Excerpt from time in the data type Date
Hi guys,.I run the query below:
select to_char(sysdate,'hh24:mi:ss') from dual
14:39:04
select to_date(to_char(sysdate,'hh24:mi:ss'),'hh24:mi:ss') from dual
01/07/2012 14:39:40
Is is possible to get just the part time in IE the date in any case data type, using the second request, I should get only the part time instead of any date and time.See you soon,.
Shaz
Hi, Shaz,
SH * wrote:
Is is possible to get just the part time in IE the date in any case data type, using the second request, I should get only the part time instead of any date and time.
Lol DATEs in Oracle always include year, month, day, hours, minutes, and seconds. There is no way to get a DATE without each of them.
You may want to store this data in an INTERVAL column, not a DATE.
Depending on how you plan to use, a NUMBER might work, too (for example, the number of minutes after midnight) or a VARCHAR2, such as ' 09: 53:32'.
If you really need to use a DATE for any reason, you may simply ignore the year, month and day or put always a default value, such as 1 January 0001.
What is the problem you're trying to solve? If you explain what you need to do, then someone can help you find a good way to do it.
Tags: Database
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excerpt from hh mm ss date field
Hi good morning all,
I have a column of type date data source event_dt
and as vales
2000/01/13 06:35:48
2008-11-04 06:27:46
2008-05-11 07:17:02
2008-11-05 08:03:37
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1 00:00 0 0 AM
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3 00:02 0 02:00
4 00:03 0 03:00
5 00:04 0 04:00
6 00:05 0 05:00
7 00:06 0 06:00
8 00:07 0 07:00
9 00:08 0 08:00
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902 15:01 15 13:00
903 15:02 15 14:00
904 15:03 15 15:00
905 15:04 15 16:00
906 15:05 15 17:00
now, I want to match the time of the event (only the hours, minutes, AM, PM) and get the key
using IAM
SELECT
EXTRACT (HOUR OF TO_TIMESTAMP (JANUARY 1, 2005 19:15:26 ',))
"HH24:MI:SS OF MON-DD-YYYY")) AS THE HOURS,
EXTRACT (MINUTE TO_TIMESTAMP (JANUARY 1, 2005 19:15:26 ',))
"HH24:MI:SS OF MON-DD-YYYY")) MINUTE,.
EXTRACT (SECOND TO_TIMESTAMP (JANUARY 1, 2005 19:15:26 ',))
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DOUBLE;
but unable to figure out how I AM/PM game and get the key...
Please suggest...
Published by: user633377 on July 1, 2009 10:14Hello
user633377 wrote:
but I want to extract hh in the a, b ss, SS band C and AM/PM d.research it work with mytime tabel and get the key, what iam doing...
My input data are already in Formate of date over time.
In your first post, it sounded like you wanted to match the lines of the two tables.
You say now that you want to add lines to the second table based on the values of the first table?
If so, use TO_CHAR to retrieve all the columns and, where necessary, convert numbers using TO_NUMBER.INSERT INTO timetable (time_value, time_hrs, time_min, ampm_ind) SELECT TO_CHAR (event_dt, 'HH24:MI'), TO_NUMBER (TO_CHAR (event_dt, 'HH24')), TO_NUMBER (TO_CHAR (event_dt, 'MI')), TO_CHAR (event_dt, 'AM') FROM sourcetable;
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Excerpt from table (insert the provided table)
I would like to get the ID with one of the specific criteria
1 iDs who ONLY have LOST STATUS and TAKEN_DTE as NULL in the YEAR 2010/2011
The ID peut have status as TAKEN previous to the YEAR 2010 but first must meet the above criteria.
CREATE TABLE CHLOE_C)
ID varchar (8),
YEAR varchar (8),
Varchar (8), the STATE
TAKEN_DTE varchar (8),
STATUS varchar (8));
INSERT ALL
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES ('80730 ","2006 ", 602" ", March 13, 2006 ', ' TAKEN')
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES (' '80730', ' 2010 ', 705', 12 March 2010 ', "LOST")
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES (' '6321 ', '2012', ' 1203', 13 March 2012 ', ' LOST')
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES (' '6321 ', '2012', ' 1209', 13 March 2012 ', ' TAKEN')
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES ('75454 ', '2010', ' 1015', ","LOST")
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES (' '75454', ' 2011 ', 602', March 13, 2011 ', ' TAKEN')
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES ('100 ', '2010', 6102', ","LOST")
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES (' '100 ', '2009', 6152', March 13, 2009 ', ' TAKEN')
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES (' '100', ' 2006 ', 61152', March 13, 2006 ', ' LOST')
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES ('99 ', '2009', 5402', ","LOST")
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES (' '99 ', '2010', 6102', 13 March 2010 ', "LOST")
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES ('88 ', '2011', 6102', ","LOST")
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES ('88 ', '2010', 6102', ","LOST")
IN chloe_c (ID, YEAR, STATE, TAKEN_DTE, STATUS) VALUES (' '88 ', '2009', 6102', 13 March 2010 ', "TAKEN")
SELECT * FROM dual;
THEN
ID 88 YES because it saisfies the criteria it has NULL in TAKEN_DTE and STATUS as LOST, for the two years
99 NO ID that she satisfied the STATE but it has a TAKEN_DTE year 2010
ID 100 YES it has the STATUS as LOST and YEAR 2010 (STATUS TAKEN is prior 2010 so its ok)
ID 6321 NO YEAR IS 2012 (DO YOU WANT ANYTHING FROM 2012)
75454 ID number STATE is LOST for 2010 which is what we want, but she also TOOK in 2011 which we do not want
80730 NO ID even if the STATUS is LOST TAKEN_DTE is not NULL
I tried something like this:ID 88 100
but it also gives me ID 75454Select distinct C.ID FROM chloe_c C WHERE c.taken_dte IS NULL AND YEAR in ('2010','2011') AND ID not in (SELECT ID FROM chloe_c c WHERE c.status = 'Taken' and c.year in ('2011','2010'))
Hello
That's what you asked for:
SELECT id FROM chloe_c WHERE year IN ('2010', '2011') GROUP BY id HAVING COUNT ( CASE WHEN status = 'LOST' AND taken_dte IS NULL THEN 'OK' END ) = COUNT (*) ;
Thnaks for the display of the sample data. don't forget why do you: that people who want to help you can recreate the problem and test their ideas. If you post code that does not work, then it is not so useful. You try to put 11 strings, for example, March 13, 2006 ", in a column of type VARCHAR (8)" Test your code before you post.
Use VARCHAR2, VARCHAR not, for strings.
Use DATE (or perhaps TIMESTAMP), no strings to the date information. -
Hi all
START_TIME RUN_DURATION
28/02/2011-21:23 0:38:02
These are my two columns. I would like to introduce a new column END_TIME which would add START_TIME and RUN_DURATION.
How to extract START_TIME time and add it to RUN_DURATION.
Thanks in advance.KRRISH... wrote:
HelloThanks for your reply.
I still need that. but at least for now, I need END_TIME so that I can get rid of manual times added.
Concerning
Well, for starters, there's some pretty nasty date calculations...
SQL> ed Wrote file afiedt.buf 1 with t as (select to_date('2/28/2011 21:23','MM/DD/YYYY HH24:MI') as start_time, '0:38:02' as duration from dual) 2 -- 3 select start_time 4 ,duration 5 ,trunc(start_time) + 6 (( 7 ((to_number(to_char(start_time,'HH24'))*3600)+(to_number(to_char(start_time,'MI'))*60)) + 8 ((to_number(to_char(to_date(duration,'HH24:MI:SS'),'HH24'))*3600)+(to_number(to_char(to_date(duration,'HH24:MI:SS'),'MI'))*60)+(to_number(to_char(to_date(duration,'HH24:MI:SS'),'SS')))) 9 )/(24*60*60)) 10 as end_time 11* from t SQL> / START_TIME DURATIO END_TIME -------------------- ------- -------------------- 28-FEB-2011 21:23:00 0:38:02 28-FEB-2011 22:01:02 SQL>
Edit: I forgot to say, that also deals with the renewal of the dates too:
SQL> ed Wrote file afiedt.buf 1 with t as (select to_date('2/28/2011 21:23','MM/DD/YYYY HH24:MI') as start_time, '5:38:02' as duration from dual) 2 -- 3 select start_time 4 ,duration 5 ,trunc(start_time) + 6 (( 7 ((to_number(to_char(start_time,'HH24'))*3600)+(to_number(to_char(start_time,'MI'))*60)) + 8 ((to_number(to_char(to_date(duration,'HH24:MI:SS'),'HH24'))*3600)+(to_number(to_char(to_date(duration,'HH24:MI:SS'),'MI'))*60)+(to_number(to_char(to_date(duration,'HH24:MI:SS'),'SS')))) 9 )/(24*60*60)) 10 as end_time 11* from t SQL> / START_TIME DURATIO END_TIME -------------------- ------- -------------------- 28-FEB-2011 21:23:00 5:38:02 01-MAR-2011 03:01:02 SQL>
Published by: BluShadow on March 1st, 2011 09:51
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