First prize of the year

I have a problem-> I have tightened itself last month and forgot to send money to my mastercard prepaid to pay the monthly subscription.

so my subscription has been cancelled and I had to buy a new one. So far so good

but the teacher version costs 19.95 / month for the first year. Then, it costs 29.95 - have I the right?

now, adobe has taken 19.95 on my card but I feel that I want to keep things straight and pay 29.95

Help, please

Thank you

Hi Stefanh1627906,

I see that you have an active subscription to creative cloud under the same Adobe id in the forum. As you have purchased a new subscription, the price is not editable. You can enjoy using the same price until he renewed next year.

Please contact Adobe support for more information:

Contact the customer service

* Be sure to stay connected with your Adobe ID before accessing the link above *.

Tags: Adobe

Similar Questions

How to extract the first day of the year quarter
Hello

How can I write a query to extract the first day in a neighborhood of declaration

for example: -.

Q1 starts from April 1 to June 30, second quarter starts from July 1 to September 30, third quarter starts from 1 October to 31 December and the fourth quarter begins from January 1 to March 31.

How can I recover then the first day of these quarters, regardless of the year. The year can be any year.
Hello

don't know exactly what you want, but if you want the first day of a quarter for any given date and then
```
select trunc(sysdate,'Q') from dual;
```
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André

first day of the year and Monday next year

Hello all;

Given a year, how to determine the first day of this year and the next two Mondays for this year...

This gives a shot:

SELECT TRUNC(TO_DATE('2010','YYYY'),'YEAR')                        AS first_day_of_year
     , NEXT_DAY(TRUNC(TO_DATE('2010','YYYY'),'YEAR')-1,'MONDAY')   AS first_monday_of_year
     , NEXT_DAY(TRUNC(TO_DATE('2010','YYYY'),'YEAR')-1,'MONDAY')+7 AS second_monday_of_year
FROM   dual
;

1st day of the year then the Monday group

Hello expert;

I have the following tables below

create table table_one
(
 v_id varchar2(60),
 close_date date
);

insert into table_one
  (v_id, close_date)
values
  ('A', to_date('1/1/2010 4:47:09 PM', 'MM/DD/YYYY HH:MI:SS:AM'));   --- First day of the year

insert into table_one
  (v_id, close_date)
values
  ('B', to_date('1/4/2010 2:47:09 PM', 'MM/DD/YYYY HH:MI:SS:AM'));   -- monday
  
  insert into table_one
  (v_id, close_date)
values
  ('C', to_date('1/11/2010 1:47:19 PM', 'MM/DD/YYYY HH:MI:SS:AM'));  -- monday
  
 insert into table_one
  (v_id, close_date)
values
  ('D', to_date('5/6/2010 5:47:09 PM', 'MM/DD/YYYY HH:MI:SS:AM'));  --- not a monday
  
 insert into table_one
  (v_id, close_date)
values
  ('E', to_date('5/3/2010 4:47:09 PM', 'MM/DD/YYYY HH:MI:SS:AM'));  ---monday
  
 insert into table_one
  (v_id, close_date)
values
  ('F', to_date('2/9/2010 5:17:09 PM', 'MM/DD/YYYY HH:MI:SS:AM'));  -- not monday

I need to modify my query below and I can't think of a good way to go about it

select t.v_id, to_char(t.close_date, 'YYYY-MM-DD') from table_one t
where t.close_date between to_date('2010/1/1', 'YYYY-MM-DD') and to_date('2010/12/31', 'YYYY-MM-DD')
group by t.v_id, to_char(t.close_date, 'YYYY-MM-DD');

what I'm trying to do is in fact I want to group by only Mondays

Edited by: user13328581 on Nov 17, 2010 8:04 AM

Edited by: user13328581 on Nov 17, 2010 8:04 AM

Edited by: user13328581 on Nov 17, 2010 8:29 AM

select t.v_id, to_char(t.close_date, 'YYYY-MM-DD')
  from table_one t
where t.close_date between to_date('2010/1/1', 'YYYY-MM-DD') and to_date('2010/12/31', 'YYYY-MM-DD')
and   to_char(trunc (t.close_date), 'dy' ) = 'mon'

V_ID     TO_CHAR(T.CLOSE_DATE,'YYYY-MM-DD')
B     2010-01-04
C     2010-01-11
E     2010-05-03

If you also want the first day of the year that you mentioned.

select t.v_id, to_char(t.close_date, 'YYYY-MM-DD')
  from table_one t
where t.close_date between to_date('2010/1/1', 'YYYY-MM-DD') and to_date('2010/12/31', 'YYYY-MM-DD')
and   to_char(trunc (t.close_date), 'dy' ) = 'mon'
or  extract( month from t.close_date) + extract( day from t.close_date) = 2

V_ID     TO_CHAR(T.CLOSE_DATE,'YYYY-MM-DD')
A     2010-01-01
B     2010-01-04
C     2010-01-11
E     2010-05-03

Published by: pollywog on November 17, 2010 11:38

How to get the last day of the year
Hi all

Thanks in advance...

How do I get the last day of the year that I'm passing date at run time.

I can manage to get the first day of the year by
SELECT TRUNC(SYSDATE,'YEAR') AS FDAY_YEAR
of the double

Thanks in advance

Concerning
Sachin
```
  1*  select ADD_MONTHS(trunc(sysdate,'yyyy'),12)-1 dd from dual
SQL> /

DD
-----------
31-DEC-2010
```

find last Monday and Thursday of the year
I use trunc (somedate, 'iyyy') to get the first Monday of the year, but have read messages that suggest that gives you the closest to the beginning of the year Monday.

I need to find the last Monday of the year and also the last Thursday of the year. If the beginning of the year falls on Monday or Thursday, respectively, at the beginning of the year is what I need.
I did extensive testing, but I think that these might get you what you want:
```
NEXT_DAY(TRUNC(SYSDATE,'YEAR')-7,'THURSDAY')
```
and
```
NEXT_DAY(TRUNC(SYSDATE,'YEAR')-7,'MONDAY')
```
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Sample:
```
SQL> edit
Wrote file sqlplus_buffer.sql

  1  SELECT  NEXT_DAY(TRUNC(SYSDATE,'YEAR')-7,'THURSDAY')    LAST_THURSDAY
  2  ,       NEXT_DAY(TRUNC(SYSDATE,'YEAR')-7,'MONDAY')      LAST_MONDAY
  3* FROM DUAL
SQL> /

LAST_THURSDAY       LAST_MONDAY
------------------- -------------------
01/01/2009 00:00:00 12/29/2008 00:00:00
```
Published by: Centinul on December 28, 2009 12:20

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user634169 wrote:

... But, how to find the first day of the third quarter of the year next (from the current year) based on any date entry (i.e. sysdate)

for example if my entry date = 12/01/2001 should be released 07/01/2015

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... etc.

Thanks in advance

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/

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First prize of the year

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