Form triggers the error when the table trigger fires.

Similar Questions

• PL/Sql error when creating a trigger

  Hello everyone m trying to set a trigger whose goal is to not allow any update insert or remove on the work table, if the day is Sunday. I tried this code but it gives me error

   create or replace trigger No_work_on_Sunday
   After insert or update or delete
  on Work When owner='MAX'
  for each row
  begin
          if (select to_char(sysdate,'D')=1) then
                   raise_application_error(-20001,'no work on sunday');
        end if;
   end;
  
   
   on Work when owner='MAX'
           *
  ERROR at line 3:
  ORA-04077: WHEN clause cannot be used with table level triggers

  Pls help
  
  Published by: 781207 on July 16, 2010 07:43

  create or replace trigger No_work_on_Sunday
   After logon on DATABASE
   begin
         if to_char(sysdate,'D')=1 then
                   if ora_login_user IN ('Jake','MAX') THEN
                       RAISE_APPLICATION_ERROR(-20001,'No work on sunday');
                 end if;
        end if;
  end;
  /
  

  SY.

• What is this error when creating a trigger

  Hello
  
  I have create a trigger and get the following error. What is - c
  
  1 CREATE OR REPLACE TRIGGER TRG_AUDIT_LOGON AFTER
  2 LOG ON TO THE DATABASE
  3 Declare
  4 v_sid v$session.sid%type;
  type of v_serial 5 v$ session.serial # %;
  v_username 6 v$session.username%type;
  v_osuserid 7 v$session.osuser%type;
  8 v_machinename v$session.machine%type.
  v_PROGRAM 9 v$session.program%type;
  v_TERMINAL 10 v$session.terminal%type;
  11 v_hostname v$instance.host_name%type;
  v_instance_name 12 v$instance.instance_name%type;
  13 v_application_id v$database.dbid%type;
  date of v_logon_time 14;
  15 v_Audit_tab_check varchar2 (30);
  16 v_system_users_tab_check varchar2 (30);
  17 v_sql_Audit_upload varchar2 (1000): = "INSERT INTO dbaoper. T_AUDIT (HOST_NAME, APPLICATION_ID, INSTANCE_NAME, SID, SERIAL #, username, OSUSERID, MACHINENAME, PROGRAM, TERMINAL, LOGON_TIME) VALUES (: v_hostname,: v_application_id,: v_instance_name,: v_sid,: v_serial,: v_username,: v_osuserid,: v_machinename,: v_program,: v_TERMINAL,: v_logon_time) ';
  18 type c_audit_cur_typ is ref cursor;
  19 C_Audit c_audit_cur_typ;
  20 V_system_users_tab: = "T_SYSTEM_USERS";
  21 No_Audit_records Exception;
  Begin 22
  23 select table_name in v_Audit_tab_check from dba_tables where owner = 'DBAOPER' and table_name = "T_AUDIT";
  24 select table_name in v_system_users_tab_check from dba_tables where owner = 'DBAOPER' and table_name = "T_SYSTEM_USERS";
  25 c_Audit open for ' SELECT sid, serial # username, osuser, machine, terminal program v $ session WHERE audsid = userenv ("' sessionid" ') and program not as "'oracle@%J0%"' and no user name (select * from dbaoper.' |) V_system_users_tab |') and type! = "' BACKGROUND"' ';
  26 c_Audit of fetch in v_sid, v_serial, v_username, v_osuserid, v_machinename, v_program, v_TERMINAL;
  27 if c_Audit % Notfound then
  28 lift No_Audit_records;
  Else 29
  30 select host_name, instance_name in v_hostname, v_instance_name from v$ instance;
  31 select dbid from v_application_id from v$ database;
  32 select sysdate in double v_logon_time;
  33 execute immediate v_sql_Audit_upload using v_hostname, v_application_id, v_instance_name, v_sid, v_serial, v_username, v_osuserid, v_machinename, v_program, v_TERMINAL, v_logon_time;
  34 end if;
  35 close C_Audit;
  exception of 36
  37 when no_data_found then
  38 dbms_system.ksdwrt (2, 'ORA-20001 Audit T_AUDIT or T_SYSTEM_USERS not found Audit information tables are not entered'
  (39);
  40 what then No_Audit_records
  41 dbms_output.put_line ('Audit number to insert records");
  42 * end;
  SQL > /.
  
  WARNING: Trigger created with compilation errors.
  
  SQL > sho err
  Errors for TRG_AUDIT_LOGON TRIGGER:
  
  LINE/COL ERROR
  -------- -----------------------------------------------------------------
  18/20 PLS-00103: encountered the symbol "=" when expecting one of the
  Next:
  constant exception < an ID >
  < a between double quote delimited identifiers > double Ref table Fedya
  char time timestamp interval date binary national character
  NCHAR
  The '< an identifier >' replaced with '=' to
  continue.
  
  
  Thank you
  Pramod

  replace * "' * with *" *. For example userenv ("' sessionid" ') to userenv ("sessionid")

• Get the error when using the UTL_SMTP function in Oracle 11 g

  Hello

  I get the error when executing a trigger e-mail code in oracle 11 g:

  I have following trigger on the temporary table:

  CREATE OR REPLACE TRIGGER temp_temp_message AFTER

  INSERT OR UPDATE ON temp_message FOR EACH LINE

  declare

  Conn UTL_SMTP . CONNECTION ;

  msg VARCHAR2 (2000);

  Start

  Conn := UTL_SMTP . open_connection ( host => '10.250.1.149', port=>25 );

  UTL_SMTP . HELO ( conn, '10.250.1.149');

  UTL_SMTP . mail ( conn, '[email protected]');

  UTL_SMTP . RCPT () conn ' [email protected]');

  msg := "Hello, this is test mail." ;

  UTL_SMTP .data( conn, msg);

  UTL_SMTP . quit smoking ( conn );

  exception when others then

  dbms_output.put_line (sqlerrm);

  raise_application_error (-20000,

  "Failed to send because of the following error messages: ' " || sqlerrm);

  end;

  Insert in temp_message values ()1

  );

  When I insert the record in the table there are given the following error.

  ORA-20000: failed to send messages because of the following error: ORA-24247: access denied by access control (ACL) of network list

  ORA-06512: at the 'APPS '. TEMP_TEMP_MESSAGE', line 14

  ORA-04088: error during execution of trigger ' APPS. TEMP_TEMP_MESSAGE'

  But if I run the next plsql through sqlplus send mail successfully:

  declare

  Conn UTL_SMTP . CONNECTION ;

  MSG VARCHAR2 (2000);

  Start

  Conn := UTL_SMTP . open_connection ( host => '10.250.1.149', port=>25 );

  UTL_SMTP . HELO ( conn, '10.250.1.149');

  UTL_SMTP . mail ( conn, '[email protected]');

  UTL_SMTP . RCPT () conn ' [email protected]');

  msg := "Hello, this is test mail." ;

  UTL_SMTP .data( conn, msg);

  UTL_SMTP . quit smoking ( conn );

  exception when others then

  dbms_output.put_line (sqlerrm);

  raise_application_error (-20000,

  "Failed to send because of the following error messages: ' " || sqlerrm);

  end;

  Thanks in advance.

  Yoann

  To resolve ORA-24247 you must:

  (1) create an acl (if it is not already created)

  (2) add the user privileges using the resources of the network

  (3) to use the ACL to a specific address

  This might be useful

  How to fix an ORA-24247: access denied by access control (ACL) of network list | DB tips

• Select the row in the table to change in a form

  Hi all

  I use Jdeveloper 12.1.3.0.0 on windows internet explore 10.

  I have the following form and the read-only table. the form and the table that are both on the same object from view.

  

  When the user clicks a row in the table, I want to choose this line in the form above for editing purpose.

  How would I do that? the first column of the table is a primary key.

  I followed shayjdev vedio http://www.youtube.com/watch?v=e0IcnXLJUgU

  but the problem is that when I click the button CreateInsert (5th button left in my case), never clear the form for the opening of new record, instead, he put the table in input mode.

  kindly help me with this.

  Thank you.

  To create a new line, you drag the operation createInsert of the data control on the create new"" button. This should create the new row.  If you like the new line being the last of them using the link from dvohra21 to https://blogs.oracle.com/jdevotnharvest/entry/how_to_add_new_adf

  In this case, you must change the listener to the button action to point to the generation of listener action code of Frank.

  Timo

• How to get multiple rows in the table is displayed on the form

  I am looking for a way to get more table rows that appear on the form.  I created a table with a header and a line with the add-in and remove button option.  I like how the sample purchase order form has it setup in the designer it shows one line and it appears on the form so the table has three rows to start with.  How do I do that?  I looked at the code on the sample and I couldn't find it anywhere.  Please help, thanks.

  Hello

  I have an example here in the construction of a dynamic array markets.

  http://www.assuredynamics.com/index.php/category/portfolio/building-dynamic-tables/

  You must select the line and then go to object > Binding palette and set it to repeat. You can set the minimum and initial number to what you want.

  The form should be saved in a dynamic form of XML in the Save as dialog box.

  Also the page must be set to Flowed, so that as the table grows, push another object down. In addition, you need to configure the paging settings so that the flow of the page as the number of lines is superior to a single page.

  Give a start and if you need more help,

  Niall

  Ensure the dynamics

• ExportCollectionAction causes the current values of lines to be copied into the first row of the table

  Greetings experts,

  I use JDev 11.1.2.3

  I am faced with a really strange behavior of the exportCollectionActionListener. I have a table for each row in this table, a link that calls a popUp. This popUp tells the story of this selected save changes (means it displays data from a different table/VO, who keeps a history of the first) in a table. I have a button that calls the exportCollection for this second table. When I press on it, an excel file is generated and downloaded and everything is perfect until now. If there was not any which record in this table, and o back to the first, by pressing the button send is not track all changes. But if there where all records from this table of history (always talking about the history of the current line), go back to the first and press on submit, that the very first line of the table of fir trees, gets all of it's values as the last row of the second table, as it is copied from one to the other. I have to press on restore back to normal (note that the popUp has it's CancelListener to call a restore of a bean to support operation).

  Why is this happening?

  Thanks in advance

  I found a work around for this problem.

  I added the code that causes the whole view Refresh (ie: the whole page), the popUp cancelListener, also I changed the commandLink partialSubmit property and set it to true. It's not like totally cool watching the screen charge for this fragment of a second after the closure of the pop-up window, but it not the drill.

• ORA-04079: specification of the invalid trigger

  CREATE OR REPLACE TRIGGER CARE. SURCHRG_UPDT
  AFTER INSERTION
  ON CARE. CHARGE_TRANS_DETAILS
  REFERRING AGAIN AS NINE OLD AND OLD
  FOR EACH LINE
  If (SELECT pad_adm_no FROM patient_adm WHERE pad_cur_pat_type = 'CRD' AND pad_cur_bill_cls IN ('SPN', 'RSH') pad_org_cd AND NOT IN ('OM6")))
  BEGIN
  UPDATE charge_trans_details
  SET ctd_surcharge_percent = 10,
  ctd_spon_surcharge_amt = ctd_item_pat_spnr_amt * 10 / 100
  WHERE <>'P1' and ctd_cancel_flag = n ctd_grp_cd
  END;
  
  I am facing above error when creating this trigger.
  
  Help...!

  Sorry, try this
  CREATE OR REPLACE TRIGGER CARE. SURCHRG_UPDT
  AFTER INSERTION
  ON CARE. CHARGE_TRANS_DETAILS
  REFERRING AGAIN AS NINE OLD AND OLD
  declare
  Temp of VARCHAR2 (10);
  BEGIN
  SELECT pad_adm_no
  IN temp
  OF patient_adm
  WHERE pad_cur_pat_type = 'CRD '.
  AND pad_cur_bill_cls IN ('SPN', 'RSH')
  AND pad_org_cd NOT IN ('OM6");
  Temp of IF IS NOT NULL
  THEN
  UPDATE charge_trans_details
  SET ctd_surcharge_percent = 10,
  ctd_spon_surcharge_amt = ctd_item_pat_spnr_amt * 10 / 100
  WHERE ctd_grp_cd = 'P1' AND ctd_cancel_flag = ' not *; *
  END IF;
  END;

  Published by: human Chen on May 26, 2012 15:50

  Published by: human Chen on May 26, 2012 15:50

• Solution for the mutation of table of error when using triggers

  Hello

  Could you please give the solution for the error table mutation during the use of triggers. I'll give you the simple scenario here,

  I created a trigger on the employees table, whenever all DML operations takes place in the employees table, it must run the trigger body. I intentionally used also of the employees in the body of the trigger table. Please give me the solution.

  Triggering factor:

  create or replace trigger test_trigger

  before you insert or update or delete employees

  for each line

  declare

  an employees.first_name%type;

  Start

  Select first_name from people where job_id = "AD_PRES";

  end;

  DML statement:

  Update employees set salary = 20000 where job_id = "AD_PRES" (I run this query)

  Error message:

  ORA-04091: table HR. Is the transfer of EMPLOYEES, the function of triggering/can not see

  ORA-06512: at "HR. TEST_TRIGGER', line 4

  ORA-04088: error during execution of trigger ' HR. TEST_TRIGGER'

  Can anyone tell, in what other scenarios, we get this error or recursive table mutation?

  Thanks in advance

  Hello

  When you create a trigger on a table, you cannot edit/query this table the trigger is not completed.

  You can use

  (1) transaction of Pragma autonomous

  (2) instead of row-level trigger, you have statement-level trigger

  (3) to 11 g, try with COMPOSITE trigger

  Try below to avoid it (a solution):

  create or replace trigger test_trigger

  before you insert or update or delete employees

  for each line

  declare

  PRAGMA AUTONOMOUS_TRANSACTION;

  an employees.first_name%type;

  Start

  Select first_name from people where job_id = "AD_PRES";

  COMMIT;

  end;

• Error in SQL syntax when inserting data to the table in the form of values using insert record

  Hello

  I was hoping that someone could help me.  I am creating a form of registration on a website to insert data into a database table.  When you try to create the form, I get the following error:

  
  

  You have an error in your SQL syntax; consult the manual for your version of the MySQL server for the right syntax to use near ' VALUES (name, regno, reason) leave (has ', 1, 'dddd')' at line 1

  I checked the syntax, but you don't know what's wrong.

  I am running Windows 7 with Dw cs6 and wamp server.

  Leave with the names of column (name, regno, reason) is the name of the table.

  Thank you for your help and please help me.

  The code is as below:

  <? php require_once('Connections/connect.php');? >

  <? PHP

  If (! function_exists ("GetSQLValueString")) {}

  function GetSQLValueString ($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")

  {

  If (via PHP_VERSION < 6) {}

  $theValue = get_magic_quotes_gpc()? stripslashes ($TheValue): $theValue;

  }

  $theValue = function_exists ("mysql_real_escape_string")? mysql_real_escape_string ($TheValue): mysql_escape_string ($theValue);

  Switch ($theType) {}

  case 'text ':

  $theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";

  break;

  case "long":

  case "int":

  $theValue = ($theValue! = "")? intval ($TheValue): 'NULL ';

  break;

  case "double":

  $theValue = ($theValue! = "")? doubleVal ($TheValue): 'NULL ';

  break;

  case "date":

  $theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";

  break;

  case "set":

  $theValue = ($theValue! = "")? $theDefinedValue: $theNotDefinedValue;

  break;

  }

  Return $theValue;

  }

  }

  $editFormAction = $_SERVER ['PHP_SELF'];

  If (isset {}

  $editFormAction. = « ? ». htmlentities($_SERVER['QUERY_STRING']);

  }

  If ((isset($_POST["MM_insert"])) & & ($_POST ["MM_insert"] == "form1")) {}

  $insertSQL = sprintf ("INSERT INTO leave (name, regno, reason) VALUES (%s, %s, %s)',

  GetSQLValueString ($_POST ['name'], "text").

  GetSQLValueString ($_POST ['reg'], "int").

  GetSQLValueString ($_POST ['reason'], "text"));

  @mysql_select_db ($database_connect, $connect);

  $Result1 = mysql_query ($insertSQL, $connect) or die (mysql_error ());

  }

  ? >

  < ! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict / / IN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd" > ""

  " < html xmlns =" http://www.w3.org/1999/xhtml ">

  < head >

  < meta http-equiv = "content-type" content = text/html"; charset = utf-8 "/ >"

  < title > online form let < /title >

  < name meta = "keywords" content = "" / > "

  < name meta = "description" content = "" / > "

  < link href = "styless.css" rel = "stylesheet" type = "text/css" media = "screen" / > "

  < / head >

  < body >

  < div id = 'wrapper' >

  < div id = "header" >

  < div id = 'menu' >

  < ul >

  < class li = "current_page_item" > < a href = "#" > home < /a > < /li >

  < li > < /li >

  < li > < /li >

  < li > < a href = "#" > on < /a > < /li >

  < li > < /li >

  < li > < a href = "#" > Contact < /a > < /li >

  < /ul >

  < / div >

  <!-end #menu->

  < div id = "Search" >

  < / div >

  <!-end #search->

  < / div >

  <!-end #header->

  < div id = "logo" >

  E - SCHOOL of CHRIST < h1 > < / h1 >

  < p > < / p >

  < / div >

  < hr / >

  <!-end #logo->

  <! - end #header - wrapper->

  < div id = "page" >

  < div id = "content" >

  < div class = "post" >

  < h2 class = "title" > leave application online < / h2 >

  < div class = "entry" > < / div >

  < / div >

  < do action = "<?" PHP echo $editFormAction;? ">" method = "POST" name = "form1" id = "form1" >

  < table width = "200" border = "2" cellspacing = "5" cellpadding = "5" >

  < b >

  < scope th 'row' = > name < /th >

  < td > < label for = "name" > < / label >

  < input type = "text" name = "name" id = "name" / > < table >

  < /tr >

  < b >

  < scope = "row" th > Reg No. < /th >

  < td > < label for = "reg" > < / label >

  < input type = "text" name = "reg" id = "reg" / > < table >

  < /tr >

  < b >

  < scope = "row" th > why < /th >

  < td > < label for = "reason" > < / label >

  < name textarea = 'reason' id = cols 'reason' = "45" rows = "5" > < / textarea > < table >

  < /tr >

  < b >

  < scope = "row" th > < /th >

  < td > < input type = "submit" name = "b1" id = "b1" value = "Submit" / > < table >

  < /tr >

  < /table >

  < input type = "hidden" name = "MM_insert" value = "form1" / >

  < / make >

  < / div >

  <!-end #content->

  < div id = "sidebar" >

  < ul >

  < li >

  Notice of < h2 > < / h2 >

  < p > students must present the appropriate documents supporting the reason for leave within 3 working days. < /p >

  < /li >

  < li id = "calendar" >

  Calendar < h2 > < / h2 >

  < div id = "calendar_wrap" >

  < table summary = "Calendar" >

  < caption >

  March 2014

  < / legend >

  < thead >

  < b >

  < th abbr = "Monday" scope = "col" title = "Monday" > M < /th >

  < th abbr = "Tuesday" scope = "col" title = "Tuesday" > T < /th >

  < th abbr = "Wednesday" scope = "col" title = "Wednesday" > W < /th >

  < th abbr = "Thursday" scope = "col" title = 'Thursday' > T < /th >

  < th abbr = "Friday" scope = "col" title = 'Friday' > F < /th >

  < th abbr = "Saturday" scope = "col" title = 'Saturday' > S < /th >

  < th abbr = "Sunday" scope = "col" title = 'Sunday' > S < /th >

  < /tr >

  < / thead >

  < tfoot >

  < b >

  < td abbr = "February" colspan = "3" id = "prev" > < a href = "#" title = "" > & laquo; Feb < /a > < table >

  < class td = "pad" > < table >

  < td abbr = "April" colspan = "3" id = "next" > < a href = "#" title = "" > Apr & raquo; < /a > < table >

  < /tr >

  < / tfoot >

  < tbody >

  < b >

  < td colspan = "5" class = "pad" > < table >

  < td > < table > 1

  < td > < table > 2

  < /tr >

  < b >

  < td > 3 < table >

  < td > < table > 4

  < td > 5 < table >

  < td > < table > 6

  < td > < table > 7

  < td > < table > 8

  < td > < table > 9

  < /tr >

  < b >

  < td > < table > 10

  < td id = 'today' > < table > 11

  < td > < table > 12

  < td > < table > 13

  < td > < table > 14

  < td > < table > 15

  < td > < table > 16

  < /tr >

  < b >

  < td > < table > 17

  < td > < table > 18

  < td > < table > 19

  < td > < table > 20

  < td > < table > 21

  < td > < table > 22

  < td > < table > 23

  < /tr >

  < b >

  < td > < table > 24

  < td > < table > 25

  < td > < table > 26

  < td > < table > 27

  < td > < table > 28

  < td > < table > 29

  < td > < table > 30

  < /tr >

  < b >

  < td > < table > 31

  < class td = "pad" colspan = "6" > < table >

  < /tr >

  < / tbody >

  < /table >

  < / div >

  < /li >

  < li > < /li >

  < /ul >

  < / div >

  <!-end #sidebar->

  < div style = "" clear: both; "> < / div >"

  < / div >

  <!-end #page->

  < div id = "footer" >

  < p > Copyright (c) University of Christ. All rights reserved. < /p >

  < / div >

  <!-end #footer->

  < / div >

  < div align = center > < / div > < / body >

  < / html >

  The LEAVE is a reserved word in MySQL. You can try to quote, but you are better to rename it.

• DB trigger error - update even table in the script of the trigger

  Hi all
  I have a table tab1, whenever any update is done on this table on column col1 and col2 also needs to get the update. (These are related to user forms can be updated only col1 form frontend)
  So I created a trigger as follows.
  ----------------
  CREATE OR REPLACE TRIGGER tri1
  AFTER UPDATE
  ON tab1
  FOR EACH LINE
  WHERE (NEW.col1 = 'YES')
  DECLARE
  PRAGMA AUTONOMOUS_TRANSACTION;
  BEGIN
  Tab1 SET col2 = 1 UPDATE
  WHERE transaction_id =: OLD.transaction_id;
  COMMIT;
  END;
  --------
  When there is no update on this table, I get following error. Please let me know if I'm missing something.
  ORA-00060: Deadlock detected while you wait resource
  ORA-06512: at "user1.tab1", line 5
  ORA-04088: error during execution of trigger 'user1.tab1 '.
  Please let me know if I'm not clear. Thank you
  
  Published by: DharV on August 23, 2011 05:17

  Your transaction_id is unique?

  If this is the case, then you could perhaps use AFTER UPDATE BEFORE UPDATE:

  CREATE OR REPLACE TRIGGER tri1
  BEFORE UPDATE
  ON tab1
  FOR EACH ROW
  WHEN (NEW.col1 = 'YES')
  BEGIN
     :NEW.col2 := 1;
  END;
  

  If your transaction_id is not unique - if you really want to update more than one line in tab1 - your update cannot update the same line that the trigger has responded, even with the use of an autonomous transaction. Then you could combine the BEFORE UPDATE trigger above with your own AFTER UPDATE, but then add ROWID! =: OLD. ROWID to where clause, but it would be a bad idea because some of your lines will be updated in a single transaction and others in another transaction.

  In general the autonomous transaction is not a great way to solve the problem of changing table within a trigger. I hope that you have a unique transaction_id and can do BEFORE the UPDATE - if it is then a better way is to save the update id in an overall picture in FOR EACH ROW triggers, and only then AFTER an UPDATE fire is NOT "for each line" update the list of saved IDs

• ERROR / T_ITEMS in the TABLE is changing, function of triggering/can not see ORA-06512... ?

  Hi all

  I CREATED THE TRIGGER TO CHECK NOM_ELEMENT BEFORE UPDATE ON THE T_ITEMS TABLE IF AN ANOTHER NOM_ELEMENT LIKE NOM_ELEMENT CURRENT OR NOT, IF AS AN ANOTHER NOM_ELEMENT DON'T SAVE UPDATED CURRENT NOM_ELEMENT.

  MY NO IS:

  1 - I CREATED the FUNCTION CALL CH_UNIQUE_ITEM_NAME

  CREATE OR REPLACE FUNCTION CH_UNIQUE_ITEM_NAME

  (NUMBER OF P_ID, P_ITEM_NAME IN VARCHAR2)

  RETURN NUMBER

  AS

  NUMBER OF X_COUNT;

  -FUNCTION "CH_UNIQUE_ITEM_NAME" TO CHECK NOM_ELEMENT LIKE OTHER NOM_ELEMENT OR NOT.

  BEGIN

  SELECT COUNT (ITEM_NAME)

  IN X_COUNT

  OF T_ITEMS

  WHERE ID! P_ID =

  AND UPPER (ITEM_NAME) AS UPPER (P_ITEM_NAME);

  RETURN X_COUNT;

  END CH_UNIQUE_ITEM_NAME;

  2. I CREATED TRIGGER CALL TRG_CH_UNIQUE_T_ITEMS

  CREATE OR REPLACE 'TRG_CH_UNIQUE_T_ITEMS' before FIRING

  UPDATE

  ON T_ITEMS FOR EACH LINE

  DECLARE

  NUMBER OF X_CHECK;

  BEGIN

  SELECT CH_UNIQUE_ITEM_NAME (: OLD.ID,: NEW.) NOM_ELEMENT) IN DOUBLE X_CHECK;

  IF (: NEW.) NOM_ELEMENT DISLIKES: OLD. Nom_element AND X_CHECK > 0)

  THEN RAISE_APPLICATION_ERROR (-20007, "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX");

  END IF;

  END;

  NOW WHEN I UPDATE ANY ITEMS FOUND ERROR "ERROR / T_ITEMS in the TABLE is changing, function of triggering/can not see ORA-06512.

  

  Please help me TO RESOLVE THIS ERROR. I TIRED TO SOLVE...

  Thank you

  You don't realize that you have just set a UNIQUE INDEX of several columns?

  create unique index index_name_uq on table_name( user#, upper(item_name) );
  

  In addition, a GUI Design point, (using the terms of the APEX) that you want to validate the data before submit you.

  (use a Page-level Validation)

  MK

• When I filled a form field using a query SQL result is displayed but not registered in the table.

  I write in the topic, I have created a form and in some of their fields, I used a SQL query to get information from a table based on the user who has been logging.

  The information displayed well, but when I press "Send button" loses information and the field in the table is shown empty.

  
  

  Anyone know what is happening?

  I enclose below a picture of the problem

  Concerning

  

  Hi ANTHONY,.

  ANTHONY wrote:

  I give you the credentials of my database, I hope you could do it works and most importantly, showing me what the error care...

  Feel free to change what you want in the application

  https://Apex.Oracle.com/pls/Apex/f?p=4550:1:2838412118981:

  BANCO_PRUEBAS

  ADMIN

  password

  It is interesting that, when I use APEX 5.0.1.00.06, I have some errors form appearing not using APEX 4.1.0.00.32

  Check your 77569 application-> Page 1. I have modified the page element attributes. Now it's working.

  Here are the changes (I will explain for P1_NOMBRE, did the same for the P1_APELLIDOS and P1_CATEGORIA):

  • 'Source' has become article attributed to him include:

  Source: Replacement always, value that exists in session state

  Source type: column database

  Source of value or an expression: NUMBER

  • The "Default" article now the following attributes:

  By default of Type: PL/SQL function body

  Default value:

  DECLARE
  
    L_NOMBRE B_LISTA_EMPLEADOS.NOMBRE%TYPE;
  
  BEGIN
  
    select NOMBRE
    into   L_NOMBRE
    from   B_LISTA_EMPLEADOS
    where  USERNAME = :APP_USER;
  
    RETURN L_NOMBRE;
  
  EXCEPTION
    WHEN NO_DATA_FOUND THEN
    RETURN NULL;
  
  END;
  

  Kind regards

  Kiran

• Errors when you create, modify, delete the upgrade userand user form

  Hello

  I get the error while trying to do operations on the user form... what they indicate. any suggestion would be appreciated.

  When tried to change the user to change the user organization, received this error. (changing other attributes works very well)

  Orchestration process moved to the step failed, and the corresponding error is - {0} []

  oracle.iam.platform.kernel.EventFailedException: an error occurred during execution of the core event handler.

  When I tried to upgrade user IOM form, received this error

  Inner exception: java.sql.SQLException: ORA-01691: impossible to extend lob IAMEXT_OIM segment. SYS_LOB0000354182C00002$ $ by 128 in tablespace IAMEXT_OIM

  When I tried to create a user received this error

  Process orchestration with the id 498509, failed with the IAM-3051103 error message: failed to create operation on the entity user at the stage of the action... [[

  oracle.iam.ui.platform.exception.OIMRuntimeException: IAM-2050243: process of Orchestration with the id 498509, failed with the IAM-3051103 error message: failed to create operation on the entity user at the stage of the action...

  Thank you

  This is related to your database and size.  Please contact your DBA with the error so they can expand the table.  You can always find the ORA code too: ORA-01691 impossible to extend LOB segment

  -Kevin

• What trigger to use to insert data into the table db forms

  Hello
  
  My form is current having a block of database with the table reference. When you enter data into the form field and click Save. Automatically record is inserted in the database table.
  I want to do this under manual insert. I changed the block of data to a data non-base. Where should I write the insert statement to insert data into the table.
  Is - shutter release key of the form-level validation?
  
  Please notify.
  
  Thank you
  Didi.

  You can guide me how to remove the message FRM-40401 no changes to save and instead, I wanted to put 1 transaction record successful... some like it like that.

  Hi didi.
  And this is my last post I'll sleep. ;)
  Take form level trigger named preform
  and write on it

  :SYSTEM.MESSAGE_LEVEL := 5;
  

  I hope this works...

  Hamid

  Mark correct/good to help others to get the right answers. *