Exact size a table takes
HelloCan someone show me how to get the EXACT size a table currently occupies.
Thank you.
Heres something I've implemented for a client recently who wanted the object sizes, it breaks down the by object type (tables, indexes, lobtables, lobindexes) and see the percentage against total db size used in the segments... throw a table_name in if you want to limit the search... to remove the commentary on the inscription 'account' below to exclude all smaller then 50 MB
as noted above, the blocks are different, but its close enough. could get some use out of it.
define 999 pages
fixed lines 180
SELECT
owner, table_name, round ((sum (bytes) / 1024/1024/1024), 4) Size_GB,.
round (TRUNC (sum (bytes) / 1024/1024) / total_size_meg * 100, 2) Percentage_of_total_size.
total_size_meg
Of
(SELECT table_name, nom_segment, owner, bytes)
FROM dba_segments
WHERE segment_type = 'TABLE '.
UNION ALL
SELECT i.table_name, i.owner, s.bytes
OF dba_indexes i, s dba_segments
WHERE s.segment_name = i.index_name
AND s.owner = i.owner
AND s.segment_type = 'INDEX '.
UNION ALL
SELECT l.table_name, l.owner, s.bytes
OF dba_lobs l, s dba_segments
WHERE s.segment_name = l.segment_name
AND s.owner = l.owner
AND s.segment_type = 'LOBSEGMENT. '
UNION ALL
SELECT l.table_name, l.owner, s.bytes
OF dba_lobs l, s dba_segments
WHERE s.segment_name = l.index_name
AND s.owner = l.owner
AND s.segment_type is 'LOBINDEX'),
(select sum(bytes/1024/1024) total_size_meg from v$ datafile)
WHERE
-table_name like '%
owner not in ('SYS', 'SYSTEM')
GROUP BY table_name, owner, total_size_meg
HAVING SUM (bytes) / 1024/1024 > 50 / * Ignore really small tables currently commented out * /.
ORDER BY OWNER, SUM (bytes) desc
Tags: Database
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Published by: vikrant dixit on April 9, 2009 12:06 AMHello..
To know the size of the scheme: -.
select owner,sum(bytes/1024/1024)MB from dba_segments group by owner;
TO know the actual size of the database
select sum(bytes/1024/1024/1024) Actual_size_gb from dba_segments
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