Select the duplicate rows, based on a combination of columns as the key
HelloI have a table with 5 columns.
Code ID S_DATE E_DATE name
1 23 01012001 null ABC
1 09 01012001 null XYZ
2 81 04022007 null TVU
1 43 03092008 null XXX
Now, I need to write a select statement to extract the lines duplicated in the table above with the combination of (Code, S_DATE, E_DATE) as the key.
So in the above example, I need to get Row1 and Row2 as output (but not Row3 as she has a different S_DATE)
Thanks in advance for your suggestions.
Thank you
Published by: thotaramesh on March 9, 2009 16:54
The XE;
WITH sample_data AS (
SELECT 1 code,23 ID, '01012001' s_date, null e_date, 'ABC' NAME FROM dual UNION ALL
SELECT 1, 09, '01012001', null, 'XYZ' FROM dual UNION ALL
SELECT 2, 81, '04022007', null, 'TVU' FROM dual UNION ALL
SELECT 1, 43, '03092008', null, 'XXX' FROM dual)
SELECT code, ID, s_date, e_date, NAME
FROM (
SELECT
sample_data.*,
COUNT(*) over (PARTITION BY code, s_date, e_date) dups
FROM sample_data)
WHERE dups > 1;
CODE ID S_DATE E_DATE NAME
---------- ---------- -------- ------ ----
1 23 01012001 ABC
1 9 01012001 XYZ
Tags: Database
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ROWNUM< 1="" will="" not="" retrieve="" any="" rows="" as="" rownum="" values="" start="" with="" 1.="" to="" get="" the="" desired="" result="" you="" have="" to="" build="" the="" result="" set,="" order="" it="" and="" then="" select="" the="" desired="">
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