Formatting string to date in BPEL

Similar Questions

• problems by analyzing a date format string...

  Hi all, I'm having a hard time to convert a date into a string.
  
  I was using to_char but after much research, I thought that it would be better to use convert so I do:
  
  SELECT CONVERT (VARCHAR (8), 'November 19, 2012', 112) twice;
  
  Where the specifications for 112 is YYYYMMDD but I get the error "ORA-00936: lack of expression ', guess is cause Oracle do not know how to read the string to be converted.
  
  How can I convert a YYYYMMDD string format string of the form dd mmm yyy (as described above)?
  
  Thanks in advance,

  It seems that your search will lead you to a SQL Server thread. SQL Server uses arbitrary numbers to represent date formats. Oracle does not - the number 112 is irrelevant for Oracle.

  In Oracle, you convert a date to a string using the function TO_CHAR

  SELECT to_char( date '2012-11-19', 'YYYYMMDD' )
    FROM dual
  

  Of course, this assumes that you start with a date (like I do with my date literal). If you start with a string representing a date and you want to convert it to a string that represents the same date in a different format, you will need to use a TO_DATE and a TO_CHAR to convert the original string to a date and date on another string

  SELECT to_char( to_date( '19 Nov 2012', 'DD Mon YYYY' ), 'YYYYMMDD' )
    FROM dual
  

  Justin

• Formatting: String > Date > String

  This is the best I could do, how to simplify this:
  

  value = new SimpleDateFormat("MMM dd, yyyy  HH:mm:ss").format((java.util.Date)new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").parse(value.toString()));

  NKA says:
  >
  The idea behind exceptions, is that you assume each step will work, and just write the code as if it does. If the method I call returns null instead of throwing an exception on failure, then I have to explicitly check for null at this point, rather than simply move on to the next step. With some exceptions, I know that if I even got to that next step, then nothing was wrong.
  >

  What is this means that the calling code must know that there is an exception thrown from code that was called?

  Well, Yes, if you call a method, and something goes wrong, you want to know about it, right? Catch the exception does not solve anything. All that's happened is always false. You catch an exception because you plan to do something about this.

  What I understand from what you said that the operation should fill in some way by throwing an exception back to the caller, and then, the caller must decide what to do with it.

  Exactly. And often - most of the time, in fact - that the appellant made with it will just continue to throw on top of the stack to its calling.

  What I do is that logs the error in the file and show a popup error message to the user. It works as the operation has not completed, so got canceled due to the outbreak of the exception.

  If you are at a high enough level layer of your code, which may be appropriate. However, I prefer to see this:

  try {
    formatDate();
  }
  catch (SomeException e) {
    showErrorMessageDialog();
  }
  

  than that:

  String s = formatDate();
  if (s == null) {
    showErrorMessageDialog();
  }
  

• Getting ORA-01861: literal does not match format string whith 2 passes DATE

  Not exactly a complete Newbie, but not an expert either but it left me speechless...
  
  I have two DATE columns in two different tables.
  In a select statement I compare these two in the where clause.
  
  ... and
  Table1. Column1 = table2.column1
  
  I then get
  
  ORA-01861: literal does not match the format string (and toad has highlighted the second column)
  
  I made a selection on the two tables to have a look at the values and found that, the values in a table (Toad), has this format: YYYYMMDD but in the other select table produces a column of values in the format YYYY-MM-DD
  
  I've made a desc on the two paintings and confirmed that the two are DATE columns...
  
  I've never seen different date formats in the same database... Thinking about it now (I'm home and can not verify) the two tables could be in different schemas... Different schemas can display different date formats?
  
  In any case, I tried to_date ([column] on the two (in the where clause) and got that a nonnumeric value has been found where a numeric value has been planned (this time for the first column).)
  
  So I guess I ask how come two different date formats and how to find the nonnumeric value in table 1 which contains lines of 5.8 million
  
  Any tips/ideas/tips?

  Please check back when you get back to work... I can almost guarantee you that one (if there is not both) of these columns is NOT a data type DATE (or timestamp).

  Or if they are, you are actually handled in a view or query to convert to this type of data.

• BUG: Date/Time Format string with %D in the format string crashes LabVIEW

  Do %D in the format string 'Format string DateTime' blocks LabVIEW 2009 SP1, as shown in this code snippet.  Should I use instead of %D %d but an incorrect format string should not crash LabVIEW.

  

  Fixed in 2010.

• format string IF (always kHz)

  Hello

  I'm reading values from rates to sample different RF bands DBL and using the value to create a file header to store binary data complex 32IQ to the file. I use the format based on string to do, but I still want to be represented in kHz, the sampling frequency and I have not thought of a way to force it is always the case. I use a format string of %.3p which, for sampling rate as 13125 and 400000 he returns 13,125 k and 400,000 k respectively, and that's what I want. However, one of my groups is 3750000 Hz and the format to a string returns Mr. 3,750, I would come back 3750,000 k instead. Does anyone have any ideas on how I might accomplish this?

  Thank you

  Tim

  If you divide the value by 1000 dbl and then apply the format to a string with the specifier %.3f you the kHz value.

  Ben

• How to convert a string of data to a table 1 d

  Dear all,

  I wonder if someone can help me.

  In the attached Elf, I have my program (in labview 8.6) who read the updates and the data of temperature for the time.

  I want to use temperature update in a calculation.  How can I get the new temperature I think it's in a format string and convert it into table 1 d?

  I tried, but the number I got the temperature wasn't the same temperature, which is shonw in the section of the program data.

  Could someone help me please?

  Kind regards

  You do not read the temperature, you read a binary file. You seem to be assuming that the string format, but do you really know? Nobody here can say since you do not have the file, if it is you need to use one of the functions of conversion of the string. And please, get rid of the local data variable. You're already usin shift registers. Do the same with the data from the file.

• Unit to the Format string

  Hi all

  If a control already has a unit, and move us to a format based on the string, its does not display is not the same exact unit. For example, under control has 'g' unit, while the format string has unit "kg".

  

  1. Is it possible to do the format to a string take the exact unit specified in the control?
  2. Is there a way to delete unit in the format based on the string, even if the digital order entry has a specified unit?

  Attachment VI to 2010.

  Thank you

  Knockaert

  Not automatically, no. The problem is that the designation of the unit in effects only control how data is displayed in a particular control. When wire you a value with units in a format to the node of the chain, it will express the value of the base unit for the wire.

  Mike.

• Compare the string to date?

  Hello everyone, I have a date recorded in this format string ' 25/05/2011' and I want to compare this string with the current date. I am able to do so if I divided the Date to a String [] string, but it's using a coding hard to compare dates, which does not work if I use: String CurDate = dateFormat.formatLocal (System.currentTimeMillis ()); Because the format is not always as DD/MM/YYYY, depending on the settings of the user's phone. I'm sure that there is a better way to compare two dates, could someone ' a please advise me on this matter. Please note that I have saved in this format DD/MM/YYYY Date String. Thanks in advance.

  create a calendar, to day/month/year and check if it's the day same long http://www.blackberry.com/developers/docs/6.0.0api/net/rim/device/api/util/DateTimeUtilities.html#is... )

• Date conversion madness! String to date and vice versa

  Hello, I am working on an application targeting the OS version 4.5.x. I read a lot of messages and the links on this topic and can't seem to make the correct code.

  OK, here's the problem. I ask a timestamp date string to a server. The timestamp is the local time on the server (IS / PST etc.) and not GMT.

  My application must take time and subtract a number of days ranging from 1 day to 1 month. to get a "start" date The application must then provide the start and end date in a string format that it understands. Seems simple isn't?

  Here's the catch, however the time stamps should NOT be changed by the local what is using the device. For example, a device in Italy can contact the server located in Ottawa and ask a timestamp, the calculations shouldn't care about DST or time zone. Just take the supplied date and subtract a fixed number of days from her. Nothing more or less. This proved incredibly hard to do. first the HttpDateParser.parse (ServerTimeStamp) will be the subject of Date GMT and my problem is back to the zone specified in ServerTimeStamp.

  Thanks for any help in advance.

  My method

  public String getDAFIXMLRange (String ServerTimeStamp) {}
  String szRange;
  First analyze the incoming date and record them at the time of the last election.
  Day DAFIEndDate = new Date (HttpDateParser.parse (ServerTimeStamp));
  m_lLastPollTime = DAFIEndDate.getTime ();
          
  define the offset. Pre-programmed for simplification.
  lOffsetNumberOfSeconds long = 2 * 24 * 60 * 60;
          
        
  Calculate the start date by subtracting the offset. Multiply by 1000 to convert to milliseconds!
  Date DAFIStartDate = new Date (DAFIEndDate.getTime () - (lOffsetNumberOfSeconds * 1000));

  !!!!!!!!!!!!! HOW the DATEFORMAT OBJECT is used to get the output format ' yyyy-MM-dd' you HH: mm: "without the marker of time zone. The server knows that it is local to it. !!!!!!!!!!

  Now format the objects date as a string that includes the XML server.
  DateFormat DafiDateFormat = DateFormat.getInstance (); ' YYYY-MM-dd' you HH.

  !!!!!!!!!!!!!! THIS IS THE PART I'M CONFUSED on, with the HELP of zone to create the good date. !!!
  Time zone tz = TimeZone.getTimeZone ("IS");
  int adjEST = tz.getRawOffset ();

  Convert 'em in string format.
  String szDAFIStart = DafiDateFormat.format (DAFIStartDate);
  String szDAFIEnd = DafiDateFormat.format (DAFIEndDate);

  Replace the date calculated in the end segment ranges date XML.
  szRange = statItems.replaceAll (XML_DATERANGE, "TAGSTARTTIME", szDAFIStart);
  szRange = statItems.replaceAll (szRange, "TAGENDTIME", szDAFIEnd);
  Return szRange;
  }

  Hello

  Yes would be better if the server could provide you date to the GMT time zone, or date as a long.

  But if you can't ask the case on the server, one way might be to manually parse your string and create a new date of parameter values in a calendar, something like this

  Calendar cal = Calendar.GetInstance ();

  Cal.Set (Calendar.DAY_OF_MONTH, date)

  Cal.Set (Calendar.MONTH, month-1)

  Cal.Set (Calendar.YEAR, year);

  ' set the new time with the values, you must cal.setTime (cal.getTime ()-,...);

  and then put the date with SimpleDateFormat.

  I think that this could be a solution if you know the format string you recived that date and it won't change.

  I'm not sure but maybe it could be a solution.

  Kind regards

• literal does not format string when collecting in bulk.

  Hello
  should work with 10.2 DB.
  

    1  declare
    2    type vcArray is table of varchar2(10);
    3    type vdateArray is table of date;
    4    l_group#   vcArray;
    5    l_status vcArray;
    6    l_date vdateArray;
    7    cursor c is select to_char(sysdate, 'YYYYMMDD_HH24MISS') data, GROUP# , status from v$log;
    8  begin
    9  open c;
   10  loop
   11     fetch c bulk collect into l_date, l_group# , l_status;
   12     for i in 1..l_date.count
   13     loop
   14      dbms_output.put_line('l_date: ' || l_date(i));
   15     end loop;
   16     exit when c%notfound;
   17  end loop;
   18  close c;
   19* end;
  declare
  *
  ERROR at line 1:
  ORA-01861: literal does not match format string
  ORA-06512: at line 11

  Just try to display loop a few output of v$ log view :).
  Concerning
  GregG

  Hello

  GregG says:
  Hello
  should work with 10.2 DB.

  1  declare
  2    type vcArray is table of varchar2(10);
  3    type vdateArray is table of date;
  4    l_group#   vcArray;
  5    l_status vcArray;
  6    l_date vdateArray;
  7    cursor c is select to_char(sysdate, 'YYYYMMDD_HH24MISS') data, GROUP# , status from v$log;
  8  begin
  9  open c;
  10  loop
  11     fetch c bulk collect into l_date, l_group# , l_status;
  12     for i in 1..l_date.count
  13     loop
  14      dbms_output.put_line('l_date: ' || l_date(i));
  15     end loop;
  16     exit when c%notfound;
  17  end loop;
  18  close c;
  19* end;
  declare
  *
  ERROR at line 1:
  ORA-01861: literal does not match format string
  ORA-06512: at line 11
  

  Just try to display loop a few output of v$ log view :).
  Concerning
  GregG

  To_char, as the name suggests, returns a VARCHAR2, c.data is therefore a VARCHAR2, but you try to store it in an array of DATEs.
  Do not use TO_CHAR. In fact, there is no need to use a column for that at all, because SYSDATE will always be the same.

  Try something like this:

  declare
      type vcArray is table of varchar2(10);
      l_group#   vcArray;
      l_status vcArray;
      cursor c is select GROUP# , status from v$log;
      run_time DATE;
    begin
    open c;
    loop
       run_time := SYSDATE;
       fetch c bulk collect into l_group# , l_status;
       for i in 1..l_group#.count
       loop
        dbms_output.put_line('run_time: ' || run_time);
       end loop;
       exit when c%notfound;
    end loop;
    close c;
  end;
  /
  

  Published by: Frank Kulash on 12 March 2012 10:26
  Added example.

• The format of the date of the next qeries even!

  After you change the value of NSL_date_format by default, why not the format of the date of the next qeries even?
  

  SQL> alter system set nls_date_format='yyyymmdd' scope=spfile;
  
  System altered.
  
  SQL> shutdown immediate;
  
  SQL> startup
  
  SQL> select sysdate from dual;
  
  SYSDATE
  ---------
  12-MAY-11
  
  SQL> show parameter nls_date_format;
  
  NAME                                 TYPE        VALUE
  ------------------------------------ ----------- ----------
  nls_date_format                      string      yyyymmdd
  
  SQL> SELECT value FROM v$nls_parameters WHERE parameter = 'NLS_DATE_FORMAT';
  
  VALUE
  ----------------------------------------------------------------
  DD-MON-RR

  Please read "why not the NLS_DATE_FORMAT in my work of init.ora sometimes ' http://asktom.oracle.com/pls/asktom/ASKTOM.download_file?p_file=6551282707163926958

• How to format a short date in the form YYYY

  Hello
  
  I would like to be able to show the form of YYYY year when I use DateFormat (int, locale aLocale style) and the locale of the user, and without hard-coding style in the source code.
  
  Here is my code:

  import java.text.DateFormat;
  import java.util.Calendar;
  import java.util.Locale;
  
  public class TestDates {
  
       public static void main(String[] args) {
            Calendar calDate = Calendar.getInstance();
            DateFormat fd = DateFormat.getDateInstance(DateFormat.SHORT, Locale.getDefault());
            System.out.println(fd.format(calDate.getTime()));
       }
  }

  The output on my machine is: 25/02/11
  But I'd like to see: 25/02/2011
  
  Is this possible? and how?
  
  Thank you for your help.

  839922 wrote:
  But then I have to hardcode the style in the source code as "MM/DD/YYYY" or ' dd/MM/YYYY', which is not desirable.

  No, you do not have to encode it. You can read from a file or user input, or whatever during execution. It is just a string. Not all channels are determined at compile time.

  I need the date of formatting to track the preferences of users that they enter in their BONES to their taste DD/MM/YYYY or MM/DD/YYYY or what they prefer.

  Then read this preference when running and create a SimpleDateFormat him.

  Currently, if I change my preferences in my operating system and set the "Format of short Date" as DD/MM/YYYY, I get 25/02/2011 in all applications except my java application, there are 25/02/11. If I go back and change the preferences of OS to MM.dd.YYYY, I see 02.25.2011 in all applications except my java application that shows 02.25.11

  So it seems that the question is now, "How to read this OS" preference "of Java? That, I don't know, and you may not be able to in the general case.

• SQLERRM: ORA-01861: literal does not match the format string

  Here's what I want to do.
  
  Select to_char (to_date (estimatedshipdate, 'DD-MM-AA'), 'YDDD')
  of cram_stg
  where estimatedshipdate = 14 January 11 ';
  
  TO_CHAR (TO_DATE(ESTIMATEDSHIPDATE,'MM-DD-YY'), 'YDDD')
  -----------------------------------------------------
  1014
  
  
  1 selected lines
  
  
  I want to convert the shipping date is DD-MM-AA YDDD, but in my program:
  
  v_est_ship_date varchar2 (10);
  
  ESTIMATEDSHIPDATE VARCHAR2 (10) in a TABLE
  
  v_est_ship_date: = to_char (to_date (CRAM_PTCLICK_REC.estimatedshipdate, 'DD-MM-AA'), 'YDDD');
  
  I get this problem
  
  SQLERRM: ORA-01861: literal does not match the format string
  
  
  I want to assign the result of the function to_char to v_ext_ship_date. What I am doing wrong? Thank you.

  Hello

  It's just one of the reasons for which the storage of dates as VARCHAR2 columns is a bad idea.
  Apparently, some (maybe just one) this column values is not the right format. To find malformed (the kind that cause the ORA-01861) values, you can do something like this:

  SELECT  primary_key
  ,     estimatedshippingdate
  FROM     cram_stg
  WHERE     TRANSLATE ( estimatedshippingdate
              , '012345678'
              , '999999999'
              ) != '99-99-99'
  ;
  

  It intercepts any mistakes as the 32nd day of the month (let alone ' 02-29-11'). See the next thread of a way to do this:
  Re: How to select valid dates only

• String to date Conversion inside XSLT

  Hi all
  
  I want to convert a string of (Eg: 2009-12-06 00:00:00) to a type of format date yyyy-mm-dd Vice versa.
  
  I managed to convert the Date to a string
  
  < element name = "input" type = "date" / > (schema)
  
  < element name = "result" type = "string" / > (schema)
  
  
  < ns1:SIDtoCRMProcessResponse >
  < ns1:result >
  < xsl: value-of select = "xp20:format - dateTime (/ ns1:SIDtoCRMProcessRequest / ns1:input,)" [M01] / [D01] / [Y0001] [H01]: [m01]: [s01] ")" / > "
  < / ns1:result >
  < / ns1:SIDtoCRMProcessResponse >
  
  
  but when try to String in Date
  
  < element name = "input" type = "string" / > (schema)
  
  < element name = "result" type = "date" / > (schema)
  
  < ns1:CRMToSIDProcessResponse >
  < ns1:result >
  < xsl: value - of select = "xp20:format - dateTime(/ns1:CRMToSIDProcessRequest/ns1:input,"[Y0001]-[M01]-[D01]")" / > "
  < / ns1:result >
  < / ns1:CRMToSIDProcessResponse >
  
  his failure
  
  I think the format dateTime function expects the entry date. Can someone kindly help me how to convert String to Date inside a xsl without using the external java function.
  Thank you

  you could use some dirty concatination to build the format yourself.

  not going to win the beauty contest but