Find the duplicate rows

Similar Questions

• Is it possible to find the duplicate files easily on XP?

  Hello

  I threw a lot of data in my hard drive & I don't know that it contains a lot of duplicates/snaps etc. Y at - it a freeware to identify & delete the duplicate, because it creates confusion & occupies space unnecessay.

  Concerns

  Hello

  I threw a lot of data in my hard drive & I don't know that it contains a lot of duplicates/snaps etc. Y at - it a freeware to identify & delete the duplicate, because it creates confusion & occupies space unnecessay.

  Concerns

  You mean other than the more than 34,000 hits referring by Google?

  http://lmgtfy.com/?q=%22find+duplicate+files%22+%2Bwindows+%2Bfree

• Find the first row of each column

  Hi all

  Request:

  I want to find the first line in the text frame columns.

  Bug:

  If the active document contains a single column, two columns, and multiple column text blocks. In this case, I'm not able to get my result

  Try the script:

  myDoc = app.activeDocument var

  var myTextFrames = myDoc.textFrames.everyItem () .getElements)

  for (i = 0; i < myTextFrames.length; i ++)

  {

  var myTextColumns1 = myTextFrames [i] .textColumns [1] .lines [0] .silence

  Alert (myTextColumns1)

  }

  Attached, I have attached the error file.

  If the active document contains only two block of text column, script executed successfully.

  If the active document contains the single column text block and the sampling error two columns of text as below:

  

  Could someone find solution for my application.

  Thanks in advance

  BEGINNER

  Try this,

  myDoc = app.activeDocument var

  var myTextFrames = myDoc.textFrames.everyItem () .getElements)

  for (i = 0; i

  {

  for (var j = 0; j)

  {

  var myTextColumns1 = myTextFrames [i] .textColumns [j] .lines [0] .silence

  $.writeln (myTextColumns1)

  }

  }

• How can I find the top row of a single table, split among several images in each image.

  Hi all.

  Thanks in advance.

  You can browse all the cells in a row column * and ask the first insertion of a text on his cell point user.user parentTextFrames [0].

  If the ID value has changed, the cell is in a different text frame. As well as its line.

  CC-2015, it might be a little different, because we have a new type of cell: CellTypeEnum.GRAPHIC_TYPE_CELL (not insertionPoints pave the way).

  You can also:

  Reproduce all text blocks in history, in that the table is sitting and control for unique tables in duplicates.

  Uwe

  * edit

• SQL to find the grouped rows that have changed their values?

  Hello
  I wonder if it is a pure SQL way do this...?
  
  I have a table that has a number of columns:
  InsertionDate
  IDENTITY
  Col - has to pass - z - some data.
  
  the pair (InsertionDate, identity) is unique.
  
  The lines represent the same values as they change over time, for example:
  
  Select * from < mytable > by its identity, InsertionDate;
  Balance InsertionDate identity
  10 February 01-1001 - 100
  11 February 01-1001-1
  1001 12 February 01 50
  10 February 01-1002-10
  11 February 01-1002-10
  1002 12 February 01 76
  
  
  I want to do the following:
  
  Select < myTable > from where InsertionDate and the next InsertionDate have a different value for the balance "grouped by" identity and InsertionDate = "10 February 01»;»»
  [I use "grouped by" with great caution - I can't explain in 'Nick sql' without using the misleading grouped by term]
  
  To produce the output:
  
  Balance InsertionDate identity
  10 February 01-1001 - 100
  11 February 01-1001-1
  
  Select < myTable > from where InsertionDate and the next InsertionDate have a different value for the balance "grouped by" identity and InsertionDate = ' 11 February 01»;»»
  Balance InsertionDate identity
  11 February 01-1001-1
  1001 12 February 01 50
  11 February 01-1002-10
  1002 12 February 01 76
  
  There may be several columns in addition to the balance that should also be checked for changes.
  
  See you soon,.
  Karl.

  A little misread your reqs:

  with t as (
             select to_date('10-Feb-01','dd-mon-yy') InsertionDate,1001 Identity,-100 Balance from dual union all
             select to_date('11-Feb-01','dd-mon-yy'),1001,1 from dual union all
             select to_date('12-Feb-01','dd-mon-yy'),1001,50 from dual union all
             select to_date('10-Feb-01','dd-mon-yy'),1002,10 from dual union all
             select to_date('11-Feb-01','dd-mon-yy'),1002,10 from dual union all
             select to_date('12-Feb-01','dd-mon-yy'),1002,76 from dual
            )
  select  InsertionDate,
          Identity,
          Balance
    from  (
           select  InsertionDate,
                   Identity,
                   Balance,
                   row_number() over(partition by Identity order by InsertionDate) rn,
                   lead(Balance,1,Balance - 1) over(partition by Identity order by InsertionDate) next_balance
             from  t
          )
    where balance != next_balance
      and rn != 1
    order by Identity,
             InsertionDate
  /
  
  INSERTION   IDENTITY    BALANCE
  --------- ---------- ----------
  11-FEB-01       1001          1
  12-FEB-01       1001         50
  11-FEB-01       1002         10
  12-FEB-01       1002         76
  
  SQL>  
  

  SY.

• How to find the locked row.

  We see a lock of line blocking other operations, but cannot identify the application JAVA thread that performs the lock. Is there a way to know which line of the table is locked. If this is possible, will help developers identify the problematic program thread.
  
  Thank you

  A good example of diagnosis here: -.

  http://Advait.WordPress.com/2008/06/21/identifying-locks-on-objects-using-vlocks/

  Select row_wait_obj #, row_wait_file #, row_wait_block #, row_wait_row #.
  session $ v where sid = 91;

  Select dbms_rowid.rowid_create (1, ROW_WAIT_OBJ #, ROW_WAIT_FILE #, ROW_WAIT_BLOCK #, ROW_WAIT_ROW #)
  session $ v where sid = 91;

• Select the duplicate rows, based on a combination of columns as the key

  Hello
  
  I have a table with 5 columns.
  
  Code ID S_DATE E_DATE name
  1 23 01012001 null ABC
  1 09 01012001 null XYZ
  2 81 04022007 null TVU
  1 43 03092008 null XXX
  
  
  
  Now, I need to write a select statement to extract the lines duplicated in the table above with the combination of (Code, S_DATE, E_DATE) as the key.
  So in the above example, I need to get Row1 and Row2 as output (but not Row3 as she has a different S_DATE)
  
  Thanks in advance for your suggestions.
  
  Thank you
  
  Published by: thotaramesh on March 9, 2009 16:54

  The XE;

  WITH sample_data AS (
     SELECT 1  code,23 ID, '01012001' s_date, null e_date, 'ABC' NAME FROM dual UNION ALL
     SELECT 1, 09, '01012001', null, 'XYZ' FROM dual UNION ALL
     SELECT 2, 81, '04022007', null, 'TVU' FROM dual UNION ALL
     SELECT 1, 43, '03092008', null, 'XXX' FROM dual)
  SELECT code, ID, s_date, e_date, NAME
  FROM (
     SELECT
        sample_data.*,
        COUNT(*) over (PARTITION BY code, s_date, e_date) dups
     FROM sample_data)
  WHERE dups > 1;
  
        CODE         ID S_DATE   E_DATE NAME
  ---------- ---------- -------- ------ ----
           1         23 01012001        ABC
           1          9 01012001        XYZ
  

• How to find the value duplicate of each column.

  I have it here are four columns,
  How can I find the duplicate of each columns value.
  
  with All_files like)
  Select ' 1000 'like BILL, "2000" AS DELIVERYNOTE, CANDELINVOICE ' 3000', '4000' CANDELIVERYNOTE of all union double
  Select ' 5000 ', ' 6000', ' 7000 ', ' 8000' Union double all the
  Select '9000 ', '1000', '1100',' 1200' from dual union all
  Select ' 1200 ', ' 3400', ' 6700 ', ' 8790' Union double all the
  Select ' 1000 ', ' 2000', ' 3000 ', ' 9000' Union double all the
  Select '1230', '2340', ' 3450 ', ' 4560' double
  )
  SELECT * from All_files
  
  
  Output should be as shown below.
  
  1000 2000 3000 4000
  9000 1000 1100 1200
  1200 3400 6700 8790
  1000 2000 3000 9000
  
  Required to check uniqueness columns.
  
  Thank you.

  Hello

  If you are not too concerned about performance, this should give you the desired result:

  SELECT distinct INVOICE, DELIVERYNOTE, CANDELINVOICE, CANDELIVERYNOTE
  FROM (
    SELECT a.*,
           count(*) over(partition by t.column_value) cnt
    FROM All_files a,
         table(
           sys.odcivarchar2list( a.INVOICE
                               , a.DELIVERYNOTE
                               , a.CANDELINVOICE
                               , a.CANDELIVERYNOTE ) ) t
  )
  WHERE cnt > 1
  ;
  

• Procedure to update duplicate rows

  In a table, I have a few duplicate lines
  
  I can get it through this query: select PARTY_ID from the XXWFS_CUSTOMER_EXT by PARTY_ID group saw County (PARTY_ID) > 1;
  
  Now for the record I got for each duplicate row, I want to update the second row with a specific value... so the duplicate rows that no longer exist
  
  Ex: I went 12 ID, 14, 16, 18 twice each
  
  Now that 12 is twice... I want to update in the second row of 12 with a value of x is the same for other values like 14.16, etc.
  
  How can I write a procedure for this
  
  Thank you

  Hello

  In my view, using the single UPDATE statement, we can do.

  Please see the example below. Please use it according to your requirement.

  SQL> create table test_emp (empno number,ename varchar2(40));
  
  Table created
  
  SQL> insert into test_emp values (1,'SURI');
  
  1 row inserted
  
  SQL> insert into test_emp values (1,'SURI');
  
  1 row inserted
  
  SQL> insert into test_emp values (2,'SRINU');
  
  1 row inserted
  
  SQL> insert into test_emp values (2,'SRINU');
  
  1 row inserted
  
  SQL> SELECT *
    2  FROM test_emp;
  
       EMPNO ENAME
  ---------- ----------------------------------------
           1 SURI
           1 SURI
           2 SRINU
           2 SRINU
  
  SQL> UPDATE test_emp t2
    2  SET t2.ename = 'X'
    3  WHERE t2.rowid > (SELECT min(t1.rowid)
    4                  FROM test_emp t1
    5                  WHERE t1.ename=t2.ename);
  
  2 rows updated
  
  SQL> SELECT *
    2  FROM test_emp;
  
       EMPNO ENAME
  ---------- ----------------------------------------
           1 SURI
           1 X
           2 SRINU
           2 X
  
  SQL> 
  

  According to the structure of your table

  UPDATE XXWFS_CUSTOMER_EXT x1
  SET x1.party_id = 
  WHERE x1.part_id = 12
  AND x1.rowid > (SELECT min(rowid)
                  FROM XXWFS_CUSTOMER_EXT x2
                  WHERE x2.party_id = x1.party_id);
  

  See you soon,.
  Suri

  Published by: Suri on 14 March 2013 19:32

• I updated itunes to 12.4.0.119 and now find under the column of the view may not display the duplicate songs

  I have updated itunes to 12.4.0.119 and now impossible to find in the duplicate songs of column - the view

  I had the same problem, but a solution was found in another forum:

  Once more, Apple settled things. It is now at...

  file/library/show-duplicate-items

  These guys are worse with each update iTunes

• I am looking for an app to download which will find and delete the duplicate on my computer... If anyone can help...

  No good on this side of the computer... Computer works more slowly not as sharp as it was, I found a lot of files and duplicate files on it. Not understand or trust myself to remove anything manually.

  You might like to try these. Read their comments/user opinions 1-links provided:

  http://www.SnapFiles.com/reviews/CloneSpy/CloneSpy.html

  CloneSpy can help you recover hard disk space by detecting and removing duplicate files. It can find files that have the same exact content, regardless of their name, the date, time and location. CloneSpy is also able to search for files that are not identical, but have the same file name, allowing you to find and remove old versions of a file. Once the scan is completed, you can decide what you want to do with the found duplicates, CloneSpy you shows the details for each file (and its duplicate proposed) and allows to keep, move or delete.

  http://www.SnapFiles.com/reviews/duplicate-cleaner/duplicatecleaner.html

  Duplicate Cleaner is an easy to use program that helps you find and remove the duplicate computer files. You can search several structures of files at a time and set of criteria to identify duplicates. You can choose to search exact matches using the comparison of CRC or use the file name, size and date as the criterion. The program offers extended support for music files, allowing you to use the tag information ID (artist, title, album) to identify duplicate titles. The results are grouped together in a list and a selection wizard allows you to select quickly the files based on age, the audio quality, location and other aspects.

  See you soon.

  Mick Murphy - Microsoft partner

• How can I find several duplicate files and remove the using Windows Explorer

  Somehow I see several duplicate on my computer files.  I can tell when they arrived as all the duplicate files ' _10-Mar-15_1. ' " However, I don't know how they arrived.  I think that Google Drive was the culprit, but I can't be sure.

  How we (me) use Windows Explorer to find all files with "_10-Mar-15_1." and delete them all?

  I am using Windows 7 64 bit

  Thank you!!!

  Windows Explorer can do no such thing. To remove recursively a certain file is easy - see below. To identify duplicates and remove some of them is much more difficult, because:

  • Are two files duplicates because
    -They have the same name?
    -They are the same size?
    -They have the same file date?
    -They have the same content?
    -Everything above?
  • When they are, which ones should be deleted?
    -The oldest?
    -The most recent?
    -The batch?

  Here's how to remove a certain file to recursively. Assume that they are in the folder "C:\Users\BHunter\Documents".

  1. Click the start planet.
  2. Type cmd. exe and press ENTER.
  3. Enter the following command and press ENTER:
     dir/s/b/p 'C:\Users\BHunter\Documents\_10-Mar-15_1 '.
     This will show you all the files whose name above.
  4. del /s /q "C:\Users\BHunter\Documents\_10-Mar-15_1."
     This will permanently delete all files with the name above. You cannot restore them.

• Music files - cannot find the settings to disable synchronizing to a device duplicate songs or remove additional music

  In I-Tunes or any Player multimedia, where can I find the settings to turn off syncing to a device duplicate songs? Is if no parameter, possible to remove the extra music using a faster method that remove them manually one by one? You try to transfer music to a device (I - pod) is a little frustrating after all downloading just to find additional music under the same artist with the repetition of the same song several times. Thank you for your help: >) Danise

  There are programs that you can get to check for duplicate files, but it would be unreliable given that music can exist in different audio formats (mp4, wma, wave, whatever), or different bit rates, etc.  It really turns to be more often a manual process, because in the end, only you know which agree delete.

• How to find duplicates of a field value? For example - in a field, I have values like {123,345,346,123}, now I want to remove the duplicate value in the field so that my output looks like {123,345,346}

  How to find duplicates of a field value? For example - in a field, I have values like {123,345,346,123}, now I want to remove the duplicate value in the field so that my output looks like {123,345,346}

  If it's an array you want to deduplicate then here is a script [for use in the Script Processor] I prepared earlier:

  var result = new Array();

  var added = new Object();

  If (input1 [0]! = null)

  {

  for (var i = 0; i)< input1[0].length;="">

  {

  var point = input1 [0] [i];

  If (! added [item])

  {

  added [item] = 1;

  result [result. Length] = item;

  }

  }

  }

  Output 1 = result;

  Kind regards

  Nick

• How can I find and get rid of the duplicates

  How can I find and get rid of the duplicates

  Hi sinkerslider,

  I apologize for the long delay. In what app work? Looking for double .jpgs, PSD etc files. ? Also, what device and operating system are you using? Thank you very much!

  -Kathleen