find the days from the date of...
Hi allI have a date saying (06-mar-2009), then how do you know what day is the same day as today (Friday)... and I need to create a table based on another table and must include all dates it's Saturday...
If someone can help me...
Thank you
Pankaj
If you are looking for the week then->
CREATE TABLE test
AS
SELECT *
FROM emp
where to_char(hiredate,'DY') NOT IN ('SAT','SUN');
Another thing,
CREATE TABLE test
AS
SELECT *
FROM emp
where to_char(hiredate,'DY') IN ('SAT','SUN');
Alternatively,.
Please post your desired output of your sample data.
Kind regards.
LOULOU.
Tags: Database
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common to the appellants for 3 days from particular date
Need to find the number of other_party which is a common call for conseutive 3 days
Create table call (key id Number (15) not null, mobile_number number primary (10), other_party number (10), call_type varchar2 (10), the call_date_time date, number (15)) duration;
insert into values of the call (1,9818764535,9899875643, 'IN', to_date (24 May 12 02:10:43 "," dd-MON-yy hh24:mi:ss'), 10);
Insert in appeal values (2, 9818764535,9215478213, 'OUT', to_date (24 May 12 08:11:13 "," dd-MON-yy hh24:mi:ss'), 20);
Insert in appeal values (3, 9818764535,9899875643, 'IN', to_date (25 May 12 18:07:02 "," dd-MON-yy hh24:mi:ss'), 30);
insert into values of the call (4,9818764535,9012451785, 'IN', to_date (26 May 12 02:11:13 "," dd-MON-yy hh24:mi:ss'), 40);
Insert in appeal values (5, 9818764535,9215478213, 'IN', to_date (26 May 12 08:17:02 "," dd-MON-yy hh24:mi:ss'), 25);
Insert in appeal values (6, 9818764535,9899875643, 'OUT', to_date (26 May 12 20:21:04 ',' dd-MON-yy hh24:mi:ss'), 67);
Entry criteria:
Mobile phone number: 9818764535
date: 24 April 13
Output:
Other_party call_type time call_date_time
9899875643 IN 24 APRIL 13 02:10:43 10
9899875643 ON APRIL 25, 13 18:07:02 30
9899875643 ON 26 MAY 13 20:21:04 67
Published by: 983567 on May 2, 2013 03:51
Published by: 983567 on May 2, 2013 03:52Hello
983567 wrote:
Need to find the number of other_party which is a common call for conseutive 3 daysCreate table call (key id Number (15) not null, mobile_number number primary (10), other_party number (10), call_type varchar2 (10), the call_date_time date, number (15)) duration;
insert into values of the call (1,9818764535,9899875643, 'IN', to_date (24 April 13 02:10:43 "," dd-MON-yy hh24:mi:ss'), 10);
Insert in appeal values (2, 9818764535,9215478213, 'OUT', to_date (24 April 13 08:11:13 "," dd-MON-yy hh24:mi:ss'), 20);
Insert in appeal values (3, 9818764535,9899875643, 'IN', to_date (25 April 13 18:07:02 "," dd-MON-yy hh24:mi:ss'), 30);
insert into values of the call (4,9818764535,9012451785, 'IN', to_date (26 May 13 02:11:13 "," dd-MON-yy hh24:mi:ss'), 40);
Insert in appeal values (5, 9818764535,9215478213, 'IN', to_date (26 May 13 08:17:02 "," dd-MON-yy hh24:mi:ss'), 25);
Insert in appeal values (6, 9818764535,9899875643, 'OUT', to_date (26 May 13 20:21:04 ',' dd-MON-yy hh24:mi:ss'), 67);AE there no set of 3 days of consctuive in the sample data.
Did you mean to say "APR" everywhere, you said 'MAY' above?Entry criteria:
Mobile phone number: 9818764535
date: 24 April 13Output:
Other_party call_type time call_date_time
9899875643 IN 24 APRIL 13 02:10:43 10
9899875643 ON APRIL 25, 13 18:07:02 30
9899875643 ON 26 MAY 13 20:21:04 67Here's one way:
WITH params AS ( SELECT 9818764535 AS mobile_number , DATE '2013-04-24' AS start_date FROM dual ) , got_cnt AS ( SELECT c.* , COUNT (DISTINCT TRUNC (c.call_date_time)) OVER ( PARTITION BY p.mobile_number , p.start_date , c.other_party ) AS cnt FROM params p JOIN call c ON c.mobile_number = p.mobile_number AND c.call_date_time >= p.start_date AND c.call_date_time < p.start_date + 4 ) SELECT * -- or list columns wanted FROM got_cnt WHERE cnt = 3 ;You can search for 2 or more distinct (mobile_number, start_date) target in the same query, if you wish.
It is easy to make consecutive (3) the number of days in this case a parameter. -
Find the Date day i.e. Monday, Tuesday etc.
Hello
I need to know the day of the Date. that is to say Monday, Tuesday etc. This is because if the date falls on Saturday or Sunday it had to impose tariffs of difference and week with normal rates.
Thank you
AmolWe should probably add a function for this that I've certainly seen the prior requirement.
Fortunately it is quite easy to calculate using a simple rule - the trick is to choose a date in the past which was a Monday, and then use the modulo operator.
For example:
The day of the week = (date data - 1980-01-07) modulo 7
That is to say January 7, 1980 was a Monday, so every 7th day after is also a Monday - combined with the modulo operator, this will give you:
0 Monday
1 Tuesday
...
5 Saturday
6 SundayThe only downside is that the dates before 1980-01-07 will give a negative modulo (this differs from the mathematical modulo operator, but must be symmetrical with the whole division operator truncate to zero)-was so before the reference date will give:
0 Monday
Tuesday-6
...
-2 Saturday
-1 SundayYou can choose to write the rules to take into account, or choose a reference date so far in the past that it is useless.
Concerning
Andrew -
transaction
ID Grp Loc qty type report_days
ABC x 21 101 1 4/1/2009
ABC x 29 101 2 4/1/2009
ABC x 22 101 3 4/1/2009
ABC x 45 101 1 15/6 / 2008
ABC 100 x 102 1 16/11/2008
I have a table called transaction
I want to generate a report like this in an another table generatereport
GenerateReport
GenerateReport
ID Grp Loc qty1 2 days report_days
ABC 101 x 0 0 Sunday, June 1, 2008 adding 7 days
101 abc x 0 0 Sunday ..
ABC 101 x 45 0 Monday, June 15, 2009
ABC 101 x 100 0 Sunday, November 16, 2008
101 abc x 0 0 Sunday …
101 abc x 50 22 Sunday until 01/04/2009 (i.e. ONE year)
Qty1 Generatereport table column is filled with the sum of the quantity of type 1 + type 2
column 2 of table Generatereport is filled with the sum of the quantity of type 3
All day should be Sunday
and we must go a year back from 01/04/09 and generate the timetable up to 2009-04-01 only for Sundays
can you help me pls
Thanks in advance
Published by: user12093849 on November 13, 2009 04:55
Published by: user12093849 on November 13, 2009 04:58This is the query, I came up with that:
WITH transaction_table AS ( SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 21 AS QTY, 1 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 29 AS QTY, 2 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 22 AS QTY, 3 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 45 AS QTY, 1 AS TYPE, TO_DATE('06/15/2008','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL SELECT 102 AS ID, 'abc' AS GRP, 'x' AS LOC, 100 AS QTY, 1 AS TYPE, TO_DATE('11/16/2008','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL ) -- END TEST DATA , sunday_date_range AS ( SELECT NEXT_DAY(TO_DATE(:pStartDate,'MM/DD/YYYY')-1,'SUNDAY') + 7*(LEVEL - 1) AS DT FROM DUAL CONNECT BY LEVEL <= (TO_DATE(:pEndDate,'MM/DD/YYYY') - TO_DATE(:pStartDate,'MM/DD/YYYY'))/7 + 1 ) SELECT ID , GRP , LOC , TO_CHAR(DT,'Day DD/MM/YYYY') AS REPORT_DAYS , SUM(CASE WHEN TYPE IN (1,2) THEN QTY ELSE 0 END) AS QTY1 , SUM(CASE WHEN TYPE = 3 THEN QTY ELSE 0 END) AS QTY2 FROM transaction_table PARTITION BY (ID, GRP, LOC) RIGHT OUTER JOIN sunday_date_range ON transaction_table.REPORT_DAYS BETWEEN sunday_date_range.DT - 7 + INTERVAL '1' SECOND AND sunday_date_range.DT GROUP BY ID , GRP , LOC , DT ORDER BY 1, 2, 3Here's the test scenario:
SQL> var pStartDate VARCHAR2(25); SQL> exec :pStartDate := '04/01/2008'; PL/SQL procedure successfully completed. SQL> var pEndDate VARCHAR2(25); SQL> exec :pEndDate := '04/01/2009'; PL/SQL procedure successfully completed. SQL> WITH transaction_table AS 2 ( 3 SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 21 AS QTY, 1 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL 4 SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 29 AS QTY, 2 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL 5 SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 22 AS QTY, 3 AS TYPE, TO_DATE('04/01/2009','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL 6 SELECT 101 AS ID, 'abc' AS GRP, 'x' AS LOC, 45 AS QTY, 1 AS TYPE, TO_DATE('06/15/2008','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL UNION ALL 7 SELECT 102 AS ID, 'abc' AS GRP, 'x' AS LOC, 100 AS QTY, 1 AS TYPE, TO_DATE('11/16/2008','MM/DD/YYYY') AS REPORT_DAYS FROM DUAL 8 ) 9 -- END TEST DATA 10 , sunday_date_range AS 11 ( 12 SELECT NEXT_DAY(TO_DATE(:pStartDate,'MM/DD/YYYY')-1,'SUNDAY') + 7*(LEVEL - 1) AS DT 13 FROM DUAL 14 CONNECT BY LEVEL <= (TO_DATE(:pEndDate,'MM/DD/YYYY') - TO_DATE(:pStartDate,'MM/DD/YYYY'))/7 + 1 15 ) 16 SELECT ID 17 , GRP 18 , LOC 19 , TO_CHAR(DT,'Day DD/MM/YYYY') AS REPORT_DAYS 20 , SUM(CASE WHEN TYPE IN (1,2) THEN QTY ELSE 0 END) AS QTY1 21 , SUM(CASE WHEN TYPE = 3 THEN QTY ELSE 0 END) AS QTY2 22 FROM transaction_table PARTITION BY (ID, GRP, LOC) 23 RIGHT OUTER JOIN sunday_date_range ON transaction_table.REPORT_DAYS BETWEEN sunday_date_range.DT - 7 + INTERVAL '1' SECOND AND sunday_date_range.DT 24 GROUP BY ID 25 , GRP 26 , LOC 27 , DT 28 ORDER BY 1, 2, 3 29 / ID GRP L REPORT_DAYS QTY1 QTY2 ---------- --- - -------------------- ---------- ---------- 101 abc x Sunday 06/04/2008 0 0 101 abc x Sunday 13/04/2008 0 0 101 abc x Sunday 20/04/2008 0 0 101 abc x Sunday 27/04/2008 0 0 101 abc x Sunday 04/05/2008 0 0 101 abc x Sunday 11/05/2008 0 0 101 abc x Sunday 18/05/2008 0 0 101 abc x Sunday 25/05/2008 0 0 101 abc x Sunday 01/06/2008 0 0 101 abc x Sunday 08/06/2008 0 0 101 abc x Sunday 15/06/2008 45 0 101 abc x Sunday 22/06/2008 0 0 101 abc x Sunday 29/06/2008 0 0 101 abc x Sunday 06/07/2008 0 0 101 abc x Sunday 13/07/2008 0 0 101 abc x Sunday 20/07/2008 0 0 101 abc x Sunday 27/07/2008 0 0 101 abc x Sunday 03/08/2008 0 0 101 abc x Sunday 10/08/2008 0 0 101 abc x Sunday 17/08/2008 0 0 101 abc x Sunday 24/08/2008 0 0 101 abc x Sunday 31/08/2008 0 0 101 abc x Sunday 07/09/2008 0 0 101 abc x Sunday 14/09/2008 0 0 101 abc x Sunday 21/09/2008 0 0 101 abc x Sunday 28/09/2008 0 0 101 abc x Sunday 05/10/2008 0 0 101 abc x Sunday 12/10/2008 0 0 101 abc x Sunday 19/10/2008 0 0 101 abc x Sunday 26/10/2008 0 0 101 abc x Sunday 02/11/2008 0 0 101 abc x Sunday 09/11/2008 0 0 101 abc x Sunday 16/11/2008 0 0 101 abc x Sunday 23/11/2008 0 0 101 abc x Sunday 30/11/2008 0 0 101 abc x Sunday 07/12/2008 0 0 101 abc x Sunday 14/12/2008 0 0 101 abc x Sunday 21/12/2008 0 0 101 abc x Sunday 28/12/2008 0 0 101 abc x Sunday 04/01/2009 0 0 101 abc x Sunday 11/01/2009 0 0 101 abc x Sunday 18/01/2009 0 0 101 abc x Sunday 25/01/2009 0 0 101 abc x Sunday 01/02/2009 0 0 101 abc x Sunday 08/02/2009 0 0 101 abc x Sunday 15/02/2009 0 0 101 abc x Sunday 22/02/2009 0 0 101 abc x Sunday 01/03/2009 0 0 101 abc x Sunday 08/03/2009 0 0 101 abc x Sunday 15/03/2009 0 0 101 abc x Sunday 22/03/2009 0 0 101 abc x Sunday 29/03/2009 0 0 101 abc x Sunday 05/04/2009 50 22 102 abc x Sunday 06/04/2008 0 0 102 abc x Sunday 13/04/2008 0 0 102 abc x Sunday 20/04/2008 0 0 102 abc x Sunday 27/04/2008 0 0 102 abc x Sunday 04/05/2008 0 0 102 abc x Sunday 11/05/2008 0 0 102 abc x Sunday 18/05/2008 0 0 102 abc x Sunday 25/05/2008 0 0 102 abc x Sunday 01/06/2008 0 0 102 abc x Sunday 08/06/2008 0 0 102 abc x Sunday 15/06/2008 0 0 102 abc x Sunday 22/06/2008 0 0 102 abc x Sunday 29/06/2008 0 0 102 abc x Sunday 06/07/2008 0 0 102 abc x Sunday 13/07/2008 0 0 102 abc x Sunday 20/07/2008 0 0 102 abc x Sunday 27/07/2008 0 0 102 abc x Sunday 03/08/2008 0 0 102 abc x Sunday 10/08/2008 0 0 102 abc x Sunday 17/08/2008 0 0 102 abc x Sunday 24/08/2008 0 0 102 abc x Sunday 31/08/2008 0 0 102 abc x Sunday 07/09/2008 0 0 102 abc x Sunday 14/09/2008 0 0 102 abc x Sunday 21/09/2008 0 0 102 abc x Sunday 28/09/2008 0 0 102 abc x Sunday 05/10/2008 0 0 102 abc x Sunday 12/10/2008 0 0 102 abc x Sunday 19/10/2008 0 0 102 abc x Sunday 26/10/2008 0 0 102 abc x Sunday 02/11/2008 0 0 102 abc x Sunday 09/11/2008 0 0 102 abc x Sunday 16/11/2008 100 0 102 abc x Sunday 23/11/2008 0 0 102 abc x Sunday 30/11/2008 0 0 102 abc x Sunday 07/12/2008 0 0 102 abc x Sunday 14/12/2008 0 0 102 abc x Sunday 21/12/2008 0 0 102 abc x Sunday 28/12/2008 0 0 102 abc x Sunday 04/01/2009 0 0 102 abc x Sunday 11/01/2009 0 0 102 abc x Sunday 18/01/2009 0 0 102 abc x Sunday 25/01/2009 0 0 102 abc x Sunday 01/02/2009 0 0 102 abc x Sunday 08/02/2009 0 0 102 abc x Sunday 15/02/2009 0 0 102 abc x Sunday 22/02/2009 0 0 102 abc x Sunday 01/03/2009 0 0 102 abc x Sunday 08/03/2009 0 0 102 abc x Sunday 15/03/2009 0 0 102 abc x Sunday 22/03/2009 0 0 102 abc x Sunday 29/03/2009 0 0 102 abc x Sunday 05/04/2009 0 0 106 rows selected.This query performs a number of things.
1. the sunday_date_range generates all the Sunday between the pStartDate and the pEndDate
2. I've made use of a JOIN OUTSIDE of SCORE to generate the date range for EACH ID, GRP and LOC. If you do not have 10g, to implement an alternative workaround.
3. I join on a date range for a little less than 7 days if all report data fall date Sunday by your condition. This is because on 01/04/2009 is not a Sunday.
HTH!
-
Hi all
In the abc table, I would find the Id name if any later date is available in the variable 'data' (CLOB data type).
I'm not able to go forward. can someone help me
Output must be Id 102 and 103, the date indicated is greater than the current date.
with abc as
(
Select 101 as id, 'Prime Minister arrived in Melbourne for the last leg of his tour of four cities in Australia on March 1, 2014 "as double data
Union
Select 102, "the prior reading of Singapore third quarter December 1, 2015 showing no response" of the double
Union
Select 103, ' there is no symptom of Malaria after December 15, 2104 meaning vaccine properly work ' from dual
)
Select * from ABC
where the data like "trunc (sysdate) %.
Thanks in advance
This model ' [(0123456789)] + [()] + ((Jan) |) () Feb) | (Mar) | (APR) | (May). (Jun) | (Jul) | (August). (MS) | (Oct) | (Nov). (Dec)) [()] + [(0123456789)] +' finds the appropriate data now or later, does not matter. We can use this model.
use regexp_count with this model. regexp_count returns "there are how many days" to open this model.
using regexp_count for your sql output:
___regexp_count___ your data
2 Prime Minister arrived in Melbourne, for the last leg of his tour of four cities in the Australia, March 1, 2014 and April 3, 2100 2 The r1eading of 234/12 ahead of Singapore December 1, 2012, for the third quarter on December 1, 2015, showing no response 1 There is no malaria symptom Minister after November 19, 2014 meaning vaccine properly work help link for regexp: Oracle of regular Expressions
hope this helps
Celal Ozdemir
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How to find the date of a table Max
Hello world
I have two tables in the database. I want to find the maximum routine for a case_id of the lock_date date between jan 20 to January 29, 2012.
But I don't get real output (output routine_date should be 'January 28, 2012' but I m getting "January 31, 2012" ")
Can someone help me where I made the mistake
Master
case_id lock_date
101 23 January 2012
101 January 24, 2012
102 27 January 2012
102 January 29, 2012
101 30 January 2012
101 January 29, 2012
Routine (for current work)
case_id routine_date
101 23 January 2012
103 28 January 2012
102 21 January 2012
102 January 29, 2012
101 21 January 2012
101 28 January 2012
101 31 January 2012
Select m.case_id, r.routine_date from master m, systematic r,
(case_id, max (routine_date) of the systematic group by selecting case_id) rr
where m.case_id = r.case_id
and m.case_id = rr.case_id
and r.routine_date = rr.routine_dateHello
Here are average dradles:
WITH universe AS ( SELECT m.case_id , r.routine_date , MAX (r.routine_date) OVER (PARTITION BY m.case_id) AS max_routine_date FROM master m , routine r WHERE m.case_id = r.case_id AND m.lock_date >= TO_DATE ('20-Jan-2012', 'DD-Mon-YYYY') AND m.lock_date < TO_DATE ('30-Jan-2012', 'DD-Mon-YYYY') ) SELECT case_id , routine_date FROM universe WHERE routine_date = max_routine_date ;You only want to view rowss whose routine_date is the maximum date in a subset. First get this subset
If the universe of data that you are interested in is just the period from January 20 to January 29, then you can start by getting all the data in this range. This is what the above subquery universe.
Now, you want to see only the rows where routine_date is the max_routine_date within this universe, for each case_id. You can use the analytic MAX function to find out what this max_routine_date.
Published by: Frank Kulash, March 2, 2013 11:59 -
With the help of several key values to find the data
Hello, it's me again.
I had a question out about data from database and display them on a page of the ADF on Jdev 11.1.1.3.
And Mr. Daniel Atwood answered my question with this blog to follow, that wrote.
http://www.avioconsulting.com/blog/datwood/2012/06/19/using-BPM-process-variable-ADF-form-retrieve-database-information-0.
But I have another question on top that.
The Mr.Atwood example is when using a value of key 'one', what happens if I have two key values, how to set?
Here are some details:
I have a table like this
ID Type_code name
0001 05 a-blabla
0002 b 25-blabla
0002 26 b-blabla
0003-08 c-blabla
0003 25 c-blabla
0003 c 79-blabla
What I want to do is after the entry of the ID (0003) and type_code (25), he will show me the result on three components of text entry in the ADF with the value 0003, 25 page and c-blabla.
Currently, I use only ID to query the data, but I would use two key values to find specific data.
Thank you very much for taking the time to think about it,
Sincerely,
AltoIf you had multiple values to use for the request, one approach would be to create a display object. Whether you are creating the view object, in step 6, you will add two bind variables. Call a "pTypeCode" and call the other "pId". Click on the back button so that you're still in step 5, and modify the WHERE clause as follows:
(ID = :pId) and (Type_code = :pTypeCode)After you have done this, double-click the Module of the Application and add your new view object. In the tab control of data, click the Refresh button. Expand your new view object tab of data control-> expand "French"-> note that you now have a new method called "ExecuteWithParams".
Open your workflow diagram-> delete your existing "SetCurrentRowKeyValues" method-> made slide on your new "ExecuteWithParams" operation on the diagram. When you do so, you should see two settings you need to complete the dialog box. Just as you did before with the SetCurrentRowKeyValue method, set the values for the pTypeCode and the nest.
Add the case of control flow of the new method to your existing view-> make the new method, the default value.
On your form, remove the fields that have been placed here who uses the old object from view. On the tab of data control, drag the fields you want to be placed on the inside of your new view object form.
Dan
-
Hi all
My dates are stored in an access database, in a DateTime format.
When I try to the production of all events for a particular day and use the following query:
< cfquery datasource = 'mydatasource' name = 'myevents' >
SELECT * FROM tbl_events WHERE the mydate = #dateFormat(mydate, 'd/mm/yyyy') #.
< / cfquery >
I get no results.
If I try to use the date as a variable that is not formatted, I get an error.
Should I try something else?
TNX!Do not use dateformat in a query. Either use:
createodbcdate()
createodbcdatetime()
or
the details are in the cfml reference manual. If you do not have one, has the internet.
-
Cannot find the data control to the Web Service in the Menu
Hello
I try to call a web service in the ADF. To do this, I want to create a web service data command
If I understand correctly, if I right click on the template project, I see the data control from the Web Service under layer Business > Web Services. (as indicated in 2.1 Sec-http://www.oracle.com/technology/products/jdev/howtos/1013/wsadf/adfcomplexwstypes.html#WsProxyPojoControl)
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I don't know I'm missing something basic. Can someone please help.
Rgds,
AmitHi Amit,
try to set the filter above in New Gallery to filter by: all Technologies
Kind regards
Branislav
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I have an old Mac Book and need to find the date he did to see if I can improve
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Go to the Apple in the upper left corner of any window, then 'about this Mac' and 'more information... "Copy and paste the information here, but omit the serial number and UUID (if present) material.
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To upgrade the power supply on a desktop HP Pavilion a730n
I'm looking to replace my power supply died on my a730n. Unfortunately, I am new to the evolution of the power supplies and the site I normally order has several categories for the PSU, ATX, ATX/BTX, ATX12V, ATX12V/EPS12V, MicroATX, EPS12V, SFX, SFX