Figure out how many years and days between two dates
Nice day
I've been dealing with the problem for a few days now so I thought that I could send it and see if someone can tell me what I'm doing wrong.
/ * Create a Date with a date object. */
var d1 = getField "(RELEASE. DATE') .value;
/ * Create a date object containing the current date. */
var d2 = getField("Text4").value;
/ * Number of years difference. */
diff = (((d2.valueOf () - d1.valueOf (()) / 1000) / 60) / 60) / 24) / 365;
Displays the field "Text3".
getField("Text3").value = (diff); & #8232;
< END >
RELEASE. Value DATE is January 1, 2011, with a date format dd/mmm/yyyy
Text4 value is March 1, 2011 with a date format dd/mmm/yyyy
The release of Text3 gives me a 'NaN' result
What I'm trying to do is calculated the number of years an employee has had with the company, and then display a balance of days that he had.
Any thoughts would be greatly appreciated.
repeated conversion from date string and number of days for the reuse of code
function Date2Num (cFormat, cDate) {}
Converts a date string formatted in days since the date of the time
Kai var = util.scand (cFormat, cDate);
Math.floor (oDate.getTime (return) / (1000 * 60 * 60 * 24));
}
/ * Create a Date with a date object. */
var d1 = (getField("Enrol_Day").value + "/" + getField("EnrolMonth").value + "/" + getField("EnrolYear").value);
Converts a date in the date object string
oD1 var = util.scand ("dd/mmm/yyyy", d1);
get the current date of the field
var d2 = (getField ("TD. RelDay") .value + ' / ' + getField ("TD. RelMonth") .value + ' / ' + getField ("TD. (RelYear') .value);
calculate the difference in days
diff var = Date2Num ("dd/mmm/yyyy", d2) - Date2Num ("dd/mmm/yyyy", d1);
increment the value if the end date should be included in the calculation
diff ++;
convert days to truncate all years - to the next intiger lowest
var carnavalSVP = Math.floor(diff / 365.25);
get the current year interval - rest of diff days divided by 365.25 days
var nDays = Math.floor (diff % 365.25);
display the entered values
CMSG var = ' end date: "+ d2 +" \t Compute days: ' "+ Date2Num (" dd/mmm/yyyy", d2);
CMSG += "\nStart date:" + d1 + "\t Compute days: '" + Date2Num ("dd/mmm/yyyy", d1);
Total difference in days
CMSG += "\nTotal elapsed days:"+ diff;»
result in years and days
CMSG += "\nYears:" + carnavalSVP + "and" + nDays + 'days'; "."
App.Alert (GSMC, 1, 0, "results");
//
Tags: Acrobat
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Is it possible to display the number of months, weeks and days between 2 dates? by using only the SQL or PL/SQL...
Entry:
Date: October 1, 2010
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October 1, 2010-(since it's in the middle of the week)
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Fox.You mean something like this...
SQL> ed Wrote file afiedt.buf 1 WITH t AS (select date '2010-09-27' as fdate, date '2010-11-21' as tdate from dual) 2 -- 3 -- END OF TEST DATA 4 -- 5 select dt2 6 from ( 7 select dt, 8 case when days_of_mn = days_in_month then 'Whole: '||to_char(dt,'Month') 9 when days_of_wk = 7 then 'Week: '||to_char(dt,'fmWW') 10 else to_char(dt, 'DD-fmMonth-YYYY') 11 end as dt2 12 ,row_number() over (partition by 13 case when days_of_mn = days_in_month then to_char(dt,'Month') 14 when days_of_wk = 7 then 'Week: '||to_char(dt,'fmWW') 15 else to_char(dt, 'DD-fmMonth-YYYY') 16 end order by dt) as rn 17 from ( 18 select dt, wk, mn, days_in_month 19 ,count(*) over (partition by wk) as days_of_wk 20 ,count(*) over (partition by mn) as days_of_mn 21 from ( 22 select fdate+rownum-1 as dt 23 ,to_number(to_char(fdate+rownum-1,'fmWW')) as wk 24 ,to_number(to_char(fdate+rownum-1,'fmMM')) as mn 25 ,to_number(to_char(last_day(fdate+rownum-1),'fmDD')) as days_in_month 26 from t 27 connect by rownum <= tdate-fdate+1 28 ) 29 ) 30 ) x 31 where rn = 1 32* order by dt SQL> / DT2 ----------------- 27-September-2010 28-September-2010 29-September-2010 30-September-2010 Whole: October Week: 44 Week: 45 Week: 46 19-November-2010 20-November-2010 21-November-2010 11 rows selected. SQL>
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Hello
I want to find the months and days between 2 dates.
For example.
1 - Date: August 25, 2013
2 - Date: October 23, 2013
If we consider each month 30 days, it should give
August 25, 2013 to August 30, 2013 = 6 days
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Total = 1 month and 14 days.
Kindly help as soon as possible.
Thanks and greetings
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Assuming that d2 > d1,.
where d)
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Union all select to_date (July 30, 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double
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d
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In my view, which corresponds to your rules.
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Dynamic calculation of the number of days between two dates in a table
Hello
I'm working on request where I dynamically calculate the number of days between two dates in a table.
The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.
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Hi BO123,
BO123 wrote:
Hello
I'm working on request where I dynamically calculate the number of days between two dates in a table.
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APEX version: 5.0
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See the sample code given below to fetch the resulting duration and making the field read only after calculation
Step 1: Change your page
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var
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I know there is lack of code and code above are may not be not correct.
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Math.ABS ((firstDate.getTime)
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Hello!
If anyone can help? ... with differences in Date? :
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When I try the regular difference:
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FIX (SOLUTION YOUR MEMBERS HERE)
"BLOCK MEMBER")Y1=@round ("Date of 1" / 10000,0);
Y2=@round ("Date 2" / 10000,0);
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ENDFIXSee you soon,.
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JavaScript anomaly on the number of days between two dates
Use ApEx 4.0, I found an anomaly in a javascript code that calculates the number of days between two dates, the current_date and the past_date. If the past and present is the or before March 10, 2013, and the current_date lies between 10 March 2013 and November 3, 2013, the number of days will be from 1 day to less than the actual number. Between November 3, 2013 and on 4 November 2013, the increments of number by 2, then the count will be accurate from this date forward.
Here are some examples:
March 10, 2013 = 69 days of December 31, 2012
March 11, 2013 = 69 days of December 31, 2012
March 12, 2013 = 70 days of December 31, 2012
November 3, 2013 = 306 days in December 31, 2012
November 4, 2013 = 308 days in December 31, 2012
11 March should be 70 and 12 March should be 71. November 3 is 307 and 4 November corrects the number of fake, which began March 11.
Change the past_date to March 10, 2013 produces the following:
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March 11, 2013 = 0 days of March 10, 2013
March 12, 2013 = 1 days of March 10, 2013
But change the past_date to 11 March 2013, product of the correct numbers:
March 11, 2013 = 0 days of March 11, 2013
March 12, 2013 = 1 days of March 11, 2013
March 13, 2013 = 2 days of March 11, 2013
I would certainly all help to determine the cause of this anomaly. Here's the javascript code:
var w1 = ($v ("P48_PAST_DATE"));
W1 = (w1.toString ());
vmon var = (w1.substr (3.3));
vyr var = (w1.substr (7));
var r = (vyr.length);
If (r == 2)
vyr. = (parseFloat (vyr) + 2000);
vday var = (w1.substr (0.2));
var y = (vmon.concat ("", vday, ",", vyr));
y = Date.parse (y);
var w2 = ($v ("P48_CURRENT_DATE"));
var vmon2 = (w2.substr (3.3));
var vyr2 = (w2.substr (7));
var vday2 = (w2.substr (0.2));
var x = (vmon2.concat ("", vday2, ",", vyr2));
x = Date.parse (x);
var numdays = (x - y);
numdays = (Math.floor(numdays / 86400000));
$s ("P48_NUMBEROFDAYS", numdays);Did you google for something like "javascript number of days between two dates. I think you will find the explanation to this observation:
This method does not work correctly if there is an advanced economies jump between the two dates.
There are examples available to calculate the difference between two dates.
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Calculate the number of days between two dates
Hello
Can someone help please change my formcalc script to calculate the number of working days between two date fields. My script currently calculates the total number of days between two dates, including the weekends which must be excluded from the total.
If
(HasValue (Start_Date1) & HasValue (End_Date1)) then
$
= Date2Num (End_Date1, "YYYY-MM-DD" "en_IE") - Date2Num (Start_Date1, "YYYY-MM-DD" "en_IE") + 1
on the other
""
endif
Any help will be most appreciated.
Thank you.
Check...
(1) you said that you put the script on the event «days1» calculate My sample imitates the variable names used in the original message, "Start_Date1" and "End_Date1". If the names of variables for the start and end dates are different, you will need to modify the script to account for these names.
(2) the Date2Num functions in the calculation of the "totalDays" use the date format "YYYY-MM-DD". If your date habits differ from "YYYY-MM-DD" FormCalc will complain.
Steve
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County of days between two dates without weekend
Hello
I need a solution in the query or another thread, which returns the number of days between two dates without considering the weekend (Saturday and Sunday), I have a column of type Date, and return need in the form of a column HH hours and days in another column.
Concerning
JonasHi and welcome to the forum.
Don't forget you can do a search on this forum.
Your question has been asked before.Some other tips:
http://asktom.Oracle.com/pls/asktom/asktom.download_file?p_file=6551242712657900129
http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:185012348071 -
Hi all
I need the days between two dates given.
Select to_date('25-mar-2014','dd-mon-yyyy') start_date, end_date to_date('30-mar-2014','dd-mon-yyyy')
of the double
Desired output:
25
26
27
28
29
30
Thanks in advance.
Kind regards
Afzal.
Select the level - 1 desired_output + to_number (to_char (start_date, 'dd'))
of (to_date('25-mar-2014','dd-mon-yyyy') select start_date, end_date to_date('30-mar-2014','dd-mon-yyyy'))
of the double
)
connect by level<= end_date="" -="" start_date="" +="">= >
DESIRED_OUTPUT 25 26 27 28 29 30 Concerning
Etbin
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days between two dates, excluding Saturday and Sunday
Hello
I have an obligation as: there are two entries in the query 1) startdate and 2) end date when the end user enter the start date and end date of the sql query to retrieve the number of days between given dates of beginning and end, and it should be retrivied with two condition 1) every Sunday between the above dates excluded 2) second and fourth Saturday of the month between the start dates and should be excluded.
example of start date: 01-May-09
end date: 16-May-09
release date: 13SELECT COUNT (*)
(SELECT TO_DATE('01-may-09') + LEVEL - dates 1)
OF THE DOUBLE
CONNECT BY LEVEL<= (to_date('16-may-09')="" -="" to_date('01-may-09'))="" +="" 1)="">=>
WHERE ((TO_CHAR (inner.dates, 'd') = 7
AND TO_CHAR(inner.dates, 'W') NOT IN (2, 4)
)
GOLD TO_CHAR (inner.dates, 'd.') not in (1.7)
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counting the days between two dates
I have 3 columns in my table
date of purchase date sold days
computer 24 April 09-11 May 09
How can I write that a sql statement will help me to create a new column days and days between date bought and sold
Thank you872959 wrote:
I have 3 columns in my tabledate of purchase date sold days
computer 24 April 09-11 May 09How can I write that a sql statement will help me to create a new column days and days between date bought and sold
Thank you
just subtract two dates & the difference will be in units of days
SQL > select to_date('11-MAY-09','DD-MON-YY') - double TO_DATE('24-APR-09','DD-MON-YY');
TO_DATE('11-MAY-09','DD-MON-YY')-TO_DATE('24-APR-09','DD-MON-YY')
-----------------------------------------------------------------
17Published by: sb92075 on July 19, 2011 10:26
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Number of occurrences of a day between two dates
Hello
I have a requirement in my code to count the number of times per day occurs between two dates. So, for example if
start date = January 1, 2014
end date = March 31, 2014
The number of times that happens day 1 is three times. That's why I want the result to be 3. My three input parameters are the number of the day, start and end dates. I know that this can be done by parsing through the days and incrementing a counter of sorts, but can it be done without any loop etc?
Looking for options of
Thank you
Birdy
SELECT COUNT (TO_CHAR (DAYS, 'DD')) IN)
SELECT DAYS START_DATE + LEVEL 1
FROM T1
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WHERE TO_CHAR (DAYS, 'DD') ='&01';
Post edited by: Parth272025
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