Find the first day of the third quarter of next year
Hello
I'm writing a sql to find "the first day of the third quarter of the year (from the current year) next»
I am able to get the first and the last day of the current quarter:
Select trunc (sysdate, 'Q'), trunc (add_months (sysdate, + 3), 'Q')-1 double
But, how to find the first day of the third quarter of the year next (from the current year) based on any date entry (i.e. sysdate)
for example if my entry date = 12/01/2001 should be released 07/01/2015
If my entry date = 07/04/2005 should be released 07/01/2015
If my entry date = 20/02/2013 should be released 07/01/2015
... etc.
Thanks in advance
Hello
The 1st day of the 3rd quarter of next year is:
ADD_MONTHS (TRUNC (SYSDATE, 'YEAR')
18 = 12 + 6
)
TRUNC (SYSDATE, 'YEAR') is the 1st day of the 1st quarter of this year
The first day of the new year is 12 months after that, and the first day of quarter 3 is another 6 months after that.
user634169 wrote:
... But, how to find the first day of the third quarter of the year next (from the current year) based on any date entry (i.e. sysdate)
for example if my entry date = 12/01/2001 should be released 07/01/2015
If my entry date = 07/04/2005 should be released 07/01/2015
If my entry date = 20/02/2013 should be released 07/01/2015
... etc.
Thanks in advance
You did some errors above?
If the effective date in 2001, why is the output in 2015, not 2002?
If the output is based only on the date of the day (currently in 2014), why even mention a start date?
Tags: Database
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I'm looking for a function that will help me find the previous quarter, then the format base quarter is YYYY | » Q'|| Q.
For example, when quater_base = 2011Q 1, I need the function returns quarter_previous = 2010Q 4.
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TERIHi, Teri,
Welcome to the forum!
user13426561 wrote:
Hello
I'm looking for a function that will help me find the previous quarter, then the format base quarter is YYYY | » Q'|| Q.
For example, when quater_base = 2011Q 1, I need the function returns quarter_previous = 2010Q 4.I think I need to convert YYYY | » Q'|| Q on a date and then subtract 91 days or use add months,.
Q1 is normally 90 days long. If you subtract 91 days March 1, you return of the last two quarters.
Q2 is always long for 92 days. If you subtract 91 days from May 31, you have not changed shifts.
Better use ADD_MONTHS.but I need help conversion YYYY | » Q'|| Q for a date.
If s is a string of 6 characters such as '2011 Q 1' (i.e. Q1 2011), then
ADD_MONTHS ( TRUNC ( TO_DATE ( SUBSTR (s, 1, 4) , 'YYYY' ) , 'YEAR' ) , 3 * ( TO_NUMBER (SUBSTR (s, 6, 1)) - 1 ) )is the start DATE of this quarter.
Subtract 3 months ago, and convert it to a string such as "2010 Q 4":TO_CHAR ( ADD_MONTHS ( TRUNC ( TO_DATE ( SUBSTR (s, 1, 4) , 'YYYY' ) , 'YEAR' ) , 3 * ( TO_NUMBER (SUBSTR (s, 6, 1)) - 2 -- NOTE: subtracting 2, to get previous quarter ) ) , 'YYYY"Q"Q' )These strings come Is it possible that you could change the strings to have a month ('01', '04', '07' or 10') instead of the district, or to include both? This work would be much simpler!
It's a shame that you can't use 'Q' in TO_DATE.
You might consider a user-defined function to perform the conversion above. It will make your code much cleaner, but it will be slower.Thank you very much in advance for your help.
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Insert into FLIGHTS (FREQ_FLYER_ID,ROUTE_ID,FLIGHT_DATE) values ('1003','001',to_date('01-JUN-06','DD-MON-RR')); insert into flights (freq_flyer_id,route_id,flight_date) values ('1003','001',to_date('01-JUL-06','DD-MON-RR')); Insert into FLIGHTS (FREQ_FLYER_ID,ROUTE_ID,FLIGHT_DATE) values ('1003','001',to_date('01-AUG-06','DD-MON-RR')); -- 1001: 0; 1002: 0; 1003: 1, 1004: 1; 1005: 11 insert into flights (freq_flyer_id,route_id,flight_date) values ('1003','002',to_date('31-JAN-06','DD-MON-RR')); Insert into FLIGHTS (FREQ_FLYER_ID,ROUTE_ID,FLIGHT_DATE) values ('1004','002',to_date('28-FEB-06','DD-MON-RR')); insert into flights (freq_flyer_id,route_id,flight_date) values ('1005','002',to_date('31-JAN-06','DD-MON-RR')); Insert into FLIGHTS (FREQ_FLYER_ID,ROUTE_ID,FLIGHT_DATE) values ('1005','002',to_date('28-FEB-06','DD-MON-RR')); insert into flights (freq_flyer_id,route_id,flight_date) values ('1005','002',to_date('31-MAR-06','DD-MON-RR')); Insert into FLIGHTS (FREQ_FLYER_ID,ROUTE_ID,FLIGHT_DATE) values ('1005','002',to_date('30-APR-06','DD-MON-RR')); insert into flights (freq_flyer_id,route_id,flight_date) values ('1005','002',to_date('31-MAY-06','DD-MON-RR')); insert into flights (freq_flyer_id,route_id,flight_date) values ('1005','002',to_date('30-JUN-06','DD-MON-RR')); insert into flights (freq_flyer_id,route_id,flight_date) values ('1005','002',to_date('31-JUL-06','DD-MON-RR')); Insert into FLIGHTS (FREQ_FLYER_ID,ROUTE_ID,FLIGHT_DATE) values ('1005','002',to_date('31-AUG-06','DD-MON-RR')); insert into flights (freq_flyer_id,route_id,flight_date) values ('1005','002',to_date('30-SEP-06','DD-MON-RR')); insert into flights (freq_flyer_id,route_id,flight_date) values ('1005','002',to_date('31-OCT-06','DD-MON-RR')); Insert into FLIGHTS (FREQ_FLYER_ID,ROUTE_ID,FLIGHT_DATE) values ('1005','002',to_date('30-NOV-06','DD-MON-RR'));Hello
Here's one way:
WITH got_r_num AS ( SELECT EXTRACT (YEAR FROM TRUNC (flight_date, 'YEAR')) AS flight_year , route_id , freq_flyer_id , COUNT (*) AS flight_count , RANK () OVER ( PARTITION BY TRUNC (flight_date, 'YEAR') , route_id ORDER BY COUNT (*) DESC ) AS r_num FROM flights GROUP BY TRUNC (flight_date, 'YEAR') , route_id , freq_flyer_id ) SELECT * -- or list all columns except r_num FROM got_r_num WHERE r_num <= 3 ORDER BY flight_year , route_id , r_num ;If there be a tie (in other words, if 4 or more people, some with exactly the same number of flights, all can to be in the top 3 for a given year and the road) then the above query will include all the contenders for the top 3. For example, if you add one more line of your sample data:
Insert into FLIGHTS (FREQ_FLYER_ID, ROUTE_ID, FLIGHT_DATE) values ('1009', '002', to_date('30-NOV-2006','DD-MON-YYYY'));Now, who are the top 3 flliers for 2006 on road '002'? Obviously, "1005" is one of them, but there is a tie of 3 - way for second place: '1003 ', '1004' and ' 1009' have exactly 1 flight, and all have equal calim to be in the top 3. Why would you exclude one of them, ratehr than the other two? The query above includes all the.
If you want to ensure that not more than 3 rows are included for the whole year and the road, and then add the columns of tiebreaker to analytical ORDER BY clause and/or use ROW_NUMBER instead of RANK.This is called a Query Top - N , because you're gathering of N (N = 3 in this case) from the top of an ordered list.
Published by: Frank Kulash, December 17, 2012 12:52
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2 Prime Minister arrived in Melbourne, for the last leg of his tour of four cities in the Australia, March 1, 2014 and April 3, 2100 2 The r1eading of 234/12 ahead of Singapore December 1, 2012, for the third quarter on December 1, 2015, showing no response 1 There is no malaria symptom Minister after November 19, 2014 meaning vaccine properly work help link for regexp: Oracle of regular Expressions
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Repeatedly offered KB2463332 update
OT: kb2463332. Hello from down under, I have a laptop Toshiba A300 Vista home premium, AVG Anti Virus and a windows automatic update. I get an update with KB2463332 repeatedly over and over again which then of course wants me to install the item. Whe
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Defender starts ok but will turn off by itself. I thought that this could be a problem to update. I asked for updates and got this error code.