Force10 VLT and fast failover
Forgive me if this belongs somewhere else, but I couldn't find a Force10 forum. We have a pair of 4820 t configured as an area of VLT. Our "leaves" are Dell 5548 s and 6224 s connected via gal to 4820 t "thorns". It seems, in a failure scenario, can we get our paths to the top 7-8 seconds. In one of the white papers, they showed 1.5 dry path recoveries. What is the determining factor to get a quick recovery? We have time Hello RSTP etc composed as low they can go on the PowerConnects FWIW. Is there something else to say LACP, etc. that we missed causing the recovery of the slow lane?
We've thought of it. It turns out that it was the Hello time in RSTP. Setting the time Hello dry a.5 we did one Force10 whitepapers described. It turns out that it's bad. The PowerConnects were both Hello 2 (the default protocol) and could not be defined as low as 0.5. Once we put the Force10s both Hello 2, everyone was happy. 700ms failovers were had by all.
Tags: Dell Switches
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DCB - Force10 MXL and Equallogic PS6210 - worth it or not?
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Flashback and accelerated failover
Hello everyone:
Environment of the guard of my data:
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I want to implement the changeover accelerated in my environment. Requirements for reading, I found that Oracle Flashback is necessary (I do not use Flashback on my databases).
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Thank you very much.791490 wrote:
Hello and thanks for the helpI have not configured backup to FRA. I do backups on an operating system partition and I don't want to make on FRA.
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-------
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Objective 2:
--------
As I explained above, all products Oracle IDM and applications to speak to the RAC database, what do know only on the RAC database, which is the main. They are not aware of the pending database.
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However before that happens, standby database should become primary because the client session can perform write operations.
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Issues related to the:
----------
1. Please throw some light to reach above features.
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Could you please help?
Thank youI didn't say that clients cannot reconnect automatically when primary fails: I meant that client sessions can generally reconnect and also keep any session state.
Yes, they can reconnect but only to keep the session state for a SELECT statement. It is also possible with Data Guard, not only in the CARS I wrote: here's a demo with 10 g
http://uhesse.WordPress.com/2009/08/19/connect-time-failover-transparent-application-failover-for-Data-Guard/.
What is not possible is to maintain a session state: (INSERT/UPDATE/DELETE) pending transactions must be cancelled.Edited by: P. Forstmann on Dec 8. 2011 20:30
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BASIC and PRECONNECT failover methods
Version: 10.2.0.4, 11.2
That's what documentation says BASIC and PRECONNECT
http://download.Oracle.com/docs/CD/B28359_01/network.111/b28316/advcfg.htm#i471200
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Yes...
>
These pre-processed sessions will appear in v$ session of the Forum of backup?
Yes...
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Check using query below:
Select
user name,
SID,
Serial No.,
failover_type,
failover_method,
failed_over
Of
session v$
where
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'PERFSTAT')
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Were there any changes made to the computer before the show?
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Hello
I have a table (one) with more 1 000 000 IP addresses and numbers (the digital equivalent of the IP address)
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-------------------------- ---------------------- --------------
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The performace of it's terrible and table (c) takes several hours to create.
Hours what do you say?
See if the following can help.
Cardinalities are similar to yours. The ETG takes 7sec. :
SQL> create table ip_numbers (ip_address, ip_number) as 2 select cast(to_char(level,'fm099G999G999G999', 'nls_numeric_characters=,.') as varchar2(15)) 3 , level 4 from dual 5 connect by level <= 1000000 ; Table created. SQL> select * from ip_numbers where rownum <= 10; IP_ADDRESS IP_NUMBER --------------- ---------- 000.000.000.001 1 000.000.000.002 2 000.000.000.003 3 000.000.000.004 4 000.000.000.005 5 000.000.000.006 6 000.000.000.007 7 000.000.000.008 8 000.000.000.009 9 000.000.000.010 10 10 rows selected. SQL> SQL> create table isp_lookup (begin_ip_range, end_ip_range, isp_name) as 2 select 1 + (level-1)*5 3 , level*5 4 , cast('ISP_'||to_char(level,'fm099999') as varchar2(10)) 5 from dual 6 connect by level <= 200000 ; Table created. SQL> select * from isp_lookup where rownum <= 10; BEGIN_IP_RANGE END_IP_RANGE ISP_NAME -------------- ------------ ---------- 1 5 ISP_000001 6 10 ISP_000002 11 15 ISP_000003 16 20 ISP_000004 21 25 ISP_000005 26 30 ISP_000006 31 35 ISP_000007 36 40 ISP_000008 41 45 ISP_000009 46 50 ISP_000010 10 rows selected. SQL> create index ip_address_number_ix on ip_numbers (ip_number); Index created. SQL> set timing on SQL> SQL> create table ip_mappings as 2 select /*+ use_nl(a b) */ 3 a.ip_address 4 , b.isp_name 5 from isp_lookup b 6 join ip_numbers a on a.ip_number between b.begin_ip_range 7 and b.end_ip_range 8 ; Table created. Elapsed: 00:00:06.94 SQL> select count(*) from ip_mappings; COUNT(*) ---------- 1000000 Elapsed: 00:00:01.22 -
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Ask the operation slow with large SGA and fast with little CMS
Hello
We have a situation where one of the insert is running slow and fast QA in PROD. Both are the same versions of database - Oracle 10.2.0.4 on HP Unix 11.31. To avoid the cause of databases running on another server, we copied from our Production database to the same server where the QA database is running and began with init.ora PROD that has 7 GB 6 GB SGA_TARGET and SGA_MAX_SIZE. For the QA database, SGA_MAX_SIZE is 700 MB and SGA_TARGET is 600 MB. Both are running on the same server, and with the same data. We have refreshed QA with data from PROD. If we start with PROD init.ora QA database, QA also behaves the same way PROD.
This problem is only with the specific insert. Here is the result of this specific statement tkprof. Can someone please interpret this for me? I am poor in SQL tuning :-( Why the statement behaves ODD with the size of the SGA PROD? Generally, we would think THAT larger SGA should give better performance.
call the query of disc elapsed to cpu count current lines
------- ------ -------- ---------- ---------- ---------- ---------- ----------
Parse 1 0.00 0.00 0 0 0 0
Run 1 56710.39 56067,75 7343 311186373 0 0
Fetch 0 0.00 0.00 0 0 0 0
------- ------ -------- ---------- ---------- ---------- ---------- ----------
Total 2 56710.39 56067,76 7343 311186373 0 0Chess in the library during parsing cache: 1
Optimizer mode: CHOOSE
The analysis of the user id: 27 (TEST)Rows Row Source operation
------- ---------------------------------------------------
0 CRDETAIL of SEQUENCE (cr = 0 pr = 0 pw = time 0 = 29 US)
0 REVIEWS (cr = 0 pr = 0 pw = time 0 = 21 US)
0 SORT GROUP BY (cr = 0 pr = 0 pw = time 0 = 20 US)
401 HASH RIGHT SEMI JOIN (cr = 23299915 pr 7343 pw = time = 0 = 93982966 en)
237 TABLE ACCESS BY INDEX ROWID CR_STRUCTURE_VALUES2 (cr = 96 pr = 0 pw = time 0 = 504 en)
253 CR_STRUCTURE_VALUES2_PK INDEX RANGE SCAN (cr = 4 pr = 0 pw = time 0 = 278 en)(object id 1467582)
TABLE ACCESS BY INDEX ROWID CR_COST_REPOSITORY 841 (cr = 23306003 pr 7343 pw = time = 0 = 94546465 en)
1317368058 NESTED LOOPS (cr = 79721182 pr 7343 pw = time = 0 = 18565176955 en)
VIEW 26912 (cr = pr 9874 7343 pw = time = 0 = 5269231 en)
26912 MINUS (cr = pr 9874 7343 pw = time = 0 = 5242317 en)
27462 SORT UNIQUE (cr = 9627 pr = 7329 pw = time 0 = 5040815 en)
271564 CR_STRUCTURE_VALUES2 TABLE FULL ACCESS (cr = 9627 pr = 7329 pw = time 0 = 1357961 en)
568 SORT UNIQUE (cr = 247 pr = 14 pw = time 0 = 43467 US)
TABLE ACCESS BY INDEX ROWID CR_STRUCTURE_VALUES2 2357 (cr = 247 pr = 14 pw = time 0 = US 14751)
2357 CR_STRUCTURE_VALUES2_PK INDEX RANGE SCAN (cr = pr 11 = 14 pw = time 0 = 10028)(object id 1467582) US
INDEX RANGE SCAN CRCR_MN_IX 1317341146 (cr = 79711308 pr = 0 pw = time 0 = 50420511 US)(object id 1469401)
Implementation plan of lines
------- ---------------------------------------------------
0 THE INSERT STATEMENT MODE: CHOOSE
SEQUENCE "CRDETAIL" 0 (SEQUENCE)
0 REVIEWS
0 TRI (GROUP BY)
401 HASH JOIN (RIGHT HALF)
HOW TO ACCESS THE TABLE 237: ANALYSES (BY INDEX ROWID) OF
"CR_STRUCTURE_VALUES2" (TABLE)
INDEX 253 MODE: SCANNED (SCAN INTERVAL) OF
"CR_STRUCTURE_VALUES2_PK" ((UNIQUE) INDEX)
ACCESS MODE TO THE 841 TABLE: ANALYSIS (BY INDEX ROWID) OF "CR_COST_REPOSITORY" (TABLE)
1317368058 NESTED LOOPS
VIEW 26912
26912 LESS
27462 SORT (SINGLE)
TABLE 271564 ACCESS MODE: ANALYZED (FULL) OF
"CR_STRUCTURE_VALUES2" (TABLE)
568 (SINGLE) SORT
HOW TO ACCESS THE TABLE 2357: ANALYSES (BY INDEX ROWID)
OF "CR_STRUCTURE_VALUES2" (TABLE)
INDEX 2357 MODE: SCANNED (SCAN INTERVAL) OF
"CR_STRUCTURE_VALUES2_PK" ((UNIQUE) INDEX)
MODE 1317341146 INDEX: ANALYSIS (SCAN INTERVAL) OF "CRCR_MN_IX".
(INDEX)********************************************************************************
And here is the statement in question:
INSERT INTO cr_allocations_stg ( "ID", "COMPANY", "GL_ACCOUNT", "COST_CENTER", "COST_ELEMENT", "PROFIT_CENTER", "MASTER_ORDER", "ORDER_NUMBER", " FUNDING_PROJECT", "POSTING_ORDER", "POSTING_COST_CENTER", "ORIG_COST_ELEMENT", "ORIG_COST_CENTER", "ORIG_PROFIT_CENTER", "TRADING_PARTNER", "WORK_ORDER_NUMBER", "DR_CR_ID", "LEDGER_SIGN", "QUANTITY", "AMOUNT", "MONTH_NUMBER", "MONTH_PERIOD", "GL_JOURNAL_CATEGORY", "AMOUNT_TYPE", "ALLOCATION_ID", "TARGET_CREDIT", "CROSS_CHARGE_COMPANY" ) SELECT crdetail.nextval, "COMPANY", "GL_ACCOUNT", "COST_CENTER", '5253000', "PROFIT_CENTER" , "MASTER_ORDER", "ORDER_NUMBER", "FUNDING_PROJECT", ' ', "POSTING_COST_CENTER", "ORIG_COST_ELEMENT", "ORIG_COST_CENTER", "ORIG_PROFIT_CENTER", " TRADING_PARTNER", "WORK_ORDER_NUMBER", CASE WHEN amount > 0 THEN 1 ELSE -1 END, 1,0, ROUND(amount * 0.0574000000, 2), month_number, 0, '593', 1 , 7, 'TARGET', ' ' FROM (SELECT "COMPANY", "GL_ACCOUNT", "COST_CENTER", "PROFIT_CENTER", "MASTER_ORDER", "FUNDING_PROJECT", "POSTING_COST_CENTER", "ORDER_NUMBER", "ORIG_COST_ELEMENT", "ORIG_COST_CENTER", "ORIG_PROFIT_CENTER", "TRADING_PARTNER", "WORK_ORDER_NUMBER", month_n umber, 0, SUM(amount) amount, SUM(quantity) quantity FROM CR_COST_REPOSITORY WHERE (amount_type = 1 ) AND (month_number = 201404) AND ( "MASTER_ORDER" IN MASTER_ORDER AND EXISTS (SELECT 1 FROM (SELECT SUBSTR(ELEMENT_VALUE, 1, DECODE(INSTR(ELEMENT_VALUE, ':'), 0, L ENGTH(ELEMENT_VALUE) + 1, INSTR(ELEMENT_VALUE, ':')) - 1) AS ELEMENT FROM CR_STRUCTURE_VALUES2 WHERE STRUCTURE_ID = 2 AND DETAIL_BUDGET = 1 AND STATUS = 1 AND UPPER(PARENT_VALUE) IN ('ELECTRIC ALL OTHER','ELECTRIC COR') MINUS SELECT SUBSTR(ELEMENT_VALUE, 1, DECODE(INSTR(ELEMENT_VALUE, ':'), 0, LENGTH(ELEMENT_VALUE) + 1, INSTR(ELEMENT_VALUE, ':')) - 1) AS ELEME NT FROM CR_STRUCTURE_VALUES2 WHERE STRUCTURE_ID = 9 AND DETAIL_BUDGET = 1 AND STATUS = 1 AND UPPER(PARENT_VALUE) = 'A&G OH ORDER EXCLUSION' ) Z WHERE Z.ELEMENT = MASTER_ORDER ) AND "GL_ACCOUNT" <> '91081001' AND "COST_ELEMENT" IN COST_ELEMENT AND EXISTS (SELECT 1 FROM CR_ST RUCTURE_VALUES2 A WHERE A.STRUCTURE_ID = 5 AND A.DETAIL_BUDGET =1 AND A.STATUS = 1 AND COST_ELEMENT = A.ELEMENT_VALUE ) AND "GL_ACCOUNT" NOT IN ('5100000','5325000','5327000') AND "SOURCE_ID" <> '7' ) GROUP BY "COMPANY", "GL_ACCOUNT", "COST_CENTER", "PROFIT_CENTER", "MASTER_ORDER", "FUNDING_PROJECT", "POSTING_COST_CENTER", "ORDER_NUMBER", "ORIG_COST_ELEMENT", "ORIG_COST_CENTER", "ORIG_PROFIT_CENTER", "TRADING_PARTNER", "WORK_ORDER_NUMBER", month_number )Enjoy your first answer on this.
Thank you and best regards,
Murali
Option 1:
You run with two different ORACLE_HOMEs - that is potentially two different copies of the Oracle executable to the patch different sets?
Option 2:
A change of size of SGA is unlikely to directly affect the execution plan, but it also has change the size of the PGA TOUR at the same time? A change in the pga_aggregate_target could affect the choice of the mechanism of the join optimizer. (But not to change an in a join; but hash semi-join to nested loop is possible).
Possibility 3:
The db_file_multiblock_read_count leaves then the size that oracle defines by default depends on the db_cache_size divided by process; so, if you have reduced the sga_target_size you (implicitly or explicitly, no doubt) reduced the db_cache_size, and if you don't reduce the process in the same way, then the default db_file_multiblock_read_count been reduced. What you did on your system stats, this could change the cost of (for example) full tablescans, which could lead to a change in execution plan.
It would be useful to see the results of a call to explain the plan / dbms_xplan.display in both cases so that we can see the variation in estimates of Oracle.
Concerning
Jonathan Lewis
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