Filter by Date PHP

Hi Chaps,

I have a bit of PHP code, which, for now, does not work.
I'm showing all projects 'late' in a different style:

PHP code:

<?php if ($row_rsProjects['projdue'] == '= DATE(NOW())') { ?>

      <tr class="overdue">
      <?php } else if ($row_rsProjects['projdue'] == '< DATE(NOW())') { ?>
      <tr class="duetoday">
      <?php } else { ?>
      <tr class="within">
      <?php }?>

The

Quote:
"= DATE (NOW ()).

works with MySQL, but I don't know how to run with PHP. Any ideas?

Date (Now ()) is the MySQL code. As you have discovered, it is not running PHP.

It is not only a question of the use of an incorrect code, MySQL and PHP to manipulate dates in a manner entirely incompatible. PHP uses the Unix timestamps, which count the number of seconds since the start of January 1970. MySQL stores dates in the ISO format YYYY-MM-DD hh: mm: recommended.

There are several ways you can do this, but the following should work:

// get the date parts from the MySQL date
$dateparts = preg_split('/[-\s]/', $row_rsProjects['projdue']);
// get the Unix timestamp for midnight at the beginning of the due date
$projdue = mktime(0,0,0, $dateparts[1], $dateparts[2], $dateparts[0]);
// get the Unix timestamp for midnight at the beginning of today
$today = mktime(0,0,0, date('n'), date('j'), date('Y'));

if ($today == $projdue) {
  // the project is due today
} elseif ($today > $projdue) {
  // the project is overdue
} else {
  // the project is not yet due
}

Tags: Dreamweaver

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