Fill with the previous 'not null' value ' Null' known values

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• Compare the value of the column with the previous column and Populate values

  Hi all
  
  
  Please help me to get the required sql
  
  I have a table T1 as example below
  
  Id1 Id2 Column1 Column2
  1 1 name1 null
  1 2 name2 XYZ
  1 3 name3 null
  1 4 name4 abc
  1 5 name5 null
  
  
  
  If the value is null, ishould then fill with the previous value. until he finds a following value.
  The result should be as below
  
  Id1 Id2 Column1 Column2
  1 1 name1 null
  1 2 name2 XYZ
  1 3 name3 XYZ
  1 4 name4 abc
  1 5 abc name5
  
  Please help me to get the required sql
  
  Thanks in advance

  Hello

  Here's one way:

  SELECT    id1
  ,       id2
  ,       column1
  ,       LAST_VALUE (column2  IGNORE NULLS)
                   OVER ( PARTITION BY  id1          -- if needed
                              ORDER BY         id2
                     )        AS column2
  FROM      t1
  ORDER BY  id1, id2                         -- if needed
  ;
  

  I'm guessing only a few things, as what makes a line 'previous' or 'next '.

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all tables and also post the results desired from these data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using. «LAST_VALUE...» IGNORE NULLS"requires that Oracle 10.1 or higher.

• Please let me know how I can add a new column with a constraint not null, table already has data, without falling off the table... Please help me on this issue...

  Hello

  I have an emp_job_det with a, b, c columns table. Note that this TABLE ALREADY has DATA OF THESE COLUMNS

  IAM now add a new column "D" with forced not null

  Fistly I alter the table by adding the single column "D", if I do, the entire column would be created with alll of nulls for the column DEFAULT D

  ALTER table emp_job_det Add number D; -do note not null CONSTRAINT is not added

  Second... If I try to add the constraint not null, get an eoor as already conatained null values...

  (GOLD)

  In other words, if I put the query

  ALTER table emp_job_det Add number D NOT NULL; -THROWS ERROR AS TABLE ALREADY CONTAINS DATA

  So my question is how how can I add a new column with a constraint not null, table already has the data, without falling off the table

  Please help me on this issue...

  Add the column without constraint, then fill the column. Once all the rows in the table are given in the new column, and then add the constraint not null.

• The doc is correct on the constraint not null and scan limited index full?

  Gave birth to the large [url http://forums.oracle.com/forums/thread.jspa?messageID=9313643] another thread:
  

  Jonathan Lewis wrote:
  >
  

  I wasn't expecting to see because the doc said about scan limited index full "...". and at least one column in the index key has the NOT NULL constraint,"which would be foolish to say if the rowid was what filled that. There are currently only 2 factory codes and code 1 company (not nulls - Oracle does know that?), so I was kind of expected Oracle to reorder the predicates with an index skip scan. Take a fresh look on the doc, I wonder if I should not specify the company code in the query and maybe spend employee and job_number in the index. I hope it's obvious that this index has been added for other queries. This request could be taken out a change in the requirements of anyway, but I don't know when.

  If you wear it as a separate thread, I'll take a look.
  Can you give a reference to the manual - the comment you quoted may not be correct.

  Just below where Hemant pointed to in the other thread, http://download.oracle.com/docs/cd/E11882_01/server.112/e16508/indexiot.htm#sthref314
  
  (Somehow I have the feeling that we had this conversation before, perhaps in a forum that no longer exists. "(Or was it all just a dream)."
  
  Edit: Also seen in
  http://download.Oracle.com/docs/CD/B28359_01/server.111/b28274/optimops.htm#i52044
  http://download.Oracle.com/docs/CD/B14117_01/server.101/b10752/optimops.htm#51111
  http://download.Oracle.com/docs/CD/F49540_01/doc/server.815/a67781/c20b_ops.htm#11004
  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14211/optimops.htm#i52044
  
  and everything on the net.
  
  Edited by: jgarry 26 January 2011 17:41
  2nd edition: link fix that edit may 1 have ransacked.
  
  Edited by: jgarry January 27, 2011 10:40

  Joel,

  I just had this 'already seen' (new) sense to speak of it.

  Mentioning the reference 11.1 gave you:
  

  
  + "Index full scans are an alternative to a full table scan when the index contains all the columns needed for the query, and at least in the index key column has the constraint NOT NULL. A full scan can access the data of the index itself, without access to the table ' + '.
  

  This so obviously must be bad that I couldn't decide if I was proven wrong or was amazed to find that I couldn't he show the falsity. (Just because something is obvious, it does not mean it is true – Terry Pratchett.)

  However, here is the obvious counter-example - that I came across 8.1.7.4 because it's the oldest version of Oracle that I have now:

  create table t1
  as
  select
       rownum               id1,
       rownum               id2,
       rownum               id3,
       lpad(rownum,10,'0')     small_vc,
       rpad('x',100)          padding
  from
       all_objects
  where
       rownum <= 10000
  ;
  
  create index t1_i1 on t1(id1, id2, id3);
  
  begin
       dbms_stats.gather_table_stats(
            ownname           => user,
            tabname           =>'T1',
            cascade           => true
  
       );
  end;
  /
  
  set autotrace traceonly explain
  
  select
       /*+ index_ffs(t1) */
       id1, id3
  from
       t1
  where
       id2 = 99
  ;
  

  No 'NOT NULL columns". But any line I will have a (non-null) value for id2, then it should be in the index - then Oracle should be able to do a full scan and get the right answer. Here is the map (I have no need of Council - but your configuration may be different):

  Execution Plan
  ----------------------------------------------------------
     0      SELECT STATEMENT Optimizer=ALL_ROWS (Cost=4 Card=1 Bytes=12)
     1    0   INDEX (FAST FULL SCAN) OF 'T1_I1' (NON-UNIQUE) (Cost=4 Card=1 Bytes=12)
  

  If you change the predicate to: "id2 is zero", then the only legal path is an analysis.

  Concerning
  Jonathan Lewis
  http://jonathanlewis.WordPress.com
  http://www.jlcomp.demon.co.UK

  + "I believe in the evidence. I believe in observation, measurement and reasoning, confirmed by independent observers. I'll believe anything, no matter how wild and ridiculous, if there is evidence for it. The wildest and most ridiculous something is, however, the firmer and more solid, the evidence should be. » +
  Isaac Asimov

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