Nth salary using the analytic function

Similar Questions

• SQL using the analytic function

  
  Hi all

  I want a help in the creation of my SQL query to retrieve the data described below:

  I have a test of sample table containing data as below:

  State ID Desc

  MICHAEL 1 T1

  ACTIVE 2 T2

  T3 3 SUCCESS

  DISABLE THE T4 4

  The thing I want to do is to select all the lines with an ACTIVE status in the table but is there is no ACTIVE status, my request will give me the last line with MICHAEL status.

  I can do this in a single request by using the analytical function for example, if yes can yiu help me on the request of unpacking.

  Kind regards

  Raluce

  Something like that?

  I had to fix it.

  with testdata until)
  Select 1 id, "T1" dsc "DISABLED" status of Union double all the
  Select 2 id, 'T2' dsc, the status "ACTIVE" of all the double union
  Select id 3, "T3" dsc, the status of 'SUCCESS' of all the double union
  Select 4 id, "T4" dsc "DISABLED" status of double
  )

  Select
  ID
  dsc
  status
  of testdata
  where
  status =
  -case when (select count (*) in testdata where status = 'ACTIVE') > 0
  then 'ACTIVE '.
  Another 'DISABLED '.
  end
  and)
  ID in (select id from testdata where status = ' ACTIVE')
  or
  ID = (select max (id) in testdata when status = 'DISABLED')
  )

  STATE ID DSC

  '2' 'T2' 'ACTIVE '.

  Maybe it's more efficient

  Select
  ID
  dsc
  status
  of testdata
  where
  status =
  -case when (select count (*) in testdata where status = 'ACTIVE') > 0
  then 'ACTIVE '.
  Another 'DISABLED '.
  end
  and
  ID =)
  -case when (select count (*) in testdata where status = 'ACTIVE') > 0
  then id
  on the other
  (select max (id) in testdata when status = 'DISABLED')
  end
  )

  Post edited by: correction of chris227

  Post edited by: chris227
  extended

• Using the analytic function

  Oracle 11g Release 2

  I'm assuming that the best solution is the use of analytical functions.

  create table test3
  ( part_type_id  varchar2(50)
  ,group_id      number
  ,part_desc_id  number
  ,part_cmt      varchar2(50)
  )
  /
  
  insert into test3 values( 'ABC123',1,10,'comment1');
  insert into test3 values( 'ABC123',1,10,'comment2');
  insert into test3 values( 'ABC123',2,15,'comment1');
  insert into test3 values( 'ABC123',2,15,'comment2');
  insert into test3 values( 'EFG123',25,75,'comment3');
  insert into test3 values( 'EFG123',25,75,'comment4');
  insert into test3 values( 'EFG123',25,75,'comment5');
  insert into test3 values( 'XYZ123',1,10,'comment6');
  insert into test3 values( 'XYZ123',2,15,'comment7');
  commit;
  
  select * from test3;
  
  PART_TYPE_ID           GROUP_ID PART_DESC_ID PART_CMT
  -------------------- ---------- ------------ --------------------
  ABC123                        1           10 comment1
  ABC123                        1           10 comment2
  ABC123                        2           15 comment1
  ABC123                        2           15 comment2
  EDG123                        25          75 comment3
  EDG123                        25          75 comment4
  EDG123                        25          75 comment5
  XYZ123                        1           10 comment6
  XYZ123                        2           15 comment7
  
  9 rows selected.
  
  Desired output:
  
  PART_TYPE_ID           GROUP_ID PART_DESC_ID PART_CMT
  -------------------- ---------- ------------ --------------------
  ABC123                        1           10 comment1 
  ABC123                        2           15 comment1
  XYZ123                        1           10 comment1
  XYZ123                        2           15 comment2
  
  RULE: where one part_type_id has multiple (2 or more distinct combinations) of group_id/part_desc_id
  
  NOTE: There are about 12 columns in the table, for brevity I only included 4.
  
  
  
  

  Post edited by: orclrunner was updated desired output and rule

  Hello

  Here's one way:

  WITH got_d_count AS

  (

  SELECT part_type_id, group_id, part_desc_id

  MIN (part_cmt) AS min_part_cmt

  COUNT AS d_count (*) OVER (PARTITION BY part_type_id)

  OF test3

  GROUP BY part_type_id, group_id, part_desc_id

  )

  SELECT DISTINCT

  group_id, part_desc_id, part_type_id, min_part_cmt

  OF got_d_count

  WHERE d_count > 1

  ;

  Output:

  GROUP_ID PART_DESC_ID MIN_PART_CMT PART_TYPE_ID

  ------------ ---------- ------------ ------------

  ABC123 1 10 comment1

  ABC123 2 15 comment1

  XYZ123 1 10 comment6

  XYZ123 2 15 comment7

  Analytical functions, such as the COUNTY and MIN, many global versions, in addition, it can give the same results.  Use the analytical versions when each row of output corresponds to exactly 1 row of input and the aggregate and GROUP BY version when each line of output corresponds to a group of lines 1 or more input.  In this issue, each line of output appears to be a group of input lines having the same group_id, part_type_id, and part_desc_id (I'm guessing just, this only has never stated), so I used GROUP BY to get 1 row of output for every input lines.

• by using the analytical function to get the right output.

  Hello all;
  
  I have the following date of sample below
  

  create table temp_one
  (
         id number(30),   
        placeid varchar2(400),
        issuedate  date,
        person varchar2(400),
        failures number(30),
        primary key(id)
  );
  
  insert into temp_one values (1, 'NY', to_date('03/04/2011', 'MM/DD/YYYY'), 'John', 3);
  
  insert into temp_one values (2, 'NY', to_date('03/03/2011', 'MM/DD/YYYY'), 'Adam', 7);
  
  insert into temp_one values (3, 'Mexico', to_date('03/04/2011', 'MM/DD/YYYY'), 'Wendy', 3);
  
  insert into temp_one values (4, 'Mexico', to_date('03/14/2011', 'MM/DD/YYYY'), 'Gerry', 3);
  
  insert into temp_one values (5, 'Mexico', to_date('03/15/2011', 'MM/DD/YYYY'), 'Zick', 9);
  
  insert into temp_one values (6, 'London', to_date('03/16/2011', 'MM/DD/YYYY'), 'Mike', 8);

  It's the output I want
  

  placeid       issueperiod                               failures
  NY              02/28/2011 - 03/06/2011          10
  Mexico       02/28/2011 - 03/06/2011           3
  Mexico        03/14/2011 - 03/20/2011          12
  London        03/14/2011 - 03/20/2011          8

  Any help is appreciated. I'll post my request as soon as I can think of a good logic for this...

  Hello

  user13328581 wrote:
  ... Please note, I'm still learning how to use analytical functions.

  It doesn't matter; analytical functions will not help in this problem. The SUM aggregate function is all you need.
  But what do you need to GROUP BY? What is the value of each row of the result will represent? A placeid? Yes, each line will represent only placedid, but it will be divided further. You want a separate line of the output for each placeid and every week, then you'll want of the week and GROUP BY placeid. You don't want to GROUP BY the raw issuedate; that would put on 3 March and 4 March in separate groups. And you don't want to GROUP BY failures; This would mean that a line with 3 failures could never be in the same group in line with 9 failures.

  This becomes the output you posted from the sample data you posted:

  SELECT       placeid
  ,             TO_CHAR ( TRUNC (issuedate, 'IW')
                , 'MM/DD/YYYY'
              ) || ' - '|| TO_CHAR ( TRUNC (issuedate, 'IW') + 6
                                           , 'MM/DD/YYY'
                             )     AS issueperiod
  ,       SUM (failures)                  AS sumfailures
  FROM        temp_one
  GROUP BY  placeid
  ,            TRUNC (issuedate, 'IW')
  ;
  

  You can use a subquery to calculate TRUNC (issuedate, 'IW') once. The code would be of about as complicated, efficiency probably will not improve substantially and the results would be the same.

• Using the analytical function.

  Hello
  
  I have this scenario.
  

  with t as 
  (
  select 21009 item_id,9 primary_available,450 max_qty,100 bulk_available,12122 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,2775 bulk_available,8704 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,524 bulk_available,15614 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,3300 bulk_available,15654 bulk_locator_id
  from dual)
  select  t.* from t;

  We have two locations for a given item_id. Primary and in bulk.
  
  I'm trying to get a select statement out of this point of view, where I will be restock the primary AMOUNT of sites in bulk, BUT the smaller bulk first. Once she gets up, I shouldn't take more product.
  
  There is an analytic function that would do this?
  
  That's the max I could come up with.
  

  with t as 
  (
  select 21009 item_id,9 primary_available,450 max_qty,100 bulk_available,12122 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,2775 bulk_available,8704 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,524 bulk_available,15614 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,3300 bulk_available,15654 bulk_locator_id
  from dual)
  select  t.*, max_qty -
                 (primary_available + SUM(bulk_available)
                  over(PARTITION BY item_id ORDER BY bulk_available)) replen_this_much 
                  from t;

  So, in this scenario, I want to replen bulk_locator_id 100 ' 12122 'and ' 15614 bulk_locator_id 341'. That's all. ZERO of the other rentals (bulk_locator_id). If the question is not clear, please let me know.
  
  Published by: RPuttagunta on September 11, 2009 16:23

  Hello

  Thanks for posting the sample data.
  It would be useful that you also posted the output you want. Is this?

  .                                 BULK_         REPLEN_
  ITEM_ PRIMARY_   MAX_  BULK_      LOCATOR_        THIS_
  ID    AVAILABLE  QTY   AVAILABLE  ID               MUCH
  ----- ---------- ----- ---------- ---------- ----------
  21009 9          450   100        12122             100
  21009 9          450   524        15614             341
  21009 9          450   2775       8704                0
  21009 9          450   3300       15654               0
  

  If so, you can get to this:

  SELECT       t.*
  ,       GREATEST ( 0
               , LEAST ( TO_NUMBER (bulk_available)
                       , TO_NUMBER (max_qty)
                      - ( TO_NUMBER (primary_available)
                        + NVL ( SUM (TO_NUMBER (bulk_available))
                                OVER ( PARTITION BY  item_id
                                       ORDER BY      TO_NUMBER (bulk_available)
                                 ROWS BETWEEN  UNBOUNDED PRECEDING
                                   AND      1           PRECEDING
                               )
                           , 0
                           )
                        )
                    )
               ) AS replen_this_much
  FROM       t
  ORDER BY  item_id
  ,            TO_NUMBER (bulk_available)
  ;
  

  You should really store your numbers in NUMBER of columns.

  You essentially posted all what you need analytical functions. The problem was just wrapping this analytical function (or something very close to it) and LESS and more GRAND, so that the replen_this_much column is always between 0 and TO_NUMBER (bulk_available).

• By using the analytical function to sort without showing this column in the result.

  Hello

  We use the Oracle 11.2

  How to use Oracle Analytics to sort the output of a query without showing this column in the result?

  Here's my query:

  Select distinct nvl(SRC_CHR_NM,'0') | » #'|| NVL(EXPL_SRC,'0') | » #'|| NVL(DIM_NM,'0') | » #'|| NVL(DIM_CHR_NM,'0') | » #'|| NVL(DIM_CHR_ABR,'0') | » #'||

  Decode (InStr (NVL(SRC_COL_NM,'0'), 'trim ('),'1 ', Replace (NVL(SRC_COL_NM,'0'),'trim (',' trim(PRM_DTL.'), '0',' PRM_DTL.)))) » || NVL(SRC_COL_NM,'0')) AS ALLOFIT,

  DIM_NM

  from EXPL_CONFIG where SBJ_AREA_CD = 'PRMDTL. '

  I want to use analytical to sort by DIM_NM but I do not want to show. I want to just just the ALLOFIT column to show in the output.

  Something like "row_number() over (order by DIM_NM desc).

  Thank you!

  Hello

  If you SELECT SEPARATE, then you can only ORDER OF things in the SELECT clause. (Do you really need to do SELECT DISTINCT?  Often, it's just an inefficient way to remove the lines that do not need to be there at all).

  Move making the SELECT DISTINCT in a subquery and make the ORDER BY (and nothing else) in the main query.

  I hope that answers your question.

  If this isn't the case, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002#9362002

• update the table by using the analytic function

  I have a table like this one:
  

  create table fred (test varchar2(50), seq_no number(18,0));
  
  
  insert into fred (test) values ('A');
  insert into fred (test) values ('A');
  insert into fred (test) values ('A');
  insert into fred (test) values ('B');
  insert into fred (test) values ('C');
  insert into fred (test) values ('D');
  insert into fred (test) values ('D');
  insert into fred (test) values ('D');
  insert into fred (test) values ('D');
  insert into fred (test) values ('E');
  insert into fred (test) values ('E');
  insert into fred (test) values ('E');

  I want a single statement that will update seq_no with a unique number for each test in seq_no insert value
  
  for example like this:
  

  SQL 001> select test, row_number() over (partition by test order by test) from fred
    2  /
  
  TEST                                               ROW_NUMBER()OVER(PARTITIONBYTESTORDERBYTEST)
  -------------------------------------------------- --------------------------------------------
  A                                                                                             1
  A                                                                                             2
  A                                                                                             3
  B                                                                                             1
  C                                                                                             1
  D                                                                                             1
  D                                                                                             2
  D                                                                                             3
  D                                                                                             4
  E                                                                                             1
  E                                                                                             2
  E                                                                                             3

  I am sure that this should be an easy thing, but for the life of me I can't figure out how do it in a single statement. I should know this... hangs head in shame

  Use MERGE

  SQL> merge into fred
    2  using (select rowid rid, test, row_number() over (partition by test order by test) sno
    3      from fred) fred1
    4     on (fred.rowid = fred1.rid)
    5  when matched then update
    6     set seq_no = sno
    7  /
  
  12 rows merged.
  
  SQL> select * from fred
    2  /
  
  TEST                                                   SEQ_NO
  -------------------------------------------------- ----------
  A                                                           1
  A                                                           2
  A                                                           3
  B                                                           1
  C                                                           1
  D                                                           1
  D                                                           4
  D                                                           3
  D                                                           2
  E                                                           1
  E                                                           2
  
  TEST                                                   SEQ_NO
  -------------------------------------------------- ----------
  E                                                           3
  
  12 rows selected.
  

• How to achieve using the analytical functions - please help

  Oracle version: 10g
  -999 means that all THE values for this key

  with input_parameters as (select 10 filter_key , '10ACCC' filter_value from dual union all
  select 50 filter_key ,'10ACCC0001' filter_value from dual union all
  select 60 filter_key , 'PIP' filter_value from dual union all
  select 70 filter_key , 'A' filter_value from dual) select * from input_parameters;
  
  
  with profile_search as(
  select 100 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all 
  select 100 profile_id , 50 filter_key , '10ACCC0001' filter_value from dual union all
  select 100 profile_id , 50 filter_key , '10ACCC0002' filter_value from dual union all
  select 100 profile_id , 60 filter_key , '999' filter_value from dual union all
  select 100 profile_id , 70 filter_key , '999' filter_value from dual union all
  select 101 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all
  select 101 profile_id , 50 filter_key , '10ACCC001' filter_value from dual union all
  select 101 profile_id , 60 filter_key , 'PIP' filter_value from dual union all
  select 101 profile_id , 70 filter_key , '999' filter_value from dual union all
  select 102 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all
  select 102 profile_id , 50 filter_key , '10ACCC0001' filter_value from dual union all
  select 102 profile_id , 60 filter_key , 'PIP' filter_value from dual union all
  select 102 profile_id , 70 filter_key , 'A' filter_value from dual)
  select filter_key , wm_concat(filter_value) from profile_search group by profile_id, filter_key ;

  need to identify profile that matches input parameters
  ---------------------------------------------------------------------------
  
  102 is first match because it matches exactly
  101 is second match because 999 can match any value
  100 is third match 

  70 KEY HAS THE HIGHEST WEIGHT,
  A next highest weight KEY 60 and 50 next highest weight BUTTON
  
  
  required results:
  profile_id: 102
  
  Published by: devarade on January 19, 2010 20:01
  
  Published by: devarade on January 19, 2010 20:01

  I guess that there is a typing error in your sample:

  Select 101 profile_id, 50 filter_key, '10ACCC001' filter_value from all the double union

  must be:

  Select 101 profile_id, 50 filter_key, '01' filter_value from all 10ACCC00 the double union

  Then:

  with input_parameters as (
                            select 10 filter_key , '10ACCC' filter_value from dual union all
                            select 50 filter_key ,'10ACCC0001' filter_value from dual union all
                            select 60 filter_key , 'PIP' filter_value from dual union all
                            select 70 filter_key , 'A' filter_value from dual
                           ),
          profile_search as(
                            select 100 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all
                            select 100 profile_id , 50 filter_key , '10ACCC0001' filter_value from dual union all
                            select 100 profile_id , 50 filter_key , '10ACCC0002' filter_value from dual union all
                            select 100 profile_id , 60 filter_key , '999' filter_value from dual union all
                            select 100 profile_id , 70 filter_key , '999' filter_value from dual union all
                            select 101 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all
                            select 101 profile_id , 50 filter_key , '10ACCC0001' filter_value from dual union all
                            select 101 profile_id , 60 filter_key , 'PIP' filter_value from dual union all
                            select 101 profile_id , 70 filter_key , '999' filter_value from dual union all
                            select 102 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all
                            select 102 profile_id , 50 filter_key , '10ACCC0001' filter_value from dual union all
                            select 102 profile_id , 60 filter_key , 'PIP' filter_value from dual union all
                            select 102 profile_id , 70 filter_key , 'A' filter_value from dual
                           )
  select  profile_id,
          sum(direct_match_cnt) || ' direct matches out of ' || (select count(*) from input_parameters) match
    from  (
           select  b.profile_id,
                   b.filter_key,
                   b.filter_value,
                   sum(case when b.filter_value = a.filter_value then 1 else 0 end) direct_match_cnt
             from  input_parameters a,
                   profile_search b
             where b.filter_key = a.filter_key
               and (b.filter_value = a.filter_value or b.filter_value = '999')
             group by b.profile_id,
                      b.filter_key,
                      b.filter_value
          ) x
    group by profile_id
    having count(*) = (select count(*) from input_parameters)
    order by sum(direct_match_cnt) desc
  /
  
  PROFILE_ID MATCH
  ---------- ----------------------------------------
         102 4 direct matches out of 4
         101 3 direct matches out of 4
         100 2 direct matches out of 4
  
  SQL> 
  

  SY.

• How to use Group by in the analytic function

  I need to write the Department that has the minimum wage in a row. She must be with analytical function, but I have problem in group by. I can't use min() without group by.
  
  Select * from (min (sal) select min_salary, deptno, RANK() ON RN (ORDER BY sal CSA, CSA rownum) of the Group of emp by deptno) < 20 WHERE RN order by deptno;
  
  Published by: senza on 6.11.2009 16:09

  Hello

  senza wrote:
  I need to write the Department that has the minimum wage in a row. She must be with analytic function

  Therefore with an analytic function? Looks like it is a duty.

  The best way to get these results is with an aggregate, not analysis, function:

  SELECT      MIN (deptno) KEEP (DENSE_RANK FIRST ORDER BY sal)     AS dept_with_lowest_sal
  FROM      scott.emp
  ;
  

  Note that you do not need a subquery.
  This can be modififed if, for example, you want the lowest Department with the sal for each job.

  But if your mission is to use an analytical function, that's what you have to do.

  but I have problem in group by. I can't use min() without group by.

  Of course, you can use MIN without GROUP BY. Almost all of the aggregate (including MIN) functions have analytical equivalents.
  However, in this issue, you don't need to. The best analytical approach RANK only, not use MIN. If you ORDER BY sal, the lines with rank = 1 will have the minimum wage.

  Select * from (min (sal) select min_salary, deptno, RANK() ON RN (ORDER BY sal CSA, CSA rownum) of the Group of emp by deptno) WHERE the RN< 20="" order="" by="">

  Try to select plain old sal instead of MIN (sal) and get reid of the GROUP BY clause.

  Add ROWNUM in the ORDER BY clause is to make RANK return the same result as ROW_NUMBER, every time that it is a tie for the sal, the output will still be distinct numbers. which line gets the lower number will be quite arbitrary, and not necessarily the same every time you run the query. For example, MARTIN and WARD have exactly the same salary, 1250. The query you posted would assign rn = 4 to one of them and rn = 5 to another. Who gets 4? It's a toss-up. It could be MARTIN the first time you try, and WARD the next. (In fact, in a very small table like scott.emp, it probably will be consistent, but always arbitrary.) If this is what you want, it would be clearer and simpler just to use ROW_NUMEBR instead of RANK.

• A question about the analytical function used with the GROUP BY clause in SHORT

  Hi all
  
  I created the following table named myenterprise
  

  CITY       STOREID    MONTH_NAME TOTAL_SALES            
  ---------- ---------- ---------- ---------------------- 
  paris      id1        January    1000                   
  paris      id1        March      7000                   
  paris      id1        April      2000                   
  paris      id2        November   2000                   
  paris      id3        January    5000                   
  london     id4        Janaury    3000                   
  london     id4        August     6000                   
  london     id5        September  500                    
  london     id5        November   1000

  If I want to find which is the total sales by city? I'll run the following query

  SELECT city, SUM(total_sales) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  that works very well and produces the expected result, i.e.

  CITY       TOTAL_SALES_PER_CITY   
  ---------- ---------------------- 
  london     10500                  
  paris      17000            

  Now in one of my books SQL (Mastering Oracle SQL) I found another method by using the SUM, but this time as an analytic function. Here's what the method of the book suggests as an alternative to the problem:

  SELECT city, 
         SUM(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  I know that the analytic functions are executed after the GROUP BY clause has been transformed completely and Unlike regular aggregate functions, they return their result for each line belonging to the partitions specified in the partition clause (if there is a defined partition clause).
  
  Now my problem is that I do not understand what we have to use two functions SUM? If we only use one only, i.e.

  SELECT city, 
         SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  This generates the following error:

  Error starting at line 2 in command:
  SELECT city, 
         SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY
  Error at Command Line:2 Column:11
  Error report:
  SQL Error: ORA-00979: not a GROUP BY expression
  00979. 00000 -  "not a GROUP BY expression"
  *Cause:    
  *Action:

  The error is generated for the line 2 column 11 which is, for the expression SUM (total_sales), well it's true that total_sales does not appear in the GROUP BY clause, but this should not be a problem, it has been used in an analytical function, so it is evaluated after the GROUP BY clause.
  
  So here's my question:
  
  Why use SUM (SUM (total_sales)) instead of SUM (total_sales)?
  
  
  Thanks in advance!
  :)
  
  
  
  
  
  In case you are interested, that's my definition of the table:

  DROP TABLE myenterprise;
  CREATE TABLE myenterprise(
  city VARCHAR2(10), 
  storeid VARCHAR2(10),
  month_name VARCHAR2(10),
  total_sales NUMBER);
  
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'January', 1000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'March', 7000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'April', 2000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id2', 'November', 2000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id3', 'January', 5000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id4', 'Janaury', 3000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id4', 'August', 6000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id5', 'September', 500);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id5', 'November', 1000);

  Edited by: dariyoosh on April 9, 2009 04:51

  It is clear that thet Analytics is reduntant here...
  You can even use AVG or any analytic function...

  SQL> SELECT city,
    2         avg(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
    3  FROM myenterprise
    4  GROUP BY city
    5  ORDER BY city, TOTAL_SALES_PER_CITY;
  
  CITY       TOTAL_SALES_PER_CITY
  ---------- --------------------
  london                    10500
  paris                     17000
  

• How can I use the SUM function to calculate the number of employees in the comp. &amp; deptnt?

  I have two tables: employees and their departments. I'm figuring the total employees by the Department and the total employees of the entire society. I know I have to use the SUM function, but I can only calculate total employees by Department and company separately. I need to get this result:
  
  

  DEPT_NAME     DEPT_TOTAL_SALARY         COMPANY_TOTAL_SALARY
  RESEARCH                  10875                        29025
  SALES                      9400                        29025    
  ACCOUNTING                 8750                        29025      
  
  
  This is my code:
  
  SELECT department_name, SUM(salary) as total_salary
  FROM employee, department
  WHERE employee.department_id = department.department_id
  GROUP BY department_name;
  
  SELECT SUM(salary)
  FROM employee;
  
  
  
  
  
  
  Can somebody help please?
  Thank you in advance.

  Published by: user13675672 on January 30, 2011 14:29
  
  Published by: user13675672 on January 30, 2011 14:31

  Hello

  Something like:

  SELECT dname,
         dept_tot_sal,
         SUM (dept_tot_sal) OVER () comp_tot_sal
  FROM   (SELECT   dname,
                   SUM (sal) dept_tot_sal
          FROM     dept, emp
          WHERE    dept.deptno = emp.deptno
          GROUP BY dname);
  

  There might be a smarter way, with no re - select.

  Concerning
  Peter

  Analytical functions:
  http://download.Oracle.com/docs/CD/E11882_01/server.112/e17118/functions004.htm

• How to define the condition in the analytic function

  Oracle 10g version

  Hi all

  I have the following data samples:

  Examples of data

  WITH DATA AS

  (

  SELECT 100 case_id, next_date, to_date('01-feb-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-jan-2015','dd-mon-yyyy')

  SELECT 100 case_id, next_date, to_date('01-mar-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-feb-2015','dd-mon-yyyy')

  SELECT 100 case_id, next_date, to_date('01-apr-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-may-2015','dd-mon-yyyy')

  SELECT 100 case_id, to_date('01-jun-2015','dd-mon-yyyy') next_date, to_date('01-apr-2015','dd-mon-yyyy') crt_date FROM dual

  )

  SELECT wagneur, MIN (next_date) OVER (PARTITION BY case_id) min_dt_analytical

  ,(

  SELECT MIN (next_date) DATA dd

  WHERE dd.case_id = d.case_id

  AND dd.next_date > crt_date

  ) min_dt_sub_query

  DATA d

  ;

  My question is that I get min_dt_sub_query using sub query but I want to use the analytical instead of query sub function so I created min_dt_analytical column, but I do not have how to give the condition that is AND dd.next_date > crt_date analytical so that I can get the same result as min_dt_sub_query data accordingly. Thanks in advance

  Concerning

  MIT

  Do not know if I understood your needs... but... something like that?

  WITH DATA AS (SELECT 100 case_id, next_date, to_date('01-feb-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-jan-2015','dd-mon-yyyy')

  SELECT the 100 case_id, next_date, to_date('01-mar-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-feb-2015','dd-mon-yyyy')

  SELECT the 100 case_id, next_date, to_date('01-apr-2015','dd-mon-yyyy') UNION double, ALL crt_date to_date('01-may-2015','dd-mon-yyyy')

  SELECT 100 case_id, next_date, to_date('01-apr-2015','dd-mon-yyyy') double crt_date to_date('01-jun-2015','dd-mon-yyyy'))

  SELECT d.

  MIN (next_date) OVER (PARTITION BY case_id) min_dt_analytical

  MIN(CASE WHEN next_date > crt_date THEN next_date ELSE NULL END) OVER (PARTITION BY case_id) AS min_dt_sub_query2

  DATA d;

  HTH

• Use of analytic functions

  Hi gurus,
  I ask someone to enlighten me on the analytical functions.
  I used the following query:

  select * from 
  (select filename,count(regexp_substr(filename,'.*era'))over(  partition by regexp_substr(filename,'.*era') ) cnt
   FROM 
  l_x12n_835_fileinfo where partitionnum=76000 and clntsysnum=76500 and radt>='01-JAN-2010')
  where cnt>1

  The sample result set is:

  FILENAME     CNT
  
  rsmedcalwa.20100105.chpwr.072.era     4
  rsmedcalwa.20100105.chpwr.072.era.1     4
  rsmedcalwa.20100105.chpwr.072.era.2     4
  rsmedcalwa.20100105.chpwr.072.era.3     4
  rsmedcalwa.20100105.chpwr.081.era     3
  rsmedcalwa.20100105.chpwr.081.era.1     3
  rsmedcalwa.20100105.chpwr.081.era.2     3
  rsmedcalwa.20100106.chpwr.088.era     3
  rsmedcalwa.20100106.chpwr.088.era.1     3
  rsmedcalwa.20100106.chpwr.088.era.2     3
  rsmedcalwa.20100108.chppr.363.era.3     4
  rsmedcalwa.20100108.chppr.363.era.1     4
  rsmedcalwa.20100108.chppr.363.era.2     4
  rsmedcalwa.20100108.chppr.363.era     4

  Now, I changed the query to:

  select * from 
  (select filename,count(regexp_substr(filename,'.*era'))over(  partition by regexp_substr(filename,'.*era') order by filename   ) cnt
   FROM 
  l_x12n_835_fileinfo where partitionnum=76000 and clntsysnum=76500 and radt>='01-JAN-2010')
  where cnt>1

  The result set has been

  FILENAME     CNT
  
  rsmedcalwa.20100105.chpwr.072.era.1     2
  rsmedcalwa.20100105.chpwr.072.era.2     3
  rsmedcalwa.20100105.chpwr.072.era.3     4
  rsmedcalwa.20100105.chpwr.081.era.1     2
  rsmedcalwa.20100105.chpwr.081.era.2     3
  rsmedcalwa.20100106.chpwr.088.era.1     2
  rsmedcalwa.20100106.chpwr.088.era.2     3
  rsmedcalwa.20100108.chppr.363.era.1     2
  rsmedcalwa.20100108.chppr.363.era.2     3
  rsmedcalwa.20100108.chppr.363.era.3     4
  rsmedcalwa.20100112.chpwr.175.era.1     2
  rsmedcalwa.20100112.chpwr.175.era.2     3

  (1) I don't understand how the addition of the order by clause changes the count. Could someone explain please?
  When I change this order by order of regexp_substr(filename,'.*era'), it gives me the correct number.
  
  My requirement is to check how many similar file names I.
  
  (2) if there are any other better elsewhere, please let me know.

  Hello

  Analytical functions still carried on in a window of the the result set, which can be smaller than the result set.
  If you have a PARTITION BY clause, the window for each row includes rows with the same values from all the PARTITION BY expressions.
  If you have an ORDER BY clause, the window includes that of a section of consecutive lines in the score, as defined by a windowing clause (in other words, LINES or KEEP them). The default value is "RANGE BETWEEN UNBOUNDED PRECEDING AND LINE CURRENT.

  In your case, if the analytical clause is:

  over(  partition by regexp_substr(filename,'.*era') )
  

  and the line you are looking at a filename = 'rsmedcalwa.20100105.chpwr.072.era.2', the window takes up the entire partition, in other words, all lines whose name includes "rsmedcalwa.20100105.chpwr.072.era". In other words, the window is identical to the partition, because theree is no ORDER BY clause.

  But if you add an ORDER BY clause:

  over(  partition by regexp_substr(filename,'.*era') order by filename   )
  

  then the window (potentially) decreases. Since there is no clause window, the default value 'RANGE BETWEEN UNBOUNDED PRECDING AND a CURRENT LINE' is used, which means that only the lines with a lower or equal to "rsmedcalwa.20100105.chpwr.072.era.2" file name (using the normal string comparison) will affect the results.

  The analytical ORDER BY clause is required for certain features (such as ROW_NUMBER) significance only in regard to certain commands. For the most part fucntions (including COUNTY), the ORDER BY clause is optional, and you do not have to use a. In this case, it seems that you do not want the effect of a smaller than the partition window, just so, do not use an ORDER byclause of Analytics for this function.

  Remember, the analytical ORDER byclause is completely independent the ORDER BY query clause. If you want the result presented in a certain order, use an ORDER BY clause at the end of the query. It will not change the results of the analytical functions.

• 2.1 EA Bug: AutoComplete group generates group by for the analytic function

  Hello
  
  When you use an analytic function in the sql text, sqldeveloper generates an automatic group by statement in the sql text.
  
  Kind regards
  Ingo

  Auto to produce group by can be disabled:

  In tools, preferences, Editor Code completion Insight you will find the option

  "Autogenerate GROUP BY clause"

  Concerning

  Ernst

• A job for the analytical function "PARTION OF?

  Hello
  
  I'm still a little fuzzy on the use of partitions, but this looks like a possible candidate for me.
  
  I need to count the number of different customers who visit an office in one day. If a customer visits an office more than once in a single day that counts for 1.
  
  
  
  Entry
  OFFICE CLIENT TRAN_DATE
  1-11-1 April 09
  1-11-1 April 09
  1-11-1 April 09
  
  1 11 2 April 09
  
  2 22 2 April 09
  2 22 2 April 09
  2 33 2 April 09
  
  Select a.office as 'OFFICE', a.customer AS 'CUSTOMER', a.tran_date AS 'TRAN_DATE', COUNT (*)
  Of
  (SELECT 1 AS 'OFFICE', AS A 'CUSTOMER' 11, APRIL 1, 2009 "AS"TRAN_DATE"OF THE DOUBLE
  UNION ALL
  SELECT 1, 11, APRIL 1, 2009 "OF THE DOUBLE
  UNION ALL
  SELECT 1, 11, APRIL 1, 2009 "OF THE DOUBLE
  UNION ALL
  SELECT 1: 11, 2 APRIL 2009 "OF THE DOUBLE
  UNION ALL
  SELECT 2: 22, APRIL 2, 2009 "OF THE DOUBLE
  UNION ALL
  SELECT 2: 22, APRIL 2, 2009 "OF THE DOUBLE
  UNION ALL
  SELECT 2: 33, APRIL 2, 2009 "OF THE DOUBLE
  ) one;
  
  
  Desired result
  1 1 April 09 1
  1-2 April 09 1
  2 2 April 09 2
  
  
  Is this possible with partitions, do I have to use subqueries, or some other methid?
  
  Thanks in advance for your help,
  
  Lou
  
  Published by: wind in the face on April 15, 2009 13:34

  Hey, Lou,

  PARTITION BY is not a function.
  COUNT is a function. There is an aggregate COUNT function and also an analytical function of COUNTY. (Almost all aggregate functions have analytical counterparts).

  How can you tell if a function is used as an aggregate function or Analytics? The analytic form will be "OVER ( )" after his altercation; the overall shape will not be.
  PARTITION BY is one of the elements that may form part of the analytical clause.
  "PARTITION BY x, y ' in an analuytic function corresponds to" GROUP BY x, y "when using functions aggreggate.

  You can get the same results for a large number of problems using either global or analytical of a function versions.
  For example, both versions global and analytical County can tell you that vistied office only 1 customer 1 April 1, but 2 clients visited the office 2 April 2.
  If you use the aggregation function ACCOUNT and ' GROUP BY Office, tran_date ', as John suggested, you will get only one line for each distinct combination of office and tran_date. In other words, even if there are 3 rows of your table where office = 1 and tran_date = April 1, the result set will have onely a row where office = 1 and tran_date = 1 April.
  Because it is exactly what you want, you can use the aggregate COUNT fucntion, as shown in John.

  If you use the analytical ACCOUNT function, there will be a line of output for each row in your table.
  So with the sample data you posted, this query:

  SELECT  office
  ,     tran_date
  ,     COUNT (DISTINCT customer) OVER ( PARTITION BY  office
                                         ,            tran_date
                             )  AS cnt
  FROM     table_x;
  

  will these results:

  .   OFFICE TRAN_DATE          CNT
  ---------- ----------- ----------
           1 01-APR-2009          1
           1 01-APR-2009          1
           1 01-APR-2009          1
           1 02-APR-2009          1
           2 02-APR-2009          2
           2 02-APR-2009          2
           2 02-APR-2009          2
  

  To get the exact results you want, you can use SELECT DISTINCT, like this:

  SELECT DISTINCT
          office
  ,     COUNT (DISTINCT customer) OVER  ...