enable intel XD, it will cause problems?

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  Lorien - MCSA/MCSE/network + / has + - if this post solves your problem, please click the 'Mark as answer' or 'Useful' button at the top of this message. Marking a post as answer, or relatively useful, you help others find the answer more quickly.

• which will cause 'notify() and wait()' mechanism no longer works?

  Hi all

  My application has worked for a few years, unless the user recently upgraded to OS7.1 and to try out my new device, all of a sudden, he is part works not properly.

  Appplcaition will download data from the server, long story Short,

  When there is no queue of download, application will wait until asked to download real.

  my code something like the follow up:

          InvokeContainer c = new InvokeContainer(r);
          synchronized (c.syncObj) {
              // push to queue
              synchronized (_queue) { _queue.addElement(c); }
              LogManager.getInstance().add("Notify queue Thread _queue size " + _queue.size());
              synchronized (_queueSyncObj) { _queueSyncObj.notifyAll(); }
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              //synchronized(c.syncObj){
                  try { c.syncObj.wait(); } catch (Exception ex) {}
              //}
              LogManager.getInstance().add("Invoke data released");
          }
  

          while (!_stop) {
              InvokeContainer c = null;
  
              // wait for invoke
              c = getNextInvoke();
              if (c == null) {
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                  synchronized (_queueSyncObj) {
                      try {
                          _queueSyncObj.wait();
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                      } catch (Exception ex) {
                          LogManager.getInstance().add("Exception happened: " + ex.toString());
                      }
                  }
                  c = getNextInvoke();
                  LogManager.getInstance().add("Get a new queue ");
              }
  

  My question is:

  my request always stop at the:

   LogManager.getInstance().add("Notify queue Thread _queue size " + _queue.size());
  

  and I saw there's a queue, waiting, however, the line after wait() never called.

  which will cause notify() citing not wait()?

  For me, in places, your code seems too complicated for what he seeks to achieve.  I'll try to simplify.

  First you have loads of protection around your creating a Singleton RuntimeStore object.  This seems pointless.  Take a look at this:

  http://supportforums.BlackBerry.com/T5/Java-development/create-a-singleton-using-the-RuntimeStore/TA...

  Go through your code, I wonder what follows:

  (1) public static synchronized IPCThread getServerInstance() {}

  Why is this it is synchronized?  Iron several people getting to this offers no additional protection.

  (2) synchronized (GlobalSync.getSyncObj (GUID))...

  This synchronized block offers no additional protection either.  Either the

  IPCThread will be there or it won't, there is no possibility of a race condition causes you a problem here.

  (3) public static synchronized IPCThread initServerInstance() {}
  synchronized (GlobalSync.getSyncObj (GUID)) {}

  Here, there might be some value to have only one person to create it at the same time.  But if it's a question, then the second person through should check if it has been created, this code is not.  Thus, each invocation of

  initServerInstance()

  will create and start a new IPCThread.  The synchronized are totally redundant and you have a potential hole in your treatment.

  (4) public synchronized static getInstance() {} IPCThread

  you have another way to get an IPCThread, which in fact is not identical to the above and, will be different if you start another instance of your Application, for example an alternative entry or a variant of starting.

  I recommend that you replace it with the unique getInstance() method based on article.  Do start the IPCThread if it creates.

  OK, I understand that you don't think that this is related to your problem, but with the code you have, there may be several IPCThreads and would not help.

  Now on your invocation code.

  Can you please remove static from the following:

  private static class InvokeContainer...

  As far as I KNOW, he does not buy you anything in this circumstance, and it confuses me.

  The idea here seems to be that you can provide an executable in this process, which it runs and then inform the task (if necessary) awaiting.  You pack the floor area in an InvokeContainer.

  The first thing to look at, it's how you entered extracting from the queue.  Here you protect with this line:

  synchronized (inasmuch)

  So what you're saying to me here, it's that you will protect this treatment in protecting access to the inasmuch.  Something we will add it to the queue. or something is going to take off it the queue, both may not occur at the same time.  That's ok.

  So how do add you to the queue?

  Ignoring the code that will process if the process id is the same, we get this:

  InvokeContainer c = new InvokeContainer (r);
  synchronized (c.syncObj) {}
  Push the queue
  synchronized (inasmuch) {_queue.addElement (c) ;}
  synchronized (_queueSyncObj) {_queueSyncObj.notifyAll () ;}
  wait for the release
  try {c.syncObj.wait () ;} catch (Exception ex) {}}
  }

  Now, we have already seen the queue is protected using "synchronized (inasmuch).  But this code will not prevent the entry we just added picked up before that we treat the notify - in other words, the notification cannot be taken into account.  But that's OK.  The reverse is not.  If the Thread that processes the code IPCThread is at this point:

  If (c == null) {}

  and the Thread that the addition of the transformation executes these two instructions:

  synchronized (inasmuch) {_queue.addElement (c) ;}
  synchronized (_queueSyncObj) {_queueSyncObj.notifyAll () ;}

  then the IPCThread will miss warn him.

  To fix this, I'll do what I suggested earlier.

  The way, this seems very strange:

  InvokeContainer c = new InvokeContainer (r);
  synchronized (c.syncObj) {...}

  but in fact, this means that the code will never fail of the treated IPCThread this practicable, since the notification

  synchronized (c.syncObj) {c.syncObj.notify () ;}

  Cannot run until this thread is waiting.  It's a good thing.

  So that leaves only one thing to discuss - the.invokeAsync.  This code looks good, if the

  synchronized (c.syncObj) {...}

  is completely redundant.

  Summary - 2 recommendations:

  (a) change your Singleton IPCThread to use the RuntimeStore method suggested in the KB article

  (b) check the inside of the protection of

  synchronized (_queueSyncObj) {}

  which

  c = getNextInvoke();

  is always set to null.

  Finally, have you thought about putting a delay time in your expectations, while without worrying about the activity or not, the Thread will pick up every now and again work?  For example:

  _queueSyncObj.wait (1000);

  Edit: Minor typo and readability...