Problem using the list separated by commas with nested table element

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• REGEXP_SUBSTR for the list delimited by commas with null values

  Hello
  
  I have a column that stores a list of values comma-delimited. Some of these values in the list may be null. I'm having some trouble trying to extract the values using the REGEXP_SUBSTR function when null values are present. Here are two things I've tried:

  SELECT
     REGEXP_SUBSTR (val, '[^,]*', 1, 1) pos1
    ,REGEXP_SUBSTR (val, '[^,]*', 1, 2) pos2
    ,REGEXP_SUBSTR (val, '[^,]*', 1, 3) pos3
    ,REGEXP_SUBSTR (val, '[^,]*', 1, 4) pos4
    ,REGEXP_SUBSTR (val, '[^,]*', 1, 5) pos5
  FROM (SELECT 'AAA,BBB,,DDD,,FFF' val FROM dual);
  
  POS P POS P P
  --- - --- - -
  AAA   BBB

  SELECT
     REGEXP_SUBSTR (val, '[^,]+', 1, 1) pos1
    ,REGEXP_SUBSTR (val, '[^,]+', 1, 2) pos2
    ,REGEXP_SUBSTR (val, '[^,]+', 1, 3) pos3
    ,REGEXP_SUBSTR (val, '[^,]+', 1, 4) pos4
    ,REGEXP_SUBSTR (val, '[^,]+', 1, 5) pos5
  FROM (SELECT 'AAA,BBB,,DDD,,FFF' val FROM dual);
  
  POS POS POS POS P
  --- --- --- --- -
  AAA BBB DDD FFF

  As you can see that neither calls work correctly. Anyone know how to change the regular expression pattern to handle null values? I tried various other models but could not get anyone to work in all cases.
  
  Thank you
  
  Martin
  -----
  http://www.ClariFit.com
  http://www.TalkApex.com

  Hi, Martin,.

  That's what you want:

  SELECT
     RTRIM (REGEXP_SUBSTR (val, '[^,]*,', 1, 1), ',') pos1
    ,RTRIM (REGEXP_SUBSTR (val, '[^,]*,', 1, 2), ',') pos2
    ,RTRIM (REGEXP_SUBSTR (val, '[^,]*,', 1, 3), ',') pos3
    ,RTRIM (REGEXP_SUBSTR (val, '[^,]*,', 1, 4), ',') pos4
    ,RTRIM (REGEXP_SUBSTR (val || ','
                        , '[^,]*,', 1, 5), ',') pos5
  FROM (SELECT 'AAA,BBB,,DDD,,FFF' val FROM dual);
  

  The query above works in Oracle 10 or 11, but in Oracle 11, you can also do it with only REGEXP_SUBSTR, without using RTRIM:

  SELECT
     REGEXP_SUBSTR (val, '([^,]*),|$', 1, 1, NULL, 1) pos1
    ,REGEXP_SUBSTR (val, '([^,]*),|$', 1, 2, NULL, 1) pos2
    ,REGEXP_SUBSTR (val, '([^,]*),|$', 1, 3, NULL, 1) pos3
    ,REGEXP_SUBSTR (val, '([^,]*),|$', 1, 4, NULL, 1) pos4
    ,REGEXP_SUBSTR (val, '([^,]*),|$', 1, 5, NULL, 1) pos5
  FROM (SELECT 'AAA,BBB,,DDD,,FFF' val FROM dual);
  

  The problem with your first request was that he was looking for sub channels of 0 or more non-virgules. There was as a substring. consisting of 3 characters starting at position 1, he returned "AAA", as expected. Then there was an another substring, the 0 characters, starting at position 4, so it returned NULL. Then, there was a substring of 3 characters starting at position 5, so he returned 'BBB '.

  The problem with your 2nd request was that he was looking for 1 or more non-virgules. 'DDD' is the 3rd this substring.

  Published by: Frank Kulash, on February 16, 2012 11:36
  Added Oracle 11 example

• list separated by commas - extraction of each element in an array?

  Is there a quick way to make a field that contains a list of items separated by commas and put them in a table or perhaps separate variables?

  for example.

  a single line in the database contains the field [matches_with] and would generally contain the following elements:

  rings, bracelets, necklaces

  I need to be put in a variable

  < cfset item1 = 'rings' >

  < cfset item2 = 'bracelets' >

  < cfset item3 = necklaces >

  or if its more simple, put them in a table

  agenda [1] = 'rings '.

  point [2] = "bracelets".

  point [3] = "necklaces."

  There is a built-in ListToArray function to CF.

• Find the occurrence of the word in a list separated by commas

  Hello
  
  I need to find the first occurrence of a word in a list separated by commas.
  
  Example list:

  monster,daemon,shark,bambi,sky

  Now I'm looking for the word: bambi
  Result should be the first calculation of the event: 4
  
  Now I'm looking for the word: Monster
  Result should be the first calculation of the event: 1
  
  Hope you can help.
  
  Tobias

  Hi, Tobias,.

  This can be more efficient, because it does not use CONNECT BY or regular expressions. Instead of splitting the string to the level of every comma, just find the target string and count how many commas occur in front of her.

  WITH     got_found_pos          AS
  (
       SELECT     list_txt
       ,     INSTR ( ',' || list_txt || ','
                  , ',bambi,'
                  )          AS found_pos
       FROM    table_x
  )
  SELECT     list_txt
  ,     found_pos + 1
              - LENGTH ( REPLACE ( SUBSTR (list_txt, 1, found_pos)
                                    , ','
                           )
                    )          AS item_num
  ,     found_pos
  FROM    got_found_pos
  WHERE     found_pos     > 0
  ;
  

  Delimited lsits storage is usually a bad idea in a relational database. It is best to store each item in the list on a separate line.

• How to store the values separated by commas

  Hi all
  
  I have a table named discount, with discount_id (number data type) as one of the columns.
  The user gives an entry as the value separated by commas, (ex: '123,27890,3543')
  I use built-in proc that separates the values separated by commas.
  

  DECLARE
     l_input   VARCHAR2 (4000) := '123,27890,3543';
     l_count   BINARY_INTEGER;
     l_array   DBMS_UTILITY.lname_array;
  BEGIN
     DBMS_UTILITY.comma_to_table (
        list     => REGEXP_REPLACE (l_input, '(^|,)', '\1x'),
        tablen   => l_count,
        tab      => l_array);
     DBMS_OUTPUT.put_line (l_count);   
  
     FOR i IN 1 .. l_count
     LOOP
        DBMS_OUTPUT.put_line (
              'Element '
           || TO_CHAR (i)
           || ' of array contains: '
           || SUBSTR (l_array (i), 2));
     END LOOP;
  END;
  
  Result:
  3
  Element 1 of array contains: 123
  Element 2 of array contains: 27890
  Element 3 of array contains: 3543

  Result set is stored in a table.
  I would like to do a select on the table of discounts
  Select * discount where discount_id (123, 27890 3543).
  
  I am looking for options,
  I need to create a new physical table as
  Create table new_table (identification number) and bulk insert in this table.
  Select * discount where discount_id in (select distinct id of new_table).
  or
  Is there a better way?
  
  THX
  Rod.

  Hello, SamFisher.
  May be the recursive subquery factoring help you?

  WITH test(f1, n) AS (select '12, 15, 235', 1 from dual
                       UNION all
                       select f1, n + 1 from test where n < regexp_count('12, 15, 235', ',') + 1)
  SELECT regexp_substr(f1, '[^, ]+', 1, n) f
  FROM test
  

• How to get the values separated by commas of multiple records in table

  How to get the values separated by commas of multiple records in table
  
  for example
  
  name address age sex
  a 12 m e
  b hh 12 f
  BB c 13 h
  
  I need to get output as a, b, c from a query

  Use the query as below he works for me, change the names of tables and columns

  SELECT SUBSTR (SYS_CONNECT_BY_PATH (PROXY_EMAIL, ','), 2) csv FROM (SELECT PROXY_EMAIL, ROW_NUMBER () ON the rn (ORDER OF PROXY_EMAIL), COUNT (*) NTC (STARS_PROXY_ASSIGNMENT) WHERE EMPLID = #EMPLID) WHERE rn = cnt START WITH rn = 1 CONNECT BY rn = rn + 1 ADVANCE

• Convert the string separated by commas in the rows

  Dear gurus,
  
  I want to convert the string separated by commas in the rows to insert in the collection.
  
  for example, the string 1234,2323,23232,2343,34234
  Higher up in the chain must be converted to ranks in order to insert into the table or the collection
  
  Thanks in advance
  Sanjeev

  String in rows separated to convert the comma.

  with t
  as
  (
  select '1234,2323,23232,2343,34234' as txt from dual
  )
  select REGEXP_SUBSTR (txt, '[^,]+', 1, level)
    from t
   connect by level <= length(regexp_replace(txt,'[^,]*'))+1
  

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  Hello. I have a problem of creating tables with nested tables.
  After you have created a few types, I would create a table based on these, but I get
  
  SQL error: ORA-00904: invalid identifier
  + 00904. 00000 - '% s: invalid identifier ' +.
  
  over and over again. This is my SQL code:
  
  1 create or replace TYPE t_indirizzo () AS OBJECT
  via VARCHAR (45), 2
  3 NUMBER,
  4 cap INTEGER (5).
  5 Città varchar (30),
  6 provincia varchar (30),
  region 7 varchar (30)
  )
  
  8 create or replace TYPE t_telefono () AS OBJECT
  9 num_tel Number (15)
  )
  
  10 create or replace TYPE t_listaTelefono AS TABLE OF THE t_telefono
  
  11 create or replace TYPE t_cliente () AS OBJECT
  12 cod_cliente NUMBER (8).
  13 address t_indirizzo,
  14 email varchar (30),
  Telefono 15 t_listaTelefono
  (16) NOT FINAL
  
  17 CREATE TABLE client (t_cliente)
  18 cod_cliente NOT NULL,
  19 address NOT NULL,
  email 20 NOT NULL,
  21 PRIMARY KEY (cod_cliente)
  (22) TABLE IMBRIQUE 'telefono' STORE AS 'numTelCli_tab '.
  23 RETURN VALUE
  
  My version of Oracle is 10.2.0. Thank you in advance.
  
  Published by: user11231503 on 2.35 giu-8-2009

  so, just to be sure, run this:

  create or replace TYPE t_indirizzo AS OBJECT (
  via VARCHAR(45),
  numero NUMBER,
  cap INTEGER(5),
  citta VARCHAR(30),
  provincia VARCHAR(30),
  regione VARCHAR(30)
  );
  / 
  
  create or replace TYPE t_telefono AS OBJECT (
  num_tel NUMBER(15)
  );
  / 
  
  create or replace TYPE t_listaTelefono AS TABLE OF t_telefono
  / 
  
  create or replace TYPE t_cliente AS OBJECT (
  cod_cliente NUMBER(8),
  indirizzo t_indirizzo,
  email VARCHAR(30),
  telefono t_listaTelefono
  ) NOT FINAL;
  / 
  
  CREATE TABLE cliente OF t_cliente(
  cod_cliente NOT NULL,
  indirizzo NOT NULL,
  email NOT NULL,
  PRIMARY KEY (cod_cliente)
  ) nested table telefono store as numTelCli_tab
  return as value
  /