Episodes of series TV programming Question

Dear all,

I have a list of series to be demand from time to time. The automatic registration process was generally made on the weekly basis,
so if I have a series of 12 episodes and they should not be scheduled on weekends, this means I'll plan 5 episodes on the first week,
-on the second and 2 - 5 on the third. The order of execution of the series must not be sequential (episode 2 is coming after
Episode 1 and then, i.e. of the TV channels for babies), so I have a table of orders running that keeps the order sought running and his last scheduled date.

My question is, based on the attached example, how can I order number running from the last scheduled episode? I played a bit, but nothing
good fate, nor the FIRST_VALUE attached. In this example, I expect to have working order = 3: there are two episodes planned for the date of the highest
and the 3rd is the most recent.

Helpe is needed, please!


WITH episodes_running_order AS)
SELECT 445 AS segment_id,
214 programme_id AS,
1 AS running_order,
1 AS episode_no,
'20090501' AS last_scheduled_date
OF the double
UNION ALL
SELECT 445,
214,
2,
3,
'20090503'
OF the double
UNION ALL
SELECT 445,
214,
3,
2,
'20090503'
OF the double
UNION ALL
SELECT 445,
214,
4,
4,
"00000000".
THE DOUBLE)

First_value (ro.running_order) SELECT DISTINCT ON (PARTITION BY ro.segment_id, ro.programme_id ORDER BY ro.last_scheduled_date DESC)
Of episodes_running_order ro
WHERE ro.segment_id = 445
AND ro.programme_id = 214;

Hello

You can do this by using aggregate functions:

SELECT       MAX (running_order) KEEP (DENSE_RANK LAST ORDER BY last_scheduled_date)  AS highest_last_ro
FROM       episodes_running_order
WHERE       segment_id     = 445
AND       programme_id     = 214;

You can find results for several programs and segments together in a single query using GROUP BY.

If you want to use analytical,.

ROW_NUMBER () OVER (ORDER BY last_scheduled_date DESC, running_order DESC)  AS rnum

It affects 1 to the line you want. Assign the number (as shown above) in a subquery and say "WHERE rnum = 1" in the Super request.

Not that you asked: you must use a DATE column to store last_scheduled_date. Storing dates as strings (or numbers) causes a lot of problems.

Published by: Frank Kulash, may 6, 2009 11:46
Originally posted without ORDER BY in "DENSE_RANK LAST * ORDER BY * last_scheduled_date.

Tags: Database

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