Find the occurrence of the word in a list separated by commas

Similar Questions

• using the function search is not finding the words I know are in my document. Why?

  using the function search is not finding the words I know are in my document. Why?

  The fact that you see a Word does not mean that it is 'real' text. You can select the word? If so, copy and paste in another application (such as Notepad). He always look the same? If the answer to each question is, you also cannot find it by using a search.

• 1 - where is the search function to find the authors muse a list?

  1 - where is the search function to find the authors muse a list?

  Hello

  Regarding your first question of the creation of a search box in your site from muse, please see this forum post:- Re: how to create a search box in MUSE?

  In addition, you can use different widgets available on Adobe Exchange .

  Now, regarding your second please can question of the creation of a bulleted in Muse, you these tutorials:

  Adobe help Muse | Bullets and numbers

  Bullets and lists numbers | Adobe Muse CC tutorials

  Now, it seems that the Muse version you are using is obsolete and it is possible that you might not find these features in it. I would ask update you your Muse to the latest version 2014.2 using the CC desktop application to take advantage of all these features. Please refer to this screenshot:- http://prntscr.com/55uvs9

  Hope this helps

  Kind regards

  Rohit Nair

• Problem using the list separated by commas with nested table element

  Hello
  
  I have a list separated by commas like this:

  H23004,H24005,T7231,T8231,T9231

  And want to create a function that creates a where clause clause for each element with an output like this:

  UPPER('H23004') IN (UPPER(charge))
  OR UPPER('H23005') IN (UPPER(charge))
  OR UPPER('T7231') IN (UPPER(charge))
  OR UPPER('T8231') IN (UPPER(charge))
  OR UPPER('T9231') IN (UPPER(charge))

  Here's my test function that is not working properly:

  create or replace function FNC_LIST_TO_WHERE_CLAUSE(v_list in VARCHAR2) return varchar2 is
   -- declaration of list type
   TYPE batch_type IS TABLE OF pr_stamm.charge%TYPE;
   -- variable for Batches
   v_batch batch_type := batch_type('''' || replace(v_list,',',''',''') || '''');
   return_script varchar2(1000);
  
   BEGIN
   -- loop as long as there are objects left
   FOR i IN v_batch.FIRST .. v_batch.LAST
   LOOP
     --DBMS_OUTPUT.PUT_LINE(offices(i));
     -- create where clause
     IF i = 1 THEN
       return_script := 'UPPER(' || v_batch(i) || ') IN (UPPER(charge))';
     ELSE
       return_script := return_script || ' OR UPPER(' || v_batch(i) || ') IN (UPPER(charge))';
     END IF;
   END LOOP;
  
   return (return_script);
   end;

  The out put looks like this:

  UPPER('H23004','H24005','T7231','T8231','T9231') IN (UPPER(charge))

  I don't know what I did wrong? It calculates the amount of the incorrect array element! (v_batch. Must be 5)
  v_batch. FIRST = 1
  v_batch. LAST = 1
  
  Kind regards
  
  Tobias

  Try this...

  declare
  text varchar2 (1000): = "H23004, H24005, T7231, T8231, T9231;
  v_where varchar2 (1000);
  Start
  Text: = text | «, » ;
  While instr (text, ',') <> 0
  loop
  v_where: = v_where | ' UPPER ("': substr (Text, 1, InStr(Text,',',1)-1) |") ' IN (UPPER (load)) OR ';
  text: = substr (text, instr(text,',',1) + 1);
  end loop;
  v_where: = substr (v_where, 1, length (v_where)-3);
  dbms_output.put_line (v_where);
  end;

  convert it to function...

• How can I find the word pad and add it to my toolbar for easy access

  I want to use the word pad.  I don't have the icon on my toolbar.  It's not in my menu start, or on my list of programs.  How can I find?  How do I put in my toolbar?  Help shows you your site just click on word pad icon located next to the Home tab.  I'd do it, but he's not here.  Is there a reason why?

  Just type in wordpad in the Windows Explorer search window

  Or try this path "%ProgramFiles%\Windows NT\Accessories\wordpad.exe" in a new shortcut

• find the word in the query

  Hello

  I want to print the word before _ @.

  request as first of all find the underscore if line _ is printing before _.

  Example:

  [email protected]

  released as:-vinoth

  If not find before underscores @ as

  [email protected]    

  Released as:-Marie Laure

  WITH t AS

  (SELECT "[email protected]" as NAME

  OF THE DOUBLE

  UNION ALL

  SELECT "[email protected]" AS NAME

  THE DOUBLE)

  SELECT THE CHECK BOX

  WHEN INSTR (NAME, '_') = 0

  THEN REPLACE ((SUBSTR (NOM, 1, (INSTR (NOM, ' @'))-1)),)

  '_',

  ''

  )

  WHEN INSTR (NAME, '_') > 0

  THEN SUBSTR (NAME, 1, (INSTR (NAME, '_') - 1))

  END

  T

  Kind regards

  friend

  Post edited by: mostwanted!

  Post edited by: mostwanted!

• How to find the words that spans end of line to the next line in pdf format?

  I use Adobe Acrobat Pro X version for our development and form maintenance. I am writing a command Acrobat JAVA script which reads through all words and run the spell check and reports the wrong words spelled in an excel sheet. Because I run this script in batch for more than 1000 PDFs - I get a lot of words together. When I looked in the PDF files all these words are good looking because it makes its appearance at the end of the right margin, and the next word is in the next line. Since there is no space between them, it was mined in one word. Where the failure.

  I have used wordf = this.getPageNthWordQuads (i, j) to get the word start and end coordinates. When I look at my values create a rectangle, and extending through the lines. I got the coordinates for the ordinary Word and which cover the two lines acoross. the coordinates are same.

  I think I'm screwed I 8000 words and not the slightest idea how to get rid of them actual misspelled words.

  Help, please. Let me know if any /method class so I give the speech will give me the end of line or I have to go to the next layer to find this split.

  the addnot is somehow marking the words using this contact information - please hellp understand me how this works. Thank you.

  for all pages

  for (var i = 0; i < this.numPages; i ++)

  {

  For all words

  PG += 1;

  numWords = this.getPageNumWords (i);

  for (j = 0; j < numWords; j ++)

  {

  get spell checking

  ckWord = spell.checkWord (this.getPageNthWord (i, j))

  If (ckWord! = null)

  {

  Jn = 0

  ml = 0

  If the misspelled word found.

  wordf = this.getPageNthWordQuads (i, j)

  swordf = wordf.toString)

  var St = swordf.split(",")

  var diffx0 = parseInt(st[0])-8

  var diffx1 = parseInt(st[1])-8

  var diffx2 = parseInt(st[2])-8

  var diffx3 = parseInt(st[3])-8

  var diffx4 = parseInt(st[4])-8

  var diffx5 = parseInt(st[5])-8

  var diffx6 = parseInt(st[6])-8

  var diffx7 = parseInt(st[7])-8

  If (bparole is csword)

  {

  Jn = 1

  }

  If (m [1]! = m [3])

  {

  ml = 1

  }

  dataLine += "\r\n writing".

  }

  on the other

  {

  ml = 2

  }

  dataLine += "\r\n"+this.documentFileName. "

  + "\t" + this.getPageNthWord (i, j)

  + "\t" + pg

  + "\t" + j

  + "\t" + ml

  + "\t" + jn

  '\t st [0]' + diffx0 + '\t m [1]' + diffx1 + '\t st [2]' + diffx2 + '\t [3] st' + diffx3

  '\t st [4]' + diffx4 + '\t st [5]' + diffx5 + '\t [6] st' + diffx6 + '\t st [7]' + diffx7

  CK = 1

  }

  }

  }

  If Acrobat is reading each part of the word and the distinct words, you have a problem.

  The way I approached it in some of my tools was to check if a word ends

  with a hyphen and if so, to check if it is the last one on the line. If the two

  conditions are met, combined with the word on the next line. It comes

  do not fool proof, of course, as there are documents with columns are another

  structural elements that prevent this from working. Better than nothing,

  Although...

  However, it is also possible that Acrobat sees both as parts of

  the same word. In this case, getPageNthWordQuads() returns several

  tables of quads. As you know, this method returns an array of arrays quad.

  He is usually alone, but in principle it could be more... Something

  to check before giving up.

• [CS3 JS] find the words in the dictionary

  I'm trying to find a way out of the words into syllables.

  The dictionary can break words, but I can't refer to the dictionary to find a Word and its setting.

  The standard I should be able to get the syllables.

  It is possible to recover the hyphenation exceptions, but I need the breaks in the custom dictionary.

  Any thoughts?

  Thank you, Kees

  [Additive] If you need only to be able to manually find the breaking points, you can use an implementation of the algorithm of Knuth-Liang. I wrote in C, and it's pretty good, ah, maybe 80% of the words. For a system purely based on rules, which qualifies as "not too bad".

  There are many free implementations; This is a http://code.google.com/p/hyphenator/ in javascript. (It is targeted on the web pages, but the basics should be transferable to your script.)

• Find the words (wild cards) using regular expressions

  I'm testing to see if the words are present for revision 1 of a drawing of the cartridge.

  The script search the digit 1 followed by a date, a title, and 4 sets of initials.

  The number 1 is static, (date, title and original are the cards that they are different for each design).

  I use regular expressions to match the words.

  The regular expression highlighted in blue is the number 1 and the date.

  Him remains highlighted in orange does not match the title and initials.

  If anyone can help with the regular expression that is most appreciated.

  Once I got that work will add the form fields for the initials, noting only the console at this point for the tests.

  numWords = this.getPageNumWords (0);

  number of words on the page

  loop through the words on the page

  for (var j = 0; j < numWords-1; j ++)

  {/ / get the pair of words to test}

  ckWords = this.getPageNthWord (0, j) + ' ' + this.getPageNthWord (0, j + 1); test words

  Check if 1 26.05.16 THE STRENGTHENING REVISED MM SB AE GM word string is present

  If (ckWords.match(/ ^ 1\s [0-9] {1,2}.)) [0-9] {1,2}. [0-9] {2} \s\w+(\s+\w+){1,7}/))

  {

  Console.println (ckWords);

  }

  }

  You can use something like this:

  ckWords = this.getPageNthWord (0, j) + ' ' + this.getPageNthWord (j, 0, + 1) + ' ' + this.getPageNthWord (0, + 2 j) + ' ' + this.getPageNthWord (0, j + 3) + ' ' + this.getPageNthWord (0, j + 4) + ' ' + this.getPageNthWord (0, j + 5) + ' ' + this.getPageNthWord (0, j + 6);

  If (! ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} \.\d {2} \s\w+ (?:-s + \w +) {1.8} \s([A-Z]{2})\s([A-Z]{2})-s ([A - Z] {2}) \s([A-Z]{2})$ /)) ckWords + ckWords + "" + this.getPageNthWord (0, j + 7);

  If (! ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} \.\d {2} \s\w+ (?:-s + \w +) {1.8} \s([A-Z]{2})\s([A-Z]{2})-s ([A - Z] {2}) \s([A-Z]{2})$ /)) ckWords + ckWords + "" + this.getPageNthWord (0, j + 8);

  If (ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} {2} \s\w+ \.\d (?:-s + \w +) 1.8 ([A - Z] {2}) \s([A-Z]{2})\s([A-Z]{2})\s {} \s([A-Z]{2})$ /))

  {

  ...

• Regex to find the word

  Anyone know the regular expression to search for if a variable contains a word has for example this var "Total of surplus percentage of an amount of $2000.00" ".

  I therefore need to know that it contains the word ' Percentage '?

  Here is my code

  cfset xyz =' Total percentage excess in the amount of $2000,00 '

  CFSET foundword = REFind (' percentage ', xyz)

  The above does not work

  Word found at position #foundword #

  Word not found

• I can't find the mobile link home &gt; list of files

  I can't find mobile link icon in the home tap water > list of files.

  How can I activate my cloud of document in the ms of the acrobat reader

  Please see KB:https://helpx.adobe.com/reader/beta-features/mobile-link.html

  Kind regards
  Rave

• How to find the word already store in your computer?

  I have Word intalled on my computer but I can find it, can anyone help?

  Hello

  I suggest you follow the procedure below:

  un) Click Start, and then click all programs.

  b) in all programs, you select Microsoft Office.

  c) open Microsoft Office and select Microsoft Word.

• Sort by or find the word long in a field of varchar2

  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
  PL/SQL Release 10.2.0.4.0 - Production
  CORE     10.2.0.4.0     Production
  TNS for HPUX: Version 10.2.0.4.0 - Production
  NLSRTL Version 10.2.0.4.0 - Production

  drop table event;
  create table event  (event_title_nm varchar2(1000));
  
  SET DEFINE OFF;
  Insert into EVENT
     (EVENT_TITLE_NM)
   Values
     ('CREATING A NEW CLASS WORD FOR INDICATOR, - _IN');
  Insert into EVENT
     (EVENT_TITLE_NM)
   Values
     ('Unknown Title');
  Insert into EVENT
     (EVENT_TITLE_NM)
   Values
     ('MASAL REASON TEXT');
  Insert into EVENT
     (EVENT_TITLE_NM)
   Values
     ('Note/Attachment Modifications and Amendments');
  Insert into EVENT
     (EVENT_TITLE_NM)
   Values
     ('Installation (replaces change request  66)');
  Insert into EVENT
     (EVENT_TITLE_NM)
   Values
     ('Unknown Title');
  Insert into EVENT
     (EVENT_TITLE_NM)
   Values
     ('Installation (replaces change request  66)');
  Insert into EVENT
     (EVENT_TITLE_NM)
   Values
     ('List Item Identifier Change');
  Insert into EVENT
     (EVENT_TITLE_NM)
   Values
     ('USER_ID in WORKFLOW_TASK_ASSIGNMENT');
  COMMIT;

  I would like to choose or order by the length of the longer term in the field
  Word defined as characters continued.
  
  so my production for the first two returned

  event_title_nm
  USER_ID in WORKFLOW_TASK_ASSIGNMENT
  Note/Attachment Modifications and Amendments

  because WORKFLOW_TASK_ASSIGNMENT is the largest word
  and Note/attachment is the second large.
  
  the reason why I was trying to find thiis is that I display this value in a web page and I need to understand about the longest
  continuous word because the css will not end a text in the middle of a Word. so, it ends up pushing my div set below where I want it to go.
  
  Published by: pollywog on October 25, 2011 08:43

  You can order by a scalar subquery returns the max length:

  SQL> select *
    2  from event e
    3  order by (
    4             select max(length(regexp_substr(e.event_title_nm, '\S+', 1, level)))
    5             from dual
    6             connect by level <= length(regexp_replace(e.event_title_nm, '\S+'))+1
    7           ) desc
    8  ;
  
  EVENT_TITLE_NM
  --------------------------------------------------------------------------------
  USER_ID in WORKFLOW_TASK_ASSIGNMENT
  Note/Attachment Modifications and Amendments
  Installation (replaces change request  66)
  Installation (replaces change request  66)
  CREATING A NEW CLASS WORD FOR INDICATOR, - _IN
  List Item Identifier Change
  Unknown Title
  Unknown Title
  MASAL REASON TEXT
  
  9 rows selected
   
  

• Could not find the word on my computer

  Microsoft Word has disappeared from my compupter.  I can't open documents, and I don't know what happened. Any suggestions?

  Did you download AND install?  I mean, once you have downloaded you double-click the file to install?

• How to find the word or the text of the geometric limits...

  I have a lot of paragraphs in my document and im searching specific word in my document.

  now, what I want to know is, this particular word limits geometric.

  Try this,

  var  myString = doc.textFrames[i].parentStory.contents;
  var  myText = doc.textFrames[i].parentStory.texts[0];
  
  for(j=0;j