Fast formula error

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• Fast formulas, and user-defined Table

  Hello world

  I defined a udt as follows:

  Structure of the table >

  Name: TEST_SLAB

  Key of the user Table: TEST_SLAB

  Match type: range

  Unit of measure for the key: number

  Rank title: Null

  The values in the table >

  Table: TEST_SLAB

  Unit of measure for the key: number

  Column name: TEST_SLAB

  Value upper limit lower limit

  0                                   1000                         10

  How to write my quick formula:

  By DEFAULT for the union 'IS'
  The ENTRIES ARE union (text)
  deduction = 0
  OTHERWISE the union WAS in default
  THEN
  deduction = TO_NUMBER (GET_TABLE_VALUE ('?', '?',?))
  
  Deduction of RETURN

  The syntax is

  GET_TABLE_VALUE ('Table_Name', 'Column_Name', l_input_value)

  More information are using the values in table in the fast formulas

  Kind regards

  Stephanie.

• Fast formula

  Hello

  Is it possible to add an item to the next payroll month calculalation? Thanks to the fast formula?

  Please guide.

  Thank you

  Hi, the result type of the JUDGMENT has the effect of end - date of the entry of the item that was the formula that generated the stop statement.

  The use is in the formula, set a local variable, i.e. L_STOP. So, if you are in a situation within the formula where it is necessary to effectively stop the entry of the element, you must set L_STOP 'Y' and BACK as well as the other things that you would normally returned. For example:

  :

  IF L_REMAINING_DEBT - L_PERIOD_DEDUCTION = 0 THEN

  (L_MESSAGE = "Entirely free from debt"

  L_STOP = 'Y '.

  RETURN L_MESSAGE, L_PERIOD_DEDUCTION, L_STOP)

  ON THE OTHER

  (RETURN L_PERIOD_DEDUCTION)

  :

  Then to your rules of the formula result for this element/formula, in addition to the existing rules for example L_PERIOD_DEDUCTION and L_MESSAGE, you must also set a rule of the formula result of L_STOP which is a type of "Stop".

  Hope this helps

  Clive

• How to debug the code for fast formula OTL plsql?

  Hello

  I have trouble understanding the flow of my code PLSQL (function), which is called by a fast formula HRMS.

  I don't know how to debug.

  Can I add lines of hr_utility.trace to the PLSQL? If so, see where you put it?

  Help, please.

  Thank you

  Germain

  Hi, Germain,.

  You can start the trace in the form and complete it in the formula. The handle of the trace will display all messages of the formula and the pl/sql functions that formula calls internally. So, indeed, you should get all the trace messages in your trace file.

  If you want to only draw a pl/sql function, add this in pl/sql code from the point you want to draw, and then add the trace_off at the end-

  hr_utility. TRACE_ON (null, 'VBATTU_TRACE');

  hr_utility.trace ('# START #');

  ..

  ..

  ..

  ..

  hr_utility.trace_off;

  Cheers,

  Vignesh

• Fast formula question

  Please, could someone confirm if a quick formula can include a statement to automatically generate the input element?
  
  I created a formula to produce the value I need, but I don't want the item to appear in the entries of the item unless the value is greater than 0.
  
  For the moment, I need to have the added element first on the inputs of the element for the formula to work, as I did not of course above all upward.
  
  So in summary I never used the fast formulas that the item is already in the entries of the element, before the execution of payroll. I would like to now the element to automatically generate than if a value is filled in the FF by operating on the payroll.
  
  Thank you very much
  
  Steve

  OK, race results are literally the results of what happened at an entrance of the specific item in a list of specific payroll executed. Normally, the payroll team will get to see these if they watch an assignment in a race on the payroll. If you access

  View-> transfer process results

  You will be able to examine the process of payroll for this assignment (these bananas are referred to as transfer Actions) - for payroll (or Express) types, there is the possibility, via a button at the bottom of the screen, display the results. Subsequently, you can see what results and values of result of track have been generated

  In a formula, when it returns something, this can go somewhere. Where he goes depends on how you have configured rules formula result. There are many mechanisms available, but the most common is "Indirect result". This allows you to fire a formula element 'X' type and are the result of a calculation that is sent as an indirect element result 'Y '. There is no actual entry element for the element 'Y', but there is an execution result and in fact a result execution for the element value 'Y' for that pay for this assignment.

  Hope this helps, but come back if you want more details.

  Clive

• Last day of the year in fast formula

  Hi all
  
  I have to deal with something special, based on the last day of the current year.
  
  How can I get the last day of the year? Is there a function available in the fast formulas?
  
  Appreciate all entries...
  
  Thank you
  SRS

  What is

  :
  L_last_day = TO_DATE (' 31 - DEC-'+ TO_CHAR (PAY_PROC_PERIOD_END_DATE, 'YYYY'), 'DD-MON-YYYY')
  :

  Clive

• Add_Months is allowed in a fast formula?

  Hello
  
  Im trying to add the following to carry him on a quick formula.
  
  : Mid_Month_DDMM = to_char (to_date (to_char (ADD_MONTHS (Continuous_Service_Date, + 1), "YYYYMM"), "YYYYMM")-1, "JJMM")
  
  But it seems that the formula does not like "Add_months. Im trying to get the formula to work when a continuous_service_date of employees is not the 1st of the passing months will happen by the end of the month.
  
  Thank you
  
  Andrew

  Hi André,.

  Have you tried using the Last_Day function.

  select last_day(sysdate) from dual;
  or
  select to_char(last_day(sysdate),'DDMM') from dual;
  

  I also see that LAST_DAY and ADD_MONTHS functions are provided with the application.
  http://docs.Oracle.com/CD/E18727_01/doc.121/e14567/T1774T1776.htm#6280105

  On the other-
  Snandard sql functions can be created in function formula from the front-end server.

  The functions TRUNC, ROUND etc... Use built-in Sql directly.
  So, you can create a new SQL - LAST_DAY function-based LAST_DAY say function.

  The engine Fast formula would decode those during execution.

  See you soon,.
  Vignesh

• Descriptive flexfield using fast formula

  Dear all,
  
  How to use the de FACTO forces in fast formula.
  
  Thank you
  Mr. Bilal

  Check-

  select user_entity_id,definition_text from ff_database_items -- user_entity_id
  where user_name = 'ACP_SERVICE_START_DATE'; -- change this to your DBI
  
  select route_id from ff_user_entities -- route_id
  where user_entity_id = 1228; -- user_entity_id from the previous query
  
  select text from ff_routes -- text
  where route_id = 286; -- route_id from previous query
  

  Now you can build a sql statement-

  Select /* definition_text */ -- from the 1st query
  from
  /* text */ -- from the 3rd query
  

  The above query returns you the value that is the same as used in a FF DBI

  Also, try to delete the aliases in your formula, instead use the DBIs directly and see if that makes a difference.

  see you soon,
  VB

• Urgent: How differentiate between retro and payroll in fast formula

  I wrote a quick formula. This quick form is attached to the element of "basic salary".
  "Base salary" item has retro setting and proration.
  We use retro processes strengthened.
  Improved retro process calls this quick formula to verify the amount of the difference.
  Similarly, oracle payroll will also call the same formula fast when running on the payroll.
  
  Now, our requirement is:
  ----------------------------------
  A few lines in fast formula should not run when FF is called by retro, but it must be run when it is called by the payroll.
  So, how could we know if FF is called process retro or payroll?
  If I have a way to find this, I can run that code using this condition.
  Any pointer in this regard will be highly appreciated.

  None of the above... Just write a function custom PLSQL who will be ID action of payroll as a context parameter & returns the table PAY_PAYROLL_ACTIONS... action_type column to the fast formula. L is for Retro throw.

  In the quick formula, place the specific code in the if condition.

  ATTENTION: Make the formula calculate differently in normal payroll & retro you can cause serious problems of consistency in payments/deductions and their debugging might become impossible in the long term.

  Published by: Maxime bushel Sep 22, 2011 07:00

• OTL entry sets the time - fast formula not triggered

  Requirement: Throw an error during the registration of the time, if time is < 40 and overtime are > 0

  Approach:

  (1) created PLSQL function and defined in HRMS

  (2) created a quick formula, using the above function

  (3) created a new TER

  (4) fixed to the TERG existing (operation TERG prod)

  Details:

  My function (only for a CEP). Returns 1 always (error throw)

  SET DEFINE OFF

  CREATE OR REPLACE

  APPS PACKAGE. XXXXX_HXC_CUST_RULES as

  -Description:

  -History

  FUNCTION XXXXX_CHK_OT_ELIGIBLE return number (p_resource_id in NUMBER);

  END XXXXX_HXC_CUST_RULES;

  /

  CREATE OR REPLACE

  PACKAGE BODY XXxxx_HXC_CUST_RULES AS

  FUNCTION XXxxx_CHK_OT_ELIGIBLE (p_resource_id NUMBER)

  RETURN number

  IS

  l_return_rule_status number: = 0;

  l_timecard_info hxc_self_service_time_deposit.timecard_info;

  l_tbb_array HXC_BLOCK_TABLE_TYPE;

  BEGIN

  l_timecard_info: = hxc_self_service_time_deposit.get_building_blocks;

  l_tbb_array: = hxc_deposit_wrapper_utilities.blocks_to_array (p_blocks = > l_timecard_info);

  RETURN 1;

  -0 is not an error

  -1 is error

  EXCEPTION

  WHILE OTHERS THEN

  null;

  END;

  END XXxx_HXC_CUST_RULES;

  /

  DEFINITION FORMULA FAST

  /* *****************************************************************

  Name of the form: XXXX_CHK_OT_ELIGIBLE

  Description: Prevent OT when not eligible (40 hrs of ST)

  Contexts: no

  *****************************************************************

  */

  /*

  Initialize Variables that may be null

  *****************************************************************

  */

  the default for db_pre_period_start is ' '

  the default for db_pre_period_end is ' '

  the default for db_post_period_start is ' '

  the default for db_post_period_end is ' '

  the default for db_ref_period_start is ' '

  the default for db_ref_period_end is ' '

  default value of timecard_hrs is 0

  /* ******************************************************************

  READ IN THE INPUT VARIABLES

  ****************************************************************** */

  The ENTRIES ARE id_ressource (number)

  submission_date (text)

  db_pre_period_start (text)

  db_pre_period_end (text)

  db_post_period_start (text)

  db_post_period_end (text)

  db_ref_period_start (text)

  db_ref_period_end (text)

  timecard_hrs (number)

  IF (XXxx_HXC_CHK_OT_ELIG_FN (resource_id) = 1)

  THEN

  (rule_status = 'E'

  Message1 = "XXxxx_CHK_OT_ELIGIBLE."

  return rule_status, message1)

  ON THE OTHER

  (s = rule_status"

  return rule_status)

  The above formula is verified successfully. I can see the FFP plsql pkg also created in the DB.

  The RULES of SEIZURE of TIME are created to record and SEND/QUOTE

  Then, they are attached to an existing rule GROUP on the TIME ENTRY. Yes, at least it is not the question, because it's a group of working time entry rules.

  MY QUESTIONS ARE BELOW

  (1) the function accepts id_ressource as an entry, should I set this as a FDF segment or is not not necessary?

  (2) even if I attach a formula seeded to my TER, it is not triggered. I suppose, then, that there is nothing wrong with the quick formula atleast.

  Pointers would be a great help.

  Thank you

  Germain

  I found the reason why it was not a device.

  The quick formula was an effective start date of November 7, 2013, the TER also had effective start date of November 7, 2013.

  The score card I used was in October.

  Silly, but he did.

  Thanks for your help.

• Curve nonlinear coupling with chain on-29083 formula error

  Dear members,

  I'm working on a curve nonlinear vi using the formula string. I just want to get the value of a connection and b through the formula y = a *(x-b) ^ 1.5. But I can't get the error with the code 23083, when I run.

  The vi and a data set is attached. I found if I choose any whole exponent instead of 1.5. The vi will run successfully.

  I wonder if I'm doing something wrong. Can someone have glance on my vi?

  concerning

  OK, your model does not fit the data. You must either change the data there are 2 or add an offset term for the model.

  Here is a quick sketch. Modify if needed.

  

• Spreadsheet formula error

  I use ColdFusion 11 and try to use the FDIST function in a worksheet to get the value of F-distribution. The error I get, is that he doesn't like the semicolon in the formula. In the exception.log file, I see this error, org.apache.poi.ss.formula.FormulaParseException: Parse error near tank 7 ';' in the specified form "FDIST(1;4;5)". Expected ","or")"

  The simplified code is the following:

  < cfset sObj = SpreadsheetNew() >

  < cfset sFormula = "FDIST (1; 4; 5)" >

  < cfset spreadsheetSetCellFormula (sObj, sFormula, 1, 1) >

  < cfset iValue = spreadsheetGetCellValue (sObj, 1, 1) >

  < cfoutput >

  < p > value = #iValue # < /p >

  < / cfoutput >

  Please let me know how this can be corrected. Any ideas?

  Info on FDIST function Documentation/How Tos/Calc: function FDIST - Apache OpenOffice Wiki

  Thank you.

  Milind

  ColdFusion does not recognize these formulas.

  I was talking to a guy at adobe, it is sure it's a bug.

  Although it seems that CF use Apache POI to do all the work behind the scenes. The Apache POI does NOT currently support FDIST as formula. - Develop the evaluation of the formula

• To_Number fast formula conversion

  Hi all
  
  I do a quick calculation of simple formula where I'm trying to convert the date of return to number.
  It start error. But what I am doing wrong. I'm trying to convert the returned date value of number.
  
  
  
  ***
  APP-FF-33983: type mismatch in parameter for the function "TO_NUMBER" on line 15
  
  Cause: The user has specified a function whose name was recognized but whose types of parameters are not all versions known to the service.
  
  Action: Please verify that the variables or literals passed to the function are types appropriate for the function definition. ***
  
  This is my code
  
  ----------------------------------------------------
  IS the DEFAULT for EMP_TERM_DATE '' 1-JAN-4712 (date)
  DEFAULT value FOR PAY_PROC_PERIOD_START_DATE IS 1 January 1951"(date)
  Value by DEFAULT FOR PAY_PROC_PERIOD_END_DATE IS 31-DEC-4712' (date)
  DEFAULT for C_Allowance_Balance_ASG_YTD is 0
  DEFAULT for L_paid_amount IS 0
  DEFAULT for Day_amount IS 0
  DEFAULT for days_deduction IS 0
  DEFAULT for deducted_amount IS 0
  Is the DEFAULT for L_last_day '' 31-JAN-4712 (date)
  
  L_last_day = TO_DATE (' 31 - DEC-'+ TO_CHAR (PAY_PROC_PERIOD_END_DATE, 'YYYY'), 'DD-MON-YYYY')
  
  Day_amount = (C_Allowance_Balance_ASG_YTD) / 365
  
  / * 15 * / days_deduction = to_number(l_last_day-EMP_TERM_DATE)
  deducted_amount = days_deduction * days_amount
  
  return deducted_amount

  Hello

  Try this once.

  days_deduction = days_between (L_last_day, EMP_TERM_DATE)

  Kind regards
  Aneesh N

• Union of the not compatible between the column in obiee formula error

  Hi Experts,
  
  Error: Union of the incompatible types
  
  I used the Case function in my column formula and got above error as well.
  
  The formula for the column goes below:
  
  IFNULL (CASE WHEN EDM_TRD_IR_LEG. LEG_ID = 1 THEN (EDM_TRD_IR_LEG. (END PAY_RECV_IND) OTHERWISE 0, 0)
  
  
  LEGID is of type number. PAY_RECV_IND is of type varchar.
  
  Please let me know how to fix this error.
  
  Thanks in advance.
  
  
  -Looks
  Mayuri

  898221 wrote:
  Hi Experts,

  Error: Union of the incompatible types

  I used the Case function in my column formula and got above error as well.

  The formula for the column goes below:

  IFNULL (CASE WHEN EDM_TRD_IR_LEG. LEG_ID = 1 THEN (EDM_TRD_IR_LEG. (END PAY_RECV_IND) OTHERWISE 0, 0)

  LEGID is of type number. PAY_RECV_IND is of type varchar.

  Please let me know how to fix this error.

  Thanks in advance.

  -Looks
  Mayuri

  @dpka, you have syntax errors in your solution. If you are casting as a varchar, then your syntax should read "1" instead of 1. Also at the end, he must be "0" instead of 0.

  Mayuri,

  To use your syntax, try this:

  IFNULL (CASE WHEN EDM_TRD_IR_LEG. LEG_ID = 1 THEN CAST (EDM_TRD_IR_LEG. (PAY_RECV_IND AS INTEGER) END ELSE 0, 0)

  .. . If you need the result as a digital for purposes of aggregation...

• validation of a member formula error

  Hi, I'm trying to write a formula in a limb that is dynamic cal, but when I try to use it with education fix formulas gives me a validation error, but when I write the same logic using if its getting validated statement.
  the formulas that I use with fix is
  
  Fix ("FY11")
  "E622".
  Endfix;
  
  but it gives an error "compiler error formula for [] (line 3): [()] without [)].
  
  but when I use it with if
  If ("FY11")
  "E622".
  Endif;
  its works fine, but it would not take more time to recover if I use it with 'IF', that's why I wanted to FIX instead of IF user
  Here FY11 is a member of the dimension of the year E622 is an entity and I apply this formula to a member of the entity
  Thanks in advance.
  I use hyperion 9.3.1

  You cannot use a FIX in a formula, you can use an IF.
  FIX can be used in calc scripts/trade rules.

  The REF can only be used in the calculation scripts, not in the forms of hierarchical member tech - "FIX statements. Use an IF command instead of a statement of FIX in the member formulas".

  See you soon

  John
  http://John-Goodwin.blogspot.com/