Formula using the following string...

Hi all

Given a set of strings that can is be parsed (see format below), possible to do a TWG
a set of such strings - i.e. the chain may have the form (from
another thread (pricing using the string formula)) the chain is a bulk
dicount "record" for a product - product code not included for now.
I want to use SQL exclusively, but am open to suggestions - examples
using WITH are especially welcome - has spent time last night, a truck load
rising WITH (of no use, it must be added ;))

_100 (20) 90 (50) 80_ String format

See the code below*-20 first purchased items cost 100,.
the cost of the next 50 90 and all the foregoing is 80/unit.

What I would like is to be able to build a 'table' that I can join real Oracle
tables - imagine these "records" of the chain are coming thick and fast and for reasons x, y
or z, prices can be written to a permanent table. A product code must be
included, but I think fundamental analysis once did, adding such a code should not
be a problem.

So, if I have a set of these strings, how build a TWG?
If it is the right approach.

Any ideas, references, URL - be it, much appreciated.

What would be really cool is if the code could take a product with an arbitrary
number of discounts - 2, some 3 (that is, for example), 4... & c...

TIA

Paul...

Code-Cerca Trova of another thread
with t as(
  select '100(20)90(50)80' str from dual
)
select regexp_replace(regexp_substr(str,'\)\d*',1,2),'\)|\(','')from t  -- 80
--select regexp_replace(regexp_substr(str,'\d*(\)|\()',1,1),'\)|\(','')from t  -- 100
--select regexp_replace(regexp_substr(str,'\d*(\)|\()',1,2),'\)|\(','')from t  -- 20
--select regexp_replace(regexp_substr(str,'\d*(\)|\()',1,3),'\)|\(','')from t  -- 90 
--select regexp_replace(regexp_substr(str,'\d*(\)|\()',1,4),'\)|\(','')from t  -- 50
My own efforts (did not know that Cerca Trova had done) - even if it's rubbish, at least
I tried ;)
WITH StrTab AS  -- *returns 100* = Price1
(
  SELECT '100(20)90(50)80' iStr FROM Dual
)
  SELECT(
          TO_NUMBER(SUBSTR(iStr, 1, INSTR(iStr, '(', 1, 1) -1))
        ) AS  "Price1" FROM StrTab;
Below retrieves the number 20 - sample - allows to extract all the numbers
SELECT -- *returns 20* = Quantity 1
TO_NUMBER(
SUBSTR('100(20)90(50)80', 
(INSTR('100(20)90(50)80', '(', 1, 1) + 1) , 
(INSTR('100(20)90(50)80', ')', 1, 1) - (INSTR('100(20)90(50)80', '(', 1, 1) + 1)))) 
AS "Quantity1" FROM Dual;
Published by: Paulie 9 may 2012 12:32

Published by: Paulie 9 may 2012 12:36

Hello

Whenever you have a problem, please post a CREATE TABLE and INSERT statements for a small example of data like this:

CREATE TABLE     table_x
(      id     NUMBER (6)     PRIMARY KEY
,      txt     VARCHAR2 (30)
)
;

INSERT INTO table_x (id, txt) VALUES (0, NULL);
INSERT INTO table_x (id, txt) VALUES (1, '75');
INSERT INTO table_x (id, txt) VALUES (2, '100(10)80');
INSERT INTO table_x (id, txt) VALUES (3, '100(20)90(50)80');
COMMIT;

In addition, to say what version of Oracle you are using. The query below work Oracle 10.1 and higher:

WITH     cntr          AS
(
     SELECT     LEVEL     AS n
     FROM     dual
     CONNECT BY     LEVEL     <= 5     -- worst case
)
,     rates          AS
(
     SELECT     x.id
     ,     x.txt
     ,     c.n
     ,     TO_NUMBER ( REGEXP_SUBSTR ( '0)' || x.txt
                                 , '[^()]+'
                                 , 1
                                 , (2 * c.n) - 1
                           )
                 )        AS start_qty
     ,     TO_NUMBER ( REGEXP_SUBSTR (  x.txt
                                 , '[^()]+'
                                 , 1
                                 , (2 * c.n) - 1
                           )
                 )        AS rate
     FROM     table_x        x
     JOIN     cntr        c  ON  c.n <= LENGTH (txt)
                                 + 1
                           - LENGTH (REPLACE (txt, '('))
)
SELECT       *
FROM       rates
ORDER BY  id
,            n
;

Output:

`       ID TXT                                     N  START_QTY       RATE
---------- ------------------------------ ---------- ---------- ----------
         1 75                                      1          0         75
         2 100(10)80                               1          0        100
         2 100(10)80                               2         10         80
         3 100(20)90(50)80                         1          0        100
         3 100(20)90(50)80                         2         20         90
         3 100(20)90(50)80                         3         50         80

If you use the WITH clauses above in any question, you can use rates in table form in the following parts of the query.

This assumes you know an upper limit for the number of items in the string. I took 5 different rates above, but you can easily change that to any fixed number. You can also derive the exact number of data themselves. I'll leave that as an exercise.

You can use the analytical function of LEAD to add another column, end_qty, rates.

Published by: Frank Kulash, 9 may 2012 10:24
It also means that txt is well-formed. A space before or after the parentheses is probably correct, but in additional brackets, letters, several decimal places or sign in the same 'number' and things like that will cause all errors.

START_QTY is a misleading name; I should have used something like LOW_QTY or PREV_QTY. In the example above, the row with id = 3 and start_qty = 20 applies in reality to the amount above 20, i.e. 21 to 50 inclusively (since 50 is START_QTY for this id).

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