracle 10 g?
  
  Thank you very much.

  Hello

  Your colleague is right. Even if the SQL query is executed by the DB server, reports must analyze the SQL query.

  The SQL parser included in reports 6i-based 8.0.6

  You can see this version using the report designer:

  Menu: Help-> on Report Builder...

  ORACLE Server Release 8.0.6.0.0

  Concerning

• Using the analytic function

  Oracle 11g Release 2

  I'm assuming that the best solution is the use of analytical functions.

  create table test3
  ( part_type_id  varchar2(50)
  ,group_id      number
  ,part_desc_id  number
  ,part_cmt      varchar2(50)
  )
  /
  
  insert into test3 values( 'ABC123',1,10,'comment1');
  insert into test3 values( 'ABC123',1,10,'comment2');
  insert into test3 values( 'ABC123',2,15,'comment1');
  insert into test3 values( 'ABC123',2,15,'comment2');
  insert into test3 values( 'EFG123',25,75,'comment3');
  insert into test3 values( 'EFG123',25,75,'comment4');
  insert into test3 values( 'EFG123',25,75,'comment5');
  insert into test3 values( 'XYZ123',1,10,'comment6');
  insert into test3 values( 'XYZ123',2,15,'comment7');
  commit;
  
  select * from test3;
  
  PART_TYPE_ID           GROUP_ID PART_DESC_ID PART_CMT
  -------------------- ---------- ------------ --------------------
  ABC123                        1           10 comment1
  ABC123                        1           10 comment2
  ABC123                        2           15 comment1
  ABC123                        2           15 comment2
  EDG123                        25          75 comment3
  EDG123                        25          75 comment4
  EDG123                        25          75 comment5
  XYZ123                        1           10 comment6
  XYZ123                        2           15 comment7
  
  9 rows selected.
  
  Desired output:
  
  PART_TYPE_ID           GROUP_ID PART_DESC_ID PART_CMT
  -------------------- ---------- ------------ --------------------
  ABC123                        1           10 comment1 
  ABC123                        2           15 comment1
  XYZ123                        1           10 comment1
  XYZ123                        2           15 comment2
  
  RULE: where one part_type_id has multiple (2 or more distinct combinations) of group_id/part_desc_id
  
  NOTE: There are about 12 columns in the table, for brevity I only included 4.
  
  
  
  

  Post edited by: orclrunner was updated desired output and rule

  Hello

  Here's one way:

  WITH got_d_count AS

  (

  SELECT part_type_id, group_id, part_desc_id

  MIN (part_cmt) AS min_part_cmt

  COUNT AS d_count (*) OVER (PARTITION BY part_type_id)

  OF test3

  GROUP BY part_type_id, group_id, part_desc_id

  )

  SELECT DISTINCT

  group_id, part_desc_id, part_type_id, min_part_cmt

  OF got_d_count

  WHERE d_count > 1

  ;

  Output:

  GROUP_ID PART_DESC_ID MIN_PART_CMT PART_TYPE_ID

  ------------ ---------- ------------ ------------

  ABC123 1 10 comment1

  ABC123 2 15 comment1

  XYZ123 1 10 comment6

  XYZ123 2 15 comment7

  Analytical functions, such as the COUNTY and MIN, many global versions, in addition, it can give the same results.  Use the analytical versions when each row of output corresponds to exactly 1 row of input and the aggregate and GROUP BY version when each line of output corresponds to a group of lines 1 or more input.  In this issue, each line of output appears to be a group of input lines having the same group_id, part_type_id, and part_desc_id (I'm guessing just, this only has never stated), so I used GROUP BY to get 1 row of output for every input lines.

• How to define the condition in the analytic function

  Oracle 10g version

  Hi all

  I have the following data samples:

  Examples of data

  WITH DATA AS

  (

  SELECT 100 case_id, next_date, to_date('01-feb-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-jan-2015','dd-mon-yyyy')

  SELECT 100 case_id, next_date, to_date('01-mar-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-feb-2015','dd-mon-yyyy')

  SELECT 100 case_id, next_date, to_date('01-apr-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-may-2015','dd-mon-yyyy')

  SELECT 100 case_id, to_date('01-jun-2015','dd-mon-yyyy') next_date, to_date('01-apr-2015','dd-mon-yyyy') crt_date FROM dual

  )

  SELECT wagneur, MIN (next_date) OVER (PARTITION BY case_id) min_dt_analytical

  ,(

  SELECT MIN (next_date) DATA dd

  WHERE dd.case_id = d.case_id

  AND dd.next_date > crt_date

  ) min_dt_sub_query

  DATA d

  ;

  My question is that I get min_dt_sub_query using sub query but I want to use the analytical instead of query sub function so I created min_dt_analytical column, but I do not have how to give the condition that is AND dd.next_date > crt_date analytical so that I can get the same result as min_dt_sub_query data accordingly. Thanks in advance

  Concerning

  MIT

  Do not know if I understood your needs... but... something like that?

  WITH DATA AS (SELECT 100 case_id, next_date, to_date('01-feb-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-jan-2015','dd-mon-yyyy')

  SELECT the 100 case_id, next_date, to_date('01-mar-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-feb-2015','dd-mon-yyyy')

  SELECT the 100 case_id, next_date, to_date('01-apr-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-may-2015','dd-mon-yyyy')

  SELECT 100 case_id, next_date, to_date('01-apr-2015','dd-mon-yyyy') double crt_date to_date('01-jun-2015','dd-mon-yyyy'))

  SELECT d.

  MIN (next_date) OVER (PARTITION BY case_id) min_dt_analytical

  MIN(CASE WHEN next_date > crt_date THEN next_date ELSE NULL END) OVER (PARTITION BY case_id) AS min_dt_sub_query2

  DATA d;

  HTH

• Nth salary using the analytic function

  I use under function to calculate second highest with empno and deptno salary.

  Is it possible to get the same result with another query without using Assembly only analytical functions condition.using and windows function is possible to get the desired output?

  SELECT e.empno,

  e.DEPTNO,

  tmp. SAL as second_higher_salary

  FROM emp e,.

  (SELECT Empno,

  DEPTNO,

  SAL,

  DENSE_RANK() (PARTITION BY deptno ORDER of sal) AS rnk

  WCP

  ) tmp

  WHERE tmp.deptno = e.deptno

  and tmp.rnk = 2

  EMPNO DEPTNO SAL

  ---------- ---------- ----------

  7934 10 2450

  7782 10 2450

  7839 10 2450

  7876 20 1100

  7369 20 1100

  7902 20 1100

  7788 20 1100

  7566 20 1100

  7900 30 1250

  7844 30 1250

  7654 30 1250

  7521 30 1250

  7499 30 1250

  7698 30 1250

  7900 30 1250

  7844 30 1250

  7654 30 1250

  7521 30 1250

  7499 30 1250

  7698 30 1250

  Here's my solution:

  Select empno,

  DEPTNO,

  FIRST_VALUE (sal) (PARTITION BY deptno ORDER by sal desc)

  de)

  SELECT EmpNo,

  DEPTNO,

  Decode (DENSE_RANK () OVER (PARTITION BY deptno order by sal desc), 1,-sal, sal) sal

  WCP

  )

  /

  EMPNO

  DEPTNO FIRST_VALUE (SAL) OVER (PARTITIONBYDEPTNOORDERBYSALDESC)

  ---------- ---------- -----------------------------------------------------

  	7782	10	2450
  	7934	10	2450
  	7839	10	2450
  	7566	20	2975
  	7876	20	2975
  	7369	20	2975
  	7788	20	2975
  	7902	20	2975
  	7499	30	1600
  	7844	30	1600
  	7654	30	1600
  	7521	30	1600
  	7900	30	1600
  	7698	30	1600

• Understanding on the analytical function sum() (order of)

  Could you please explain Having_order_by of the calculation of values of below query column?
  I understand that No_Partition column was calculated on the full set of results
  

  select level
  ,sum(level) over(order by level) Having_order_by
  ,sum(level) over() No_Partition
  from dual 
  connect by level < 6

  Hello

  ActiveSomeTimes wrote:
  Could you please explain Having_order_by of the calculation of values of below query column?
  I understand that No_Partition column was calculated on the full set of results

  select level
  ,sum(level) over(order by level) Having_order_by
  ,sum(level) over() No_Partition
  from dual
  connect by level < 6
  

  When you have an ORDER BY clause, the function works only on a window, which is a subset of the result set, compared to the current line.
  When you say 'ORDER OF LEVEL', it only will work on levels less than or equal to its current LEVEL, etc.
  LEVEL = 1, the analytic fucntion will only look at the LEVEL<= 1,="" that="" is,="" just="" 1;="">
  LEVEL = 2, the analytic fucntion will only look at the LEVEL<= 2,="" that="" is,="" 1="" and="" 2;="">
  LEVEL = 3, the analytic fucntion will only look at the LEVEL<= 3,="" that="" is,="" 1,="" 2="" and="">
  ...
  LEVEL = 6, the analytic fucntion will only look at the LEVEL<= 6,="" that="" is,="" 1,="" 2,="" 3,="" 4,="" 5="" and="">

  In the call to function without the ORDER BY clause, the examines the entire results full regrdless of what value LEVEL has on the current line.

• Purpose of the ORDER BY clause in the analytic function Min Max

  I was always using analytical functions like Min Max without ORDER BY clause. But today I used with the ORDER BY clause. The results are very different. I would like to know the purpose of the ORDER BY clause in Min, Max and analogues of analytical functions.

  user10566312 wrote:
  I was always using analytical functions like Min Max without ORDER BY clause. But today I used with the ORDER BY clause. The results are very different. I would like to know the purpose of the ORDER BY clause in Min, Max and analogues of analytical functions.

  It is a good point that many developers are not so aware. As far as I understand it the way it works.

  Some analytical functions do not need an order by or windowing clause (SUM, COUNT, MIN, etc.). If there is no specified window, then the full score is the window.
  As soon as you add a command also add you a windowing clause. This window has the default value of 'rank ofrows between unbounded preceding and current_row. So as soon as you add an order by clause, you get a sliding window.

  Documentation: http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions001.htm

  windowing_clause
  ...
  You cannot specify this clause unless you specified the order_by_clause. Window limits defined by the clause RANGE you can not specify only a single expression to the > order_by_clause. Please refer to 'Restrictions on the ORDER BY Clause'.

  example of

  with testdata as (select 10 numval, level lv from dual connect by level < 10)
  select lv, numval, sum(numval) over () sum1, sum(numval) over (order by lv) sum2
  from testdata;
  
  LV NUMVAL SUM1 SUM2
  -- ------ ---- ----
   1     10   90   10
   2     10   90   20
   3     10   90   30
   4     10   90   40
   5     10   90   50
   6     10   90   60
   7     10   90   70
   8     10   90   80
   9     10   90   90 
  

  Published by: Sven w. on 25 Sep 2012 16:57 - default behavior has been corrected. Thanks to Chris

• Helps the analytic function

  Here is an example of the table data:

  ID    NAME             Start                  
  1     SARA             01-JAN-2006     
  2     SARA             03-FEB-2006     
  3     LAMBDA             21-MAR-2006     
  4     SARA             13-APR-2006     
  5     LAMBDA             01-JAN-2007     
  6     LAMBDA             01-SEP-2007     

  I would get this:

  Name        Start               Stop
  SARA        01-JAN-2006    20-MAR-2006
  LAMBDA      21-MAR-2006     12-APR-2006
  SARA        13-APR-2006     31-DEC-2006
  LAMBDA      01-JAN-2007      <null>

  I tried using partition and run the function but partition name combines all the lines of Sara and Lambda lines into a single group/partition that is not I am trying to get.
  Is there an analytic function or other means to achieve to combine date ranges only when the same person appeared conescutively?
  Thank you.

  This can be easily achieved using tabibitosan:

  First of all, you need to identify 'groups', that each name in the list belongs

  with sample_data as (select 1 id, 'SARA' name, to_date('01/01/2006', 'dd/mm/yyyy') start_date from dual union all
                       select 2 id, 'SARA' name, to_date('03/02/2006', 'dd/mm/yyyy') start_date from dual union all
                       select 3 id, 'LAMBDA' name, to_date('21/03/2006', 'dd/mm/yyyy') start_date from dual union all
                       select 4 id, 'SARA' name, to_date('13/04/2006', 'dd/mm/yyyy') start_date from dual union all
                       select 5 id, 'LAMBDA' name, to_date('01/01/2007', 'dd/mm/yyyy') start_date from dual union all
                       select 6 id, 'LAMBDA' name, to_date('01/09/2007', 'dd/mm/yyyy') start_date from dual)
  select id,
         name,
         start_date,
         lead(start_date, 1, to_date('31/12/9999', 'dd/mm/yyyy')) over (order by start_date) next_start_date,
         row_number() over (order by start_date)
           - row_number() over (partition by name order by start_date) grp
  from   sample_data;
  
          ID NAME   START_DATE NEXT_START_DATE        GRP
  ---------- ------ ---------- --------------- ----------
           1 SARA   01/01/2006 03/02/2006               0
           2 SARA   03/02/2006 21/03/2006               0
           3 LAMBDA 21/03/2006 13/04/2006               2
           4 SARA   13/04/2006 01/01/2007               1
           5 LAMBDA 01/01/2007 01/09/2007               3
           6 LAMBDA 01/09/2007 31/12/9999               3
  

  You can see the group number is generated by comparing the rownumber overall of all lines (in order) with the rownumber of the rowset by name (in the same order) - when there is a gap because another name appears between the two, the group number changes.

  Once you have identified the number of group for each set of rows, it is easy to find the min / max values in this group:

  
  with sample_data as (select 1 id, 'SARA' name, to_date('01/01/2006', 'dd/mm/yyyy') start_date from dual union all
                       select 2 id, 'SARA' name, to_date('03/02/2006', 'dd/mm/yyyy') start_date from dual union all
                       select 3 id, 'LAMBDA' name, to_date('21/03/2006', 'dd/mm/yyyy') start_date from dual union all
                       select 4 id, 'SARA' name, to_date('13/04/2006', 'dd/mm/yyyy') start_date from dual union all
                       select 5 id, 'LAMBDA' name, to_date('01/01/2007', 'dd/mm/yyyy') start_date from dual union all
                       select 6 id, 'LAMBDA' name, to_date('01/09/2007', 'dd/mm/yyyy') start_date from dual),
       tabibitosan as (select id,
                              name,
                              start_date,
                              lead(start_date, 1, to_date('31/12/9999', 'dd/mm/yyyy')) over (order by start_date) next_start_date,
                              row_number() over (order by start_date)
                                - row_number() over (partition by name order by start_date) grp
                       from   sample_data)
  select name,
         min(start_date) start_date,
         max(next_start_date) stop_date
  from   tabibitosan
  group by name, grp
  order by start_date;
  
  NAME   START_DATE STOP_DATE
  ------ ---------- ----------
  SARA   01/01/2006 21/03/2006
  LAMBDA 21/03/2006 13/04/2006
  SARA   13/04/2006 01/01/2007
  LAMBDA 01/01/2007 31/12/9999
  

  If you want the date to appear as null max, you will need to use a cast or decode to change it - I'll leave that as an exercise for you to do! I'll also let you to find how to get the day before for the stop_date.

• Need help with the analytic function

  I want to get the highest employee details and the 2nd highest employee for a particular service. But also the Department should have more than 1 employee.
  I tried the query and it gave me the correct results. But I wonder if there is another solution than to use the subquery.
  
  Here is the table and the query result:
  

  with t as
  (
  select 1 emp_id,3 mgr_id,'Rajesh' emp_name,3999 salary,677 bonus,'HR' dpt_nme from dual union
  select 2 ,3 ,'Gangz',4500,800,'Finance' from dual  union
  select 3 ,4 ,'Sid',8000,12000,'IT' from dual  union
  select 4 ,null,'Ram',5000,677,'HR' from dual  union
  select 5 ,4,'Shyam',6000,677,'IT' from dual union
  select 6 ,4 ,'Ravi',9000,12000,'IT' from dual   
  )
  select * from 
  (select emp_id, mgr_id, emp_name, dpt_nme, salary, row_number() over (partition by dpt_nme order by salary desc) rn from t where dpt_nme in 
  (select dpt_nme from t group by dpt_nme having count(*) > 1)) where rn < 3

  Hello

  You need a subquery, but you don't need more than that.
  Here's a way to eliminate the additional subquery:

  WITH     got_analytics     AS
  (
       SELECT  emp_id,     mgr_id,     emp_name, dpt_nme, salary
       ,     ROW_NUMBER () OVER ( PARTITION BY  dpt_nme
                                 ORDER BY          salary     DESC
                         )         AS rn
       ,     COUNT (*)     OVER ( PARTITION BY  dpt_nme
                                     )         AS dpt_cnt
       FROM     t
  )
  SELECT  emp_id,     mgr_id,     emp_name, dpt_nme, salary
  ,     rn
  FROM     got_analytics
  WHERE     rn     < 3
  AND     dpt_cnt     > 1
  ;
  

  Analytical functions are calculated after the clause WHERE is applied. Since we need to use the results of the analytical ROW_NUMBER function in a WHERE clause, which means that we have to calculate ROW_NUMBER in a subquery and use the results in the WHERE clause of the main query. We can call the COUNT function analytical in the same auxiliary request and use the results in the same WHERE clause of the main query.

  Would what results you if there is a link for the 2nd highest salary in some Department? For example, if you add this line to your sample data:

  select 7 ,3 ,'Sunil',8000,12000,'IT' from dual  union
  

  ? You can use RANK rather than ROW_NUMBER.

• by using the analytical function to get the right output.

  Hello all;
  
  I have the following date of sample below
  

  create table temp_one
  (
         id number(30),   
        placeid varchar2(400),
        issuedate  date,
        person varchar2(400),
        failures number(30),
        primary key(id)
  );
  
  insert into temp_one values (1, 'NY', to_date('03/04/2011', 'MM/DD/YYYY'), 'John', 3);
  
  insert into temp_one values (2, 'NY', to_date('03/03/2011', 'MM/DD/YYYY'), 'Adam', 7);
  
  insert into temp_one values (3, 'Mexico', to_date('03/04/2011', 'MM/DD/YYYY'), 'Wendy', 3);
  
  insert into temp_one values (4, 'Mexico', to_date('03/14/2011', 'MM/DD/YYYY'), 'Gerry', 3);
  
  insert into temp_one values (5, 'Mexico', to_date('03/15/2011', 'MM/DD/YYYY'), 'Zick', 9);
  
  insert into temp_one values (6, 'London', to_date('03/16/2011', 'MM/DD/YYYY'), 'Mike', 8);

  It's the output I want
  

  placeid       issueperiod                               failures
  NY              02/28/2011 - 03/06/2011          10
  Mexico       02/28/2011 - 03/06/2011           3
  Mexico        03/14/2011 - 03/20/2011          12
  London        03/14/2011 - 03/20/2011          8

  Any help is appreciated. I'll post my request as soon as I can think of a good logic for this...

  Hello

  user13328581 wrote:
  ... Please note, I'm still learning how to use analytical functions.

  It doesn't matter; analytical functions will not help in this problem. The SUM aggregate function is all you need.
  But what do you need to GROUP BY? What is the value of each row of the result will represent? A placeid? Yes, each line will represent only placedid, but it will be divided further. You want a separate line of the output for each placeid and every week, then you'll want of the week and GROUP BY placeid. You don't want to GROUP BY the raw issuedate; that would put on 3 March and 4 March in separate groups. And you don't want to GROUP BY failures; This would mean that a line with 3 failures could never be in the same group in line with 9 failures.

  This becomes the output you posted from the sample data you posted:

  SELECT       placeid
  ,             TO_CHAR ( TRUNC (issuedate, 'IW')
                , 'MM/DD/YYYY'
              ) || ' - '|| TO_CHAR ( TRUNC (issuedate, 'IW') + 6
                                           , 'MM/DD/YYY'
                             )     AS issueperiod
  ,       SUM (failures)                  AS sumfailures
  FROM        temp_one
  GROUP BY  placeid
  ,            TRUNC (issuedate, 'IW')
  ;
  

  You can use a subquery to calculate TRUNC (issuedate, 'IW') once. The code would be of about as complicated, efficiency probably will not improve substantially and the results would be the same.

• Help me on the analytic function

  Hello
  
  I use oracle version

  SQL> select * From v$version;
  
  BANNER
  ----------------------------------------------------------------
  Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64bit Production
  PL/SQL Release 9.2.0.8.0 - Production
  CORE    9.2.0.8.0       Production
  TNS for Solaris: Version 9.2.0.8.0 - Production
  NLSRTL Version 9.2.0.8.0 - Production

  I have a following tables

  CREATE TABLE emp_info(emp_id number,ename varchar2(10),chk_date date);
  
  CREATE TABLE emp_month(emp_id number,emp_month_date date,chk_amt number(10,2));
  
  insert into emp_info VALUES (101,'PAUL',to_date('01-MAR-2009','DD-MON-YYYY'));
  insert into emp_info VALUES (102,'JOHN',to_date('01-APR-2009','DD-MON-YYYY'));
  insert into emp_info VALUES (103,'KRIS',to_date('01-MAY-2009','DD-MON-YYYY'));
  
  
  insert into emp_month values (101,'01-DEC-2008',1432);
  insert into emp_month values (101,'01-JAN-2009',1412);
  insert into emp_month values (101,'01-FEB-2009',1632);
  insert into emp_month values (101,'01-MAR-2009',1672);
  --
  insert into emp_month values (102,'01-DEC-2008',2678);
  insert into emp_month values (102,'01-JAN-2009',2786);
  insert into emp_month values (102,'01-FEB-2009',2883);
  insert into emp_month values (102,'01-MAR-2009',2653);
  insert into emp_month values (102,'01-APR-2009',2653);
  --
  insert into emp_month values (103,'01-NOV-2008',2343);
  insert into emp_month values (103,'01-DEC-2008',2311);
  insert into emp_month values (103,'01-JAN-2009',3122);
  insert into emp_month values (103,'01-FEB-2009',3412);
  insert into emp_month values (103,'01-MAR-2009',3312);
  insert into emp_month values (103,'01-APR-2009',3315);
  insert into emp_month values (103,'01-MAY-2009',4321);

  I use following the QUERY for results. Is it possible to get these same results using ANALYTICAL functions
  or I would appreciate any solution better than this.

  Select e.emp_id,e.ename,e.chk_date,sum(chk_amt) year_amt
  from emp_month em
  ,(select emp_id,ename,chk_date
  from emp_info)e
  where e.emp_id = em.emp_id
  and em.emp_month_date between trunc(e.chk_date,'YY') AND e.chk_date
  group by e.emp_id,e.ename,e.chk_date

  user12212962 wrote:

  I use following the QUERY for results. Is it possible to get these same results using ANALYTICAL functions

  or I would appreciate any solution better than this.

  I have no idea why you need analytic function. I know: there is no need to view inline in your query:

  SQL> Select e.emp_id,e.ename,e.chk_date,sum(chk_amt) year_amt
    2  from emp_month em
    3  ,(select emp_id,ename,chk_date
    4  from emp_info)e
    5  where e.emp_id = em.emp_id
    6  and em.emp_month_date between trunc(e.chk_date,'YY') AND e.chk_date
    7  group by e.emp_id,e.ename,e.chk_date
    8
  SQL> /
  
      EMP_ID ENAME      CHK_DATE    YEAR_AMT
  ---------- ---------- --------- ----------
         102 JOHN       01-APR-09      10975
         101 PAUL       01-MAR-09       4716
         103 KRIS       01-MAY-09      17482
  
  SQL> Select e.emp_id,e.ename,e.chk_date,sum(chk_amt) year_amt
    2  from emp_month em,
    3       emp_info e
    4  where e.emp_id = em.emp_id
    5  and em.emp_month_date between trunc(e.chk_date,'YY') AND e.chk_date
    6  group by e.emp_id,e.ename,e.chk_date
    7  /
  
      EMP_ID ENAME      CHK_DATE    YEAR_AMT
  ---------- ---------- --------- ----------
         102 JOHN       01-APR-09      10975
         101 PAUL       01-MAR-09       4716
         103 KRIS       01-MAY-09      17482
  
  SQL> 
  

  SY.

• confusion with the analytical functions

  I created an example where I am right now with the help of analytical functions. However, I need the query below to return an additional column. I need to return the result from:-' factor_day_sales * max (sdus)'. Any ideas?
  
  If the first column is located and must have the following results
  
  777777, 5791, 10, 1.5, 15, 90, 135, 7050
  
  the 1350 is the result, I don't know how to do. (some how to multiply factored_day_sales max (sdus) 15 470 = 7050

  create table david_sales (
  pro_id number(38),
  salesidx number (38,6),
  tim_id number(38));
  
  truncate table david_sales
  
  create table david_compensations (
  pro_id number(38),
  tim_id number(38),
  factor number(38,6));
  
  
  insert into david_sales values
  (777777, 10.00, 5795);
  insert into david_sales values
  (777777,20.00, 5795);
  insert into david_sales values
  (777777, 30.00, 5794);
  insert into david_sales values
  (777777, 40.00, 5794);
  insert into david_sales values
  (777777, 100.00, 5793);
  insert into david_sales values
  (777777, 10.00, 5793);
  insert into david_sales values
  (777777,80.00, 5791);
  insert into david_sales values
  (777777, 10.00, 5791);
  
  insert into david_compensations values
  (777777, 5795, 1.5);
  insert into david_compensations values
  (777777, 5793, 2.0);
  insert into david_compensations values
  (777777, 5792, 1.0);
  insert into david_compensations values
  (777777, 5791, 1.5);
  
  
  
      SELECT  s.pro_id sales_pro
      ,       c.pro_id comp_pro
      ,       s.tim_id sales_tim
      ,       c.tim_id comp_tim
      ,       s.salesidx day_sales
      ,       NVL(c.factor, 1) factor
      ,       s.salesidx * NVL(c.factor, 1) factored_day_sales
      ,       sum(s.salesidx                   ) over (partition by s.pro_id order by s.pro_id, s.tim_id) Sdus
      ,       sum(s.salesidx * NVL(c.factor, 1)) over (partition by s.pro_id order by s.pro_id, s.tim_id) sumMjCj 
        FROM david_sales s
        ,    david_compensations c
        WHERE s.pro_id    = c.pro_id(+)
        AND s.tim_id      = c.tim_id(+)
        AND s.tim_id     BETWEEN 5791  AND 5795

  Thanks for looking

  Is that what you want?

      SELECT  s.pro_id sales_pro
      ,       c.pro_id comp_pro
      ,       s.tim_id sales_tim
      ,       c.tim_id comp_tim
      ,       s.salesidx day_sales
      ,       NVL(c.factor, 1) factor
      ,       s.salesidx * NVL(c.factor, 1) factored_day_sales
      ,       sum(s.salesidx                   ) over (partition by s.pro_id order by s.pro_id, s.tim_id) Sdus
      ,       sum(s.salesidx * NVL(c.factor, 1)) over (partition by s.pro_id order by s.pro_id, s.tim_id) sumMjCj
      , (s.salesidx * NVL(c.factor, 1) * sum(s.salesidx                   ) over (partition by s.pro_id order by s.pro_id, s.tim_id))
        FROM david_sales s
        ,    david_compensations c
        WHERE s.pro_id    = c.pro_id(+)
        AND s.tim_id      = c.tim_id(+)
        AND s.tim_id     BETWEEN 5791  AND 5795
  
  SALES_PRO              COMP_PRO               SALES_TIM              COMP_TIM               DAY_SALES              FACTOR                 FACTORED_DAY_SALES     SDUS                   SUMMJCJ                SUMMEDMULTI
  ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ---------------------- ----------------------
  777777                 777777                 5791                   5791                   80                     1.5                    120                    90                     135                    10800
  777777                 777777                 5791                   5791                   10                     1.5                    15                     90                     135                    1350  
  

  I get the 1350

  or did you mean:

      SELECT  s.pro_id sales_pro
      ,       c.pro_id comp_pro
      ,       s.tim_id sales_tim
      ,       c.tim_id comp_tim
      ,       s.salesidx day_sales
      ,       NVL(c.factor, 1) factor
      ,       s.salesidx * NVL(c.factor, 1) factored_day_sales
      ,       sum(s.salesidx                   ) over (partition by s.pro_id order by s.pro_id, s.tim_id) Sdus
      ,       sum(s.salesidx * NVL(c.factor, 1)) over (partition by s.pro_id order by s.pro_id, s.tim_id) sumMjCj
      ,  s.salesidx * NVL(c.factor, 1) * (sum(s.salesidx * NVL(c.factor, 1)) over (partition by s.pro_id order by s.pro_id, s.tim_id)) summedMulti
        FROM david_sales s
        ,    david_compensations c
        WHERE s.pro_id    = c.pro_id(+)
        AND s.tim_id      = c.tim_id(+)
        AND s.tim_id     BETWEEN 5791  AND 5795 
  
  SALES_PRO              COMP_PRO               SALES_TIM              COMP_TIM               DAY_SALES              FACTOR                 FACTORED_DAY_SALES     SDUS                   SUMMJCJ                SUMMEDMULTI
  777777                 777777                 5795                   5795                   10                     1.5                    15                     300                    470                    7050
  

  Note, in the second block, I changed it just to use sumMjCj instead of sDus which seems to correlate with what you wanted (15 * 470 = 7050) while sdus is 15 * 300 = 4500

  Published by: tanging on December 11, 2009 06:17

• How to use Group by in the analytic function

  I need to write the Department that has the minimum wage in a row. She must be with analytical function, but I have problem in group by. I can't use min() without group by.
  
  Select * from (min (sal) select min_salary, deptno, RANK() ON RN (ORDER BY sal CSA, CSA rownum) of the Group of emp by deptno) < 20 WHERE RN order by deptno;
  
  Published by: senza on 6.11.2009 16:09

  Hello

  senza wrote:
  I need to write the Department that has the minimum wage in a row. She must be with analytic function

  Therefore with an analytic function? Looks like it is a duty.

  The best way to get these results is with an aggregate, not analysis, function:

  SELECT      MIN (deptno) KEEP (DENSE_RANK FIRST ORDER BY sal)     AS dept_with_lowest_sal
  FROM      scott.emp
  ;
  

  Note that you do not need a subquery.
  This can be modififed if, for example, you want the lowest Department with the sal for each job.

  But if your mission is to use an analytical function, that's what you have to do.

  but I have problem in group by. I can't use min() without group by.

  Of course, you can use MIN without GROUP BY. Almost all of the aggregate (including MIN) functions have analytical equivalents.
  However, in this issue, you don't need to. The best analytical approach RANK only, not use MIN. If you ORDER BY sal, the lines with rank = 1 will have the minimum wage.

  Select * from (min (sal) select min_salary, deptno, RANK() ON RN (ORDER BY sal CSA, CSA rownum) of the Group of emp by deptno) WHERE the RN< 20="" order="" by="">

  Try to select plain old sal instead of MIN (sal) and get reid of the GROUP BY clause.

  Add ROWNUM in the ORDER BY clause is to make RANK return the same result as ROW_NUMBER, every time that it is a tie for the sal, the output will still be distinct numbers. which line gets the lower number will be quite arbitrary, and not necessarily the same every time you run the query. For example, MARTIN and WARD have exactly the same salary, 1250. The query you posted would assign rn = 4 to one of them and rn = 5 to another. Who gets 4? It's a toss-up. It could be MARTIN the first time you try, and WARD the next. (In fact, in a very small table like scott.emp, it probably will be consistent, but always arbitrary.) If this is what you want, it would be clearer and simpler just to use ROW_NUMEBR instead of RANK.