Extraction of the data from a string

Hi all

I'm using Oracle 11.2.0.1.0

CREATE TABLE BENEFIT(
  BENVAL       VARCHAR2(255 BYTE))


  insert into BENEFIT values ('Included - 365 days/50%/50%   ');
    insert into BENEFIT values ('Included - 120 days/50%/50%   ');
        insert into BENEFIT values ('Included - 365 days/75%/50%  ');

I would like the following output.

BENVAL Days FIRSTPER SECONDPER
Included - 365 days/50%/50%3655050
Included - 120 days/50%/50%1205050
Included - 365 days/75%/50%3657550

The days column must be set in the chain before days, the firstper column must be set between Prime ' / ' and the second ' / ', the secondper must be set after the last ' / '.

Currently, I created a table to store the distinct values in a table and by referencing tables in my select query. Instead, I wanted to know if I can create a SQL statement.

Thanks in advance.

Hello

Perhaps the easiest way is:

SELECT benval

, REGEXP_SUBSTR (benval, '\d+', 1, 1) AS days - or TO_NUMBER (REGEXP_SUBSTR...

, REGEXP_SUBSTR (benval, '\d+', 1, 2) AS firstper - or TO_NUMBER (REGEXP_SUBSTR...

, REGEXP_SUBSTR (benval, '\d+', 1, 3) AS secondper - or TO_NUMBER (REGEXP_SUBSTR...

BENEFITS

;

Guess what

  1. all 3 numbers are present,
  2. the days always appear first (as they do in the sample data),
  3. If there are other numbers in the chain, these additional staff come after percentages, and
  4. 3 numbers you want are unsigned integers.

If any of these assumptions are false, then you can always use REGEXP_REPLACE, but things get a little more complicated.

REGEXP_SUBSTR returns a VARCHAR2.  If you want a NUMBER, call the string passed by REGEXP_SUBSTR TO_NUMBER.

Tags: Database

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