Find the top level of a VM folder
I want to find the name of the top-level folder that contains a virtual machine in a data center and looking for the root tree.
For example \\datacenter\folder1\folder2\folder3\TestVM
I try to find as a parameter of the TestVM folder1.
I need to sort all the VM in our sphere of their top-level folder
In all cases to do this would be appreciated.
Also it would be quite in powercli with scripts
Try something like this
$vm = Get-VM -Name TestVM$object = $vm.ExtensionData$parent = Get-View $object.Parent while($parent -is [VMware.Vim.Folder] -and $parent.Name -ne "vm"){ $object = $parent $parent = Get-View $object.Parent}$object | Select @{N="VM";E={$vm.Name}}, @{N="Top Folder";E={$object.Name}}
Tags: VMware
Similar Questions
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Find the top level element in SQL
Hi all
I have a table with the following format. item_id, sup_item_id and a few other columns.
And that's the real problem:
We have parts (elements) mounted in designed, says let cars for example. also is it a tyre_1 element with car_A, car_B and car_C have entries in the table like this
item_id sup_item_id
tyre_1 car_A
tyre_1 car_B
tyre_1 car_C
but sometimes we are small element in someother element, then it goes to the main product. For example, we adjust wire_1 in circuit_1 which then goes to car_A and car_B. This number can have any levels and wire_1 can be in any number of circuits.
If the data table will be like this
item_id sup_item_id
wire_1 circuit_1
wire_1 circuit_2
circuit_1 car_A
circuit_1 car_B
You can identify high most of the elements in the table because they have no value in the sup_item_id field.
item_id sup_item_id
car_A
car_B
so, I want to write a sql to discover all the elements of highest level of the page for a given part. Can someone help me with this.I think that's what you're looking for
"Rim_1", I took as a point of entrywith data as ( select 'bolt_1' item_id,'rim_1' sup_item_id from dual union all select 'rim_1' item_id,'tyre_1' sup_item_id from dual union all select 'tyre_1' item_id,'frame_1' sup_item_id from dual union all select 'frame_1' item_id,'car_1' sup_item_id from dual union all select 'rim_1' item_id,'car_2' sup_item_id from dual union all select 'car_1' item_id,null sup_item_id from dual union all select 'car_2' item_id,null sup_item_id from dual ) select item_id from data where sup_item_id is null start with item_id = 'rim_1' connect by item_id = prior sup_item_id;
Thank you
Andy -
Find a specific sublayer and pass to the top-level layer
I have a lot of illustrator files which are organized by a model size. The layers are configured so that the top-level layer is always model. However the underlayment I need to pass to the next level could be called 42 border Pg or 30 border Pg or Pg 24 border.
Y at - it a way for a script to search through the layers and if it finds '42 Pg border' or 'border Pg 30' or "24 Pg border" in the base layer model it it would move to the top level, but if he does not see an of these he does not give an error?
I'm still new to scripting so the extent of my knowledge on this is to scan all the layers and unlock them. Then, find a specific layer name. This is the base layer and moving it to the next level that I'm not sure.
Here is my current code:
var doc = app.activeDocument; var allLayers = doc.layers; for (var i = allLayers.length-1; i >= 0; i--){ allLayers[i].locked = false; if (allLayers[i].name == "42 Pg Border" || allLayers[i].name == "30 Pg Border" || allLayers[i].name == "24 Pg Border") { alert("I found the " + allLayers[i].name + " layer") } else { alert("Not the right layer") } }
Any help would be greatly appreciated!
I'm using CS4 on a PC running Windows 64 Bit with JavaScript
This gives a shot.
its still very early and my brain completely does not work yet.
bring all the layers in the beginning (May) will ruin the stacking order much.
var doc = app.activeDocument; var allLayers = doc.layers; for (var i = allLayers.length-1; i >= 0; i--){ allLayers[i].locked = false; deeper(allLayers[i]); } function deeper(parent){ var subLayers = parent.layers; if (subLayers.length > 0){ for (var i = subLayers.length-1; i >= 0; i--){ subLayers[i].locked = false; deeper(subLayers[i]); if ((subLayers[i].name).substr(-6) == "Border") { subLayers[i].move(allLayers[0],ElementPlacement.PLACEBEFORE); } } } }
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Remove the top bar in the top-level navigation page
Hello
Is it possible to disable the top with Burger icon bar in the top-level navigation page and make it appear only served as in the articles? I thought that it was an option, but I can't seem to find anywhere in the dashboard or in tutorials.
Thank you!
Hi Jenn,
There is no option to remove it when you're on a navigation page.
Neil
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How can I find the ink levels in the Photosmart D110 series?
How can 8.1 Windows, I find the ink levels in the Photosmart D110 series?
Ink levels can be checked from the front as shown in the document here.
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Subgroup of experts can pass events to the top-level event loop?
I'm working on a VI that may have up to 1000 controls (Yes, she really need that much). To reduce the size of the user interface and increase the modularity of code, I partitioned design into subgroups that are loaded in tabs.
Subgroups are responsible for:
"VI reference to open"--> "invokes the method: Run VI '--> ' invoke the method: Insert VI»
(Sorry, I don't know how to incorporate images here, yet)
The upper level has some of its own controls in addition to the case of the Sub-group of experts, and it will be built on the design of producer-consumer model. The loop of consumer manages the interaction with the hardware (write-only). Each sub-group of experts will also have its own event loop to manage coordination of the user interface within the Sub-group of experts and also a preprocessing of data that results from the activity of the user within the Sub-group of experts.
Here's the problem: go in the subgroup of experts, how do I pass an event up to the top-level event loop so that the hardware access request can be entered into the queue of the consumer?
At first it seems I could solve this problem in two ways:
(1) rather than to use an Invoke node to insert the Sub-group of experts, is it possible to connect the frame of the Sub-group of experts against a VI that is instantiated in the block diagram? If there is, I can simply use dataflow to bring jury secondary to the upper level events. But for now, it seems there is no way to have a subgroup of experts except by using the Invoke node.
2) there is another way, that we have found, but this is an ugly hack. The reference to the 'Open VI' VI using, I use ' call method: control value: Get. Gives me the value of a control in the Sub-group of experts, but there is no case of signaling, so I have to resort to polling stations, which slows down the user interface and breaks the model "Event Loop".
Y at - it of other ideas for how to get events from the Panel under treaty to the next level?
(of course, this isn't * all * the events we manage.) The Sub-group of experts will actually a pre-treatment and then send only the selected events to the highest level user-defined)
Thank you and best regards,
J.
I have not used the secondary method before, so I can't save what I think with real experience.
But,
If the Subvi who is put in a secondary control on front panel for a queue reference, I think you'd be able to do the Invoke node to set the reference queue control before calling the functioning of the VI.
The other idea would be do not to have a reference of queue control to pass. But use named queues and leave the Subvi in high school to create its own queue reference based on the same name that was created in the main VI. When it ends, it could destroy its unique queue reference and not to force a destroy all and reference to the queue in the main VI would still be a queue works valid waiting for an another sub - VI at the secondary level to generate his reference to the same queue and sends the data in.
-
How do you find the ink level
that is, when to change an ink cartridege
Thank you Mr
Yes, we decided to try this earlier...
and that's all.
However, grace, too.
RM
-
How to find the current level of the tree in oracle forms?
Hi, I want to find the current level of the tree when the user click on a node wants to find current level how to do this?
Dear Mohammed,
You can use the FTREE. GET_TREE_NODE_PROPERTY ('tree_block.tree_name',: SYSTEM.) TRIGGER_NODE, FTREE. NODE_DEPTH); To achieve the current level of the node.
Kind regards
Manu.
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To find the Top most parent SQL
How to find the top most parent SQL. I want to avoid the hierarchical query that shows a high cost to run. Please suggest alternative options to find the parent
Maybe (when having multiple hierarchy trees) to be adapted to your needs
Select empno, I
from (select empno, I
WCP
where empno = 7876
model
hierarchy of reference on (select employee empno,
Manager Mgr
WCP
)
dimension (employee)
measures (Manager)
main main_model
size of (0 I)
measures (empno)
rules iterate (100) until (empno [iteration_number + 1] is null)
(
EmpNo [iteration_number + 1] = hierarchy.manager [empno [iteration_number]]
)
)
where empno is not null
order by I desc
EMPNO I 7839 3 7566 2 7788 1 7876 0 Concerning
Etbin
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How to find the child level for each table in a relational model?
Earthlings,
I need your help, and I know that, "Yes, we can change." Change this thread to a question answered.
So: How to find the child level for each table in a relational model?
I have a database of relacional (9.2), all right?
Tips:. O /* This is a child who makes N references to each of the follow N parent tables (here: three), and so on. */ /↑\ Fks O"O O" <-- level 2 for first table (circle) /↑\ Fks "o"o"o" <-- level 1 for middle table (circle) ↑ Fk "º"
-Each circle represents a table;
-Red no tables have foreign key
-the picture on the front line of tree, for example, a level 3, but when 3 becomes N? How is N? That is the question.
I started to think about the following:
First of all, I need to know how to take the kids:
Thought...select distinct child.table_name child from all_cons_columns father join all_cons_columns child using (owner, position) join (select child.owner, child.constraint_name fk, child.table_name child, child.r_constraint_name pk, father.table_name father from all_constraints father, all_constraints child where child.r_owner = father.owner and child.r_constraint_name = father.constraint_name and father.constraint_type in ('P', 'U') and child.constraint_type = 'R' and child.owner = 'OWNER') aux using (owner) where child.constraint_name = aux.fk and child.table_name = aux.child and father.constraint_name = aux.pk and father.table_name = aux.father;
We will share!
Thanks in advance,
Philips
Published by: BluShadow on April 1st, 2011 15:08
formatting of code and hierarchy for readbilityHave you looked to see if there is a cycle in the graph of dependence? Is there a table that has a foreign key to B and B has a back of A foreign key?
SQL> create table my_emp ( 2 emp_id number primary key, 3 emp_name varchar2(10), 4 manager_id number 5 ); Table created. SQL> ed Wrote file afiedt.buf 1 create table my_mgr ( 2 manager_id number primary key, 3 employee_id number references my_emp( emp_id ), 4 purchasing_authority number 5* ) SQL> / Table created. SQL> alter table my_emp 2 add constraint fk_emp_mgr foreign key( manager_id ) 3 references my_mgr( manager_id ); Table altered. SQL> ed Wrote file afiedt.buf 1 select level lvl, 2 child_table_name, 3 sys_connect_by_path( child_table_name, '/' ) path 4 from (select parent.table_name parent_table_name, 5 parent.constraint_name parent_constraint_name, 6 child.table_name child_table_name, 7 child.constraint_name child_constraint_name 8 from user_constraints parent, 9 user_constraints child 10 where child.constraint_type = 'R' 11 and parent.constraint_type = 'P' 12 and child.r_constraint_name = parent.constraint_name 13 union all 14 select null, 15 null, 16 table_name, 17 constraint_name 18 from user_constraints 19 where constraint_type = 'P') 20 start with child_table_name = 'MY_EMP' 21* connect by prior child_table_name = parent_table_name SQL> / ERROR: ORA-01436: CONNECT BY loop in user data
If you have a cycle, you have some problems.
(1) it is a NOCYCLE keyword does not cause the error, but that probably requires an Oracle version which is not so far off support. I don't think it was available at the time 9.2 but I don't have anything old enough to test on
SQL> ed Wrote file afiedt.buf 1 select level lvl, 2 child_table_name, 3 sys_connect_by_path( child_table_name, '/' ) path 4 from (select parent.table_name parent_table_name, 5 parent.constraint_name parent_constraint_name, 6 child.table_name child_table_name, 7 child.constraint_name child_constraint_name 8 from user_constraints parent, 9 user_constraints child 10 where child.constraint_type = 'R' 11 and parent.constraint_type = 'P' 12 and child.r_constraint_name = parent.constraint_name 13 union all 14 select null, 15 null, 16 table_name, 17 constraint_name 18 from user_constraints 19 where constraint_type = 'P') 20 start with child_table_name = 'MY_EMP' 21* connect by nocycle prior child_table_name = parent_table_name SQL> / LVL CHILD_TABLE_NAME PATH ---------- ------------------------------ -------------------- 1 MY_EMP /MY_EMP 2 MY_MGR /MY_EMP/MY_MGR 1 MY_EMP /MY_EMP 2 MY_MGR /MY_EMP/MY_MGR
(2) If you try to write on a table and all of its constraints in a file and do it in a valid order, the entire solution is probably wrong. It is impossible, for example, to generate the DDL for MY_EMP and MY_DEPT such as all instructions for a table come first, and all the instructions for the other are generated second. So even if NOCYCLE to avoid the error, you would end up with an invalid DDL script. If that's the problem, I would rethink the approach.
-Generate the DDL for all tables without constraint
-Can generate the DDL for all primary key constraints
-Can generate the DDL for all unique key constraints
-Can generate the DDL for all foreign key constraintsThis is not solidarity all the DOF for a given in the file object. But the SQL will be radically simpler writing - there will be no need to even look at the dependency graph.
Justin
-
Exit on the top-level shape does not work.
Hi I have 10g deployed forms on the web.
On the top-level form, there is an exit to this topic button.
And for this form, under ALERTS, I have two alerts: QUIT_ALERT and BANNER_ALERT.
Now when I press the EXIT button on the form, nothing happens. Prompting the ALERT and close the FORM.
Where and what could be the problem?
I have the following code for the exit button
And the function G$ _DISPLAY_ALERT a following codeIF G$_DISPLAY_ALERT('QUIT_ALERT','Do you really wish to quit?') = ALERT_BUTTON1 THEN
EXIT_FORM;
END IF
Published by: Charlie on March 30, 2011 14:01FUNCTION G$_DISPLAY_ALERT(ALERT_NAME IN VARCHAR2,
MSG_STRING IN VARCHAR2) RETURN NUMBER IS
ALERT_ID ALERT;
AL_NAME VARCHAR2(30);
ALERT_BUT NUMBER;
BEGIN
IF ALERT_NAME IS NULL THEN
AL_NAME := 'G$_WARNING_ALERT';
ELSE
AL_NAME := ALERT_NAME;
END IF;
ALERT_ID := FIND_ALERT(AL_NAME);
IF ID_NULL(ALERT_ID) THEN
RAISE FORM_TRIGGER_FAILURE;
END IF;
SET_ALERT_PROPERTY(ALERT_ID, ALERT_BUT, MSG_STRING);
ALERT_BUT := SHOW_ALERT(ALERT_ID);
RETURN ALERT_BUT;
END;Hello
What happens if you changeSET_ALERT_PROPERTY (ALERT_ID, ALERT_BUT, MSG_STRING);
for this
SET_ALERT_PROPERTY (ALERT_ID, ALERT_MESSAGE_TEXT, MSG_STRING);
?
-Clément
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MenuBar navigator - the top-level node are clickable
I use a browser from the menu bar in the application of mu. The data for the menu from an XML file. The menu contains the top-level nodes, but also of subnodes. All the nodes under work as expected. I can click on the node and the action runs. However, none of the top-level nodes have no subnodes do anything when you click it. I need these nodes also be clickable and enforcement actions, as do the subnodes. Is there a property in the menu bar control that I put?
Thank you!
Try this
http://www.Adobe.com/cfusion/CommunityEngine/index.cfm?event=ShowDetails&ProductID=2&postI d = 12506
-
OBIEE BI answers: measures bad aggregation at the top level of the hierarchy
Hi all,
I have the following problem. I hope to be clear in my English because it is somewhat complicated to explain.
I did following:
ID of drugs classified in quantity
1 9
2 4
1 3
2 2
and drugs following table:
Drug brand Id brand Description drug whose active ingredient Id drug whose active principle Description
Aulin Nimesulide 1 1
2 Asprina 2 Acetilsalicilico
In AWM, I've defined a Dimension of drugs based on the following hierarchy: drug whose active ingredient (parent) - brand name of medication (sheet) mapped as Description:
The active ingredient of drug = drug Active ingredient Id of my Table of drugs (pharmaceutical = Description of the active ingredient LONG DESCRIPTION attribute)
Pharmaceutical brand Description = drug brand Id of my drugs Table (LONG DESCRIPTION = Description of drug brand attribute)
Indeed, in my cube, I have traced pharmaceutical leaf-level brand Description = Id of the drug of my fact table. In AWM drugs Dimension is mapped as Sum aggregation operator
If I select on answers drug whose active ingredient (parent of my hierarchy) and the quantity, in my view, after the result
Description of the active ingredient drugs classified in quantity
Acetilsalicilico 24
Nimesulide 12
indeed of the correct values
Description of the active ingredient drugs classified in quantity
Acetilsalicilico 12
Nimesulide 6
EXACTLY the double! But if I dig drug Description of the active ingredient Acetilsalicilico I can't see correctly:
Drug whose active ingredient Description pharmaceutical brand classified in quantity Description
Acetilsalicilico
-12 Aspirina
Total 12
Aggregation of evil is only at the top level of the hierarchy. The aggregation on the lower level of the hierarchy is correct. Perhaps the answers also amount Total line? Why?
I'm frustrated. I ask your help, please!
GiancarloOK your on 10G but the view of the cube and the obligation to limit the levels in the LTS in the RPD is valid in both.
I think we found the problem,
Go to each source logical table this logic table (x 2 in your case you have two levels) and on the content tab, window background ' use this "Clause Where" filter to limit the rows returned. »
Open the expression builder, locate LEVEL_NAME according to your cube and limit accordingly, it is to say LEVEL_NAME = "BRAND_DESCRTIPION" for the aggregation BRAND_DESCRIPTION LTS and LEVEL_NAME = "XXXX" in detail, SFF, where XXXX is the name of level of hierarchy in your cube for details (leaves) records.Can you try that and let us know?
Thank you
Alastair -
How to find the location of a file or folder in windows 7
I have a few games on my computer. I can't find the location of the original file for them however. What I find is that they are in the 'games' folder that is included with windows 7. However, the whole files are not there. Only a little bit of information for the game is stored here. What I need to know is: how to find the original location? I tried the search bar "search programs and files" under the start menu, but the only place that appears is the Games folder. I need to know this, because I want to try modding my game called "Civilization 4. Can you please help?
Try this...
Start button > in the search box, type the name of the gam, i.e. of Civilization 4 > (do NOT press enter) > top left corner, you see the name "Civilization 4 '?
If so, right click on it > click Open File Location > the game exe file show be on the highlighted list > right click it > click on create a shortcut.
Happens to you?
-
How to move album to the top-level category?
I have album B inside the album of category A category. I want to move B to the upper level. How do I do that? I can easily drag B and drop it on another category, but I can't find where to drop them off to make a top-level category. Thank you.
Hi Bazsl,
If you click with the right button on the Green album and choose CHANGE a new window pane opens on the right side of the screen showing the album and its content...
At the top there are a menu drop down titled CATAGORY, you can select "None (Top Level)" and then click on the OK button at the bottom of the pane.
When I did, it took a few minutes to process the change.
Just loaded PES 11 myself, quite a change, a big curve of learning before (sigh)
Good luck
Al
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